SQL Server 2014 :: DATEADD - Grouping By Week
Aug 25, 2015
We have bee using something like the following to get the Monday for the specified date.
However, we came across a scenario where this is not working
DECLARE @dt AS datetime
SET @dt = '2/19/2006'
SELECT DATEADD( ww, DATEDIFF( ww, 0, @dt),0)
It had seemed to be working as expected, but we recently came across a problem where The above is returning 2/20, not 2/13
View 9 Replies
ADVERTISEMENT
Oct 25, 2014
I am trying to create a job that would backup a DB dynamically to a different folder based on the week day. So if it's Saturday, backup to folder Saturday.
I have this
DECLARE @BackupLoc nvarchar (100)
DECLARE @DayOfWeek nvarchar (100)
set @BackupLoc = N'D:Backup'
set @DayOfWeek = (SELECT DATENAME(dw,GETDATE()))
set @BackupLoc = @backuploc + @DayOfWeek
[Code] ....
But it's giving me permission errors, although the AGENT and MSSQL service accounts are members of the local admins group.
View 2 Replies
View Related
Aug 7, 2007
Hi
SQL Server 2000
Table_A, Col_1 datetime
I want a query to group the date on weeks.
Please advise how ?
Thanks
Jawad
View 3 Replies
View Related
Mar 14, 2007
Hi all,
I am using the below statement to get some dates grouped by date, in my SP.
SELECT TOP 100 PERCENT COUNT(dbo.test.CallDate) AS CallCount, year(dbo.test.CallDate) AS CallYear, datepart(wk, dbo.test.CallDate) AS [Week] FROM dbo.test LEFT OUTER JOIN dbo.view1 ON dbo.test.CallID = dbo.view1.CallID LEFT OUTER JOIN dbo.view2 ON dbo.test.CallID = dbo.view2.CallID WHERE (dbo.view1.[ACCOUNT ID] = @accountid OR (dbo.view2.[ACCOUNT ID] = @accountid AND (convert(varchar(10),dbo.test.CallDate,121) BETWEEN CONVERT(DATETIME, @StartDate, 102)AND CONVERT(DATETIME, @EndDate, 102)) GROUP BY year(dbo.test.CallDate), datepart(wk, dbo.test.CallDate) ORDER BY year(dbo.test.CallDate), datepart(wk, dbo.test.CallDate) i gave startdate as 1/1/2007 and endDate as 2/18/2007 i am getting the reuslt as count year week 42 2001 32 2 2001 39 1 2001 51 1 2002 17 1 2002 19 106 2002 21 183 2002 22 226 2002 23 ................................. ................................... 1208 2007 1 1292 2007 2 actually i should get only the last 2 rows. Can anyone please point out, why i am getting the 2001, 2002 data? and how to fix that?Thanks
View 2 Replies
View Related
Apr 9, 2013
How can I get Saturday's date given the week number?
This is my week number, SELECT DATEPART(WEEK, DATEADD(MONTH, +3, ApptDt2)). I need to get Saturday's date from this week.
View 9 Replies
View Related
Oct 5, 2007
Hi,
I need to run report that shows activity for Paediatrics Consultants who starts their audit week on Fri 5pm and finish next Fri at 5pm.
Set datefirst would work Fri to Thur but not with hours. And does not always seem to work either.
I need to be able to see historical data and do not want people to enter dates (from to), will group it by wek, consultant
Any clues? Cheers
Petr
View 3 Replies
View Related
Nov 30, 2015
We are trying to compare our current calendar week (based on Monday being the first day of the week) with the previous calendar week.
I'm trying to produce a line chart with 2 axis:
- x axis; the day of the week (Mon, Tues, Wed etc - it is fine for this to be a # rather than text e.g. 1 = Mon, 2 = Tues etc)
- y axis; the cumulative number of orders
The chart needs two series:
Previous Week. The running count of orders placed that week.
Current Week. The running count of orders placed this week.
