Simple Query
Oct 2, 2005I have a table like
create table sample (Column1 , Column2 int)
I want to select say 3 or 4 Column1's for each Column2 with out using a cursor.
Can u help
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Help With A Simple Query
Oct 1, 2007I am trying to make a single display page for an author's books.the books page only displays books of a type "type" (novels, non-fiction, etc)I would like to make it so that it can also show all books if "type" isn't selected. I THOUGHT the string would look like this: <asp:SqlDataSource ID="SqlDSBooks" runat="server" ConnectionString="<%$ ConnectionStrings:csK2Reader %>"
SelectCommand="SELECT * FROM [Books] ( If @Type <> "" then WHERE ([Type] = @Type)) ORDER BY [SortDate] DESC"> But it doesn't seem to want to work. I get a "server tag is not well formed" error.
I Need Help With A Simple Query
Jan 7, 2008I have a table called "member" that has two fields (amongst others) called "firstname" and "city"I want to return a list that sorts people who live in the same city, but does not return people who do not have a city in common.For example if this is my data:Karen - ParisMike - RomeTim - Dallas
Jim - ParisChris - DallasJohn - ManhattanSarah - OrlandoDavid - DallasThe query would return this:Dallas - ChrisDallas - DavidDallas - TimParis - JimParis - KarenI have this SQL so far: Select city, firstname From member Order By city, firstnamebut it includes all the cities including those that only have 1 resident.Can someone tell me how to do this?Thanks a lot,Chris
Simple Sql Query
Mar 18, 2008hi,i have three fields in the database tablep1 p2 rank10% 20% 3 21% 40% 2now i am passing the input as 15%...this 15% is related to 3rd rank.. so i need the o/p rank as 3..if the p1 and p2 datatypes are varchar..then how we can we write the query for that one tgo get the rank as 3.Ramesh
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Apr 21, 2005Hi All
Can anyone tell me what this simple SQL query would be:
Find all the words "black", "dvd" and "player" from any of the fields "Product", "Brand" or "Description".
Many thanks
accelerator
Simple Query Help...
May 15, 2005I am trying to select players from a database based on the userid not having any user's name in it with an order by ASC. I basically want all the players that haven't been taken. Here is what I came up with and it gives me empty.
strSQLA="SELECT UserID, playerName from Allplayers WHERE UserID = '' ORDER BY playername ASC"
Simple SQL Query -- Perhaps You Can Help
May 28, 2006I hope it's considered appropriate to post a SQL query question here; it's not I'll gladly post this question elsewhere. That having been said, I've run into a simple but quite tricky SQL query and was wondering if the community might be able to help. Here's what's going on:
I have a "Documents" table. Let's call it DI have a "Benefits" table. Let's call it B.There is a many-to-many relationship between D and B so I have a third table to store the relationships. Let's call that table BD.
When I create a document it creates a row in D. Let's call that D1, D2...DN. When I create a benefit it creates a row in B. Let's call that B1, B2...BN
When I associate a document to a paritcular benefit, let's say that if D1 and B2 are associated, that I created row B2-D1 in my BD table. Now here's what my challenge is. Suppose I have these entries in my tables:
D: D1, D2, D3B: B1, B2, B3
Table BD:B1-D1B2-D1B2-D2
When the user goes to add documents to benefit B1, I want to show the user only documents that are not yet added to B1. In this case, I want to show the user D2 and D3 but not D1 since that one's already added. How do I write a SQL query to do this?
Here's what I've been using, but it shows too many results (e.g. included D1, D2, D3)
SELECT D.*, BD.*FROM Documents AS d LEFT JOIN rel_BenefitsDocuments AS bd ON d.doc_id = bd.doc_idWHERE (benefit_id <> @benefit_id OR benefit_id IS NULL)
Any thoughts?
Simple Query Help
Mar 7, 2003Hi,
I want to write a sql query for an asp page which will display only unique rows from the specified column along with the number of count for each unique row.
