SetComponentProperty - Possible Key / Value Combinations

Oct 12, 2007

I was using the code in this thread (http://forums.microsoft.com/MSDN/ShowPost.aspx?PostID=1371094&SiteID=1) to create a console application which can build the SSIS package dynamically and run the package.

I'm not clear on what all could be the possible key / value combinations for the SetComponentProperty Method. From the examples I have seen its either SqlCommand or OpenRowSet. But I'm not sure about the "AccessMode" with values either 0 or 2. Is there any reference where I get more information on these?




Code Block
// Set the custom properties of the source.
srcDesignTime.SetComponentProperty("AccessMode", 2);
srcDesignTime.SetComponentProperty("SqlCommand", "Select * from devdb..empl_karun");



Thanks

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SetComponentProperty Not Working

Mar 12, 2007

Hi,

I am creating a custom UI. From this UI, I want the custom properties to be updated once the user clicks the OK button.

From what I have read, this is done by the setComponentProperty command. However, even though I am setting the proper property, with a value that has indeed changed, the change is not being reflected in properties view in the SSIS Designer.

Here is a code sample, I followed a sample found on the MSDN site exactly:

private void okBtn_Click(object sender, EventArgs e)

{

if (designTimeInstance == null) {

designTimeInstance = metaData.Instantiate();

}

//set component custom properties

designTimeInstance.SetComponentProperty("BatchSize",5);

this.close();

}

What am I missing?

Thanks

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Combinations

Jan 14, 2008

Hi,

I have a table with 2 columns (S.No,Name) with rows
1,Raja
2,Ramu
3,Rane

I need to generate all 2 pair combinations of the names(i,e)

(Raja -Ramu)
(Raja -Rane)
(Ramu -Rane)

Can some one give me a generalized query for this problem?

Thanks,

Prakash.P

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Jul 31, 2004

I want to start with a table that has 4 records:

-Self
-Supervisor
-Peer
-Direct Rep

And I want to end with a table that has every unique combination of these records (the order being reversed would be considered 'unique' in this context)

-Self , Supervisor
-Supervisor , Self
-Self , Peer
-Peer , Self
-Self , Direct Rep
-Direct Rep , Self
-Peer , Direct Rep
-Direct Rep, Peer

How would I do this in an SQL Query? Thanks for your help!

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Jul 9, 2006

The requirement in to write a query which will return top 2 rows (in terms of lst_updt_timestamp column) for every combinations of cust_alias_nm, carrier_cd, acct_nbr columns.

Here I wrote a query which selects top 1 only.
Please help me to write to get the top 2nd along with the top 1st row.

select A.cust_alias_nm_id,
A.carrier_cd_id, A.acct_nbr_id,
sum(A.pd_clm_amt) clm_amt,
sum(A.pd_med_amt) med_amt,
sum(A.pd_exp_amt) exp_amt,
A.lst_updt_timestamp
from bal_load_stg A
group by A.cust_alias_nm_id, A.carrier_cd_id, A.acct_nbr_id, A.lst_updt_timestamp
having A.lst_updt_timestamp
in (
(select max(lst_updt_timestamp) from bal_load_stg B
where
A.cust_alias_nm_id = B.cust_alias_nm_id
and A.carrier_cd_id = B.carrier_cd_id
and A.acct_nbr_id = B.acct_nbr_id))


The output looks like:
cust_alias_nm_id carrier_cd_id acct_nbr_id clm_amt med_amt exp_amt lst_updt_timestamp
---------------- ------------- -------------- ---------------------------------------- ---------------------------------------- ---------------------------------------- ------------------------------------------------------
aaa 101 1234567891 500.00 500.00 500.00 2005-07-31 00:00:00.000
aaa 102 1234567891 500.00 500.00 500.00 2005-08-31 00:00:00.000
aaa 100 1234567890 700.00 700.00 700.00 2005-10-31 00:00:00.000


The desired output should look like:

cust_alias_nm carrier_cd acct_nbr clm_amt med_amt exp_amt lst_updt_timestamp
---------------- ------------- -------------- ---------------------------------------- ---------------------------------------- ----------------------------------------
aaa 100 1234567890 700.00 700.00 700.00 2005-10-31 00:00:00.000
aaa 100 1234567890 500.00 500.00 500.00 2005-08-31 00:00:00.000
aaa 102 1234567891 500.00 500.00 500.00 2005-08-31 00:00:00.000
aaa 101 1234567891 500.00 500.00 500.00 2005-07-31 00:00:00.000
aaa 101 1234567891 400.00 400.00 400.00 2005-05-31 00:00:00.000


All rows present in the table are
cust_alias_nm carrier_cd acct_nbr clm_amt med_amt exp_amt lst_updt_timestamp
---------------- ------------- -------------- ---------------------------------------- ---------------------------------------- ----------------------------------------
aaa 100 1234567890 700.00 700.00 700.00 2005-10-31 00:00:00.000
aaa 100 1234567890 500.00 500.00 500.00 2005-08-31 00:00:00.000
aaa 102 1234567891 500.00 500.00 500.00 2005-08-31 00:00:00.000
aaa 101 1234567891 500.00 500.00 500.00 2005-07-31 00:00:00.000
aaa 100 1234567890 400.00 400.00 400.00 2005-05-31 00:00:00.000
aaa 101 1234567891 400.00 400.00 400.00 2005-05-31 00:00:00.000





Thanks in advance.

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May 7, 2008

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******************************************************************
SELECT SUM("TR_1"."AmountLCU")*-1 "Budget",rtrim("TR_1"."COSTCENTER") "Cost Centre",rtrim("TR_1"."ACCOUNT") "Account Num",rtrim("TR_1"."DONOR") "Donor Num", "TR_1"."AmountLCU"*-1 "Amount","TR_1"."TTYPE", rtrim("TR_1"."ACTIVITY") "Activity Code" FROM "scalaDB"."dbo"."A_GL0601_PREVIOUS" "TR_1"
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**********************************************************************
Note: the report is written in Crystal reports and the database is SQL Server (not sure of the version)

Thanks in advance
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Sep 6, 2013

How would I write a query to produce all combinations for a situation such as the following?

Suppose I wanted to write a sentence, "This is [adjective] [noun]." where [adjective] comes from the Adjective table and [noun] come from the Noun table.

Adjective table looks like e.g.

ID Adj
1 good
2 so so
3 bad

Noun table looks like e.g.

ID Noun
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2 orange
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And the result set would look like

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This is so so apple.
This is bad apple.
This is good orange.
This is so so orange.
This is bad orange.
This is good banana.
This is so so banana.
This is bad banana.

I would take a stab at this myself and post even something that doesn't work...

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Oct 26, 2007

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select count(distinct One, Two) from MyTable

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Code:
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pear
blueberry
apple, pear
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pear, blueberry
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[Code] ...

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