Removing The Duplicates
Aug 2, 2000I need to remove the duplicates from a table. If a record exits 4 times in a
table I need to delete 3 records and retain only one occurance of that.
I need a query to do this.
Can anybody help.
-Rajesh
ADVERTISEMENT
Removing Duplicates
Jan 27, 2005I have a members table and have added an extra few thoushand members to it. Now I need to remove the duplicates.
It doesnt matter which duplicate i remove as long as there are unique email addresses.
so here is the format of the table:
id
email
firstname
lastname
datebirth
if i do a:
SELECT COUNT(DISTINCT Email) AS Expr1
FROM Customer
it returns 21345
and
SELECT Count(Email)
FROM Customer
returns 28987
I can get the unique email addresses into another table by going:
SELECT DISTINCT emailaddress INTO DistinctCustomer
FROM Customer
but this will only return unique email addresses. How do i select distinct email address and all other fields into a new table? or just remove duplicates where email address appears more then once?
Thanks in advance
Tom the SQL beginner
Removing Duplicates
Jul 20, 2005HiI have inherited a web app with the following table structure, and need toproduce a table without any duplicates. Email seems like the best uniqueidentifier - so only one of each e-mail address should be in the table.Following http://www.sqlteam.com/item.asp?ItemID=3331 I have been able toget a duplicate count working:select Email, count(*) as UserCountfrom dbo.Membersgroup by Emailhaving count(*) > 1order by UserCount descBut the methods for create a new table without duplicates fail. My code forthe 2nd method is:sp_rename 'Members', 'temp_Members'select distinct *into Membersfrom temp_MembersTable....CREATE TABLE [dbo].[Members] ([MemberID] [int] IDENTITY (1, 1) NOT NULL ,[Username] [varchar] (10) COLLATE Latin1_General_CI_AS NOT NULL ,[Password] [varchar] (10) COLLATE Latin1_General_CI_AS NOT NULL ,[Email] [varchar] (50) COLLATE Latin1_General_CI_AS NOT NULL ,[Title] [varchar] (10) COLLATE Latin1_General_CI_AS NOT NULL ,[FirstName] [varchar] (50) COLLATE Latin1_General_CI_AS NOT NULL ,[Surname] [varchar] (50) COLLATE Latin1_General_CI_AS NOT NULL ,[Address1] [varchar] (35) COLLATE Latin1_General_CI_AS NOT NULL ,[Address2] [varchar] (35) COLLATE Latin1_General_CI_AS NOT NULL ,[City] [varchar] (25) COLLATE Latin1_General_CI_AS NOT NULL ,[Country] [varchar] (25) COLLATE Latin1_General_CI_AS NOT NULL ,[Profession] [varchar] (50) COLLATE Latin1_General_CI_AS NOT NULL ,[Publication] [varchar] (40) COLLATE Latin1_General_CI_AS NOT NULL ,[DateAdded] [smalldatetime] NOT NULL ,[SendMail] [smallint] NOT NULL) ON [PRIMARY]GOThanks B.
View 2 Replies View RelatedRemoving Duplicates
May 19, 2008
Using a sort transform to remove duplicates takes a very long time to execute.Is there a better way to remove duplicate information.
I have alot of duplicates within the data.
I would like to know a better way than using sort transform
Please let me know
Error When Removing Duplicates
Jan 12, 2006I found a query on here to find all my duplicates (altered to fit mine)
----
select * from yourtable
where WCD_no in
( select WCD_no from yourtable
group by WCD_no having count(*) > 1 )
----
and it works great. However, when I try and delete one of these, I get the following error message.
"key column is insufficient or incorrect. Too may rows were affected by update"
Any idea on how I can delete these without having to drop the table or anything?
Removing Duplicates From Inner Joins
Sep 27, 2004Hi There,
I was wondering if someone could help me with the results on this query, at the moment I am getting values repeated and I was wondering if it was possible to have some of the columns grouped, I have tried to have grouping at the end of the query but this still did not group the rows.
