Substring With Patindex - Break Value Into 5 Different Columns
Dec 18, 2013
I have a value in a column '01-08-087-0101W5'. I would like to break this value down into 5 different columns. The column will be broken down at the dashes , so the 5 columns will have values like
01
08
087
101
5
I would also like to trim any leading 0's in the above values. i have been trying the following
SUBSTRING(column1,patindex('%[^0]%',column1) ,2) AS FROM_TWP
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Oct 30, 2007
Hi All,
Can we use the SUBSTRING or PATINDEX function with a User Defined Function as one of the parameters? Something like this:
Code Block
Select SUBSTRING(Select * from DB.dbo.Function('Parameter'), PATINDEX('%\%', Select * from DB.dbo.Function('Parameter'), 8)
Mannu.
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Jan 2, 2015
I am recieving complete row in one single column and I have pipe delimeter in this row . I want to retrieve the data in individual columns...Currently row is in one column
Data
02|vinod sahu
Expected output
Col1 col2
02 VInod Sahu
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Feb 21, 2008
hi,
i have labels for data stored in one cell
eg: item1; item22; item231;
and i want to convert it in following output
(probably using substring and charindex)
No_question| item_position | label
1|1| item1
1|2| item22
1|3| item231
any idea?
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Jun 6, 2014
I have data as below:
columnA
D7 330 4/13/2014 0:0:0 KUL PVG 4/13/2014 18:35:0 4/13/2014 19:15:0 4/13/2014 23:45:0 4/14/2014 0:45:0
How can I separate it to 5 additional columns?
columnB: D7 330 4/13/2014 0:0:0
columnC: KUL PVG 4/13/2014 18:35:0
columnD: 4/13/2014 19:15:0
columnE: 4/13/2014 23:45:0
columnF: 4/14/2014 0:45:0
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Apr 23, 2015
I have two columns "Project Name" and "Flag".
Now i want to find out all the project names which contain a particular substring in it, like say - "SRM" and update the "Flag" column to value 1 for all those projects.
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Jul 14, 2015
I have a table with 100 rows, 1 field (ID), and I would like to write a query to output it as 4 rows, and 25 columns.
Row data
ID
1
2
3
4
5
6
7
8
9
...
98
99
100
Output will be like
c1 c2 c3 c4 c5....
1 5 9 13
2 6 10 14
3 7 11 15
4 8 12 16
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Jul 1, 2015
Part 1: When there is ~ (tilde) and has any value after it then it goes into a new row and duplicating the other columns like the facility in the screenshot attached and new column having the sequence.
Part 2: When there is ^ (Caret) its a new column irrespective of a value present or not
CREATE TABLE [dbo].[Equipment](
[EQU] [VARCHAR](50) NOT NULL,
[Notes] [TEXT] NULL,
[Facility] [VARCHAR](50) NULL)
INSERT INTO [dbo].[Equipment] ([EQU] ,[Notes] ,[Facility])
SELECT '1001','BET I^BOBBETT,DAN^1.0^REGULAR^22.09^22.090~BET II^^^REGULAR^23.56^0~','USA' union
SELECT '998','BET I^JONES, ALANA^0.50^REGULAR^22.09^11.0450~BET II^^^REGULAR^23.56^0~','Canada' UNION
select '55','BET I^SLADE,ADAM F.^1.5^REGULAR^27.65^41.475~','USA'
SELECT * FROM dbo.Equipment
I created the table in excel and attached the screenshot for a clear picture as to what is required. I use text to Columns in excel to achieve this not sure if there is anything similar in sql.
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Dec 6, 2007
I have a report with several matrix objects. The data contained in each matrix is simple. One matrix has one column of labels and a column of data. The other has 3 columns of data. Both matrix's only show about 25 rows of data. A variable amount of data is displayed above the matrix's so that sometime the render across a page boundary. Whenever this happens the matrix doesn't render rows down to the bottom of the page. A considerable amount of empty space is left on the page, the completed matrix is displayed on the next page. I'm wondering how to get the matrix to render in this empty space.
This problem only occurs when I view the report on screen, in the Visual Studio "Preview" window, or from the Report Server web site. Tiff, pdf and printed output doesn't contain the extra space.
