I have a standard datetime and I need to convert it to the client specification of:
YYYY-MM-DDThh:mm:ssTZD
eg: 2009-04-16T19:20:30+08:00
I am not sure of the easiest way to do this.
The test code below gets me part of the way but I am unsure on how to get the offset on the end without hardcoding to much.
DECLARE @datetime DATETIME = '2014-12-20 12:30:00'
SELECT CONVERT(VARCHAR(30),@datetime,127)
We have 2 columns:
StartDate - data type Date
StartTime - data type Time
I need to combine them into a DateTime data type. For now, I convert each of them into varchar, insert space in between, and convert to DateTime, like this:
convert(datetime, convert(varchar(10), EndDate , 101) + ' ' + CONVERT(varchar(20), EndTime,24))
Is there a better, more elegant way to do this?
Working on a new database where the Date and Time are stored in a Date Time Field.
Then working on an OLDER database file within the same SQL Database contains these 2 items as integers:
transDate = "71615" (July 16, 2015)
transTime = "12345" (01:23:45 AM)
How do we convert both of them into a single SQL DateTime field such as "2015-07-16 01:23:45.000" so that it can be used in a join restricting to a date time in a different SQL File that properly has the DateTime in it?
This works well for converting the transDate Part in the select statement:
  dbo.IntegerToDate(at.transDate) as transDate
  * That returns: "2015-07-16 00:00:00.000"
* The resulting data must work directly in a Microsoft SQL Server Management Studio Query using either using the "on" statement or part of the "where" clause. In other words, NOT as a stored procedure!
Also must be able to be used as a date difference calculation when comparing the 2 files Within say + or - 5 seconds.
I want to convert a datetime type into and speciically formatted time:the table contains this:1899-12-30 10:00:00.000I want to reformat it to appear like this:10:00 AM I want to do this with SQL using a CONVERT of something along that line.I've been able to find all kinds of date and date/time formats, but not time alone in the above format.And suggestions?TIA</chaz>
View 3 Replies View RelatedHow to get this out put.
Details:
declare @deadline Datetime = '2014-03-23 15:30:10.000'
SELECT CONVERT(VARCHAR(30),@deadline, 100) AS DateConvert
----With this I am able to produce that like
----o/p: Mar 23 2014 3:30PM
declare @deadline1 Datetime = '2014-03-03 15:30:10.000'
SELECT CONVERT(VARCHAR(24),@deadline1, 100) AS DateConvert
--o/p: Mar 3 2014 3:30PM
--expected O/p: Mar 03 2014 03:30PM
What is the correct date format to achieve this.
Precisely, here's what I need:When I run getdate(), I get, for example:August 9 2004 5:17 P.M.I want to turn the date portion into:8/9/2004 format and update one column with itI want to turn 5:17 P.M. into:hhmmss and update another column with it.I've been playing around with datepart, with substr, with you name it,and I'm stumped.Any code samples, other help most appreciated.Thanks,Google Jenny*** Sent via Developersdex http://www.developersdex.com ***Don't just participate in USENET...get rewarded for it!
View 1 Replies View RelatedIm working with a breaking system and I wont to convert the (FROM) datetime column to accept just time like (4:00:00 AM) without the date (7/23/2004) but it doesn’t have column format like the access ??
I found something in the SQL help :
How to convert the format of a Date Time String transformation (Enterprise Manager)
To convert the format of a Date Time String transformation
1.On the Transformations tab of the Transform Data Task Properties or Data Driven Query Task Properties dialog box, click the Source column containing the date or time to be modified, and then click the Destination column where you want the modified string to be placed.
2.Do one of the following:
•If there is a mapping arrow connecting the two columns, click Delete, and then click New.
•If there is no mapping arrow, click New.
3.In the Create New Transformation dialog box, click DateTime String.
4.Click the General tab, and then click Properties.
5.In the Date Format list, select the format you want.
6.Click Naming to display the Calendar Names dialog box, where you can select long or short day or month names and the A.M. and P.M. designators you want.
7.In the Language list, select the language you want, and then click Set Language Defaults.
