Selecting Lowest DateTime If It Meets Some Conditions

ID (PK), userID (FK), from [Datetime], to[datetime], type [int] , value [nvarchar]

Conditions
I want to select the column "to" which is a datetime-column for all users within the table.

One user can have multiple registered rows in "mytable", so I want to select the row that contains the newest "from" date.The newest "from"-column for a specific user is where I am struggling... Because if the "to"-column of any of the registered rows by the current user is equal to the newest "from -1 day" column for the user, I want to select the second newest from-date.

Code:
//Handwritten
DECLARE @from DATETIME //Current Selected datetime [the newest of the current user doing the query]
DECLARE @id INT //userID
DECLARE @tbl TABLE (from datetime, userid int)

[code]....

But for user ID 201 [all users with Type = 1], I need to run through some more code, to figure out which date we want... Which date do I want? The "from"-date that is the newest, but if "to" is just 1 day before "from", I want to select the "from" at that row instead... Example with numbers [integers] instead of Date:

Code:
From - To
5 8
10 15
16 20

I want to select "10" in the from column as the maximum "from"-integer, and not 16. Because in the "To" column we have a match in the "from" column on the condition "To + 1" [15+ 1 == 16], so then I want the "from" value where "To" equals 15, which is 10. The top row I do not want, because the difference between From and To [10 - 8 is larger than 1]...

This means that the Image shown... I am first selecting the "1", then I do some checks, if the "to" for the user is 1 day earlier than the MAX(from) I grab a new "from" value...

Code:
SELECT MIN (t1.from) FROM table as t1
WHERE
t1.from IN
(
SELECT t2.to+ 1 FROM table as t2
WHERE t2.userID = @id
)