Replacing Multiple Spaces With A Single Space

May 21, 2008

I have records where there are multiple spaces between items of text. I would like to strip out all the excess spaces characters. To that end I have written to separate functions (both are listed below) neither of which I would imagine will be particularly efficient. The first uses an int table and the second a while loop. I am presently ignoring the leading and trailing space issue as this can easily be recitfied with LTRIM and RTRIM. However, I would be keen to know if there is a better way of achieving a similar result.

CREATE FUNCTION dbo.StripAdditionalSpaces (@Input varchar(1000))
RETURNS varchar(1000)
AS
BEGIN
DECLARE @Changed int, @Output varchar(1000)
SELECT @Output = ''
DECLARE @String TABLE ([Output] varchar(1000))
INSERT INTO @String ([Output]) VALUES (@Input)

SELECT @Output = @Output + SUBSTRING([Output], i1.Position, 1)
FROM @String
LEFT JOIN dbo.Ints i1
ON SUBSTRING([Output], i1.Position, 1) <> ' '
or ISNULL(SUBSTRING([Output], i1.Position - 1, 1), '') <> ' '
RETURN @Output
END
GO
CREATE FUNCTION dbo.StripAdditionalSpaces2 (@Input varchar(1000))
RETURNS varchar(1000)
AS
BEGIN
DECLARE @Output varchar(1000)
SELECT @Output = @Input

WHILE @Output LIKE '% %'
BEGIN
SELECT @Output = REPLACE(@Output, ' ' , ' ')
END
RETURN @Output
END
GO

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