But unfortunately I didn't find the "Transformations tab" I look a lot in the SQL Enterprise Manager
Do anybody work with the Transformations or at least know where is it please ???
I have two fields DSRHADTI which is an isodate and DSRHTIME which is 8 char time field in format 10.31.00. I want to take both these fields and put them into a field that is database timestamp so I have converted DSRHDATI to 10 character field. I am then trying to use substring to put both into 18 character field using derived column transformation editor. but it does not like the below. It's red syntax error what am I missing.
(SUBSTRING(Copy of DSRHDATI,1,4) +' /' + SUBSTRING( Copy of DSRHDATI,6,2) + '/ ' + SUBSTRING(Copy of DSRHDATI,9,2)) + SUBSTRING(DSRHTIME,1,2) + '.' + SUBSTRING(DSRHTIME,4,2) + '.' + SUBSTRING(DSRHTIME,7,2)
One I get the above to work I plan on convert 18 char to datetimestamp.
Am I on the right track on how to do this?
E.g, i have a store procedure. The start date is long date (4/15/2007 3:00pm). i want to select the start date with a particular date (short date format 4/15/2006). Thanks in advance.
View 1 Replies View RelatedHi,
I am trying to access a date column up to millisecond precession. So I cast date to as follows:
Code BlockCONVERT(varchar(23),CREATE_DATE,121)
I get millisecond part as a result of query but it€™s €œ000€?.
When I try to test the format by using getDate instead of DateTime column I get right milliseconds.
CONVERT(varchar(23),GetDate(),121) --Gives right milliseconds in return
e.g.
1st March 2005 12:00:00
is showing as
01/03/2005 00:00:00
instead of
01/03/2005
Why does this happen?
HiI am using SQL 2005, VB 2005I am trying to insert a record using parameters using the following code as per MotLey suggestion and it works finestring insertSQL; insertSQL = "INSERT INTO Issue(ProjectID, TypeofEntryID, PriorityID ,Title, Area) VALUES (@ProjectID, @TypeofEntryID, @PriorityID ,@Title, @Area)"; cmdInsert SqlCommand; cmdInsert=new SqlCommand(insertSQL,conn); cmdInsert.Parameters.Add("@ProjectID",SqlDbType.Varchar).Value=ProjectID.Text; My query is how to detail with dates my previous code wasinsertSQL += "convert(datetime,'" + DateTime.Now.ToString("dd/MM/yy") + "',3), '";I tried the code below but the record doesn't save?string date = DateTime.Now.ToString("dd/MM/yy"); insertSQL = "INSERT INTO WorkFlow(IssueID, TaskID, TaskDone, Date ,StaffID) VALUES (@IDIssue, @IDTask, @TaskDone, convert(DateTime,@Date,3),@IDStaff)"; cmdInsert.Parameters.Add("IDIssue", SqlDbType.Int).Value = IDIssue.ToString();cmdInsert.Parameters.Add("IDTask",SqlDbType.Int).Value = IDTask.Text;cmdInsert.Parameters.Add("TaskDone",SqlDbType.VarChar).Value = TaskDoneTxtbox.Text;cmdInsert.Parameters.Add("Date",SqlDbType.DateTime).Value = date;cmdInsert.Parameters.Add("IDStaff",SqlDbType.Int).Value = IDStaff.Text;Could someone point to me in the right direction?Thanks in advance
View 3 Replies View RelatedI am inserting date and time data into a SQL Server 2012 Express table from an application. The application is providing the date and time as a string data type. Is there a TSQL way to convert the date and time string to an SQL datetime date type? I want to do the conversion, because SQL displays an error due to the
My date and time string from the application looks like : 3/11/2014 12:57:57 PM
I have date coming to one page as a string in the following format"May 4 2005 12:00AM"
I need to query one of my tables using this date in combination of other nondate values. How can I convert this date into valid sql server datetime format before I query a database tables
Please help
I have a data column coming in from a 3rd party vendor in the format of CCYYMMDDHHMMSS. How can I convert this data to a [datetime] format?