Obviously in such a chart the 'Current Week' series is going not going to have values along the whole axis until the end of the week. This is expected and the aim of the chart is to see the current week compares against the previous week for the same day.
I have two tables:
Orders TableCalendar Table
The calendar table's main date column is [calDate] and there are columns for the usual [calWeekNum], [calMonth] etc.
My measure for counting orders is simply; # Orders: = countrows[orders].
How do I take this measure and then work out my two series. I have tried numerous things such as adapting TOTALMTD(), following articles such as these:
- [URL] ...
- [URL] ...
But I have had no luck. The standard cumulative formulas do work e.g. if I wanted a MTD or YTD table I would be ok, it's just adjusting to a WTD that is causing me big issues.
View 3 Replies
View Related
Sep 17, 2015
i have the following table I need to select dates grouping them by weeks, my week start is Saturday to Friday
CREATE TABLE weekdays
(
datevalue datetime NOT NULL
, numericvalue INT NOT NULL
);
INSERT INTO weekdays (datevalue, numericvalue) VALUES
[code]....
The output should look like this
weeknototalvalue
362015-09-01 00:00:00.000
362015-09-02 00:00:00.000
372015-09-07 00:00:00.000
372015-09-08 00:00:00.000
382015-09-12 00:00:00.000
382015-09-13 00:00:00.000
382015-09-14 00:00:00.000
392015-09-19 00:00:00.000
View 4 Replies
View Related
May 23, 2007
Hi all,
I'd like to add a yesterday dimension member to a new dimension, like a "Time Utility" dimension, that references the second last day of non empty data in a cube.
At the moment, I'm doing this:
Code Snippet
create member [MIA DW].[DATE TIME].[Date].[Yesterday]
as [DATE TIME].[Date].&[2007-01-01T00:00:00]
select [Measures].members on 0,
non empty [DATE TIME].[Date].members on 1
from [MIA DW]
But the [yesterday] member does not seem to belong to [DATE TIME].[Date].members?
So I guess there's two questions:
1) Can I have a new empty dimension which contains all these special members like "Yesterday" or "This Week" and "Last Week" (these last two obviously refer to a set of Dates)
2)How come the Yesterday member is not returned by the .members function?
Thanks
Greg
View 3 Replies
View Related
Jan 29, 2014
I am adding week hrs using while loop , but it can continue next week hrs also.
I can get every week start hrs while update @tem1 table
employeeidreportdatereportatleftattoaccountwrhrn
12902014-01-29 00:00:00.00009:3019:1556001
12902014-01-28 00:00:00.00009:0018:4555802
12902014-01-27 00:00:00.00009:0018:455585583
12902014-01-25 00:00:00.00008:0010:0012004 -- week end
12902014-01-24 00:00:00.00009:1718:4554105
12902014-01-23 00:00:00.00009:1918:4654606
12902014-01-22 00:00:00.00009:1718:4754507
12902014-01-21 00:00:00.00009:1618:3552608
12902014-01-20 00:00:00.00009:1818:555435439
My loop statement
while(select MAX(wrh) from @tem1 where wrh = 0) < 1
begin
update @tem1
set wrh = (select toaccount from @tem1
where reportdate = (select min(reportdate) from @tem1 where wrh = 0))+(select max(wrh) from @tem1)
where wrh = (select max(wrh) from @tem1 where wrh = 0 )
and reportdate = (select min(reportdate) from @tem1 where wrh = 0)
end
this is the result while executing loop statement .
employeeidreportdatereportatleftatdehdrhwehwrh
129029 Jan 201409:3019:15008:0009:20024:00065:54
129028 Jan 201409:0018:45008:0009:18016:00056:34
129027 Jan 201409:0018:45008:0009:18008:0009:18
129025 Jan 201408:0010:00005:0002:00045:00047:16 -- week end
129024 Jan 201409:1718:45008:0009:01040:00045:16
129023 Jan 201409:1918:46008:0009:06032:00036:15
129022 Jan 201409:1718:47008:0009:05024:00027:09
129021 Jan 201409:1618:35008:0008:46016:00018:04
129020 Jan 201409:1818:55008:0009:03008:0009:03
How to update only that week hrs , don't continue next week...
