Select Most Recent Customer Record From Table Only?

Nov 6, 2007

If I have a table structure similar to the following, how might I query it to obtain the Transaction ID, Transaction Date, and Customer Name for the most recent transaction per customer only:


TransactionTable:
TransactionID TransactionDate TransactionType CustomerName
1 10/1/07 1 Bob
2 8/30/07 2 Janet
3 9/17/07 1 Mike
4 9/25/07 1 Bob


The following query will return all records in the table other than Janets...not what I want:
SELECT Transaction ID, TransactionDate, CustomerName
FROM TransactionTable
WHERE TransactionType = 1
ORDER BY TransactionDate DESC


The following query will return all records in the table other than Janets again, because DISTINCT will use the combo of TransactionID, TransactionDate, and Customer name for uniqueness...not what I want:
SELECT DISTINCT Transaction ID, TransactionDate, CustomerName
FROM TransactionTable
WHERE TransactionType = 1
ORDER BY TransactionDate DESC

The results set I'm looking for would be the following, where only the most recent entry per customer with TransactionType 1 is returned (i.e. one record for Bob):


TransactionTable:
TransactionID TransactionDate CustomerName
1 10/1/07 Bob
3 9/17/07 Mike


I believe I need an appropriate subquery to yield the results I desire, but can't sort out what it is? I do not want to execute multiple queries but subqueries are fine. Unfortunately there's probably an easy answer that my brain is not currently generating. Any help would be appreciated.


Note, this is not a real table, but a sample to illustrate the concept for the query I need.

Thanks.

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SELECT
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la.[bundle_id],
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[Code] ....

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How do I construct the SQL query?


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Code Snippet
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Code:


Table: Reports_AccountID
ReportID | AccountID
--------------------------
5 | 1234
5 | 987
4 | 1234
3 | 1234
5 | 5677

Log: Reports_Log
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----------------------------------------
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9866 | 5 | 5677 | 9/2/2007 10:35:43 AM
9865 | 4 | 1234 | 9/2/2007 9:05:43 AM
9864 | 3 | 1234 | 9/2/2007 9:30:17 AM



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here is the code


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Compnetsyslc

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[code]....

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Code Snippet
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