CAST(CAST([TransactionDate] AS CHAR(14)) AS datetime)
Is that correct?
Using DTS package in 2000 version, I am dumping TXT file contents into SQL Table,
I have one column having date in format YYYYMMDD(20070929) and corresponding column in SQL is datetime, but it fails on data type mismatch.
I have no choice of making date column in SQL to string or Varchar etc,
is there any way to make that date column in SQL to convert the value upon transformation from format (YYYYMMDD) to M/DD/YYYY (9/29/2007).
many many thanks,
i am trying to take a field that has part of a date in it, so I have to parse it out as follows:
SUBSTRING(a1.Field1, 3, 2) + SUBSTRING(a1.Field1,5,2) + '20' + LEFT(a1.Field1,2)
This is because a date of 04/16/2014 will show as 160416 in the first part of the field I need to parse it out of, thus becoming 04162014.
From there I then need to convert this "date" into a legitimate SQL datetime type, so that I can then run a DATEDIFF to compare it to when the record was actually entered, which is a separate field in the table, and already in datetime format.
When I use the below statement, I am getting the message that, "Conversion failed when converting date and/or time from character string."
CAST((SUBSTRING(a1.Field1, 3, 2) + SUBSTRING(a1.Field1,5,2) + '20' + LEFT(a1.Field1,2)) as datetime)
I also tried CONVERT(datetime, (SUBSTRING(a1.Field1, 3, 2) + SUBSTRING(a1.Field1,5,2) + '20' + LEFT(a1.Field1,2)), and got the same message.
how I can parse that field, then convert it to a datetime format for running a DATEDIFF statement?
I am trying to produce a report that will show a duration in minutes of a time when a room was occupied for a category. Whilst I have the start and end dates and times, the end user must be able to specify not only a range of dates, but a start and endtime of hours in the day in which they are interested in (it will be applied to all days in the range - they are not allowed to specify a different start/endtime per day).
The example I have is a date range of 6 to 17 October, but they only want the times from 09:00 to 21:00, so if a room was occupied from 08:00 to 11:00 they would only want to know the duration as 120 minutes (09:00 to 11:00) not 180.
The data is supplied by a third party, and duration in minutes is supplied, but it is not much use when they are not interested in the 'real' duration.
CREATE TABLE [dbo].[Evts](
[Location_name] [nvarchar](200) NULL,
[Event_Category] [nvarchar](500) NULL,
[Start_Time] [datetime] NULL,
[End_Time] [datetime] NULL,
[Duration] [int] NULL
[Code] ....
---but the expected output is
Location_nameEvent_Categoryduration
RS8CM240
RS8OD480 -- eliminating 08:00 - 09:00 on 17th
RS8OOT300 -- eliminating 08:00 - 09:00 on 13th
RS8SCC150
RS8SODT1740
RS8 SODT180
RS8SODTB60
RS8SODTNT180
RS8TR60
Looking for info regarding to the minute calculation when the start time specified by the user differs from that of the actual startime?
Hi,
I Have this simple convertion in a Script component
Dts.Variables("dateOfProcess").Value = CDate(lineMCF.Substring(30, 2) + "/" + lineMCF.Substring(28, 2) + "/" + lineMCF.Substring(24, 4))
this works fin in my development environment which has a spanish version of SQL Server and uses "DD/MM/YYYY" as date format.
but the production environment has an english version of SQL Server and "MM/DD/YYYY" date format, so the package crashes in this server.
How do I convert the string to date not depending on the SQL server language.
thanks.
Hello, everyone:
I have a customer time duration format like "12:15" that means 12 minutes and 15 seconds. I want to convert to be "12.25 " that means 12.25 minutes. Any suggestion please. Thanks a lot.
ZYT
Hi expert.. I am doing a project that have function to capture the Day and Night time talking duration of caller.... I make use of MSSQL to store the date time file..Let say I have this date: "2006-10-02 00:02:09".. How di I select "00:02:09" only???? Thanks in advancesuigion
View 2 Replies View RelatedHi there.