Example:
Table that I want to query
Last Name || First Name
Gates || Bill
Boyce || Mike
Gates || Bill
Gates || Phil
Results I want:
Last Name || First Name || Count
Gates || Bill || 2
Boyce || Mike || 1
Gates || Phil || 1
Thanks a lot,
Heta
Simple Query
Aug 21, 2004Hi,
I have a very simple question:
declare @treshold int
set @treshold = 10
SELECT
dbo.fn_Calc(t.column1) as calc,
t.column2
FROM
mytable t
WHERE
dbo.fn_Calc(t.column1) > @treshold
I can't think of a way to get rid of the function call in the WHERE clause.
Is this actualy a problem ?
I mean does realy the function fn_Calc execute 2 times in this statement and isn't this a performance issue then?
thanks
Simple Query
Jan 17, 2002Hi,
I am new to SQL and this question may be most easiest to many of you. Here is what I need.
I have two identical tables (exactly the same in structure) having a compound primary key with a combination of 3 columns. Can someone give me the most efficient query that fetches all the rows from table1 that are not in table2.
Thanks in advance for your help
Kevin
Query Help Please Max() Simple?
Oct 21, 2006This is my query...I am attempting to only return the records for each
sales_contact with the greatest issue_id
select
sc.sales_contact_id
, idd.issue_id
, sr.code
from
sales_contact sc
, invoice i
, invoice_line_item il
, sales_region_special_section srss
, sales_region sr
, issue_date idd
where
sc.sales_contact_id = i.sales_contact
and i.invoice_id = il.invoice
and srss.sales_region = sr.sales_region_id
and il.issue_date = idd.issue_date_id
and srss.invoice_line_item = il.invoice_line_item_id
order by
sc.sales_contact_id
================
heres some of the result set I want only the records with the greatest id
for each unique sales contact...
AF85F32E-8E34-4C40-9468-00148A34E903, 41, N
AF85F32E-8E34-4C40-9468-00148A34E903, 42, N
5D26328A-192B-4E4E-9B34-010C4E077CF8, 77, N
5D26328A-192B-4E4E-9B34-010C4E077CF8, 70, N
5D26328A-192B-4E4E-9B34-010C4E077CF8, 34, BC
B44C914E-6001-40CE-8AB6-0126BD572D45, 25, NW
B44C914E-6001-40CE-8AB6-0126BD572D45, 26, NW
B44C914E-6001-40CE-8AB6-0126BD572D45, 24, NW
B44C914E-6001-40CE-8AB6-0126BD572D45, 28, HC
B44C914E-6001-40CE-8AB6-0126BD572D45 , 28, NW
this would be an ideal result set using the data above...note there are
situtations where there are n* for a greatest issue id.
AF85F32E-8E34-4C40-9468-00148A34E903, 42, N
5D26328A-192B-4E4E-9B34-010C4E077CF8, 77, N
B44C914E-6001-40CE-8AB6-0126BD572D45, 28, HC
B44C914E-6001-40CE-8AB6-0126BD572D45, 28, NW
thanks in advance for your help.
Simple Query
Jan 7, 2005This should be easy, I'm just having a brainfart at the moment, can't remember how to do this:
Say I have a bunch of records in a table, with an ID field as Key. I want to return the count of times each ID shows up, so for the following example data:
Code:
-----
| ID |
-----
| 1 |
| 2 |
| 1 |
| 4 |
| 1 |
| 4 |
------
Would return something like:
Code:
----------------
| ID | Count |
----------------
| 1 | 3 |
| 2 | 1 |
| 4 | 2 |
-----------------
This should be obvious but for some reason I can't see it.
When this is done I'm going to join in another table to get a name based on the ID with the highest count. I believe it's faster to do a TOP 1 here rather than after the join, but I want to verify that while I'm at it also.
Simple Query
Sep 26, 2006OLD_TABLE
CustomerPost_ClosestStore1_ClosestStore2_ClosestStore3
00501_____9339_____9193_____9445
02151_____9161_____9838_____9185
02917_____9788_____9105_____9626
06443_____9644_____9102_____9286
43434_____9258_____9496_____0
NEW_TABLE
CustomerPost_ClosestStore1_ClosestStore2_ClosestStore3
00501_____9339_____9193_____9445
02151_____9161_____9838_____9185
02917_____9788_____9105_____9626
06443_____9644_____9102_____9286
43434_____9258_____9496_____1111
(end result)
FINAL_TABLE
43434_____9258_____9496_____1111
I have two tables ... I am trying to get only the rows that are different.