Thanks in advance for your answer - Sean
The structure that i'm trying to acheive is like the following:
with each colour having multiple quantitys for each size:
colourdesc| sizedesc | xs | s | m | l
-----------
black |qoh| | 0 | 2 | 0 | 7
-----------
white |qoh| | 0 | 0 | 0 | 0
-----------
!-- query results
+------------+------+------+-----------+--------+---------------+----------+
| qoh | size | shop | style | colour | colourdesc | sizedesc |
+------------+------+------+-----------+--------+---------------+----------+
| 0000000007 | 6 | 1 | 10475RIB1 | 2 | BLACK | L |
| 0000000000 | 6 | 1 | 10475RIB1 | 36 | CORRECTOR6771 | L |
| 0000000000 | 6 | 1 | 10475RIB1 | 15 | SPEARMINT6581 | L |
| 0000000000 | 6 | 1 | 10475RIB1 | 6 | WHITE | L |
| 0000000007 | 5 | 1 | 10475RIB1 | 2 | BLACK | M |
| 0000000000 | 5 | 1 | 10475RIB1 | 36 | CORRECTOR6771 | M |
| 0000000000 | 5 | 1 | 10475RIB1 | 18 | MERINGUE4016 | M |
| 0000000000 | 5 | 1 | 10475RIB1 | 6 | WHITE | M |
| 0000000002 | 4 | 1 | 10475RIB1 | 2 | BLACK | S |
+------------+------+------+-----------+--------+---------------+----------+
!--- query
select qoh
, shopsales.size, shopsales.shop, shopsales.style, shopsales.colour, co.colourdesc, sz.sizedesc
from shopsales
inner
join shops
on shopsales.shop = shops.shop
inner
join colours co
on shopsales.style = co.style
and shopsales.colour = co.colour
inner
join sizes sz
on shopsales.style = sz.style
and shopsales.size = sz.size
where shopsales.shop = 1
and shopsales.style = '10475RIB1'
Removing Duplicates In The Table
Mar 21, 2014The database has Name,Email, and skill. Though the name is distinct it is repeated as it has different skills. I would like to remove duplicate names and add the corresponding skill to the only one row.
From the stored procedure, combining 3 tables I got the output as:
NameemaildepartmentSkill
ArunemailidTech teamTechnical
ArunemailidTech teamLeadership
ArunemailidTech teamDecision Making
BinayemailidMarketingTechnical
BinayemailidMarketingDecision Making
I would like to remove the duplicate Name fields and combine the Skill in a single row as other fields are same.
So the output should be
NameemaildepartmentSkill
ArunemailidTech teamTechnical, Leadership, Decision Making
BinayemailidMarketingTechnical,Decision Making
Reg: Duplicates Removing Problem
Jul 5, 2007I have Data like below
TableA
Col1 Col2 Col3
1 'Test One' 4/7/2007
1 'Test One-1' 4/7/2007
2 'Test' 4/7/2007
3 'Test Three' 4/7/2007
3 'Test Three-1' 4/7/2007
3 'Test Three-2' 4/7/2007
I need to delete the duplicate records[Latest record has to be remaining like that] from above table. i need the out put like below
Col1 Col2 Col3
1 'Test One-1' 4/7/2007
2 'Test' 4/7/2007
3 'Test Three-2' 4/7/2007
If any body know the solution please help me.
Regards
Hanu
Removing Duplicates To Create A Primary Key
Jan 3, 2008Hi, I'm in the midst of an Access 2003 to SQL server 2000 upsizing project and have come across a table on Sql Server that has a field that looks like it's supposed to be the PK but it contains duplicates. What I'd like to do is to have a cursor start at the first value and increment the next value by 1. Could someone explain how I'd go about this?
Many thanks,
Peter
Process For Removing Duplicates In Table?
May 18, 2012I have a very large table that can contain up 3 to 5 duplicate records. Every month around 100,000 new records come in. Sometimes it's an ammended record, other times is just duplicated by error.
Is it possible to keep the latest record dumped into the table and delete the others? Does SQL track the order of the data being dropped into the table?
The layout would look like this. There are 10-15 other columns in the table where adjustments can also be made.
