SQL Server 2012 :: How To Get Row Of First Change

May 12, 2015

I would like to get extract the first row of some time based data where any of the other values changes. For example, in the following 10 rows

ABDTE
112015-01-01
112015-01-02
112015-01-03
212015-01-04
112015-01-05
1NULL2015-01-06
1NULL2015-01-07
212015-01-08
212015-01-09
222015-01-10

I want to remove the rows where A and B are the same as on the previous row. So rows 2, 3, 7 and 9 should be eliminated. Note that A and B can have the same values multiple times, just not in succession in the extract. I've tried ranking but I can't figure out how to keep it from lumping all the values of A and B in the same group. The following incorrectly eliminates rows 5 and 8:

;with data as (
select 1 as A, 1 as B, '2015-01-01' as DTE union
select 1 as A, 1 as B, '2015-01-02' as DTE union
select 1 as A, 1 as B, '2015-01-03' as DTE union
select 2 as A, 1 as B, '2015-01-04' as DTE union

[Code] .....

Of course the real data has many columns and multiple data types that can have nulls. I just want get the row when anything changes. Is there a slick way to do this in SQL?

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[Code] .....

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*/
DECLARE
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[code]....

Problem is (and I seem not to be the only one with tis) described here:

"If the executed string contains a USE statement that changes the database context, the change to the database context only lasts until sp_executesql or the EXECUTE statement has finished running." There is nothing magical in SQL server that knows you intend a series of dynamic sql commands to be part of a single job running in a single context. You have to build the entire string for the job you want to execute."

[URL]

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[Code] ....

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[code]...

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[URL]

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