SQL Insert Statement That Returns The ID Field

Sep 7, 2000

I'm fairly new to SQL, so this might be simple question:

I am adding records to an SQL7 database by using the INSERT statement. The table has an IDENTITY field which is auto-incremented, so a value is not needed for the field in the query.

Is there any parameters for INSERT that returns to me the value of the IDENTITY field for the record I just created?...

Any help or suggestions would be appreciated.

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Nov 20, 2006

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Example:
A query may currently return:
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Title1 - Subtitle1 - Author 1b - etc
Title1 - Subtitle1 - Author 1c - etc
Title2 - Subtitle2 - Author 2a - etc
Title3 - Subtitle3 - Author 3a - etc

When I would like
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My actual SQL code, if you are interested, is:

SELECT dbo.edition.ISBN, dbo.edition.title, dbo.party.first_name+' '+dbo.party.surname as name, dbo.edition.reviews, dbo.edition.long_blurb, dbo.series.series_id, dbo.series.series_number,
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Also, what's the "proper" method for inserting a bit value? I noticed 'True', 'TRUE', 'true', True, TRUE, and true do not execute.

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Code:
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PS: Handwritten...

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I've tried various things:
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I am using the following conditional select statement but it returns no results.


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SELECT CallNumber AS [Call Number], Problem, Solution, Note
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Open10/6/2002 2:34:56 PMTEST2845
Hold10/11/2002 12:19:29 PMTEST2845
Closed10/29/2002 2:00:54 PMTEST2845
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Is there some way I can select all "Open" jobs, between a certain date, that do not exist anywhere in the table previous to the date it was entered? This would give me a result set containing only new jobs.

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Query1
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Query2
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2 Item1 10000
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I am guessing I am encountering this problem because of how
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Code:


select emailAddress from Users union
select user_name from PersonalPhotos union
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select email_address from LastLogin) drv
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SQL CODE:
DECLARE 
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[code]....

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Code Block
SELECT DISTINCT Field01 AS 'Field01', Field02 AS 'Field02'
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The results are just as I need:


Field01 Field02

------------- ----------------------

192473 8461760

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Code Block
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The the results are:

Field02

----------------------

22810
8461760

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Field02

----------------------

8461760
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Here's the sql management studio diagram :

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2
3 SqlDataAdapter myCommand1 = new SqlDataAdapter("select * from SurveyTemplate", myConnection);
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10
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25 myCommand3.InsertCommand.Connection = myConnection;
26
27 ds.Relations.Add(new DataRelation("FK_Question_SurveyTemplate", ds.Tables["SurveyTemplate"].Columns["id"], ds.Tables["Question"].Columns["surveyTemplateID"]));
28 ds.Relations.Add(new DataRelation("FK_Possible_Answer_Question", ds.Tables["Question"].Columns["id"], ds.Tables["Possible_Answer"].Columns["questionID"]));
29
30 DataRow dr = ds.Tables["SurveyTemplate"].NewRow();
31 dr["name"] = o[0];
32 dr["description"] = o[1];
33 dr["active"] = 1;
34 ds.Tables["SurveyTemplate"].Rows.Add(dr);
35
36 DataRow dr1 = ds.Tables["Question"].NewRow();
37 dr1["questionIndex"] = 1;
38 dr1["questionContent"] = "q1";
39 dr1.SetParentRow(dr);
40 ds.Tables["Question"].Rows.Add(dr1);
41
42 DataRow dr2 = ds.Tables["Possible_Answer"].NewRow();
43 dr2["answerIndex"] = 1;
44 dr2["answerContent"] = "a11";
45 dr2.SetParentRow(dr1);
46 ds.Tables["Possible_Answer"].Rows.Add(dr2);
47
48 dr1 = ds.Tables["Question"].NewRow();
49 dr1["questionIndex"] = 2;
50 dr1["questionContent"] = "q2";
51 dr1.SetParentRow(dr);
52 ds.Tables["Question"].Rows.Add(dr1);
53
54 dr2 = ds.Tables["Possible_Answer"].NewRow();
55 dr2["answerIndex"] = 1;
56 dr2["answerContent"] = "a21";
57 dr2.SetParentRow(dr1);
58 ds.Tables["Possible_Answer"].Rows.Add(dr2);
59
60 dr2 = ds.Tables["Possible_Answer"].NewRow();
61 dr2["answerIndex"] = 2;
62 dr2["answerContent"] = "a22";
63 dr2.SetParentRow(dr1);
64 ds.Tables["Possible_Answer"].Rows.Add(dr2);
65
66 myCommand1.Update(ds,"SurveyTemplate");
67 myCommand2.Update(ds, "Question");
68 myCommand3.Update(ds, "Possible_Answer");
69 ds.AcceptChanges();
70