Lease# Year Month Production
12345 2008 10 1,231
12345 2008 10 1,250
12345 2008 10 1,250
Removing Duplicates Selecting MIN Date
Jun 4, 2014I have table like this and I need to remove the duplicates selecting the Min Date
IDDate Alloc ProdWater Tub Cas
3752011-10-10 00:00:00.00000014.70
3752011-10-11 00:00:00.00000014.70
3232014-04-24 00:00:00.000000352555.7
3232014-04-26 00:00:00.000000352555.7
3562014-04-01 00:00:00.000000318.8471.1
3562014-04-02 00:00:00.000000318.8471.1
3562014-04-03 00:00:00.000000318.8471.1
3562014-04-04 00:00:00.000000318.8471.1
3232014-05-20 00:00:00.000000649.1976.9
3232014-05-21 00:00:00.000000649.1976.9
3232014-05-22 00:00:00.000000649.1976.9
I would like my result set to be like this:
3752011-10-10 00:00:00.00000014.70
3232014-04-24 00:00:00.000000352555.7
3562014-04-01 00:00:00.000000318.8471.1
3232014-05-20 00:00:00.000000649.1976.9
Transact SQL :: Way To Keep Duplicates Without Removing Group By
May 6, 2015I'm trying to pull records from a source/staging table where there is a duplicate row in it.I don't need that as the requirement is to garbage in /garbage out.when I do that from mart and use joins btw fact and dimensions, Im not getting this duplicate record as Im using distinct/group by. If I removed it, then it returns more than 3000 rows which is not correct. Is there a way I can keep these duplicates without removing group by...Im using correct joins and filters.
View 5 Replies View RelatedHi, Pls See The Query Inside, Reg. Removing Duplicates..
Mar 17, 2008-- declared variables
declare @database_name varchar(100), @table_name varchar(100), @primary_key_field varchar(100)
declare @list varchar(8000)
-- set values to variables
set @list = ''
set @database_name = 'data200802_dan'
set @table_name = 'other02'
set @primary_key_field = 'callid'
use database
select @list = @list + column_name + ', '
from information_schema.columns
where table_name = @table_name --table name
and column_name != @primary_key_field --unique identifier
select @list = substring(@list, 1, len(rtrim(@list)) - 1)
--above 5 lines btw came from a helper in the msdn forum. thanks
SELECT DISTINCT @list
INTO '#' + @table_name
FROM @table_name
@table_name + ':'
IF (SELECT COUNT(*) FROM @database_name + '.dbo.' + @table_name) = 0
BEGIN
INSERT INTO
@database_name + '.dbo.' + @table_name + '(' + @list + ')'
SELECT
@list
FROM
'#' + @table_name
END
ELSE
BEGIN
DELETE @database_name + '.dbo.' + @table_name +' ( ' + @list + ')'
GOTO @table_name
END
DROP TABLE '#' + @table_name
the query above is basically.. selecting all the fields from a table in database W/OUT their primary key. then putting them in a temp table.. delete all the records in the original table. then paste the records from the temp table into the original table.
is there a way for this to work? i don't know how to use the variables w/ this script. please help me correcting this query..
this is for removing duplicates btw. thanks!
Removing Duplicates Based On Highest Record ID
Dec 20, 2013I have a query which finds duplicate spec_items linked to a work order. What I want to do it remove the duplicates (and in some cases there will be more than one) leaving only the record with the highest [sr.id]
select sr.id, sr.linked_to_worknumber, sr.spec_checklist_id from spec_checklist_remind sr inner join spec_checklist_remind sc on sc.linked_to_worknumber = sr.linked_to_worknumber
group by sr.id,sr.linked_to_worknumber, sr.spec_checklist_id
Having sr.spec_checklist_id = 30 and count(*)>1
order by sr.linked_to_worknumber
Sample of query results:
idlinked_to_worknumberspec_checklist_id
18323IP-DN-03377430
24229IP-DN-03377430
18294IP-DN-03380830
28027IP-DN-03380830
18295IP-DN-03381030
19924IP-DN-03381030
In the 3 cases, I would want to retain only records with ids 24229,28027 and 19924.
Transact SQL :: Removing Duplicates Rows With OVER Clause
Jun 2, 2015I have an existing stored table with duplicate rows that I want to delete.Using a cte gives me
WITH CTE AS
(
SELECT rn = ROW_NUMBER()
OVER(
PARTITION BY employeeid, dateofincident, typeid, description
ORDER BY Id ASC), *
FROM dbo.TableName
)
DELETE FROM cte
WHERE rn > 1
This is what I want to do basically. But this is only deleting in my CTE, is there anyway I can update my existing table "TableName" with this, without using temp tables?
