Transact SQL :: Date Difference Between Two Dates In Due And OverDue
Sep 25, 2015
I want a difference in daysÂ
Select datediff(dd,Target_Date,Achv_Date)Â
Now , checks areÂ
1] when target date greater than achv_Date the difference should be greater than 0Â
means for FileIDÂ 77608Â
Select datediff(dd,'2015-09-24 00:00:00.000','2015-09-24 10:42:32.823')
Â
i am getting -6 it should be 6 cant switch Target_Date and Achv_Date in datediff else i will get opposite result in first four records basically, i want a two column TAT and Status beside  achv_date based on the values of two dates difference see above ..and also want a result of (No. of Yes in status / No. of Files that has achv_date )i.e. result= (7/8) = 87%Â
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Oct 14, 2015
Here I have 2 Dates. CreatedDttm & ModifiedDttm.
I want  - DATEDIFF(Day,CreatedDttm,ModifiedDttm)  and I have to exclude the Weekend days from that query result.
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Jun 18, 2014
I have a field called 'LOG_COMMENTS' in a table named T_PRODUCTION_WORK_LOG.
In the 'LOG_COMMENTS' whenever a request is placed on hold comments are added by the application, such as 'Status changed from Open to On Hold' and 'Status changed from On Hold to Open' along with a 'LOG_DATESTAMP' field. A request can go on and off Hold multiple times, how do I determine the days a request is On Hold?
I know I can use the sql function DATEDIFF ( datepart , startdate , enddate ), but how do I account for the possiblity that the request was On Hold more than once? And how would I get LOG_DATESTAMP' times for 'LOG_COMMENTS' that contain 'Status changed from Open to On Hold' and 'Status changed from On Hold to Open''?
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Aug 27, 2012
I have already seen stored procedures that can calculate a difference in dates, excluding the weekends. Any extension of such a SQL query to exclude not only weekends, but other dates as well. We have a table of "holidays" (not necessarily standard holidays), and I am wondering if there is a way to exclude them from the calculation.
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Sep 11, 2015
I require outputting the date difference between two date's if it is greater than 7(DateDiff(day, DateAdd(day, t.[Started], Nxt.started), (t.[started])) > 7).I get incorrect syntax on my operator.What is the correct code?
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Apr 16, 2015
I'm trying to calculate the time difference between a date field and today's date in days. The date field is not mandatory and can therefore be blank. I'm trying to execute the following query:
SELECT employee_code, Civil_ID, DATEDIFF(Day, Civil_ID, GETDATE())
FROM ODEV_VIEW_Credentials_Expiry_Dates
WHERE Civil_ID IS NOT NULL AND Civil_ID != ''
ORDER BY employee_code
I keep getting the following message:
The conversion of a varchar data type to a datetime data type resulted in an out-of-range value.
Warning: Null value is eliminated by an aggregate or other SET operation.
No matter what filter I use to process non-blank dates, it never works.
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May 21, 2015
declare @siva1 datetime;
declare @siva2 datetime;
set @siva1='2014-03-10 05:02:11'
set @siva2='2014-03-12 23:52:11'
i want output like this 2.18 means 2day 18hours difference how using query
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Aug 22, 2015
i have a table like below
CREATE TABLE #Test (FromDate DATE,ToDate DATE)
insert into #Test VALUES ('2015-08-08','2015-08-11')
insert into #Test VALUES ('2015-08-13','2015-08-16')
insert into #Test VALUES ('2015-08-19','2015-08-21')
SELECT * from #Test
drop TABLE #Test
i need to display the dates as single column between from and todate.my expected result is like below
CREATE TABLE #Result (ResDate DATE)
insert into #Result VALUES ('2015-08-08')
insert into #Result VALUES ('2015-08-09')
insert into #Result VALUES ('2015-08-10')
insert into #Result VALUES ('2015-08-11')
[code]....
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Aug 20, 2015
Basically, I have a membership table that lists each member with an effective period, Eff_Period, that indicates a month when a member was active. So, if a member is active from Jan to Mar, there will be three rows with Eff_Periods of 201501, 201502 and 201503.
All well and good.But, a member may not necessarily have continuous months for active membership. They might have only been active for Jan, Feb and Jun. That would still give them three rows, but with noncontinuous Eff_Periods; they'd be 201501, 201502 and 201506.There is also a table that logs member activity. It has an Activity_Date that holds the date of the activity - betcha didn't see that comin'. What I'm trying to do is determine if an activity took place during a period when the member was active.
My original thought was to count how many rows a member has in the Membership table and compare that number to the number of months between the MIN(Eff_Period) and the MAX(Eff_Period). If the numbers didn't matchup, then I knew that the member had a disconnect somewhere; he became inactive, then active again. But, then I thought of the scenario I detailed above and realized that the counts could match, but still have a discontinuity.So, is there a nifty little SQL shortcut that could determine if a target month is contained within a continuous or discontinuous list of months?