View 4 Replies
View Related
Apr 29, 2008
In my reports I am extracting the data of number of people joined in all the weeks of the year. And in one of reports I have to extract the data of the number of people joined until the last week from the first week. I am trying out all the logics but nothing is working for me as such. Can any one help me with this issue??????
View 4 Replies
View Related
Jul 23, 2015
I need a Select sentence that return me the first week of the month for a given week.
For example If I have week number 12 (Begins 2015/03/16 and Ends 2015/03/22) I need that returns 9, I mean Week number 9 wich is the first week of march (having in mind @@DATEFIRST).
I only need give a week number of the year and then returns the week number of the first week of that month.
View 34 Replies
View Related
Feb 2, 2008
I'm looking for a way to convert the [week number, year] back to the date for the 1st day of that week.
Example (assuming DATEFIRST has been set to 1) : Week 3, 2008 = January 14, 2008
Is there a SQL function that will do this?
Thanks,
Mike
View 11 Replies
View Related
May 20, 2006
hello all !!!
i have a table having fields
table _ project 1)Duration 2)Enddate (null by default) these 2 fields
now i want to set constraint that
Enddate should be equal to Duration values from the dat User inputs in Duration field data.... .... Enddate = todays date + Duration (int)
i tried
1)DateAdd(days,project.Duration,Getdate())
2)DateAdd(dd,project.Duration,Getdate())
please help me !!!!
View 2 Replies
View Related
Jan 8, 2014
I am trying to generate a @StartDate and @EndDate. The @StartDate would be the 1st of January and the year is dependent on the @EndDate.
The @EndDate would be
select max(DateValue) from dbo.testtableThe column DateValue in the testtable contains dates such as 2013-12-09, 2013-12-15.
What I am trying to accomplish is if the @EndDate is populated by select max(DateValue) from dbo.testtable returns '2013-12-15' as the max(DateValue). I want the @StartDate to '2013-01-01' because the year of the EndDate is 2013.
So something along the lines of
@StartDate = DateAdd(yy,?,@EndDate)
View 2 Replies
View Related
Jun 6, 2006
seriously now
View 1 Replies
View Related
Aug 15, 2006
I have a query that run every day to update a summary table which has week number and day of week. what I currently do is delete all records from the summary table and then summarize all the data availabe from four tables adn then populate the table daily. I want to know if I can run the update query to run only for the week number and day of week depending on getdate. Can I do this?
Please help..
View 1 Replies
View Related
Jan 18, 2006
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK returns the ISO 8601 Year Week Day of Week in format YYYY-W01-D for the date passed. W01 represents the week of the year from W01 through W53, and D represents the day of the week with 1 = Monday through 7 = Sunday.
The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.
This code creates the function and demos it for the first day, first date+60, and first date+364 for each ISO week/year from 1990 to 2030.
drop function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
GO
create function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
(
@Datedatetime
)
returnsvarchar(10)
as
/*
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK
returns the ISO 8601 Year Week Day of Week
in format YYYY-W01-D for the date passed.