Removing Duplicates Records From A Column Populate Randomly?
Jan 26, 2015I ran this query to populate a field with random numbers but it keeps populating with some duplicate records. how I can remove the duplicates?
UPDATE APRFIL
SET ALTATH = CONVERT(int, RAND(CHECKSUM(NEWID())) * 10000);
Below are sample output that I need the dupes not show. The table already exist and its sql 2008
155957
155957
155968
155974
155976
15599
155990
155997
155997
156005
156008
T-SQL (SS2K8) :: Rank Duplicates But Only Rows Involved In Duplicates?
Oct 22, 2014I have a table with 22 million Business records. I can see that there are duplicates when I group by BusinessName and Address and Phone. I'd like to place only the duplicates into a table, with a ranking, oldest business key gets a ranking of 1.
As a bonus I'd like each group to have a distinct group name (although not necessary, just want to know how to do this)
Later after I run more verifications to make sure these are not referenced elsewhere I'll delete everything with a matchRank > 1 out of the main Business table.
DROP TABLE [dbo].[TestBusiness];
GO
CREATE TABLE [dbo].[TestBusiness](
[Business_pk] INT IDENTITY(1,1) NOT NULL,
[BusinessName] VARCHAR (200) NOT NULL,
[Address] VARCHAR(MAX) NOT NULL,
[code]....
Converting Duplicates Records Into Non Duplicates?
Jan 26, 2015Is there a query or a way to convert duplicates value in a column to non duplicates.
View 14 Replies View RelatedSQL Duplicates
Mar 2, 2006I need some help.
I have created a database that looks like the following:
FirstName Table link to Main Table.
I have created a Stored procedure that looks like this:
Create procedure dbo.StoredProcedure
(
@FirstName varchar(20)
)
Declare FirstNameID int
Insert Into Main Table
(
FirstName
)
Values
(
@FirstName
)
Select @FirstNameID = Scope_Identity()
How could I redesign this to check if a value exists and if it exists then simply use that value instead of creating a new duplicate value?
Thanks!!
Getting Rid Of Duplicates
Jun 27, 2001I have a dilema..... I have a databas eof about 60,000 users and i need to get rid of those users where there is a duplicate email address. I have written an asp utilty that works but is far too taxing on our little server and i thinkk itwill kill it. what it does is for each email address it compares it against all the others.... so for each address it checks against 60,000 other records 60,000 times.... you know what i mean. its pretty phucked.... i tested it on just one record and took about 5mins.
anyway ive been trying to do it in SQL with no luck
here is a simplified version of my dilema
*****
NAMEEMAILAGE
tomtom@mail23
tombomb tom@mail23
petepete@email23
davecool@mail21
stevesteve@mail17
marycool@mail89
thomas tom@mail13
richrich@mail65
richdick@mail65
tomtom@mail23
tomtom@mail23
so what i want to do is cut it down so there are no duplicate email addresses. I want the table looking like this:
*****
NAMEEMAILAGE
tomtom@mail23
petepete@email23
davecool@mail21
stevesteve@mail17
richrich@mail65
richdick@mail65
Can you think of a way to do this?
i tried the following but it gets rid of duplicates of other fields which is not what i want to do
CREATE table distinct_records
SELECT name, Email, Age
FROM duplicate_records
GROUP BY name, Email, Age;
any ideas guys?
thanks
tom.harrow@netpoll.net
Duplicates
Nov 7, 2005i've imported a number of spreadsheets into a database
the schema is
directoryid firstname, lastname, extension
703168 Andrew Lim 78094
703154 Joseph Egan 78888
704548 Andrew Lim 78094
I realized the spreadsheet had a large number of duplicates. How can i delete the duplicates ?
like deleting directoryid 703168 only.
Duplicates
Nov 9, 2005i'm trying to get duplicates out of the my database
SELECT COUNT(*) AS Amount,
Firstname,
surname,
Internalextension
FROM iac.dbo.sf_profil
GROUP BY FirstName, surname, internalextension
HAVING COUNT(*) > 1 order by firstname, surname
How do i alter the query just retrieve records which have firstname and lastname which are similar but different extension numbers ?
