Simple Date Problem

I'm trying to find the first Monday for any given year. I've found something
that works, but I typically find the most convoluted way to do a simple task.
Is there something simpler/cleaner than this?



DECLARE @intYear INTEGER
DECLARE @dtmFirstMon DATETIME
DECLARE @dtmWorkDate DATETIME

SET @intYear=YEAR(GETDATE())+2

SET @dtmWorkDate=CAST('01/01/' +CAST(@intYear AS CHAR(4)) AS DATETIME)
SET @dtmFirstMon=(SELECT CASE
WHEN DATEPART(dw, @dtmWorkDate)=2 THEN @dtmWorkDate
WHEN DATEPART(dw, DATEADD(D,1,@dtmWorkDate))=2 THEN DATEADD(D,1,@dtmWorkDate)
WHEN DATEPART(dw, DATEADD(D,2,@dtmWorkDate))=2 THEN DATEADD(D,2,@dtmWorkDate)
WHEN DATEPART(dw, DATEADD(D,3,@dtmWorkDate))=2 THEN DATEADD(D,3,@dtmWorkDate)
WHEN DATEPART(dw, DATEADD(D,4,@dtmWorkDate))=2 THEN DATEADD(D,4,@dtmWorkDate)
WHEN DATEPART(dw, DATEADD(D,5,@dtmWorkDate))=2 THEN DATEADD(D,5,@dtmWorkDate)
WHEN DATEPART(dw, DATEADD(D,6,@dtmWorkDate))=2 THEN DATEADD(D,6,@dtmWorkDate)
END)
PRINT(@DTMFIRSTMON)