Report Containing Sequential Dates (removing Date Gaps)

Jul 23, 2005

I have a table containing typed log entries. One log entry is supposed
to be created every twelve hours, but sometimes there are gaps. I need
to create a report showing the time of entry, and the actual log entry.
I can't just list the contents of the log table, because if I do that
there will be dates missing. Instead, when there isn't a log entry for
a date, I need to print the date, and then just leave the log entry
blank.

The SQL bellows shows what the output should look like. HOWEVER, the
code below makes use of a temp table containing all possible dates. My
question is, is there a better way to do this - one that doesn't
involve the temp table? Thanks in advance.


create table StationLog (LogDate datetime, LogText char(11))
insert StationLog values ('1/1/2005 00:00:00','entry one')
insert StationLog values ('1/1/2005 12:00:00','entry two')
insert StationLog values ('1/2/2005 00:00:00','entry three')
insert StationLog values ('1/3/2005 00:00:00','entry four')

create table Date_List (TempDate datetime)
insert Date_List values ('1/1/2005 00:00:00')
insert Date_List values ('1/1/2005 12:00:00')
insert Date_List values ('1/2/2005 00:00:00')
insert Date_List values ('1/2/2005 12:00:00')
insert Date_List values ('1/3/2005 00:00:00')
insert Date_List values ('1/3/2005 12:00:00')

select TempDate, LogText
from Date_List
left outer join StationLog on Date_List.TempDate = StationLog.LogDate

drop table StationLog
drop table Date_List

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Islands And Gaps In Sequential Data

Aug 23, 2007

I couldn't find a topic suitable for testing this, so I thought I'd start one.

Here is one way to get the islands without a tally table.declare@test table (symbol char(3), dt smalldatetime)

insert@test
select'abc','01/01/1990' union all
select'abc','01/02/1990' union all
select'abc','01/03/1990' union all
select'abc','01/04/1990' union all
select'abc','01/05/1990' union all
select'def','01/03/1990' union all
select'def','01/04/1990' union all
select'def','01/05/1990' union all
select'def','01/06/1990' union all
select'def','01/07/1990' union all
select'ghi','01/01/1990' union all
select'ghi','01/02/1990' union all
select'ghi','01/06/1990' union all
select'ghi','01/07/1990' union all
select'ghi','01/08/1990'

selectsymbol,
min(dt),
max(dt2)
from(
selectt1.symbol,
t1.dt,
t2.dt as dt2,
(select count(distinct t3.symbol) from @test as t3 where t3.symbol < t1.symbol and t3.dt <= t1.dt) AS r
from@test as t1
inner join@test as t2 on t2.symbol = t1.symbol
wheret2.dt - 1 = t1.dt
) as d
group bysymbol,
r
E 12°55'05.25"
N 56°04'39.16"

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Mar 25, 2014

I'm trying to find gaps in times in a table of sessions where the session endings aren't sequential. That is, session 1 can start at 10:00 and finish at 10:30, while session 2 started at 10:05 and finished at 10:45, and session 3 started at 10:06 and finished at 10:20. Only the starting times are in order; the ending times can be anywhere after that.Here's a bunch of sample data:

CREATE TABLE #SessionTest(SessionId int,Logindatetime datetime, Logoutdatetime datetime)

INSERT INTO #SessionTest
SELECT '1073675','Mar 3 2014 1:53PM','Mar 3 2014 1:53PM' UNION ALL
SELECT '1073676','Mar 3 2014 2:26PM','Mar 3 2014 3:51PM' UNION ALL
SELECT '1073677','Mar 3 2014 2:29PM','Mar 3 2014 3:54PM' UNION ALL
SELECT '1073678','Mar 3 2014 2:29PM','Mar 3 2014 5:47PM' UNION ALL
SELECT '1073679','Mar 3 2014 2:30PM','Mar 3 2014 3:37PM' UNION ALL

[code]....

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Jul 20, 2005

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Mar 29, 2007

Hi all,

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I have a function to get starting months for a report parameter.
The function is below:-

--------------------------------------------------------------
Shared Function GetStartingMonths() as String
dim strDefault as string
dim CurrentMonth as String
Dim SqlString as String

'strDefault = Month(Now) & "/1/" & Year(Now)
CurrentMonth = "5/1/2002"
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CurrentMonth = dateadd("m",1,CDate(CurrentMonth))

if Cdate(CurrentMonth) = Now then
Exit Do
else
sqlString = SqlString & " Union "
end if

Loop

return SqlString

End Function
---------------------------------------------------------------
what i am trying to do here, and hopefully produce a sql string that would fill my dataset of dates and their representation.

In the dataset, I had put the following expression
=Code.GetStartingMonths()

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Additionally, I was wondering whether there is a better SQL code that would achieve the same thing I am doing ?

thanks !

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Jan 30, 2005

I need to write a procedure to check if I have any gaps in my dates...

