SQL Server 2008 :: Partition Sliding Window Causing Loads Of Blocks
Oct 29, 2015
We have a massive database with an almost massive amount of traffic to and from it.
I've been requested to implement a sliding window partitioning with 2 partitions an active and passive 1,I managed to test this on a very small testbed last month.
I currently moved 97k table on to the partition function leaving me another 26 k to go
I'm using the following stored procedure to implement the sliding window
CREATE PROCEDURE [dbo].[ManageFactSlidingWindow](@pFunction nvarchar(max),@pSchema nvarchar(max),@FG nvarchar(max),@moveDays int)
/*****************************************************************************
PROCEDURE NAME: [ManageFactSlidingWindow]
AUTHOR: Arshad Ali
CREATED: 02/24/2013
DESCRIPTION: This stored procedure manages sliding window for the partitioned table
VERSION HISTORY:
DATE EMAIL Company DESCRIPTION
[Code] .....
When I try to move the partition even a single day I get loads of locks.
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Nov 13, 2007
I began with a partition function as follows:
CREATE PARTITION FUNCTION [TimeTicksRangePFN](bigint) AS RANGE RIGHT FOR VALUES (633294720000000000, 633320640000000000, 633347424000000000, 633374208000000000, 633399264000000000)
These numbers happen to correspond to the dates 11/1/7, 12/1/7, 1/1/8, 2/1/8 and 3/1/8 in ticks respectively.
I began with a partition scheme as follows:
CREATE PARTITION SCHEME [TimeTicksRangePScheme] AS PARTITION [TimeTicksRangePFN] TO ([FG_xxx_EventArchive00001], [FG_xxx_EventArchive00002], [FG_xxx_EventArchive00003], [FG_xxx_EventArchive00004], [FG_xxx_EventArchive00005], [PRIMARY])
While running my “sliding window script� , which I hoped would 1) roll off the oldest partition of my EventArchive table and 2) add a new partition with a tick boundary that equates to 3/5/8, I get an error related to my switch out table's index, the same table's Filegroup and Primary.
After getting the error, I scripted the partition function as a create in mgt studio and got…
CREATE PARTITION FUNCTION [TimeTicksRangePFN](bigint) AS RANGE RIGHT FOR VALUES (633320640000000000, 633347424000000000, 633374208000000000, 633399264000000000, 633402720000000000)
...which looks like what I had intended cuz the last boundary is the tick representation of 3/5/8 and the oldest has rolled off
scripting the scheme produced...
CREATE PARTITION SCHEME [TimeTicksRangePScheme] AS PARTITION [TimeTicksRangePFN] TO ([FG_xxx_EventArchive00001], [FG_xxx_EventArchive00003], [FG_xxx_EventArchive00004], [FG_xxx_EventArchive00005], [PRIMARY], [FG_xxx_EventArchive00001])
which looks nothing like what I intended, I thought I’d end up with …00002,…00003,…00004,…00005,…00001,PRIMARY
the script steps that seem most relevant start at the 5th step as follows...
5) creates table [dbo].Switch on the switch out filegroup with columns, PK and indexes matching exactly those of [dbo].EventArchive
6) switches partition 1 of [dbo].EventArchive to [dbo].Switch
7) ALTER PARTITION FUNCTION TimeTicksRangePFN() MERGE RANGE (633294720000000000) --this was the oldest date corresponding to 11/1/7
8) truncates [dbo].Switch
9) drops all indexes on [dbo].Switch except a clustered index (IX_TimeTicks), leaves PK constraint alone
10) ships the new data whose values range from 3/1/8 to less than 3/5/8 to [dbo].Switch and deletes them from their source
11) recreates all non clustered indexes on [dbo].Switch
12)ALTER TABLE [dbo].[Switch] WITH CHECK ADD CONSTRAINT RangeCK CHECK ([TimeTicks] < the number of ticks represented by 3/5/8)
13)ALTER PARTITION SCHEME TimeTicksRangePScheme NEXT USED [FG_xxx_EventArchive00001] --fg isnt really hardcoded
14)ALTER PARTITION FUNCTION TimeTicksRangePFN() SPLIT RANGE (the number of ticks represented by 3/5/8)
15)ALTER TABLE [dbo].[Switch] SWITCH TO [dbo].[EventArchive] PARTITION 5
step 15 is the one that fails with message "ALTER TABLE SWITCH statement failed. index 'xxx.dbo.Switch.IX_TimeTicks' is in filegroup 'FG_xxx_EventArchive00001' and partition 5 of index 'xxx.dbo.EventArchive.IX_TimeTicks' is in filegroup 'PRIMARY'.