I've tried adding my matrix to a List and a Rectangle to see of this would fix the problem but it didn't help.
I've check the dimensions and margins or the page and I don't think I have any sizing problems, everything should fit on the page.
--Mark
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Jul 19, 2000
Good morning.
I was wondering if someone would point out my flaw. I am attempting to get information separated by spaces, placed into separate columns. I tried without success several times yesterday to get what I desired and was not able to get it done. I am fairly new at developing SQL code and am low on the SQL coding totem pole of experience but would like your help.
Here is what I have so far.
SELECT
CONVERT(char(16), SUBSTRING(c1,
1,
PATINDEX('% %', c1))) SSI_House_Number,
CONVERT(char(15), SUBSTRING(c1,
PATINDEX('% %', c1)+1,
LEN(c1)-PATINDEX('% %', c1)+1)) SSI_Directional
FROM
t1
WHERE
c2 = 4254
My problem arises when I, in the second column, attempt to get only the information BETWEEN the first space: PATINDEX('% %', c1)+1 and the second space. I am coming up short and would like someone to point out my error or assist me in getting the query pointed in the right direction.
Thanks,
Daimon
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Feb 13, 2007
Hello everyone:
how do i find a single quote ['] with the patindex function.
SELECT 'a company's name'
thx,
F.
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Nov 7, 2007
hi!
i have one datatable with some file's details like id, name, createdate. i wrote one storedprocedure to search in that table by filename using wildcard character. its also working perfectly. But the problem is i want to arrange the results in ascending order depended by matching level. If I search for 'file123' it should give results in one order by matching level, means - lets think the results are 'fil23', file123', 'file', 'file1'. the results should be in order like 'file123', 'fil23', 'file1', 'file'. the results of the sp which i used, are order by datecreated. Please help me to do this.
the storeprocedure i used -
"CREATE PROCEDURE [dbo].[SP_DYN_SearchinFiles_DynByWildcardsADMIN] @searchparam nvarchar(50)
AS
BEGIN
select
Id,
OriginalName,
ContentType,
FullName,
Department,
DateCreated,
Client,
username
from Files_Dyn where PATINDEX('%' + @SearchParam + '%', OriginalName) > 0
END"
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Jul 23, 2005
Hello,I am trying to update a column in a table with an 8 digit string.The 8 digit number is obtained from another column which is a commentsfield.e.g.Comments Field :1) RD-V0216970 RQST NON SMKING KING Unknown # : 223389212) Received verbal authorization Authorization # 0403453) international plaza, singapore # 96722540The code that I am using isUPDATE U SET U.NUM =CASEWHEN U.BOOKED_COMMENTS_TXT LIKE('%[0123456789][0123456789][0123456789][0123456789][0123456789][0123456789]%')THENSUBSTRING(U.BOOKED_COMMENTS_TXT,PATINDEX('%[0123456789][0123456789][0123456789][0123456789][0123456789][0123456789]%',U.BOOKED_COMMENTS_TXT), 8)ELSE NULLENDFROM UNKNOWN1_RESERVATIONS UHere's what my result set looks like1)V02169702)0403453)96722540But this is how I want my result set to look like1)223389212)null3)96722540What I need is a way to restrict the search criteria to exactly 8numeric digits. Any suggestions will be helpful.Thanks in advance
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Jul 20, 2005
Hi allUsing SQL Server 2000 SP3 on WIn2K Pro with SP2.When I do thisSELECT PATINDEX('%[%', 'ABC[DEF')GOI get a result of 0, when I would expect a result of 4.This works as I expect:SELECT PATINDEX('%]%', 'ABC]DEF')GOI must be missing something really obvious here Any help would beappreciated.
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Aug 21, 2007
Hi all,
My database is not case-sensitive, but I want output like...
SELECT patindex('%[A-Z]%','gaurang Ahmedabad')
The output should be first occurrence of uppercase A to Z, so output should be 9 it should not be 1.
Above query is giving output as 1 bcoz the 1st character in the expression is 'g' and it is in A to Z, but this is not capital 'G'. The 1st capital letter in the expression is 'A' (9th character in the expression).