Start Date............End Date
10/6/2004............10/6/2005
10/6/2003............10/6/2004
7/10/2003..........10/6/2003
7/10/2002.............7/10/2003

What I need to do is test the End Date to the next row under the Start Date Column. (in bold to clarify) (moving upward from bottom)

sSQL011$ = "SELECT * FROM TableName " & _
"WHERE ID = '" & ID & "'"
Set rs011 = DB.OpenRecordset(sSQL011$, dbOpenDynaset)
Set Data1.Recordset = rs011
rs011.FindFirst "ID = " & ID

With rs011
do while .eof = False

if .eof then
exit sub
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Date in the next record then
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loop

end with




pseudo...
if the end date in one consecutive row is not the same as the start date in the next row then there is a date gap

thanks...

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Mar 5, 2008

Hi,

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I have a hard time wrapping my head around the logic, weither using a datetables or not, so any help would be appreaciated

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CREATE TABLE [dbo].[InternalUser](
[userid] [int],-- IDENTITY(1,1) NOT NULL,
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}
insert into [InternalUser] values(1,'a')
insert into [InternalUser] values(2,'b')
insert into [InternalUser] values(3,'c')
insert into [InternalUser] values(4,'d');
insert into [InternalUser] values(5,'e');
insert into [InternalUser] values(6,'f');

CREATE TABLE [dbo].[Activity2](
[activityid] [int] NOT NULL, --IDENTITY(1,1)
[userid] [int] NOT NULL,
[startdate] [datetime] NULL,
[enddate] [datetime] NULL
)

insert into [Activity2] values(1,1,'2007-02-15 00:00:00.000','2008-03-15 00:00:00.000')
insert into [Activity2] values(2,2,'2007-01-01 00:00:00.000','2008-01-02 00:00:00.000')
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insert into [Activity2] values(4,3,'2008-02-20 00:00:00.000','2008-10-10 00:00:00.000')
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Sep 13, 2013

I have a group of date ranges and wanted to identify all of the date gaps within the ranges, outputting the dates as another date range dataset.

Example dataset SQL below:

CREATE TABLE #test (daterow int identity, obj_id int, datestart DATETIME, dateend DATETIME)
INSERT INTO #test
SELECT 1, '20130428', '20130523'
UNION
SELECT 1, '20130526', '20130823'

[Code] ....

I would expect a dataset to be returned consisting of:

1, 24/05/2013, 25/05/2013
1, 24/08/2013, 25/08/2013
2, 16/05/2013, 24/05/2013

I have found a lot of examples of problems where I have just a single date column, and then I find the gaps in between that, but I'm having difficulty finding examples where it works with start and end date columns...

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See sample data below. I want hourly breakdown for the last X years, the month and day will be the same for each year.

SELECT '2013-12-10 04:00:00.000' as dt, 220.50 as amt UNION ALL
SELECT '2013-12-10 06:00:00.000' as dt, 24.50 as amt UNION ALL
SELECT '2013-12-10 07:00:00.000' as dt, 527.50 as amt UNION ALL
SELECT '2013-12-10 08:00:00.000' as dt, 28.50 as amt UNION ALL
SELECT '2013-12-10 11:00:00.000' as dt, 25.50 as amt UNION ALL

[Code] .....

-- expected result

SELECT '2013-12-10 00:00:00.000' AS dt, NULL AS Amt UNION ALL
SELECT '2013-12-10 01:00:00.000', NULL AS Amt UNION ALL
SELECT '2013-12-10 02:00:00.000', NULL AS Amt UNION ALL
SELECT '2013-12-10 03:00:00.000', NULL AS Amt UNION ALL
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[code].....

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Oct 7, 2007

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PoDet is child table having PoNo and PoQty

Suppose following records are in both tables

Po:-

OrderNo : 1
PoNo :- Po No 1
ShipDate :- Oct 5, 2007

OrderNo : 1
PoNo :- Po No 2
ShipDate :- Dec 5, 2007


OrderNo : 1
PoNo :- Po No 3
ShipDate :- Oct 5, 2007

PoDet:

PoNo :- Po No 1
PoQty :- 2000

PoNo :- Po No 2
PoQty :- 3000

PoNo :- Po No 3
PoQty :- 4000


I want to generate a Delivery No. which will be generated in this way :-

1. Earlier Shipdates should be assigned a Lower Number
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So meeting the above two conditions, a single SQL should return

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PoNo :- Po No 1
DelNo : 2

PoNo :- Po No 2
DelNo : 3

Can anybody help on this.

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below is a mock data base
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1 01/02/2006
2 01/04/2006
3 01/06/2006
4 01/09/2006
5 01/20/2006

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3 01/06/2006
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insert into #Test VALUES ('2015-08-13','2015-08-16')
insert into #Test VALUES ('2015-08-19','2015-08-21')
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Calculate Date Difference Excluding Dates

Aug 27, 2012

I have already seen stored procedures that can calculate a difference in dates, excluding the weekends. Any extension of such a SQL query to exclude not only weekends, but other dates as well. We have a table of "holidays" (not necessarily standard holidays), and I am wondering if there is a way to exclude them from the calculation.

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Transact SQL :: Check If A Date Is Within A Range Of Dates?

