MS SQL Server :: SQL 2012 :: How To Calculate Date Difference In Months

Date Difference In Months

Feb 24, 2006

Hi to all,

I want to make an sql query that will subtract two dates and the difference will be number in months.

i have this table TestTable with Fields ACost, Adate, AMonth

my formula is this X = (Now-Adate), should give me number in months
and Y = (ACost/AMonth)
i want to get the product of X and Y, (X*Y).

how can i make this in sql views?

can anyone help me with this?

thanks a lot!

best regards,

saldiboy

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I have a table like this.

CREATE TABLE Table1
([S_ID] varchar(7), [S_ACTV_CODE] varchar(4), [S_USER] varchar(5), [S_DATETIME] varchar(19), [S_ACT_IND] int)
;
INSERT INTO Table1
([S_ID], [S_ACTV_CODE], [S_USER], [S_DATETIME], [S_ACT_IND])
VALUES
('AAA-111', NULL, 'USER1', '2015-06-15 00:21:06', 0),
('AAA-111', '2', 'USER1', '2015-06-15 00:21:07', 0),

[code]....

Basically I want to calculate the time spent by S_Users on a particular S_ACTV_CODE:

- S_ACTV_CODE_PREV means the previous active records.

- S_START_TIME is the time of S_DATETIME when a S_ACTV_CODE starts

- S_END_TIME is the time before a S_ACTV_CODE changes to another S_ACTV_CODE

- For the first record, S_ACTV_CODE is null, so there is no S_ACTV_CODE_PREV, so S_ACTV_CODE_PREV is NULL

- For the second record S_ACTV_CODE has some value, but S_ACTV_CODE_PREV is NULL for first record. So second record S_ACTV_CODE_PREV is also NULL

- For the last record (means S_ACTV_IND = 1), the user is currently working on it and S_ACTV_CODE is not changed. So S_END_TIME is a open time and we want to keep it as NULL

So the result should be as below:

S_ID S_ACTV_CODE_PREV S_ACTV_CODE_CURR S_USER S_START_TIME
S_END_TIME TIME_SPENT (in Sec)
AAA-111 NULL NULL USER1 2015-06-15 00:21:06
2015-06-15 00:21:07 1
AAA-111 NULL 2 USER1 2015-06-15 00:21:07
2015-06-17 03:20:33 183566
AAA-111 2 4 USER2 2015-06-17 03:20:33

[code]....

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Create FUNCTION [dbo].days_diff ( @date1 datetime,@date2 datetime )
RETURNS int
AS
BEGIN
declare @i int
Declare @count int

[Code] .....

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I have a database of the table payments
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Is there an easy way to calculate a sum for the previous three months?

Data
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197904,6,888888,9589,30
197905,6,888888,27403,31
197906,6,888888,17130,30
197907,6,888888,14321,31
197908,6,888888,15234,31

[Code] .....

Desired Output

Date,Area,PropertyID,Volume,DaysInMonth,3MonthSum, DaysInMonthSUm
197904,6,888888,9589,30,NULL,NULL
197905,6,888888,27403,31,NULL,NULL
197906,6,888888,17130,30,NULL,NULL
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[Code] .....

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Jan FebMar AprMay JunJul AugSep Oct Nov Dec
321 394571 577 617 692924 944956 1010 1308 1686

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BEGIN
/*
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[code]...

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(
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[code].....

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