Duplicates
May 8, 2008Hi,
This is the query which shows me the duplicates
Some of the records have more than one records
I would like to know how to delete the extra records so that I will end up with one record per row.
select
Pricing_Source,
VaR_Identifier,
Price_Date,
PX_Last,
Count(*) as 'count'
from
tblPricesClean
group by
Pricing_Source,
VaR_Identifier,
Price_Date,
PX_Last
having count(*) > 1
order by
count desc
Duplicates
Jun 13, 2008Hi,
Is there a way to find duplicates in one field? For example my query has person_nbr and for each person_nbr on one day they could have used multiple payer_names. I want to be able to count each person_nbr one time but also I want to group by description(which is the name of the provider) and by payer name to see how many person's that the provider seen with each payer. My problem is that if the person had more than one payer they are counted twice. Is there some type of aggregate function to use the first payer in the list??
With PersonMIA (person_id,person_nbr,first_name,last_name,date_of_birth) as
(
select distinct person_id,person_nbr,first_name,last_name,date_of_birth from
(select count(*) as countenc,a.person_id,a.person_nbr,
a.first_name,a.last_name,
a.date_of_birth
from person a
join patient_encounter b on a.person_id = b.person_id
group by a.person_id,a.person_nbr,a.first_name,a.last_name,a.date_of_birth )tmp
where tmp.countenc <=1
)
select person_nbr,payer_name,first_name,last_name,description,year(create_timestamp),create_timestamp
from
(
select distinct c.description,tmp.person_id,tmp.person_nbr,tmp.first_name,
tmp.last_name,tmp.date_of_birth,d.payer_name,b.create_timestamp
from PersonMIA tmp
join person a on a.person_id = tmp.person_id
join patient_encounter b on a.person_id = b.person_id
join provider_mstr c on b.rendering_provider_id = c.provider_id
join person_payer d on tmp.person_id = d.person_id
where c.description = 'Leon MD, Enrique'
group by c.description,tmp.person_id,tmp.person_nbr,tmp.first_name,tmp.last_name,
tmp.date_of_birth,d.payer_name,b.create_timestamp
)tmp2
where year(create_timestamp) IN (2005,2006)
group by person_nbr,payer_name,first_name,last_name,description,create_timestamp
Thanks in Advance!
Sherri
Duplicates
May 10, 2006Hi,
I'll see if I can explain this clearly. The query below
selects rows from the "hdr_ctl_nbr_status" table if the value in the field "tcn" from that table is found in the table "temp_tcn". I want all fields from the "hdr_ctl_nbr_status" table to be selected BUT only one row. In other words for a tcn with a value "12345678" there are 10 rows returned from the hdr_ctl_nbr_status table, I want only 1. Is there a way I can use SELECT DISTINCT to do this ? I know this usually functions on one or more fields but I want the DISTINCT to be on tcn only BUT return all fields in the query.
Select h.*,'' from hdr_ctl_nbr_status as h WITH (NOLOCK)
where h.tcn in (select tcn from temp_tcn)
Thanks, sorry if this is too confusing. Jeff
No Duplicates Please
Mar 10, 2008Hi, All,
I have two columns of int data in the a table, as my example data shows below.
I want my data returned to be something like those in #test3, but my question is this, how can I do it without using #test2 and #test3?
By the way, the business requirement doesn't care it's min/max or any ID when one side has duplicated values.
Thanks!
Use tempdb
Go
if object_ID ('#test') is not null drop table #test
create table #test (col1 int, col2 int)
insert into #test
Select 123, 222 union
Select 124, 222 union
Select 125, 222 union
Select 111, 223 union
Select 111, 224
if object_ID ('#test2') is not null drop table #test2
create table #test2 (col1 int, col2 int)
Insert into #test2
Select distinct col1, min(col2) from #test group by col1
if object_ID ('#test3') is not null drop table #test3
create table #test3 (col1 int, col2 int)
Insert into #test3
Select min(col1), col2 from #test2 group by col2
Select * from #test3
Msg 512 But No Duplicates!?!