Simple SQL Query
Sep 19, 2005Hi folks,
I am a complete newbie to SQL. I have a simple query to make in SQL, but I'm not being able to construct the statement properly. I've already tried googling this info, but with little luck. If someone could help me here, I'd be very thankful.
The problem:
I have a table with a list of questions. All questions have a serial number. The query has to return whether a particular question is the last one in the table or not (according to serial no.)
Logically, this is the query -
Code:
select islast = 0
if count(*) from question where serialno > $serial != 0
else
select islast = 1;
The '$serial' part will get replaced dynamically before query execution through another program.
Any idea how to code this in valid SQL? I would like to make it a simple statement and not a stored procedure. Thanks.
Simple SQL Query Help
Sep 1, 2006Hi,
This is probably a simple SQL statement question, so please bear with me.
Basically I have a CustomerMaster with the following fileds
1) CustomerID
2) CustName
3) Address
4) ResTelNo
I want retreive the CustName,Address and ResTelNo if the ResTelNo has occured in the table more than twice.
Could someone please help with this. I would like to use the same query in MS Access as well.
Thanks in advance for your help.
Simple Sql Query..help Please
Sep 17, 2004Hey.. hope someone can help, i desperatly need some assistance. I have a few query issues but first things first.. one is that i have a table of messages and users having an online conversation, so fields are msg id, subject, topic, message, user, reply to and time it was sent. Im trying to do a query that will tell me which user sent the most messages, ive tried using count and stuff like that but not really getting anywhere. It will basically have to count each time a user has spoken and then give me the name of the user that has sent the most messages, ive been playing around with stuff like
SELECT Count(*) AS Expr1
FROM Table1
WHERE User='andro8472' OR User='bumies';
That will count the times those users have spoken but cant get further
any help would be greatly appreciated really stuck at the mo..
thanks
What Should Be A Simple Query
Feb 29, 2008I'm having a bad day as I just cannot get a query to work and its doing my head in and it should be a simple query.
I'll try and explain what I need.
Have a simple query with one join, this is it so far:
SELECT DISTINCT Replace(StaffName,'''''',' ') AS StaffName,OutReason,OutStartDate
,OutEndDate,OutStartTime,OutEndTime,OutID
FROM vwOutOfOffice
LEFT OUTER JOIN vwStaffList ON OutUser=StaffID
WHERE OutComplete=0
What I'm having trouble with adding to the WHERE is as follows, I need a list of Staff who are out of the office based on the various criteria:
Example
Current date=29/02/2008
Current time=14:00
Start date---End Date----Start Time--End Time--Should Appear
27/02/2008--28/02/2008--09:00------17:00-----No (because of date)
28/02/2008--03/03/2008--08:00------17:00-----Yes
28/02/2008--29/02/2008--17:00------17:00-----Yes
29/02/2008--29/02/2008--12:00------14:00-----Yes
29/02/2008--29/02/2008--14:30------17:00-----No (because of time)
02/03/2008--02/03/2008--08:00------10:00-----No (because of date)
There may be others I've missed but as long as the dates combined with the times match correctly I need the records to appear.
Please help before I end up putting my head through the monitor.
Simple Query?
Nov 29, 2004I have a table that looks like this:
c1c2
1a
1b
1c
2a
2b
2c
2d
3a
3b
3c
3d
3e
I want a result set that looks like this:
c1c2c3
1a1
1b2
1c3
2a1
2b2
2c3
2d4
3a1
3b2
3c3
3d4
3e5
Basically, grouping/numbering the rows by column c1. The number of distinct c1 columns and distinct c1,c2 columns is varying.
A Simple Query...plz Help
Sep 4, 2007Hi All,
The following table is entitled "class".