Is there anyway to achieve this using PATINDEX? or Is there any other way to achieve this?
Thanks,
Gaurang Majithiya
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Feb 11, 2007
Hi,
How to search the last occurance of one String in to another string..Using function PATINDEX() in a column of data type Text..
plz Give some solution i really need it ...
Thanks Yogesh
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May 1, 2007
Alright, I am trying to write a query that will select a column.. then search through the column and return me the fields with no underscores in them.
i.e we have fields that are like ABCD and ABCD_1. I want to basically return all of them up to the underscore.
so i am trying to use a substring combined with patindex. Here is my statement for patindex. patindex('%_%', short_name)
however, i cannot get patindex to ignore the fact that _ is a wildcard and treat it as character. Ive tried ('%[_]%', short_name) and ive tried ('%!_%', short_name) escape '!' and i just keep getting errors... If someone could help me out, that would be most appreciated. thank you.
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Sep 6, 2013
I have a number of columns I'm selecting from a table, and I'd like to use PATINDEX to search for a string within a field. Upon finding this string it would return another string...:
SELECT
CASE PARTNERID
WHEN PATINDEX('%INX%',PARTNERID)>0 THEN 'AXXENT'
ELSE PARTNERID
END AS PARTNERID
However, I'm getting this error:Incorrect syntax near '>'.
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May 8, 2008
Hi
I have a table which stores a big chunk of html text, which I have to search for and replace some strings.
How can I write a query that makes use of regular expressions to do the following:
Below is a block of example text
======================================================================
" src="http://aaaa/bbbb/cccc.nsf/blind%2010x10.gif?OpenImageResource" width=10> <img height=10 alt="" src="http://aaaa/bbbb/cccc.nsf/blind%2010x10.gif?OpenImageResource" width=10><img height=11 alt=""
http://aaaa/bbbb/cccc.nsf/blablablabla?OpenDocument src="http://aaaa/bbbb/cccc.ns http://aaaa/bbbb/cccc.nsf/d8d4f0dfa09ba71142256cc50040ee51/ee9b4493dac727be422571c30027df61? OpenDocument" target=_self>
======================================================================
Now I want to search and replace the string that is highlighted in red with something like "FOUND"
The below string is what I want to search for - I will used PATINDEX on the string below to find the start index of the string in the body, and then I will add on 114 to the when doing a replace:
'%http://aaaa/bbbb/cccc.nsf/%some guid%/%some guid%?OpenDocument%'
For example
REPLACE
(
TheField,
SUBSTRING
(
TheField,
PATINDEX(''%http://aaaa/bbbb/cccc.nsf/%some guid%/%some guid%?OpenDocument%', TheField),
,114
)
,
'FOUND'
)
QUESTION:
what would the regular expression be and how does one type it in the query?
I tried something like the below but it does not work, please advise .....
[a-z][0-9]{32} %/% [a-z][0-9]{32}
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Sep 30, 2014
I want to search a table and display only results that contain particular Hotmail and yahoo email addresses. The code I am using currently is:
Select Name, Email, PATINDEX('%Hotmail%, Email) From tblPerson
How do I search for more than one email domain? Do I use a case statement, if so how?
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Feb 14, 2008
Hello,
I forget. How can PATINDEX be used to find column values where the data is all numeric? I've tried, the following:
select distinct acct from tbl_CYProcessedSales
where PatIndex('%[0-9]%',Acct) > 0
order by acct
Acct is varchar(8). What am I doing wrong?
Thank you for your help!
CSDunn
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Dec 6, 2007
I am creating a view to pull data for a UPS integration I am doing. I currently have this view where I pull my data from. All is well accept for my PATINDEX,
Currently I have this PATINDEX So when a user puts this into delivery instructions "#999999" UPS_FINAL returns 999999 which is good for me to use. But The PATINDEX will also grab all kinds of neat stuff out of the delivery instructions field when I really only want whatever is after the # sign in the field.