*/
begin
declare @YearWeekDayOfWeekvarchar(10)
Select
--Format to form YYYY-W01-D
@YearWeekDayOfWeek =
convert(varchar(4),year(dateadd(dd,7,a.YearStart)))+'-W'+
right('00'+convert(varchar(2),(datediff(dd,a.YearStart,@Date)/7)+1),2) +
'-'+convert(varchar(1),(datediff(dd,a.YearStart,@Date)%7)+1)
from
(
select
YearStart =
-- Case finds start of year
case
whenNextYrStart <= @date
thenNextYrStart
whenCurrYrStart <= @date
thenCurrYrStart
elsePriorYrStart
end
from
(
select
-- First day of first week of prior year
PriorYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aaa.Jan4))/7)*7,-53690),
-- First day of first week of current year
CurrYrStart =
dateadd(dd,(datediff(dd,-53690,aaa.Jan4)/7)*7,-53690),
-- First day of first week of next year
NextYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aaa.Jan4))/7)*7,-53690)
from
(
select
--Find Jan 4 for the year of the input date
Jan4=
dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0))
) aaa
) aa
) a
return @YearWeekDayOfWeek
end
go
-- Execute function on first day, first day+60,
-- and first day+364 for years from 1990 to 2030.
select
DT= convert(varchar(10),DT,121),
YR_START_DT =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT),
YR_START_DT_60 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+60),
YR_START_DT_365 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+364)
from
(
select DT = getdate()union all
select DT = convert(datetime,'1990/01/01') union all
select DT = convert(datetime,'1990/12/31') union all
select DT = convert(datetime,'1991/12/30') union all
select DT = convert(datetime,'1993/01/04') union all
select DT = convert(datetime,'1994/01/03') union all
select DT = convert(datetime,'1995/01/02') union all
select DT = convert(datetime,'1996/01/01') union all
select DT = convert(datetime,'1996/12/30') union all
select DT = convert(datetime,'1997/12/29') union all
select DT = convert(datetime,'1999/01/04') union all
select DT = convert(datetime,'2000/01/03') union all
select DT = convert(datetime,'2001/01/01') union all
select DT = convert(datetime,'2001/12/31') union all
select DT = convert(datetime,'2002/12/30') union all
select DT = convert(datetime,'2003/12/29') union all
select DT = convert(datetime,'2005/01/03') union all
select DT = convert(datetime,'2006/01/02') union all
select DT = convert(datetime,'2007/01/01') union all
select DT = convert(datetime,'2007/12/31') union all
select DT = convert(datetime,'2008/12/29') union all
select DT = convert(datetime,'2010/01/04') union all
select DT = convert(datetime,'2011/01/03') union all
select DT = convert(datetime,'2012/01/02') union all
select DT = convert(datetime,'2012/12/31') union all
select DT = convert(datetime,'2013/12/30') union all
select DT = convert(datetime,'2014/12/29') union all
select DT = convert(datetime,'2016/01/04') union all
select DT = convert(datetime,'2017/01/02') union all
select DT = convert(datetime,'2018/01/01') union all
select DT = convert(datetime,'2018/12/31') union all
select DT = convert(datetime,'2019/12/30') union all
select DT = convert(datetime,'2021/01/04') union all
select DT = convert(datetime,'2022/01/03') union all
select DT = convert(datetime,'2023/01/02') union all
select DT = convert(datetime,'2024/01/01') union all
select DT = convert(datetime,'2024/12/30') union all
