SQL Server 2005 Database Generating Script DDL In Alphabetical Order

Jun 21, 2007

Using the scripting wizard in SQL Server 2005 database engine, I have been able to script all my DDL out to a flat file which is great; however, when I scripts for instance all views I would like to have the script in alphabetical order by view name, is there a value I can set to accomplish this?



Thanks

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Generate A Database Script In SQL 2005 In Alphabetical Order

Nov 7, 2007

In SQL 2000, when you generated an SQL script for a database, it was logical and the tables in the script were in alphabetical order. In SQL 2005 they are all mixed up. Am I missing something?

Thanks

Peter

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Hello
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Hi there,



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[CriteriaName] [varchar](255) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,

[TargetScore] [numeric](5, 0) NULL,

[HRPlan] [uniqueidentifier] NULL,

[ActualScore] [numeric](18, 0) NULL,

[Criteria] [uniqueidentifier] NULL,

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[IsActive] [bit] NULL,

[addDate] [datetime] NULL,

[totalscore] [numeric](5, 0) NULL,

[isCalc] [bit] NULL,

[Weight] [decimal](18, 2) NULL,

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[rowguid] [uniqueidentifier] ROWGUIDCOL NOT NULL CONSTRAINT [MSmerge_df_rowguid_7FF25DF903B6415FBFF24AC954BC88E4] DEFAULT (newsequentialid()),

CONSTRAINT [PK_AssignedCriteria] PRIMARY KEY CLUSTERED

(

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)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]

) ON [PRIMARY] TEXTIMAGE_ON [PRIMARY]



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Title is probably poorly worded

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Code:

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-------------------------------------------
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FR


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FR

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Apologies if this has been done before, but I couldn't find a completed example. If anyone has time, I'd love to see some improvements...

Where's fribble when you need him?
/*
function:
numeric_order

arguments:
@numeric_string - a string of mixed alpha and numeric values
@max_digits- the maximum length of digits to compare

description:
Function numeric_order creates an orderable string based on the "numeric" value of @numeric_string
which can be ordered alphabetically.

Ideally the strings should really be broken up into constituent parts and ordered properly,
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eg
select title from regulations order by title
returns:

Regulation 1(a) section 3
Regulation 11 section 100(b)
Regulation 11 section 2(c)(iii)
Regulation 2 section 1
Regulation 21 section 3 (b)

whereas
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Regulation 2 section 1
Regulation 11 section 2(c)(iii)
Regulation 11 section 100(b)
Regulation 21 section 3 (b)

which is the order most users would expect.

NOTE: because the original strings are mixed, the user may include alphas between digits which are to be
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expected output:
select dbo.numeric_order('Part 1(b) subsection 1',4)
returns
Part 0001(b) subsection 0001

test data:
use test
--go

if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[regulations]') and OBJECTPROPERTY(id, N'IsUserTable') = 1)
drop table [dbo].[regulations]
--go

create table regulations (id int identity(1,1), title varchar(200))
--go

insert into regulations (title) select 'Regulation 1(a) section 3'
insert into regulations (title) select 'Regulation 11 section 100(b)'
insert into regulations (title) select 'Regulation 11 section 2(c)(iii)'
insert into regulations (title) select 'Regulation 2 section 1'
insert into regulations (title) select 'Regulation 21 section 3 (b)'
--go

select title as [Incorrectly Ordered] from regulations order by title
--go

select title as [Correctly Ordered] from regulations order by dbo.numeric_order(title, 10)
--go

drop table [dbo].[regulations]
--go

*/

if exists (select * from dbo.sysobjects where id = object_id(N'[dbo].[numeric_order]') and xtype in (N'FN', N'IF', N'TF'))
drop function [dbo].[numeric_order]
go

create function [dbo].[numeric_order](
@numeric_string as varchar(1000),
@max_digits as int)
returns varchar(8000) as
begin
declare @return varchar(8000)

declare @part varchar(1000)
declare @digit_position int
declare @rest varchar(1000)
declare @non_digit_position int
declare @numeric_term varchar(1000)
declare @after varchar(1000)
declare @between varchar(1000)
declare @first_time int
declare @digits varchar(100)

--create a string of zeros equal in length to max number of digits of enclosed numeric values
set @digits = replace(space(@max_digits),' ','0')

--handle length issues
--worst case scenario is a number every second character multiplied by padlen < 8000
--which would potentially add len(@numeric_string)/2 * padlen characters - so subtract this from the string
set @part = left(@numeric_string, ((len(@numeric_string)/2) * @max_digits))

--starting values
set @non_digit_position = 0
set @first_time = 1
set @return = ''

--loop while not at end of string
while ((@non_digit_position > 0 or @first_time > 0) and (len(@part) > 0))
begin
--if there are digits in the string
set @digit_position = patindex('%[0-9]%', @part)
if @digit_position > 0
begin
--get the part of the string after the first digit
set @rest = substring(@part, patindex('%[0-9]%', @part) + 1, len(@part)-patindex('%[0-9]%', @part) + 1)
set @non_digit_position = patindex('%[^0-9]%',@rest)

--extract the string of digits
set @numeric_term = case
when @non_digit_position > 0 then substring(@part, @digit_position, @non_digit_position)
else substring(@part, @digit_position, len(@part) - @digit_position + 1)
end

--keep track of the rest of the string after and between the digits
set @after = substring(@part, @digit_position + len(@numeric_term), len(@part) - @digit_position + @non_digit_position)
set @between = '' + substring(@part, 1, @digit_position - 1)

--build return string
set @return = @return + @between + right(@digits + @numeric_term, @max_digits)
end
else
begin
--no more digits, just add back the rest of the original string
set @return = @return + @part
set @after = ''
end

--iterate
set @first_time = 0
set @part = @after
end

return @return

end
go

--
I hope that when I die someone will say of me "That guy sure owed me a lot of money"

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