ID Number NameJoin DateSex
101 Jason01/02/1996M
117 Robert06/25/1999M
113 Doug08/12/1999M
161 Marian07/30/1998F
Please let me know the SQL queries for the following questions for the above table:
1)Write a Select statement that selects the persons whose Type is "M" and who have joined in the last four years and place the result in an array. Today's date is 12/31/1999.
2) Write a Select statement that selects the persons who do not have unique ID Number and place the results in an array.
3) Write code to sort the array by Name + Join Date. Assume that the array has already been created and is sorted in the same manner as the table above. The Join Date is of type smalldatetime. The Name field should be sorted case insensitively.
Thanks for your help.
Simple SQL Query
Nov 8, 2007I have a teams table with an id col (primark key) and name col.
I also have a fixtures table. its has an Id, hometeam, awayteam and date cols.
I would like to use the Pk of the Teams table as a foreign key in the fixtures table for both the hometeam and away team cols.
How could I write the SQL to get a list of fixtures for a specific team given the ID of the team.
Many thanks for your help
Need Help On Simple SQL Query
Jan 27, 2008Hi
I am just starting out on sql programming.
I have one table with three columns
Item Name | Price |Date
Item1 | 44 |25-Jan-08
Item1 | 45 |26-Jan-08
Item1 | 43 |27-Jan-08
Item2 | 21 |26-Jan-08
Item2 | 34 |28-Jan-08
Item3 | 91 |27-Jan-08
Item3 | 98 |29-Jan-08
I want to pick latest price of all items and produce a result as below
Item1 | 43 |27-Jan-08
Item2 | 34 |28-Jan-08
Item3 | 98 |29-Jan-08
Please help me on this
Thank You
-Jag
Simple Query Help
Feb 26, 2008How do I retrieve all rows from a middle_name column that have a character length of <= 2. This table is populated with middle names and middle initials. I want to isolate the middle initials only.
View 5 Replies View RelatedI Need Some Help With This Simple Query !!
Mar 10, 2008Hi,
I have this query:
SELECT ('Section : ' + F.Section + ' ' + (SELECT S.SectionName FROM SFM_Section AS S
WHERE S.Company = F.Company
AND S.Department = F.Department
AND S.Section = F.Section ) ),
F.Variety, F.Category,
isnull(SUM(F.AreaCutCurrent), 0) AS AreaCutCurrent,
isnull(SUM(F.TonnageCurrent), 0) AS TonnageCurrent,
isnull(SUM(F.YieldCurrent), 0) AS YieldCurrent
FROM SFM_Field AS F
WHERE F.CropYear = 2007 and ActiveFlag = 1 and Section = 04
GROUP BY F.Company, F.Department, F.Section, F.Variety, F.Category
ORDER BY F.Section, F.Variety, F.Category
that returns me the following results:
Section:04 Region Haute|M0052/78|R07|1.84 |137.64 |74.804
Section:04 Region Haute|M0695/69|R01|37.71|2817.65|434.009
Section:04 Region Haute|M0695/69|R02|35.08|2282.33|523.234
Section:04 Region Haute|M0695/69|R05|21.2 |1563.01|147.579
Section:04 Region Haute|M0695/69|R09|6.52 |484.39 |74.293
Section:04 Region Haute|M0695/69|R11|0 |0 |0
Section:04 Region Haute|M1397/86|R04|8.35 |793.61 |190.141
Section:04 Region Haute|M1400/86|GS |18.03|2093.91|116.135
What should I do if I don't want the records that the sum is equal to 0 to appear in my results? (Like the 3rd row from the end)
Thanks for your help
Simple Query?
Mar 18, 2008Hello,
You probably seen this Q before but I have no idea what to search and and therefor any direction would be appreciated.
I have three columns table, two are int and one is datetime (for sorting). I would like to query all values witch are unique within the two integers, however, in some cases data looks like this:
int1 = 1
int2 = 2
and another record like:
int1 = 2
int2 = 1
this pair should be considered as a duplicate and second record should not come with the results set.
Any suggestions?
Help! Should Be A Simple Query
Mar 19, 2008Hi I've got what should be a simple query but I'm not sure how to write it.