select DT = convert(datetime,'2025/12/29') union all
select DT = convert(datetime,'2027/01/04') union all
select DT = convert(datetime,'2028/01/03') union all
select DT = convert(datetime,'2029/01/01') union all
select DT = convert(datetime,'2029/12/31') union all
select DT = convert(datetime,'2030/12/30')
) a
Function Test Results:
DT YR_START_DT YR_START_DT_60 YR_START_DT_364
---------- ----------- -------------- ---------------
2006-01-18 2006-W03-3 2006-W11-7 2007-W03-3
1990-01-01 1990-W01-1 1990-W09-5 1991-W01-1
1990-12-31 1991-W01-1 1991-W09-5 1992-W01-1
1991-12-30 1992-W01-1 1992-W09-5 1992-W53-1
1993-01-04 1993-W01-1 1993-W09-5 1994-W01-1
1994-01-03 1994-W01-1 1994-W09-5 1995-W01-1
1995-01-02 1995-W01-1 1995-W09-5 1996-W01-1
1996-01-01 1996-W01-1 1996-W09-5 1997-W01-1
1996-12-30 1997-W01-1 1997-W09-5 1998-W01-1
1997-12-29 1998-W01-1 1998-W09-5 1998-W53-1
1999-01-04 1999-W01-1 1999-W09-5 2000-W01-1
2000-01-03 2000-W01-1 2000-W09-5 2001-W01-1
2001-01-01 2001-W01-1 2001-W09-5 2002-W01-1
2001-12-31 2002-W01-1 2002-W09-5 2003-W01-1
2002-12-30 2003-W01-1 2003-W09-5 2004-W01-1
2003-12-29 2004-W01-1 2004-W09-5 2004-W53-1
2005-01-03 2005-W01-1 2005-W09-5 2006-W01-1
2006-01-02 2006-W01-1 2006-W09-5 2007-W01-1
2007-01-01 2007-W01-1 2007-W09-5 2008-W01-1
2007-12-31 2008-W01-1 2008-W09-5 2009-W01-1
2008-12-29 2009-W01-1 2009-W09-5 2009-W53-1
2010-01-04 2010-W01-1 2010-W09-5 2011-W01-1
2011-01-03 2011-W01-1 2011-W09-5 2012-W01-1
2012-01-02 2012-W01-1 2012-W09-5 2013-W01-1
2012-12-31 2013-W01-1 2013-W09-5 2014-W01-1
2013-12-30 2014-W01-1 2014-W09-5 2015-W01-1
2014-12-29 2015-W01-1 2015-W09-5 2015-W53-1
2016-01-04 2016-W01-1 2016-W09-5 2017-W01-1
2017-01-02 2017-W01-1 2017-W09-5 2018-W01-1
2018-01-01 2018-W01-1 2018-W09-5 2019-W01-1
2018-12-31 2019-W01-1 2019-W09-5 2020-W01-1
2019-12-30 2020-W01-1 2020-W09-5 2020-W53-1
2021-01-04 2021-W01-1 2021-W09-5 2022-W01-1
2022-01-03 2022-W01-1 2022-W09-5 2023-W01-1
2023-01-02 2023-W01-1 2023-W09-5 2024-W01-1
2024-01-01 2024-W01-1 2024-W09-5 2025-W01-1
2024-12-30 2025-W01-1 2025-W09-5 2026-W01-1
2025-12-29 2026-W01-1 2026-W09-5 2026-W53-1
2027-01-04 2027-W01-1 2027-W09-5 2028-W01-1
2028-01-03 2028-W01-1 2028-W09-5 2029-W01-1
2029-01-01 2029-W01-1 2029-W09-5 2030-W01-1
2029-12-31 2030-W01-1 2030-W09-5 2031-W01-1
2030-12-30 2031-W01-1 2031-W09-5 2032-W01-1
(43 row(s) affected)
CODO ERGO SUM
View 2 Replies
View Related
May 2, 2007
hi friends,
how to get the date of the first/last day of the week in sql...
can any one help me
Cheers,
raj
View 5 Replies
View Related
Nov 26, 2007
I'm really stumped on this one. I'm a self taught SQL guy, so there is probobly something I'm overlooking.
I'm trying to get information like this in to a report:
WO#
-WO Line #
--(Details)
--Work Order Line Detail #1
--Work Order Line Detail #2
--Work Order Line Detail #3
--Work Order Line Detail #etc
--(Parts)
--Work Order Line Parts #1
--Work Order Line Parts #2
--Work Order Line Detail #etc
WO#
-WO Line #
--(Details)
--Work Order Line Detail #1
--Work Order Line Detail #2
--Work Order Line Detail #3
--Work Order Line Detail #etc
--(Parts)
--Work Order Line Parts #1
--Work Order Line Parts #2
--Work Order Line Parts #etc
I'm unable to get the grouping right on this. Since the line details and line parts both are children of the line #, how do you do "parallel groups"?