I'm trying to extract data from my SQL server & everything in the script I've got is working (extracting correct data) except for one field - which is for the most part it's off by +2 days (on a few occasions - I see it off by just +1 day or even +3, but it's usually the +2 days).
I'm told that it's due to the conversion formula - but - since SQL is not my native language, I'm at a bit of a loss.
The DB table has the date field stored as a type: CHAR (as opposed to 'DATE')
Can anyone out there help?
Please advise. Thanks.
Best.
K7
How to convert bigint time to datetime (CST)
Declare @MyBigIntTime BIGINT =1397750400000
I have a datetime field for e.g 2015-09-15 00:00:00.000 and an integer field for e.g.100809.
The integer field is actually a time value as in hours,minutes,seconds. For e.g. the value
100809Â means
10-hours
08-minutes
09-seconds
I need to combine the datetime and the int field to get the output as below
2015-09-15 10:08:09
Dear Expert!
A server with SQL 2005 sp2, Reporting Services and Sharepoint services (ver 3.0) (in integrated mode) gives an odd error. When viewing a Reporting Services report with a Date Time Picker, the date chosen is wrong. The preferred setting is Danish with the date format dd-mm-yyyy. The date picker shows the months in Danish but when selecting a date, and clicking on the Apply-button, the date reformats to US (mm-dd-yyyy).
Example:
When choosing 5th of September 2007 and clicking apply, it shows in the picker, 9th of May 2007.
When choosing 26th of September 2007 and clicking apply, it shows, again in US format, the RIGHT date but adds a timestamp €œ12:00 AM€? in the end, making further enquiries to fail.
The report itself receives the right date and shows correctly. The only case it fails is, when the time stamp appears.
The server is a 32-bit one with 4 GB RAM. A testserver with identical collation on the Reportserver database cannot recreate the error. The site containing the reports has been set to Danish in the regional settings. To Reinstall is not an option.
The test report has no database connection whatsoever.
When setting the site to US, the timestamp won€™t appear at all.
The server has been restarted and the installation procedure was of the simple kind. No special tweaks at all.
Any advice would be greatly appreciated.
Kind Regards
Johan Rastenberger
I have this stored procedure, and im trying to figured out how i can convert the date field into something i can actually sort in the right order in reporting services. Such as mm-dd-yy , whats the SQL code for doing that?
View 6 Replies View Related
I have a web application which is running UK and SQL Server is in US
Is there a way to convert UK date to ISO Format?
Date is passed as a string '31/01/2008 19:58:07'
Thanks.
I'm importing dates into a table with Bulk insert
SET DATEFORMAT DMY
it works with dates e.g. "14/01/2009"
However sometimes I get dates in the format
"Fri 14/01/2009"
What is the best way to convert these.
I can only think of putting them in a staging table with all date fields as varchars Then updating these varchar fields
LTRIM(REPLACE(dtField, 'Mon', ''))
LTRIM(REPLACE(dtField, 'Tues', ''))
Hi
i have the following situation. in my database i have a datetime field (dd/mm/yy hh:mms) and i also have a field timezone.
the timezone field has values in minutes that i should add to my datetime field so i have the actual time.
afterwards i split the datetime into date and time.
the last part i can accomplish (CONVERT (varchar, datetime, 103) as DATEVALUE and CONVERT (varchar, DATETIME, 108) as TIMEVALUE).
could anybody tell me how i can add the timezone value (in minutes) to my datetime value ?
i do all the calculations in my datasource (sql).
Thanks
V.
I have passed createdDate from UI to Stored procedure.createdDate field declared with DateTime.it is having value 2014-07-01.I need to fetch records from the database based upon the created field.but Create_TM in database having value Date with timestamp.so how would i change the createdfield in stored procedure.