I am new to sql and dont quite understand how this search is working but I think I am in need of a better way to search the field
Code:
WHEN SUBSTRING(P21PLAY.dbo.p21_view_oe_hdr.delivery_instructions, PATINDEX('%[^a-z ]%', P21PLAY.dbo.p21_view_oe_hdr.delivery_instructions) + 1, 6) IS NULL
THEN dbo.Address_Table.ups_code
ELSE SUBSTRING(P21PLAY.dbo.p21_view_oe_hdr.delivery_instructions,
PATINDEX('%[^a-z ]%', P21PLAY.dbo.p21_view_oe_hdr.delivery_instructions) + 1, 6) END AS UPS_FINAL
-------------------------------------------------------------------------------------
What I am looking to accomplish is a SUBSTRING that will search delivery_instructions
Code:
SELECT
TOP (100) PERCENT P21PLAY.dbo.p21_view_oe_pick_ticket.pick_ticket_no,
P21PLAY.dbo.p21_view_oe_hdr.order_no, P21PLAY.dbo.p21_view_oe_hdr.customer_id,
P21PLAY.dbo.p21_view_oe_hdr.ship2_name, P21PLAY.dbo.p21_view_oe_hdr.ship2_add1,
P21PLAY.dbo.p21_view_oe_hdr.ship2_add2,
P21PLAY.dbo.p21_view_oe_hdr.ship2_city,
P21PLAY.dbo.p21_view_oe_hdr.ship2_state,
P21PLAY.dbo.p21_view_oe_hdr.ship2_zip,
P21PLAY.dbo.p21_view_oe_hdr.po_no,
P21PLAY.dbo.p21_view_oe_pick_ticket.carrier_id AS Carrier,
P21PLAY.dbo.p21_view_oe_pick_ticket.carrier_id AS Supplier,
P21PLAY.dbo.p21_view_oe_hdr.cod_flag,
P21PLAY.dbo.p21_view_oe_hdr.terms,
P21PLAY.dbo.p21_view_oe_hdr.ship2_country,
P21PLAY.dbo.p21_view_oe_hdr.ship_to_phone,
P21PLAY.dbo.p21_view_oe_hdr.delivery_instructions,
dbo.Address_Table.ups_code,
-----------Looks for special character and returns next 6 spaces as UPS_Shipper----------
SUBSTRING(P21PLAY.dbo.p21_view_oe_hdr.delivery_instructions, PATINDEX('%[^a-z ]%',
P21PLAY.dbo.p21_view_oe_hdr.delivery_instructions) + 1, 6)
AS UPS_Shipper,
------------------Checks view for email address or assigns alternate------------------
(CASE WHEN charindex('@', p21_view_contacts.email_address) > 0 THEN p21_view_contacts.email_address ELSE
'email@domain.com' END) AS alternate_address,
'Y' AS QVN, 'email@domain.com' AS failureaddress,
P21PLAY.dbo.p21_view_contacts.email_address,
------------When carrier_id is not one of these # then Null; else ------------------------------
CASE WHEN P21PLAY.dbo.p21_view_oe_pick_ticket.carrier_id NOT IN (105188, 105191, 105194, 105197, 105200,
105203, 105206, 105209, 105212) THEN NULL
----------------- Looks for special Character in delivery_instructions; if NULL then ups_code;
ELSE return value from delivery_instructions as UPS_Final--------------------
WHEN SUBSTRING(P21PLAY.dbo.p21_view_oe_hdr.delivery_instructions,
PATINDEX('%[^a-z ]%', P21PLAY.dbo.p21_view_oe_hdr.delivery_instructions) + 1, 6) IS NULL
THEN dbo.Address_Table.ups_code
ELSE SUBSTRING(P21PLAY.dbo.p21_view_oe_hdr.delivery_instructions,
PATINDEX('%[^a-z ]%', P21PLAY.dbo.p21_view_oe_hdr.delivery_instructions) + 1, 6) END AS UPS_FINAL
FROM dbo.Address_Table INNER JOIN
P21PLAY.dbo.p21_view_oe_pick_ticket INNER JOIN
P21PLAY.dbo.p21_view_oe_hdr ON P21PLAY.dbo.p21_view_oe_pick_ticket.order_no =
P21PLAY.dbo.p21_view_oe_hdr.order_no ON
dbo.Address_Table.id = P21PLAY.dbo.p21_view_oe_hdr.customer_id LEFT OUTER JOIN
P21PLAY.dbo.p21_view_contacts ON P21PLAY.dbo.p21_view_oe_hdr.contact_id = P21PLAY.dbo.p21_view_contacts.id
WHERE
(P21PLAY.dbo.p21_view_oe_hdr.completed <> 'Y')
AND (P21PLAY.dbo.p21_view_oe_hdr.delete_flag <> 'Y')
AND (P21PLAY.dbo.p21_view_oe_hdr.will_call <> 'Y')
ORDER BY P21PLAY.dbo.p21_view_oe_pick_ticket.pick_ticket_no
Hope this makes since