There are 4 tables:
Work Order Header
Work Order Line
Work Order Line Details
Work Order Line Requisitions
The Header has a unique PK.
The Line uses the Header and a Line # as foreign keys that together are unique.
The Detail and requisition tables use the header and line #'s in addition to their own line number foreign keys. My queries ends up looking like this:
WO WOL WOLR WOLD
226952 10000 10000 10000
226952 10000 10000 20000
226952 10000 10000 30000
226952 10000 10000 40000
226952 10000 20000 10000
226952 10000 20000 20000
226952 10000 20000 30000
226952 10000 20000 40000
399999 10000 NULL 10000
375654 10000 10000 NULL
etc
Hierarchy:
WO > WOL > WOLD
WO > WOL > WOLR
It probobly isn't best practice, but I'm kinda new so I need some guidance. I'd really appreciate any help! Here's my query:
SELECT [Work Order Header].No_ AS WO_No, [Work Order Line].[Line No_] AS WOL_No,
[Work Order Requisition].[Line No_] AS WOLR_No, [Work Order Line Detail].[Line No_] AS WOLD_No
FROM [Work Order Header] LEFT OUTER JOIN
[Work Order Line] ON [Work Order Header].No_ = [Work Order Line].[Work Order No_] LEFT OUTER JOIN
[Work Order Line Detail] ON [Work Order Line].[Work Order No_] = [Work Order Line Detail].[Work Order No_] AND
[Work Order Line].[Line No_] = [Work Order Line Detail].[Work Order Line No_] LEFT OUTER JOIN
[Work Order Requisition] ON [Work Order Line].[Work Order No_] = [Work Order Requisition].[Work Order No_] AND
[Work Order Line].[Line No_] = [Work Order Requisition].[Work Order Line No_]
View 1 Replies
View Related
Jul 23, 2005
Dear All,I have one field in my table which shows the day of the week. It isshowingSunday = 1Monday = 2Tuesday = 3But i want Monday is the first day. I know i can use DATEFIRST tochange it but it works in Query Analyzerbut when i come and see mytable it is showing the old settings. Is it possible i can change itpermanently. Any help in this regard will be higly appreciatedRegardsS
View 2 Replies
View Related
May 28, 2015
I need to generate the week ranges like this format :
Here from date and to date would be picked up from the table but just to make you understand i have hardcoded it but this is the real date which is falling inside the table.
Note : Week should be generated from Monday to Sunday within desired date range
View 9 Replies
View Related
Jan 10, 2008
Hi,
Can anybody tell me to How to get the week number of a specific Date in SQL Server 2005.
Like : say Date "03/01/2008" belongs to the 1st week of the year 2008, same way "21/02/2008" is 8th week of the year 2008.
So, the same way I need to know the week number of a given (variable) date.
I need to write / use a Function in SQL server which will return the Number (INT) (i.e. 1 or 8 or 10 etc...) against a specific (Parameter) date.
regards,
Saibal
Note : Please feel free to write me if my question is not clear.
View 5 Replies
View Related
Oct 21, 2014
I need to build a report that compares a count on a certain day of the week by month by year by stacks. That is,for first Monday in October 2012 against first Monday in October 2013 for stack DM1 against first Monday in October 2014 stack DM1, same for second Monday, first Tuesday, second Tuesday, ect. Attached is a sample dataset and what I want to achieve.
View 9 Replies
View Related
Nov 6, 2015
I have a table where hours are being loaded in a weekly basis. The YearWeek is populated when the data is loaded. The value format of the Year Week is 2015-39, 2015-41, etc. I need to calculate the total hours per Fiscal Year.For example, week '2015-39' will be return FY15 and week '2015-41' will return FY16, and so on. By extracting the year, I can do a group by and have total hours for each year.