Aug 20, 2015

Basically, I have a membership table that lists each member with an effective period, Eff_Period, that indicates a month when a member was active. So, if a member is active from Jan to Mar, there will be three rows with Eff_Periods of 201501, 201502 and 201503.

All well and good.But, a member may not necessarily have continuous months for active membership. They might have only been active for Jan, Feb and Jun. That would still give them three rows, but with noncontinuous Eff_Periods; they'd be 201501, 201502 and 201506.There is also a table that logs member activity. It has an Activity_Date that holds the date of the activity - betcha didn't see that comin'. What I'm trying to do is determine if an activity took place during a period when the member was active.

My original thought was to count how many rows a member has in the Membership table and compare that number to the number of months between the MIN(Eff_Period) and the MAX(Eff_Period). If the numbers didn't matchup, then I knew that the member had a disconnect somewhere; he became inactive, then active again. But, then I thought of the scenario I detailed above and realized that the counts could match, but still have a discontinuity.So, is there a nifty little SQL shortcut that could determine if a target month is contained within a continuous or discontinuous list of months?

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Transact SQL :: Date Difference Between Two Dates In Due And OverDue

Sep 25, 2015

I want a difference in days 

Select datediff(dd,Target_Date,Achv_Date) 
Now , checks are 
1] when target date greater than achv_Date the difference should be greater than 0 
means for FileID 77608 
Select datediff(dd,'2015-09-24 00:00:00.000','2015-09-24 10:42:32.823')
 
i am getting -6 it should be 6 cant switch Target_Date and Achv_Date in datediff else i will get opposite result in first four records basically, i want a two column TAT and Status beside  achv_date based on the values of two dates difference see above ..and also want a result of (No. of Yes in status / No. of Files that has achv_date )i.e. result= (7/8) = 87% 

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Exporting Dates To Excel As Date Format

Jan 12, 2007

Hi,

I'm currently having problems exporting formatted dates from reporting services 2005 to excel.

Basically what I require is a way to format a date in reporting services so that it only shows the date without the time (preferably british format) and when it is exported to excel it is still formatted as a date.

This is so the user can sort the data file via date, I appreciate it is easy to select the column and format the cells but i would prefer to have a 'cleaner' solution to this problem which avoids the need for users to be formatting exported reports.

Originally I was formatting the dates as convert(varchar,@date,103) in the SP which converts it to a character string and excel picks this up as a character as would be expected. So I changed this to a date and set about trying to format the date in Reporting Services, so far i've been unsuccesfull using cdate (brings back the time) and format as it again converts it to a character string.

Any help or advice would be greatly appreciated,

R

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Transact SQL :: Combining Parts Of 2 Dates Into Third Date

May 7, 2015

In a stored procedure I have 2 dates that I need to combine parts of into a third date. I need the year from date1 and the month/day from date2.

Date1 = '2015/6/1'
Date2 = '2016/1/1'
Date3 needs to be '2015/1/1'

I have been messing around with datepart and dateadd with no luck.

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Transact SQL :: How To Get Four Quarter End Dates Based On Given Date

Jun 3, 2015

I have a simple following table which is having only one date column.

CREATE TABLE TEST_DATE
(
InputDate DATE
)
GO
INSERT INTO TEST_DATE VALUES('01-01-2015')
INSERT INTO TEST_DATE VALUES('06-25-2015')
INSERT INTO TEST_DATE VALUES('11-23-2014')
GO
SELECT * FROM TEST_DATE;

And the expected out put would be as follows:

I want to derive a Four Quarter End Date based on Date selected.

For Example if i select 01-01-2015 then
First Quarter End Date would be Previous Quarter End Date
Second Quarter End Date would be Current Quarter End Date
Third Quarter End Date would be Next Quarter End Date
Fourth Quarter End Date would be Next +1 Quarter End Date Like that

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Transact SQL :: Query To Get Date Span Between Dates

May 23, 2015

I need to calculate the amount of time between each visit. I am pulling the Row Number for my visits and now I need the date span that goes between each day. I also need a new column that returns a Yes or a No if the date span exceeds 3 years.

SELECT
ROW_NUMBER ( ) OVER ( PARTITION BY pv.PatientProfileId ORDER BY pv.Visit ASC ) AS RN
, CONVERT ( VARCHAR ( 20 ) , pv.Visit , 101 ) AS Visit
, pv.TicketNumber
, vstatus.Description AS VisitStatus
, doc.ListName AS Doctor

[Code] ....

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Dates Get Alphabetized When Report Is Shown

Mar 28, 2007

I've built a report from a cube that I have had made. After selecting a few dimensions, the columns will be showing a drill down action related to different dates. Problem is, when you preview the report, the dates get alphabetized; they don't show up in an order like dates, days should.



ex: monday, friday, thursday, tuesday, wednesday

or april, august, july, june, may



How can this be changed, or is it related to the dimensions in the way they were made? Possibly something from the tables then? If more information is needed, please specify.



Im running Sql 2005 Developer Edition, with BIDS.

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