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Sep 5, 2007
---Checks that input only contains numbers
if PatIndex('%[^0-9]%','11') > 0
Begin
Print 'Not all numbers'
End
Else
Begin
Print 'All numbers'
End
---Checks that input only contains letters
if PatIndex('%[^a-z]%','aaaaa') > 0
Begin
Print 'Not all letters'
End
Else
Begin
Print 'All letters'
End
--Checking for mixed input
If PatIndex('%[^0-9][0-9]%','abc') > 0
Begin
Print 'Alpha numeric data'
End
Else
Begin
Print 'Either all numbers or all letters'
End
--Checks that value must start with a letter and a number
If PatIndex('[^0-9][0-9]%','A1anamwar11') > 0
Begin
Print 'Starts with a letter and a number'
End
Else
Begin
Print 'Does not start with a letter and a number'
End
--Checks that value must End with a letter and a number
If PatIndex('%[^0-9][0-9]','A1anamwar11a1') > 0
Begin
Print 'Ends with a letter and a number'
End
Else
Begin
Print 'Does not End with a letter and a number'
End
--Checks that value must Start with a letter and Ends with a number
If PatIndex('[^0-9]%[0-9]','namwar1') > 0
Begin
Print 'Starts with a letter and ends with a number'
End
Else
Begin
Print 'Does not start with a letter and ends with a number'
End
Namwar
<Link removed by georgev>
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Oct 30, 2007
Hello,
I understand that it is not possible to use PATINDEX in a Derived Column transform. I'm trying to eliminate leading zeros from a column where the string is always 14 characters long, but the first non zero character could occur any number of characters from the left of the string. The following achieves what I need:
substring([Account No w/0s], patindex('%[^0]%', [Account No w/0s]), 14) AS ExtractedAcctNo
Does anyone happen to know how I might express this differently in a Derived Column transform? Should I consider a calling a function through an OLE DB Command transform on each row instead? Maybe I should have a SQL Task that runs an UPDATE statement against the column.
Thank you for your help!
cdun2
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Aug 21, 2007
Hi,
My database is not case-sensitive, but I want output like...
SELECT patindex('%[A-Z]%','gaurang Ahmedabad')
The output should be first occurrence of uppercase A to Z, so output should be 9 it should not be 1.
Above query is giving output as 1 bcoz the 1st character in the expression is 'g' and it is in A to Z, but this is not capital 'G'. The 1st capital letter in the expression is 'A' (9th character in the expression).
Is there anyway to achieve this using PATINDEX? or Is there any other way to achieve this?
Thanks,
Gaurang Majithiya
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Jul 17, 2015
I would like solving the following issue using the Patindex function i cannot retrieve or extract the single numeric value as an example in the the values below i would like retrieve the Value 2, but in my result set the value 22 also appears or it is completely omitted.
"2 8 7"
"2 8"
"2"
"22"
"3 2 8"
I have tried the following
Patindex('%[2]% [^0-9] [^1] [^3] [^4] [^5] [^6] [^7] [^8] [^9]' ,Replace(Replace(Marketing_Special_Attributes, '"',''),'^',' ')) as Col3,
Patindex('[2]' ,Replace(Replace(Marketing_Special_Attributes, '"',''),'^',' ')) as Col4,
Patindex('%[2][^0-9]%',Replace(Marketing_Special_Attributes,'^',' ')),
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Dec 13, 2007
Hello:
I am running into an issue with RS2k PDF export.
