SQL - Return Number Of Matches

May 26, 2007

Hi...

Need help with some SQL-code:

Im just interesting in how many rows in my table 'Location' that has 'New York' in the column called 'City'....

So I just want to return the number of rows that is macthing...

How do I write the sql-part for this??

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Query Doesn't Return Any Records Unless All Joins Have Matches

Jan 1, 2008

Problem is that if the [Receiving] table doesn't have a match then no records are return. I want all matches from the [Orders Subtable] and any matches from the [Receiving] Table. If no [Receiving] table matches then I still want all matches from the [Orders Subtable]. Attached is the query.

Note: The query has to run in Access 2000 and I will be coding it in VB.



SELECT Orders.[Orders ID],
[Orders Subtable].ID,
[Orders Subtable].Quantity,
Receiving.Quantity,
Receiving.[Component #]

FROM (Orders
LEFT JOIN Receiving ON Orders.[Orders ID] = Receiving.[Orders ID])
INNER JOIN [Orders Subtable] ON Orders.[Orders ID] = [Orders Subtable].[Orders ID]

GROUP BY Orders.[Orders ID], [Orders Subtable].ID,
[Orders Subtable].Quantity, Receiving.Quantity,
Orders.[Project #], [Orders Subtable].On_Order,
[Orders Subtable].[Component #],
Receiving.[Component #]

HAVING (((Orders.[Project #])="Speed1aaaaa") AND
(([Orders Subtable].On_Order)=True) AND
(([Orders Subtable].[Component #])="R02101A") AND
((Receiving.[Component #])="R02101A"));

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Nov 19, 2012

I have a list of ClassID that is stored based on users multi select on a listview

For example ClassID might contain

301
302
303
304

Now I need to find InstructorID where classID matches all the value in the above list.

I am using this query

Code:
Dim assSQL = "Select InstructorID from ClassInstructors where ClassID = @P0"
For i = 1 To classIDs.Count - 1
assSQL &= " UNION Select InstructorID from ClassInstructors where ClassID = @P" & i.ToString
Next

[Code] ....

But the problem is the query is returning InstructorID where ClassID matches any of the ClassIDs. I want it to return Instructor ID where ClassID matches all of the ClassIDs in the string.

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May 14, 2008

hi,i have a stored procedure like this in SQL server ,it returns proper value if data is there for a given id.But if there is no data,it returns row/rows of NULL value and that is counted towards "number of row returned"..Shouldn't it be like,if there are null values in a row,that row should not be counted towards rows returned value .?Rightnow if no value returned from either of the select,it still returns as 2 rows instead of 0 rows.How do handle this situation in SQL? thanks for your help
SELECT     SUM(col1) AS SUM_COL1, SUM(col2) AS SUM_COL2, SUM(col3) AS SUM_COL3, SUM(col4) AS SUM_COL4FROM         TABLE1WHERE     (ID = nn)     UNION all
 SELECT      SUM(col22) AS SUM_COL22 ,cast(null as int) as c1,cast(null as int)as c2,cast(null as int) as c3FROM         table2WHERE     TABLE2 = nn)

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Feb 4, 2004

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anytime there is an error in the stored proc i have an error page which looks like this

**********************
Server Error in '/WebApplication3' Application.
--------------------------------------------------------------------------------

Error converting data type varchar to bigint. 139 pdiscnum 37 3429 4978 139 139 4979 50.93 189.93 4980 -189.93 0 4981 139 139 4982 -139 0 4986 23 23 4987 0 23 4988 0 23 5121 139 162 5122 -328.93 -166.93 3430 4983 89 89 4984 -89 0 5096 89 89 5097 -178 -89 5135 89 0 5144 139 139 3431 4989 89 89 4990 -89 0 5100 89 89 5101 -178 -89 3432 4991 139 139 4992 4.32 143.32 4993 -143.32 0 5102 139 139 5103 -278 -139 3433 4994 139 139 4995 50.93 189.93 4996 8.64 198.57 4997 -198.57 0 5003 0 0 5123 139 139 5124 -328.93 -189.93 3434 4998 59 59 4999 -59 0 5000 59 59 5001 -59 0 5002 0 0 5041 19 19 5042 0 19 5043 -2.39 16.61 5044 -16.61 0 5045 19 19 5046 -2.39 16.61 5047 -16.61 0 5056 0 0 5084 39 39 5085 -5.85 33.15 5086 -49.76 -16.61 5104 59 42.39 5105 .........