Currently, I have it working by splitting the value into year and week and then looping through each year and week, so I can assign the totals to the corresponding FY.select sum(hours) as total, yearweek from tablename group by yearweek...Then I loop through using C#.I can return the FY using an actual date,how to do it for year-week format for any given year.
select CASE
WHEN CAST(GETDATE() AS DATE) >
SMALLDATETIMEFROMPARTS(DATEPART(YEAR,GETDATE()),09,30,00,000)
THEN
DATEPART(YEAR,GETDATE()) + 1 ELSE DATEPART(YEAR,GETDATE())
END AS FY
View 9 Replies
View Related
Oct 17, 2006
Just want to double check this.To add 30 days to the current date in a stored procedure using SQL Server should be this: DATEADD(day, 30, GETDATE())Right?Thanks,Zath
View 1 Replies
View Related
Mar 1, 2006
Hi
Hope someone can help.
I've got to produce a report that filters information dependent on the purchase date based on various parameters.
The parameters are:
@yearend (Datetime)
@months(int)
the script that I wrote in SQL is
select assetno from assets where purch_date < = dateadd(mm,-@months, @yearend)
but when I try to use this in the dataset it comes up with the following error:
"Application usess a value of the wrong type for the current operation"
Any help would be very much appreciated.
View 3 Replies
View Related
Feb 6, 2006
Hi guys I am trying to convert this to date add because MS SqL and Jet SQL dont exactly speak the same language
=DateSerial(Year([FINALSUIT])4,Month([FINALSUIT]),Day([FINALSUIT]))
I am trying to calcuate the finalsuit date for every 2 years becasue that when employees have to get their gaming license renewed, so I'm trying to add the renewal year by 2 because they have to get it done every two years
View 2 Replies
View Related
Mar 22, 2007
If I am running a scheduled job at the first of the month and I want to run an update sequence for the previous month, i was essentially using this sql:
@startdate = dateadd(mm, -1, getdate())
@enddate = dateadd(dd, -1, getdate())
So, will the @enddate represent the last day in the previous month or will that not work?
The Yak Village Idiot
View 1 Replies
View Related
Apr 17, 2008
What is the correct format for getting the last three months of data. in sql its DATEADD(mm-3,getdate()) but for some reason the report doesnt want to take this? what am i doing wrong?
Code Snippet
=IIF(Sum(iif(Fields!Database_Size_Datetime.Value >= DATEADD(mm, - 3, GETDATE()), Cdbl(Fields!MonthlyDBTotal.Value), 0.0))/ 3)
By the way, im trying to get the average over the last three months by doing this.
View 3 Replies
View Related
Sep 26, 2006
I am using Derived Column Transformation Task to format my data as I am converting my DTS to SSIS. One of the columns requires to use DATEADD where I add 1 month and substruct one day from the date that I get in the flat file.(note that I always hardcode the day to "01" regardless of what I get in my flat file)
The current script looks like this:
DTSDestination("PeriodEndDate") =
dateadd("d",-1,dateadd("m",1,cdate(mid(cstr(DTSSource("Col004")),1,4) & "-" & mid(cstr(DTSSource("Col004")),5,2) & "-" & "01")))
Does any one know how to convert it so it works in my derived column?
Thanks...
Maria
View 3 Replies
View Related
Nov 19, 2007
when I execute the following:
select dateadd(dd,92710,1/1/1753)
I get 2153-10-31 00:00:00.000
in managed code I get the right answer 11/1/2006. Between 1753 and 2007, there should have been 2007 - 1753 = 254 yrs x approx 365 = 92,710 days. Where is the year 2153 coming from?
View 1 Replies
View Related
Sep 20, 2006
Hi, I have a problem with working out some dates. I have a query that has a start date field and a number of days field. I know i can create another field that could provide the return date (DATEADD function) by adding the number of days to the start date. However the problem I have is that i need to discount the weekends from the return date. For example if the start date was a wednesday and the number of days was 3 the datadd sum would give a return date of saturday when in reality it should be monday. I am not sure if i am making sense but if anyone out there has any ideas it would be more than welcome. Andrew
View 8 Replies
View Related