Transact SQL :: Count Weeks With More Than Two Records

Aug 22, 2015

My table is test and I have an ID and DateTest columns

I would like to count the weeks with more then one record.

So far I got this and return the weeks with 1 record per week. How can I count the weeks with more then one record

select sum(c)
from (
select c = count( id) over (partition by id, datepart(week, DateTest))
from test where id = '1' and DateTest >= '7-7-2015'
) a where c = 1

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Nov 21, 2013

Aim - Looks at the “CreatedDate” for the latest month and count how many created dates fall within a given week

Currently the created date is displayed as

2013-11-01T09:08:54.000Z
2013-11-05T12:32:26.000Z
2013-11-15T12:37:17.000Z

So for Example

Week 1 = 2
Week 2=1
Week 3=0
Week 4= 0

My table is

select
[CreatedDate],
from #build

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SELECT DISTINCT Standard, COUNT(Standard) AS Total,month(ReportDate) Month
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GROUP BY Standard, Standard ,
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NULL 0 1 //Jan
NULL 0 2 //Feb
NULL 0 3
NULL 0 4
NULL 0 5
OSHA 18001, 1 5
NULL 0 6
NULL 07
NULL 08
OSHA 18001,158
TL 9000,18
NULL 09
OSHA 18001,139

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[Code] ....

Current Result

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PAYER_NAME
CLAIM_ICN
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[code]....

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Is there something I am doing incorrectly in the following sql?

DECLARE @startdate date = '03-06-2015'
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SELECT
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Feb 14, 2008

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Dec 5, 2005

Hi

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Code Snippet

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[code]...

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