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Nov 7, 2007
I have a partition function as follows:
CREATE PARTITION FUNCTION [TimeTicksRangePFN](bigint) AS RANGE RIGHT FOR VALUES (633294720000000000, 633320640000000000, 633347424000000000, 633374208000000000, 633399264000000000)
These numbers happen to correspond to the dates 11/1/7, 12/1/7, 1/1/8, 2/1/8 and 3/1/8 in ticks respectively.
I have a partition scheme as follows:
CREATE PARTITION SCHEME [TimeTicksRangePScheme] AS PARTITION [TimeTicksRangePFN] TO ([FG_xxx_EventArchive00001], [FG_xxx_EventArchive00002], [FG_xxx_EventArchive00003], [FG_xxx_EventArchive00004], [FG_xxx_EventArchive00005], [PRIMARY])
After running my €śsliding window script€? , which I wanted to switch out the lowest partition with, and add a new partition with a new tick boundary that equates to 3/5/8, I get an error saying that 1 of my switch out table€™s indexes is in filegroup 1 but partition 5€™s index of the same name is in PRIMARY. At this point the partition function looks like€¦
CREATE PARTITION FUNCTION [TimeTicksRangePFN](bigint) AS RANGE RIGHT FOR VALUES (633320640000000000, 633347424000000000, 633374208000000000, 633399264000000000, 633402720000000000) which looks like what I had intended cuz the last boundary is tick representation of 3/5/8 and the oldest has rolled off
and the scheme looks like€¦
CREATE PARTITION SCHEME [TimeTicksRangePScheme] AS PARTITION [TimeTicksRangePFN] TO ([FG_xxx_EventArchive00001], [FG_xxx_EventArchive00003], [FG_xxx_EventArchive00004], [FG_xxx_EventArchive00005], [PRIMARY], [FG_xxx_EventArchive00001]) which looks nothing like what I intended, I thought I€™d end up with €¦00002,€¦00003,€¦00004,€¦00005,€¦00001,PRIMARY
the relevant script steps are...
5) creates table [dbo].Switch on the switch out filegroup with columns, PK and indexes matching those of [dbo].EventArchive (allows default location for indexes)
6) switches partition 1 of [dbo].EventArchive to [dbo].Switch
7) ALTER PARTITION FUNCTION TimeTicksRangePFN() MERGE RANGE (633294720000000000)
8) truncates [dbo].Switch
9) drops all indexes on [dbo].Switch except a clustered index (IX_TimeTicks), leaves PK constraint alone
10) ships the new data whose values range from 3/1/8 to less than 3/5/8 to [dbo].Switch and deletes them from their source
11) recreates all non clustered indexes on [dbo].Switch
12)ALTER TABLE [dbo].[Switch] WITH CHECK ADD CONSTRAINT RangeCK CHECK ([TimeTicks] < the number of ticks represented by 3/5/8)
13)ALTER PARTITION SCHEME TimeTicksRangePScheme NEXT USED [FG_xxx_EventArchive00001]
14)ALTER PARTITION FUNCTION TimeTicksRangePFN() SPLIT RANGE (the number of ticks represented by 3/5/8)
15)ALTER TABLE [dbo].[Switch] SWITCH TO [dbo].[EventArchive] PARTITION 5
step 15 is the one that fails with message "ALTER TABLE SWITCH statement failed. index 'xxx.dbo.Switch.IX_TimeTicks' is in filegroup 'FG_xxx_EventArchive00001' and partition 5 of index 'xxx.dbo.EventArchive.IX_TimeTicks' is in filegroup 'PRIMARY'.