ALTER PROCEDURE [dbo].[ByDateRange]
@Feed VARCHAR(50),
@CreatedDate DATETIME
select * from Date_table where Create_TM = @CreatedDate
i am trying to convert a string like this 'le dd/mm/yyyy' into a datetime.I have removed the 'le ' part and used covert(datetime, 'dd/mm/yyyy',103) to convert into datetime. This works for example for 'le 22/11/1799' but for 'le 09/11/1716' it does not work.
select convert(datetime,RIGHT('le 22/11/1799', LEN('le 22/11/1799') - 3), 103) -> it works
select convert(datetime,RIGHT('le 09/11/1716', LEN('le 09/11/1716') - 3), 103) -> it does not work
I am trying to convert a date-string of this format (DDMMMYY - ex. 06JAN15) to datetime but I keep on getting errors:
codes that I tried:
convert(datetime, '06JAN15', 6)
convert(datetime, '06JAN15', 112)
What date format code should I use for DDMMMYY?
This UDF will strip off the time portion of a DateTime. It can give you either midnight last night, or midnight tonight.
Lets say you have two datetime values @dateStart and @dateEnd, and you want to select records between these dates (excluding any time portion), then you would do:
SELECT *
FROM MyTable
WHERE MyDateTimeColumn >= dbo.kk_fn_UTIL_DateRound(@dateStart, 0)
AND MyDateTimeColumn < dbo.kk_fn_UTIL_DateRound(@dateEnd, 1)
If you want to display dates, without the time, then do:
SELECT dbo.kk_fn_UTIL_DateRound(MyDateColumn, 0) AS [My Date]
FROM MyTable
--
PRINT 'Create function kk_fn_UTIL_DateRound'
GO
IF EXISTS (SELECT * FROM dbo.sysobjects WHERE id = object_id(N'[dbo].[kk_fn_UTIL_DateRound]') AND xtype IN (N'FN', N'IF', N'TF'))
DROP FUNCTION dbo.kk_fn_UTIL_DateRound
GO
CREATE FUNCTION dbo.kk_fn_UTIL_DateRound
(
@dtDatedatetime,-- Date Value to adjust
@intRoundint-- 0=Round down [Midnight last night], 1=Round up [Midnight tonight]
)
RETURNS datetime
/* WITH ENCRYPTION */
AS
/*
* kk_fn_UTIL_DateRoundConvert date to midnight tonight
*For a "limit" date of '01-Jan-2000' the test needs to be
*MyColumn < '02-Jan-2000'
*to catch any item with a time during 1st Jan
*
*SELECTdbo.kk_fn_UTIL_DateRound(GetDate(), 0)-- Midnight last night
*SELECTdbo.kk_fn_UTIL_DateRound(GetDate(), 1)-- Midnight tonight
*
* Returns:
*
* datetime
*
* HISTORY:
*
* 28-Jul-2005 KBM Started
*/
BEGIN
SELECT@dtDate = DATEADD(Day, DATEDIFF(Day, 0, @dtDate)+@intRound, 0)
RETURN @dtDate
/** TEST RIG
SELECT'01-Jan-2000', dbo.kk_fn_UTIL_DateRound('01-Jan-2000', 0)
SELECT'01-Jan-2000', dbo.kk_fn_UTIL_DateRound('01-Jan-2000', 1)
SELECT'01-Jan-2000 01:02:03', dbo.kk_fn_UTIL_DateRound('01-Jan-2000 01:02:03', 0)
SELECT'01-Jan-2000 01:02:03', dbo.kk_fn_UTIL_DateRound('01-Jan-2000 01:02:03', 1)
SELECT'28-Feb-2000 01:02:03', dbo.kk_fn_UTIL_DateRound('28-Feb-2000 01:02:03', 0)
SELECT'28-Feb-2000 01:02:03', dbo.kk_fn_UTIL_DateRound('28-Feb-2000 01:02:03', 1)
SELECT'29-Feb-2000 01:02:03', dbo.kk_fn_UTIL_DateRound('29-Feb-2000 01:02:03', 0)
SELECT'29-Feb-2000 01:02:03', dbo.kk_fn_UTIL_DateRound('29-Feb-2000 01:02:03', 1)
**/
--==================== kk_fn_UTIL_DateRound ====================--
END
GO
PRINT 'Create function kk_fn_UTIL_DateRound DONE'
GO
--
Kristen