TSQL : How To Delete Duplicated Rows Except The Top 1 Order By Some Fields?

Apr 15, 2004

the table is like :

ID F1 F2 F3
--- --- --- ---
1 A 1 VR
2 B 2 VR
3 A 3 VF
4 A 2 VF
5 B 1 VF
......

the rules is:
if there are rows with same values of F3 field,then choose the top 1 row order by F1,F2 in the group,and delete other rows.

how can I delete rows with ID in (2 , 3 , 5)?

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TSQL - Avoid Duplicated Rows - Using Distinct / Group By

Sep 3, 2007

Hi guys,
need some help here please...

The code below shows 4 rows.
The first two rows are almost identical, but the two of them exists in the same table as different rows.
Row number 1 is also related to Row number 3 and Row number 2 is also related to Row number 4
The problem is that I have to use only one of then (Rows number 1 or 2) togheter with row 3 & 4.

I thought using GROUP BY RECEIPTJURNALMATCH.JURNALTRANSID, but getting error.
Thanks in advance,
Aldo.




Code Snippet
SELECT
RECEIPTJURNALMATCH.JURNALTRANSID AS 'R.JURNALTRANSID',
RECEIPTJURNALMATCH.MATCHNUM AS 'R.MATCHNUM',
JURNALTRANSMOVES.ACCOUNTKEY AS 'J.ACCOUNTKEY',
JURNALTRANSMOVES.SUF AS 'J.TOTAL',
STOCK.REMARKS AS 'S.REMARKS'

FROM
RECEIPTJURNALMATCH
INNER JOIN JURNALTRANSMOVES ON RECEIPTJURNALMATCH.JURNALTRANSID = JURNALTRANSMOVES.ID
LEFT OUTER JOIN STOCK ON RECEIPTJURNALMATCH.STOCKID = STOCK.ID

WHERE
JURNALTRANSMOVES.ACCOUNTKEY IN ('123456')


Below the results:

R.JURNALTRANSID R.MATCHNUM J.ACCOUNTKEY J.TOTAL S.REMARKS
89634 16702 123456 1155 עח: ;5752
89634 16703 123456 1155 עח: ;5752
89637 16702 123456 400 NULL
89639 16703 123456 155 NULL





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Oct 21, 2005

Hello,

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This is OK and works fine, my trouble comes when i have a duplicated ID on both A and B. Instead of return 2 fields, it returns me 4.

Is there some way to force SQl server to return only the first founded on B, but the 2 duplicated IDs on the A table?

Thanks for all.

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Hello,
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Hello,
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Oct 31, 2006

Hi,

I have just started developing in SQL Express in the last 2 months so still learning. The problem Im having with my stored procedure is that I get duplicate rows in my results. The row is a duplicate in terms of column 'Job No' as when the query runs in access only one instance of each 'Job No' is returned but when I recreate the query in SQL server I get a number of rows back for the same 'Job No'? How would I go about getting just 1 instance of each 'Job No' back? With column 'Days to Date' showing the total 'Days to Date' for each Job No. Please see Ms Access results if unsure of what Im asking.

A copy of the stored procedure is below and a sample of the out-put with Ms Access results at very bottom.

ALTER PROCEDURE [dbo].[sl_DaysDonePerJob] AS

SELECT CASE WHEN [Job No] IS NULL THEN '' ELSE [Job No] END AS [Job No], SUM([Actual Days]) AS [Days to Date], CONVERT(nvarchar(10),MIN(SessionDate),101) AS [Start Date],

CONVERT(nvarchar(10),MAX(SessionDate),101) AS [End Date],

MAX(CASE WHEN DATEPART(MM,SessionDate)=1 THEN 'Jan'

WHEN DATEPART(MM,SessionDate)=2 THEN 'Feb'

WHEN DATEPART(MM,SessionDate)=3 THEN 'Mar'

WHEN DATEPART(MM,SessionDate)=4 THEN 'Apr'

WHEN DATEPART(MM,SessionDate)=5 THEN 'May'

WHEN DATEPART(MM,SessionDate)=6 THEN 'Jun'

WHEN DATEPART(MM,SessionDate)=7 THEN 'Jul'

WHEN DATEPART(MM,SessionDate)=8 THEN 'Aug'

WHEN DATEPART(MM,SessionDate)=9 THEN 'Sep'

WHEN DATEPART(MM,SessionDate)=10 THEN 'Oct'

WHEN DATEPART(MM,SessionDate)=11 THEN 'Nov'

WHEN DATEPART(MM,SessionDate)=12 THEN 'Dec' END) AS 'End Month'

FROM Sessions

GROUP BY [Job No], Sessions.SessionDate

ORDER BY [Job No]

Results in SQL Server Express

'Job No' 'DaystoDate' 'Start Date' 'End Date' 'End Month'

1113-001 0 08/16/2001 08/16/2001 Aug
1113-002 0.5 07/11/2000 07/11/2000 Jul
1113-002 0.5 02/09/2000 02/09/2000 Feb
1116-001 1 07/07/1999 07/07/1999 Jul
1116-001 1 07/06/1999 07/06/1999 Jul
1118-001 1 01/12/1999 01/12/1999 Jan
1118-001 0.5 03/17/1999 03/17/1999 Mar
1118-001 1 02/23/1999 02/23/1999 Feb
1118-001 1 01/26/1999 01/26/1999 Jan
1118-001 0.5 03/09/1999 03/09/1999 Mar
1118-001 1 12/15/1998 12/15/1998 Dec
1118-001 1 02/09/1999 02/09/1999 Feb

Results in Ms Access



Days Done per Job


JobNo
Days to Date
Start Date
End Date
End Month


1113-001
0.00
16/08/2001
16/08/2001
Aug01

1113-002
1.00
09/02/2000
11/07/2000
Jul00

1116-001
2.00
06/07/1999
07/07/1999
Jul99

1118-001
6.00
15/12/1998
17/03/1999
Mar99

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/****** Object:  Trigger    Script Date: 24/07/2015 3:41:38 PM ******/
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Hi Guys,


I am using the query below to retrieve these results:
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ACCOUNTKEY DATFID DATFNAME DATF SUFID SUFNAME SUF

--------------- ----------- -------------------------------------------------- ----------------------- ----------- -------------------------------------------------- ----------------------

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Code Snippet
SELECT DISTINCT

Accounts.ACCOUNTKEY,

ExtraDates.DATFID,

ExtraDateNames.DATFNAME ,

ExtraDates.DATF ,

ExtraSums.SUFID ,

ExtraSumNames.SUFNAME ,

ExtraSums.SUF
FROM
EXTRADATES AS ExtraDates
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RIGHT OUTER JOIN ACCOUNTS AS Accounts ON ExtraDates.KEF = Accounts.ACCOUNTKEY
LEFT OUTER JOIN EXTRASUMS AS ExtraSums
LEFT OUTER JOIN EXTRASUMNAMES AS ExtraSumNames ON ExtraSums.SUFID = ExtraSumNames.SUFID ON Accounts.ACCOUNTKEY = ExtraSums.KEF
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Hi guys,
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Code Block
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The results are just as I need:


Field01 Field02

------------- ----------------------

192473 8461760

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Code Block
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378 9/05

388 9/05

4/05

1/06 606

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