I have a table which holds employee assignments to positions, which holds historical data.
Eg:
ID EmployeeID StartDate PositionID
--- ---------- --------- ----------
1 7663 23/1/2007 234
2 7663 28/6/2007 272
3 7663 1/02/2008 983
4 81212 2/03/2008 2888
Now, what I'm after for each employee is their current position based on the highest "StartDate" for that employee.
So from the above table I want the results:
3 7663 1/02/2008 983
4 81212 2/03/2008 2888
Can anyone help? Do I need a Group By? That clause always confuses me!!!
Thanks!!!!
Simple MAX Query?
Jul 23, 2005Hi AllI know that I am supposed to submit a schema of my table, but it is a verybasic one so I'll crack straight on with my query.In essence I have a 3 column table called STOCKTRANS, which consists ofSTOCKCODE, TRANSACTIONDATE and TRANSACTIONTYPE.Each time a user orders a stock item I insert the stock code and the datethey ordered it into this table, egSTOCKCODE TRANSACTIONDATE TRANSACTIONTYPEIVP 1-4-04 1STP 31-6-04 8KGC 8-7-04 6IVP 11-8-04 8etc etcetcWhat I want to create is a simple query that informs what the last orderdate was for a stock code. As you can see from the above example, I mayhave hundreds of the same stock code with different dates so I thought thatthe following query would work:select STOCKCODE, MAX(TRANSACTIONDATE) as 'LastOrderDate'from STOCKTRANSwhere STOCKCODE = 'IVP' and TRANSACTIONTYPE in (1,8)But it doesn't.NOTE: the reason for the transaction types of 1 and 8 is because these arethe types I want. The other types are used for credits, returns, etc.First of all the above, brings me back loads of rows when all I want is:IVP 11-8-04 << this being the last date of order for this stock item.Just as a test I removed the STOCKCODE out of the select and found that Idid get my one liner, but for some reason I was only getting the last datefor transaction types 1 only - not the last date for a combination of 1 and8 transactions.Can you help??Many thanksRgds Robbie
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Jul 23, 2005I have Two Tables, TableA and TableB, both containing a common field,Feild1.How do I find all records in TableA, where Field1 is not in TableB?Regards,Ciarán
View 3 Replies View RelatedSimple Query
Jul 20, 2005I know this is super-basic, but I'm a newbie and I can't get it to work...I'm trying to call a stored procedure that has a datetime as one of itsparameters. How the heck do I get a datetime?? I'd even settle for knowing Iwas declaring variables correctly...DECLARE @Date datetime (right?)???EXEC usp_AddRequest 313,'E',@Date,'QUAL'^^^^^ <- this is the parameter that wants to be adatetimeHow do I make Date correspond to an actual date/time? How do I assign it tobe equal to SELECT GETDATE()? Why doesn't SET @DATE = SELECT GETDATE() work?And why the heck is it so hard to find the answers online?? I've Googledendlessly and found nothing...--Christopher Benson-Manica | Jumonji giri, for honour.ataru(at)cyberspace.org |
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Apr 1, 2008
Hello there, this is my first time here,please tell me if I'm posting in the wrong place.
well I have a table with three columns: nb,date and place; a query like
(select * from table where date<'3/19/2008 11:00:00' and date<>3/19/2008 8:00:00' )
returns:
nbr date place
11 '3/19/2008 08:05:00 aa
11 '3/19/2008 08:06:00 aa
11 '3/19/2008 08:07:00 aa
22 '3/19/2008 08:08:00 ab
22 '3/19/2008 08:09:00 ab
11 '3/19/2008 10:00:00 aa
11 '3/19/2008 10:05:00 aa
My prob is that I don't need all those records: the first three records for me refer to the same object so I want just one of them, same for the 4th and 5th records I just want one, and for the last 2 records, so I need a query that returns
11 '3/19/2008 08:05:00 aa
22 '3/19/2008 08:08:00 ab
11 '3/19/2008 10:00:00 aa
How To Do This Simple Query?
