SQL 2012 :: CheckSum Agg Function Returns 0 For Even Number Of Repeated Values?

Aug 14, 2014

From what I've seen, the CheckSum_Agg function appears to returns 0 for even number of repeated values. If so, then what is the practical use of this function for implementing an aggregate checksum across a set of values?

For example, the following work as expected; it returns a non-zero checksum across (1) value or across (2) unequal values.

declare @t table ( ID int );
insert into @t ( ID ) values (-7077);
select checksum_agg( ID ) from @t;
-----------
-7077
declare @t table ( ID int );
insert into @t ( ID ) values (-7077), (-8112);
select checksum_agg( ID ) from @t;
-----------
1035

However, the function appears to returns 0 for an even number of repeated values.

declare @t table ( ID int );
insert into @t ( ID ) values (-7077), (-7077);
select checksum_agg( ID ) from @t;
-----------
0

It's not specific to -7077, for example:

declare @t table ( ID int );
insert into @t ( ID ) values (-997777), (-997777);
select checksum_agg( ID ) from @t;
-----------
0

What's curious is that (3) repeated equal values will return a checksum > 0.

declare @t table ( ID int );
insert into @t ( ID ) values (-997777), (-997777), (-997777);
select checksum_agg( ID ) from @t;
-----------
-997777

But a set of (4) repeated equal values will return 0 again.

declare @t table ( ID int );
insert into @t ( ID ) values (-997777), (-997777), (-997777), (-997777);
select checksum_agg( ID ) from @t;
-----------
0

Finally, a set of (2) uneuqal values repeated twice will return 0 again.

declare @t table ( ID int );
insert into @t ( ID ) values (-997777), (8112), (-997777), (8112);
select checksum_agg( ID ) from @t;
-----------
0

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SQL Server 2012 :: Finding First And Repeated Values

Aug 26, 2014

I'm trying to come up with a query for this data:

CREATE TABLE #Visits (OpportunityID int, ActivityID int, FirstVisit date, ScheduledEnd datetime, isFirstVisit bit, isRepeatVisit bit)

INSERT #Visits (OpportunityID, ActivityID, FirstVisit, ScheduledEnd)
SELECT 1, 1001, '2014-08-17', '2014-08-17 12:00:00.000' UNION ALL
SELECT 1, 1002, '2014-08-17', '2014-08-17 17:04:13.000' UNION ALL
SELECT 2, 1003, '2014-08-18', '2014-08-18 20:39:56.000' UNION ALL

[Code] ....

Here are the expected results:

OpportunityIDActivityIDFirstVisitScheduledEndisFirstVisitisRepeatVisit
110012014-08-172014-08-17 12:00:00.00010
110022014-08-172014-08-17 17:04:13.00001
210032014-08-182014-08-18 20:39:56.00001
210042014-08-182014-08-18 18:00:00.00010

[Code] ....

Basically I'd like to mark the first Activity for each OpportunityID as a First Visit if its ScheduledEnd falls on the same day as the FirstVisit, and otherwise mark it as a Repeat Visit.

I have this so far, but it doesn't pick up on that the ScheduledEnd needs to be on the same day as the FirstVisit date to count as a first visit:

SELECT*,
CASE MIN(ScheduledEnd) OVER (PARTITION BY FirstVisit)
WHEN ScheduledEnd THEN 1
ELSE 0
END AS isFirstVisit,
CASE MIN(ScheduledEnd) OVER (PARTITION BY FirstVisit)
WHEN ScheduledEnd THEN 0
ELSE 1
END AS isRepeatVisit
FROM#Visits

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Days_in_warehouse
20
30
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Table 1 :

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Updated Table 1:

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2
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3
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id no sequence
------------------------------------
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35 35432 2
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36 35432 1
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------
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0

// Zero. ZERO??!?!!
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//
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//
// Incidently, SQRT(VAR(Latitude....)) gives 4.80354E-4, which is also way off.

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