and that causes (at line 67):"The INSERT statement conflicted with the FOREIGN KEY constraint
"FK_Question_SurveyTemplate". The conflict occurred in database
"ankietyzacja", table "dbo.SurveyTemplate", column
'id'.
The statement has been terminated.
at System.Data.Common.DbDataAdapter.UpdatedRowStatusErrors(RowUpdatedEventArgs rowUpdatedEvent, BatchCommandInfo[] batchCommands, Int32 commandCount)
at System.Data.Common.DbDataAdapter.UpdatedRowStatus(RowUpdatedEventArgs rowUpdatedEvent, BatchCommandInfo[] batchCommands, Int32 commandCount)
at System.Data.Common.DbDataAdapter.Update(DataRow[] dataRows, DataTableMapping tableMapping)
at System.Data.Common.DbDataAdapter.UpdateFromDataTable(DataTable dataTable, DataTableMapping tableMapping)
at System.Data.Common.DbDataAdapter.Update(DataSet dataSet, String srcTable)
at AnkietyzacjaWebService.Service1.createSurveyTemplate(Object[] o) in J:\PL\PAI\AnkietyzacjaWebService\AnkietyzacjaWebServicece\Service1.asmx.cs:line 397"


Could You please tell me what am I missing here ?
Thanks a lot.
 

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Jan 14, 2008


This problem is being seen on SQL 2005 SP2 + cumulative update 4

I am currently successfully using the output clause of an insert statement to return the identity values for inserted rows into a table variable

I now need to add an "instead of insert" trigger to the table that is the subject of the insert.

As soon as I add the "instead of insert" trigger, the output clause on the insert statement does not return any data - although the insert completes successfully. As a result I am not able to obtain the identities of the inserted rows

Note that @@identity would return the correct value in the test repro below - but this is not a viable option as the table in question will be merge replicated and @@identity will return the identity value of a replication metadata table rather than the identity of the row inserted into my_table

Note also that in the test repro, the "instead of insert" trigger actually does nothing apart from the default insert, but the real world trigger has additional code.

To run the repro below - select each of the sections below in turn and execute them
1) Create the table
2) Create the trigger
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4) Drop the trigger
5) Re-run the insert from 3) - note that table variable is now correctly populated with the @@identity value in the row

I need the behaviour to be correct when the trigger is present

Any thoughts would be much appreciated

aero1


/************************************************
1) - Create the table
************************************************/
CREATE TABLE [dbo].[my_table](
[my_table_id] [bigint] IDENTITY(1,1) NOT NULL,
[forename] [varchar](100) NULL,
[surname] [varchar](50) NULL,
CONSTRAINT [pk_my_table] PRIMARY KEY NONCLUSTERED
(
[my_table_id] ASC
)WITH (PAD_INDEX = OFF, IGNORE_DUP_KEY = OFF, FILLFACTOR = 70) ON [PRIMARY]
)

GO
/************************************************
2) - Create the trigger
************************************************/
CREATE TRIGGER [dbo].[trig_my_table__instead_insert] ON [dbo].[my_table]
INSTEAD OF INSERT
AS
BEGIN

INSERT INTO my_table
(
forename,
surname)
SELECT
forename,
surname
FROM inserted

END

/************************************************
3) - Do the insert
************************************************/

DECLARE @my_insert TABLE( my_table_id bigint )

declare @forename VARCHAR(100)
declare @surname VARCHAR(50)

set @forename = N'john'
set @surname = N'smith'

INSERT INTO my_table (
forename
, surname
)
OUTPUT inserted.my_table_id INTO @my_insert
VALUES( @forename
, @surname
)

select @@identity -- expect this value in @my_insert table
select * from @my_insert -- OK value without trigger - zero with trigger

/************************************************
4) - Drop the trigger
************************************************/

drop trigger [dbo].[trig_my_table__instead_insert]
go

/************************************************
5) - Re-run insert from 3)
************************************************/
-- @my_insert now contains row expected with identity of inserted row
-- i.e. OK

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when mycasefield = 2 then 99862
when mycasefield = 3 then 99863
when mycasefield = 4 then 99864
when mycasefield = 5 then 99865
when mycasefield = 6 then 99866
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end,
alt_min,
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(
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MTB.model_ID
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null, --alt max
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from MyTblB MTB
);

The error I'm getting is:
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This is what I have so far,

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[code]...

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