************************************************

a very lengthy page...the numbers are prbly due to the print stmts of the results of some calculations...
but my q is..is there any way to return the xact line number where the error occured in the stored proc instead of these infinite list of numbers...its taking pretty long time to go through the entire stored proc to isolate the error...

thanks

dinakar

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Hello,
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All of the row information will stay the same except the Value that will count off of the original value.
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========
Public Sub CreateMySqlCommand(myExecuteQuery As String, myConnection As SqlConnection)
Dim myCommand As New SqlCommand(myExecuteQuery, myConnection)
myCommand.Connection.Open()
myCommand.ExecuteNonQuery()
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========

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CREATE FUNCTION dbo.[f_Rec_cnt]
(@InTableName NVARCHAR(100),
@InDtColName NVARCHAR(50),
@InDate NVARCHAR(50)
)
RETURNS INT

[Code] .....

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Group 2

Group 3

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Select DISTINCT ws.p4Districtnumber, ws.cycle, ws.worksetid, count(msi.MeterSessionInputKey) as ASND
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left outer join fcs.dbo.WorkAssignment as wa
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[code]....

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Dim strSql As String

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May 18, 2007

Hi. I am new to SQL.I hope you veteran out there to help me solve the simple problem i met.

CREATE TABLE BASKET(
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My statement

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the result is

ITEM ITEM COUNT(L1.B#)
------ ------ ------------
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BEER BUTTER 2
MILK BEER 5
MILK BREAD 6
MILK BUTTER 5
BREAD BEER 4
BREAD MILK 6
BREAD BUTTER 5
BUTTER BEER 2
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BUTTER BREAD 5

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Apr 26, 2008

Hello.

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What code i need to write to ?



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Oct 18, 2005

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Nov 24, 2007

Hello. I'm quite new to SQL so have included as many details as i can think of here. The scenario is a wordsearch style puzzle. The user can select their answers in any order and these answers are stored in a table. I need help with the UPDATE statement to compare the users answers against the correct answers for that puzzle.
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The Tables:
-- These are the correct answers for a given grid (gridid).
-- Due to the nature of the puzzle, answers can be in any order.
-- Each level may contain one,two,or no 'bonusanswers' which are harder to find, so these are scored separately so bonus points can be awarded.
CREATE TABLE correctanswers
(
gridid smallint IDENTITY(1,1)PRIMARY KEY CLUSTERED,
answer1 char(15),
answer2 char(15),
bonusanswer1 char(15),
bonusanswer2 char(15)
)

-- These are the user submitted set of answers 'answerid' for level 'gridid'.
-- Answers may be submitted in any order.
CREATE TABLE useranswers
(
answerid smallint IDENTITY(1,1)PRIMARY KEY CLUSTERED,
gridid smallint,
firstanswer char(15),
secondanswer char(15),
thirdanswer char(15),
fourthanswer char(15),
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-- A user (userid) submits their answers which get stored as answerid.
-- This table shows the scores for each set of answerid's the user has submitted.
-- A high score table for both the individual user, and all users may be created using this table.
CREATE TABLE userscores
(
userid smallint,
answerid smallint,
mainmatches smallint,
bonusmatches smallint
)

The Test Data:
-- sample test data
-- 2 users userid's '1' and '2' each have two goes on level1 (gridid 1)

-- correct answers for gridid 1
INSERT INTO correctanswers (answer1, answer2, bonusanswer1, bonusanswer2) VALUES ('cat','dog','rabbit','elephant')

-- user submitted answers for gridid 1
INSERT INTO useranswers (gridid, firstanswer, secondanswer, thirdanswer, fourthanswer) VALUES (1,'dog','rabbit','horse','cow')
INSERT INTO useranswers (gridid, firstanswer, secondanswer, thirdanswer, fourthanswer) VALUES (1,'dog','cat','elephant','horse')
INSERT INTO useranswers (gridid, firstanswer, secondanswer, thirdanswer, fourthanswer) VALUES (1,'rabbit','cat','elephant','donkey')
INSERT INTO useranswers (gridid, firstanswer, secondanswer, thirdanswer, fourthanswer) VALUES (1,'horse','cat','dog','sheep')

-- scores for users attempts - columns 3 and 4 needs calculating
INSERT INTO userscores VALUES (1,1,null,null) -- one main answer and one bonus answer, so null,null should be 1,1
INSERT INTO userscores VALUES (1,2,null,null) -- two main answers and one bonus answer, so null,null should be 2,1
INSERT INTO userscores VALUES (2,3,null,null) -- one main answer and two bonus answers, so null,null should be 1,2
INSERT INTO userscores VALUES (2,4,null,null) -- two main answers and no bonus answers, so null,null should be 2,0

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I haven't used SQL much but from the little i know then i think the answer will include JOIN, COUNT and IN statements as part of the UPDATE statement...but i haven't a clue where to start with the order/logic etc.

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Many thanks.
Roger

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