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Oct 31, 2007
Kimberly Tripp describes a recipe for switching partitions in and out, thru the use of staging tables, when it comes time to "slide the window" on a partitioned table. She says that the clustered index (on staging) must be the same as that chosen for the partitioned table itself but she doesnt discuss whether or not all of the non clustered indexes need to be the same too once the
ALTER TABLE Orders
SWITCH PARTITION 1
TO OrdersOctober2002
and
ALTER TABLE OrdersOctober2004
SWITCH TO Orders PARTITION 24
run. For the data being switched out, I wouldnt want to do anything extra. For the data being switched in, I'd like to understand if she is implying that all other indexes would be built automatically as a result of the 2nd ALTER statement?
Kimberly's article is at http://www.sqlskills.com/resources/Whitepapers/Partitioning%20in%20SQL%20Server%202005%20Beta%20II.htm#_Toc79339965
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Apr 9, 2007
Hi
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Has anyone come across this
thanks
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Feb 28, 2015
What is the syntax to verify that the partition data is loaded into the correct partition.
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Dec 14, 2006
Dear members,
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protected System.Web.UI.WebControls.Label Label1;
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/*
comment : I login to my windows as deltakoronx, and I want to every user (including me), connected to sql server through IIS, will be identified as deltasqluser not as user's login (impersonate)
*/
private void Page_Load(object sender, System.EventArgs e)
{
SqlConnection conn = new SqlConnection(_connString);
SqlCommand cmd = new SqlCommand();
cmd.Connection = conn;
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conn.Close();
conn.Close();
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at web.config, I add :
<identity impersonate="false" userName="deltasqluser" password="" />
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Regards,
Koronx
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This is the code i use.
Dim cnn As ADODB.Connection
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Set cnn = New ADODB.Connection
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Sheldon
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Oct 28, 2006
Hi folks,
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The problem is that when I try to run the web form, either from the IDE debug menu, or by accessing the .aspx file on localhost using Firefox, I get the error:
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Jan 14, 2005
Hello all,
Thought I would post here in case anybody can give some information.
Here is the background information:
I have 2 tables (stores and sales) from the Pubs database in Sql Server 2000 copied down to a SQL Server CE database. There is no foreign key/primary key relationship between the 2 tables in the CE database.
Here are the update queries that cause the error:
UPDATE st
SET st.zip = 66668
FROM stores st
INNER JOIN sales sa ON st.stor_id = sa.stor_id
AND st.stor_id = 6380
Update stores SET stores.zip = 55555
FROM sales, stores
WHERE stores.stor_id = 6380
AND stores.stor_id = sales.stor_id
Here is the error message that is generated when I run the query (Param 0 and Param 1 change according to what column and line the FROM clause is in):
Error: 0x80040e14 DB_E_ERRORSINCOMMAND
Native Error: (25501)
Description: There was an error parsing the query. [Token line number,Token line offset,,Token in error,,]
Interface defining error: IID_ICommand
Param. 0: 2
Param. 1: 1
Param. 2: 0
Param. 3: FROM
Param. 4:
Param. 5:
I ran the 2 queries in SQL Query Analyzer in SQL Server 2000 and they worked just fine. I also created 2 new tables (stores1 and sales1) in SQL Server 2000 using the Select Into clause. The new tables were created from the sales table and stores table in the Pubs database. The new tables had no foreign key/primary key relationship.
I ran the queries again in Query Analyzer against the new tables and the queries produced no errors.
Any suggestions?
Thank you,
Aaron B
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Hi everybody,
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Thanks,
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