Apr 11, 2008
Hi,
I have two tables with a one to many relation.
Tbl 1 - POs (stands for purchase orders)
Tbl 2 Invoices
Each is linked by a POID which a varchar field. there is one POID which can have none to several Invoices
I need to work a query to work out the total money left outstanding from the PO's.
I thought the easiest way would be to SUM the subtotal field in the POs tbl, and from that minus off the SUM total of the InvoiceSubTotal from the Invoices tbl.
This would give me a figure which is what was left outstanding.. pretty straight forward.
however every attempt I've had so far is not grouping the Invoices together correctly for each PO so I'm getting incorrect totals.
Here's my first attempt:
Code Snippet
SELECT SUM(dbo.Suppliers_POs.SubTotal - dbo.Suppliers_Invoices.InvoiceSubTotal) AS TotalOutstanding
FROM dbo.Suppliers_POs INNER JOIN
dbo.Suppliers_Invoices ON dbo.Suppliers_POs.POID = dbo.Suppliers_Invoices.POID
Although that returned a result it wasn't correct.
What seems to be happening is that for each PO with a matched invoice it gets the SubTotal and then get the InvoiceSubTotal and gets a figure.. if there is another invoice for the same PO.. it does the same thing..
So lets say I have a PO for £50,000
There are three invoices on the system for £10,000 each
(Therefore there is £50,000 on the PO, £30,000 on the invoices.. I should be left with £20,000)
Instead it gets the first invoice.. see the PO for £50,000 and minus' the £10,000 giving £40,000
It then does the same for the other two..
So I get a figure of £120,000!!!
How do I get around this?
Thanks for any help you guys can offer..
How To Do This Simple Query ?
Sep 27, 2007I have a table with these columns,
Warehouse, Items
ABC, 2
CDEF, 0
Something, 10
Something 0
I want to get Warehouse and count of Items grouped by Warehouse. Omit all Items that have count greater than 2. Show only groups having ferwer than 2 item counts and have the result displayes in descending order of Items count.
Need Help With A Simple Query
Dec 23, 2005Hi Everyone:
I am new to SQL, and I would like to request if someone could provide me with a query that could do a find and replace in a column in MSDE. I have an image path column in a table, the current image path is set to /images/xxxx.gif
I would like to add another folder so the image
path looks like this --> /images/imagesA/xxxx.gif
The problem is i have 4500 records to update, so I cannot do this manually, so my question is can someone provide me with a query that can do this find and replace, i guess in this situation you are finding /images and replacing it with /images/imagesA
Please advise. Thanks.
It would be nice if you can send me this query to my email. My email address is aleemmansoor@hotmail.com
Help On Simple Query
Apr 21, 2008
What is wrong with the following code
declare @today datetime
set @today = getdate()
DECLARE @l_PPA_CONTACT_VALUES_Tbl TABLE(
PARTY_ID NUMERIC(10,0),
CONTACT_VALUES VARCHAR(7000)
)
INSERT INTO @l_PPA_CONTACT_VALUES_Tbl
SELECT PARTY_ID ,CONTACT_VALUES
FROM PEGASUS.PEGASUS_AP_GET_PARTY_CONTACTS_TABLE_FUN(NULL, NULL,0, NULL, 'Business', 'Yes', 1, @today, NULL, 'ACTIVE', 0)
select ppaCon.PARTY_ID,
(SELECT TOP 1 VALUE_TEXT
FROM PEGASUS.PEGASUS_AP_SPLIT_FUN(ppaCon.CONTACT_VALUES, 0)
WHERE VALUE_TEXT LIKE 'Business Phone:'
) OfficePhone
from @l_PPA_CONTACT_VALUES_Tbl ppaCon
right join PEGASUS.PARTY_PAIRS ppa
on ppaCon.PARTY_ID = ppa.PPA_ID
I am getting the following error
Msg 170, Level 15, State 1, Line 15
Line 15: Incorrect syntax near '.'.
and the error is poiting to the portion of code
PEGASUS.PEGASUS_AP_SPLIT_FUN(ppaCon.CONTACT_VALUES, 0)
THanks