Case: Exporting Report to PDF/Printing/TIFF
Report: Contains 1 table with 19 Columns. 1 column is static, the other 18 are visible at the users descretion. Report when printed/exported to pdf spans 2 pages naturally, 16 on the first page, 3 on the second, and the column widths have been adjusted to provide a perfect page span .
User A elects to hide two of the columns, and show the rest. The report complies and the viewable version is perfect, the excel export is perfect.. the PDF export on the first page causes every fith column, starting with the last column that was hidden to be expanded to take up additional width. On the spanned page, it renders the first column on that page correctly, then there is a white space gap equal to the width of the hidden columns and then the rest of the cells show with the last column expanded to take up the same width that the original 2 columns were going to take up, plus its width.
We have tried several different settings to see if it helps this issue or makes it worse. So far cangrow/canshrink/keep together have made no impact. It is not possible to increase the page size due to limited page size selection availablility for the client. There are far too many combinations of what the user can elect to show or hide to put together different tables to show and hide on the same report to remove this effect.
Any help or suggestion on this issue would be appreciated
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Jul 5, 2001
Hi all,
I have just started using SQL7 and quite dumb at it.
Here is my problem
i have tables ip_address and ip_subnets. both contains more than 20,000 records. Though ideally each subnet should correspond to only one ip address it is not so due to SMS inventory and remote clients configurations etc.
As an example If my ip address is 141.151.128.78 I need to select only 141.151.128.64 ( or atleast 141.151.128.*)as the valid subnet. In other words I need to compare upto 3rd octet and only if it matches with ip address then declare that as the valid subnet.
Pls note that ip addresses vary for each machine though there will 4 octets, I can't use character positions as the nos in each octet might vary from 1-255.
Any help would be greatly appreciated
Pasted here under is the query script I am playing around with charcter poistions which are not working in my favor. Just added to explain my problems in more clearer way
select distinct system_data.name0, System_IP_Address_ARR.ip_addresses0, System_IP_subnets_Arr.ip_subnets0, system_disc.client0 from system_Data, System_IP_Address_ARR, system_ip_subnets_arr, system_disc where system_data.machineid = System_IP_Address_ARR.itemkey and system_data.machineid = system_ip_subnets_arr.itemkey and system_data.machineid = system_disc.itemkey and system_disc.client0 = 1 and substring(System_IP_Address_ARR.ip_addresses0,1,10 ) = substring(System_IP_subnets_ARR.ip_subnets0,1,10) and substring(System_IP_Address_ARR.ip_addresses0,10,1 ) = '.' and System_IP_subnets_ARR.ip_subnets0 not in ('11%.%.%.%','12%.%.%.%', '10%.%.%.%' , '10.%.%.%' , '1.%.%.%') order by System_DATA.name0
Arun
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Nov 5, 2001
Hey you sql programming guru's
I need help seperating a name from first name and last name
The field is like this,
last name, first name
example Doe, John
I need to seperate the last name from the , to the first character
and the last name from the , to the last character.
I think I have to use a substring but not sure how tell it to stop and
start when it gets to the comma.
Can someone please help me.
Thanks,
Dianne
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Aug 8, 2001
Need to do something like SUBSSTRING in Access, any ideas?
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Oct 4, 2004
Hi
Can anyone show me how to do the following:
I have this snippet of data
ids
-----------------------------------
1582270|1582277
1582270|1582277|1582286
1582270
I want to return the id (the id may not always have the same number of numbers) after the last pipe (|) delimter.
So i want a rs like this :
ids
-----------------------------------
1582277
1582286
1582270
Thanks in advance
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Feb 4, 2005
Hi,
please help me in developing query to satisfy this...
i have table called test and the table data looks like this.
col1
123.abc
1.ab
12.cba
the query needs to return all rows data after . the result set should return this
abc
ab
cba
appreciate your help..
thanks
sskris
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Feb 3, 2004
I have a field that contaings 15 characters. I want to just pull the first 6. So anything that matches these 6 will be returned.
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