Jul 28, 2005I am attempting to execute the Stored Procedure at the foot of thismessage. The Stored Procedure runs correctly about 1550 times, butreceive the following error three times:Server: Msg 512, Level 16, State 1, Procedure BackFillNetworkHours,Line 68Subquery returned more than 1 value. This is not permitted when thesubquery follows =, !=, <, <= , >, >= or when the subquery is used asan expression.I've done some digging, and the error message is moderatelyself-explanatory.The problem is that there is no Line 68 in the Stored Procedure. It'sthe comment line:-- Need to find out how many hours the employee is scheduled etc.Also, there are no duplicate records in the Employee table nor theWeeklyProfile table. At least I assume so - if the following SQL todetect duplicates is correct!SELECT E.*FROMEmployee Ejoin(select EmployeeIDfromEmployeeGroup by EmployeeIDhaving count(*) > 1) as E2On(E.EmployeeID = E2.EmployeeID)SELECTW.*FROMWeekProfile Wjoin(SelectWeekProfileIDFROMWeekProfileGROUP BYEmployeeID, MondayHours, WeekProfileIDHAVING COUNT(*) > 1) AS W2ONW.WeekProfileID = W2.WeekProfileIDNOTE: In the second statement, I have tried for MondayHours thruFridayHours.Anyone got any ideas? The TableDefs are set up in this thread:<http://groups-beta.google.com/group/comp.databases.ms-sqlserver/browse_frm/thread/fff4ef21e9964ab8/f5ce136923ebffc3?q=teddysnips&rnum=1&hl=en#f5ce136923ebffc3>The Stored Procedure that causes the error is here:--************************************************** ***********CREATE PROCEDURE BackFillNetworkHoursASDECLARE @EmployeeID intDECLARE @TimesheetDate DateTimeDECLARE @NumMinutes intDECLARE @NetworkCode int-- Get the WorkID corresponding to Project Code 2002SELECT@NetworkCode = WorkIDFROM[Work]WHERE(WorkCode = '2002')-- Open a cursor on a SELECT for all Network Support Employees whereany single workday comprises fewer than 7.5 hoursDECLARE TooFewHours CURSOR FORSELECTEmployeeID,CONVERT(CHAR(8), Start, 112) AS TimesheetDate,SUM(NumMins) AS TotalMinsFROM(SELECTTI.EmployeeID,W.WorkCode,TI.Start AS Start,SUM(TI.DurationMins) AS NumMinsFROMTimesheetItem TI LEFT JOIN[Work] W ON TI.WorkID = W.WorkIDWHERE EXISTS(SELECT*FROMEmployee EWHERE((TI.EmployeeID = E.EmployeeID) AND(E.DepartmentID = 2)))GROUP BY TI.EmployeeID, TI.Start, W.WorkCode) AS xGROUP BYEmployeeID,CONVERT(char(8), Start, 112)HAVINGSUM(NumMins) < 450ORDER BYEmployeeID,CONVERT(CHAR(8), Start, 112)-- Get the EmployeeID, Date and Number of Minutes from the cursorOPEN TooFewHoursFETCH NEXT FROM TooFewHours INTO @EmployeeID, @TimesheetDate,@NumMinutesWHILE (@@FETCH_STATUS=0)BEGINDECLARE @NewWorkTime datetimeDECLARE @TimesheetString varchar(50)DECLARE @Duration intDECLARE @RequiredDuration int-- Set the correct date to 08:30 - by default the cast from thecursor's select statement is middaySET @TimesheetString = @TimesheetDate + ' 08:30'SET @NewWorkTime = CAST(@TimesheetString AS Datetime)-- Need to find out how many hours the employee is scheduled to workthat day.SET @RequiredDuration = CASE (DATEPART(dw, @NewWorkTime))WHEN 1 THEN(SELECT CAST((60 * SundayHours) AS int) FROM WeekProfile WHERE(EmployeeID = @EmployeeID))WHEN 2 THEN(SELECT CAST((60 * MondayHours) AS int) FROM WeekProfile WHERE(EmployeeID = @EmployeeID))WHEN 3 THEN(SELECT CAST((60 * TuesdayHours) AS int) FROM WeekProfile WHERE(EmployeeID = @EmployeeID))WHEN 4 THEN(SELECT CAST((60 * WednesdayHours) AS int) FROM WeekProfile WHERE(EmployeeID = @EmployeeID))WHEN 5 THEN(SELECT CAST((60 * ThursdayHours) AS int) FROM WeekProfile WHERE(EmployeeID = @EmployeeID))WHEN 6 THEN(SELECT CAST((60 * FridayHours) AS int) FROM WeekProfile WHERE(EmployeeID = @EmployeeID))WHEN 7 THEN(SELECT CAST((60 * SaturdayHours) AS int) FROM WeekProfile WHERE(EmployeeID = @EmployeeID))ENDIF @NumMinutes < @RequiredDurationBEGIN-- Set the Start for the dummy work block to 08:30 + the number ofminutes the employee has already worked that daySET @NewWorkTime = DateAdd(minute, @NumMinutes, @NewWorkTime)-- Set the duration for the dummy work block to be required durationless the amount they've already workedSET @Duration = @RequiredDuration - @NumMinutes-- Now we have the correct data - insert into table.INSERT INTO TimesheetItem(EmployeeID,Start,DurationMins,WorkID)VALUES(@EmployeeID,@NewWorkTime,@Duration,@NetworkCode)ENDFETCH NEXT FROM TooFewHours INTO @EmployeeID, @TimesheetDate,@NumMinutesENDCLOSE TooFewHoursDEALLOCATE TooFewHoursGO--************************************************** ***********ThanksEdward
View 3 Replies View RelatedGetting Rid Of Duplicates
Jul 20, 2005I have a table, TEST_TABLE, with 6 columns (COL1, COL2, COL3, COL4,COL5, COL6).... I need to be able to select all columns/rows whereCOL3, COL4, and COL5 are unique....I have tried using DISTINCT and GROUP BY, but both will only allow meto access columns COL3, COL4, and COL5..... i need access to allcolumns...I just want to get rid of duplicate rows (duplicates ofCOL3, COL4, and COL5)...Thanks in advance.Joe
View 1 Replies View RelatedSum Of Duplicates
Apr 23, 2008Anyone know how to sum duplicated values so it only sums the distinct values?
View 3 Replies View RelatedDuplicates Only
May 21, 2008I have the following data.
CustID RoleID RelatID StartDate EndDate
20 RIX AGQ 5/05/2007 31/12/9999
20 RIX AGR 10/06/2007 31/12/9999
18 LRS AGQ 3/09/2004 31/12/9999
22 SRT AGP 5/03/2007 31/12/9999
22 SRT AGP 10/03/2007 31/12/9999
I wish to SELECT only the records that have duplicates. So, in the above data example, RoleID of LRS should be excluded.
How to do?
Duplicates
Feb 12, 2007Hi!
Grateful for some help as a newbie...
I have a
OLE db SQL command: SELECT DISTINCT convert (char(8),date,112) as day,...etc
Resulting in error "Violation of PRIMARY KEY constraint 'PK_Dim_Date"... so Column Day in Dim_date contains duplicates.
I suppose i need a delete in Lookup or how would I eliminate duplicates in Dim?
DELETE day from dim_date where day in(Select day from date ...
How Do I Stop These Duplicates
Feb 25, 2004I have these two tables and I cant prevent duplicates.
SEARCH
Item
ItemID
Info
CATEGORYDATA
CategoryID
ItemID
SELECT DISTINCT SEARCH.ItemId, SEARCH.Item, CATEGORYDATA.CategoryId
FROM SEARCH
INNER JOIN CATEGORYDATA
ON SEARCH.ItemID = CATEGORYDATA.ItemID
And I get something like:ItemID Item CategoryID
1 item1 1
3 item3 1
1 item1 2 <---duplicate
1 item1 3 <---duplicate
2 item2 3
4 item4 3
Thanks in advance
Dealing With Duplicates
Feb 15, 2002Hello!
Just looking for advise on dealing with duplicates in database.
I have a contact table that have a bunch of duplicated customer records.
My goal is to combine all duplicated records into one record.
This involves couple tables:contact,contact history ,calendar.
All tables related by common column "accountno".
What would be the best approach for this?
Thank you,
Lena