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May 7, 2015
In a stored procedure I have 2 dates that I need to combine parts of into a third date. I need the year from date1 and the month/day from date2.
Date1 = '2015/6/1'
Date2 = '2016/1/1'
Date3 needs to be '2015/1/1'
I have been messing around with datepart and dateadd with no luck.
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Jun 3, 2015
I have a simple following table which is having only one date column.
CREATE TABLE TEST_DATE
(
InputDate DATE
)
GO
INSERT INTO TEST_DATE VALUES('01-01-2015')
INSERT INTO TEST_DATE VALUES('06-25-2015')
INSERT INTO TEST_DATE VALUES('11-23-2014')
GO
SELECT * FROM TEST_DATE;
And the expected out put would be as follows:
I want to derive a Four Quarter End Date based on Date selected.
For Example if i select 01-01-2015 then
First Quarter End Date would be Previous Quarter End Date
Second Quarter End Date would be Current Quarter End Date
Third Quarter End Date would be Next Quarter End Date
Fourth Quarter End Date would be Next +1 Quarter End Date Like that
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May 23, 2015
I need to calculate the amount of time between each visit. I am pulling the Row Number for my visits and now I need the date span that goes between each day. I also need a new column that returns a Yes or a No if the date span exceeds 3 years.
SELECT
ROW_NUMBER ( ) OVER ( PARTITION BY pv.PatientProfileId ORDER BY pv.Visit ASC ) AS RN
, CONVERT ( VARCHAR ( 20 ) , pv.Visit , 101 ) AS Visit
, pv.TicketNumber
, vstatus.Description AS VisitStatus
, doc.ListName AS Doctor
[Code] ....
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Sep 10, 2015
I want generating Valid date ranges from any list of dates.
The List of Dates could be generated from the below TSQL -Â
SELECT '2015-06-02' [Date] UNION ALL
SELECT '2015-06-13' UNION ALL
SELECT '2015-06-14' UNION ALL
SELECT '2015-06-15' UNION ALL
SELECT '2015-06-16' UNION ALL
SELECT '2015-06-22' UNION ALL
SELECT '2015-06-23' UNION ALL
SELECT '2015-06-24'
And the expected output should look like -Â
SELECT '2015-06-02' FromDate, '2015-06-02' ToDate UNION ALL
SELECT '2015-06-13' FromDate, '2015-06-16' ToDate UNION ALL
SELECT '2015-06-22' FromDate, '2015-06-24' ToDate
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Nov 17, 2015
My scenario is: a person has many events, all based on a date. I need to aggregate the person to show min and max dates for a period, the period being defined as ending when there is not an event following the next date.
DECLARE @Events TABLE
(
PK_EventINTIDENTITY(1,1) PRIMARY KEY
,FK_UserINTNOT NULL
,EventDateDATENOT NULL
)
DECLARE @User TABLE
[Code] ....
I would expect the groups to look something like below:
Is this where a recursive CTE may be used?
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May 17, 2005
Hey people,
i was wondering if it was possible to get the difference bettween the current date/time and a date feild and store it in a feild in the same table. id like to do this to prevent constant php update querys.
cheers
mish
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Oct 23, 2007
I have 2 datatime columns....i want to get the difference in the dates...
EXample
Startdate Enddate Difference
10/10/2007 20/10/2007
11/10/2007 21/10/2007
12/10/2007 22/10/2007
13/10/2007 23/10/2007
14/10/2007 25/10/2007
I want the difference to be in the Difference column...
Kindly help me...thanks in advance...
pavan
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Mar 15, 2007
By using DateDiff we can do.Could you please send me the expression
Thanks
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Apr 10, 2008
advance thanks to all...can anybody helpme soon...........
i am using sql server 2005........i want to find out time difference between two dates in HH,MM,SS format
eg i want the time difference of these two dates
02/Nov/06 9:14:21 AM
19/Apr/07 11:52:31 AM
now i am using this calculation in my procedure is as follows...but i think this is wrong...if we will seperatly calculate like this wrong i am getting
set @totaltravelHr=datediff(HH,@datediff1,@datediff2)
set @totaltravelMI=datediff(MI,@datediff1,@datediff2)
set @totaltravelSE=datediff(SS,@datediff1,@datediff2)
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Oct 18, 2006
Hi, i'm trying to calculate the number of days between two dates, but within an UPDATE statement, so far I can't wrap my head around how I can update a field with the number of days.
I was thinking something like
Code:
Update #ClaimMaster
Set covered_days = (then insert select statement that subtracts the two dates)
Does that make any sense?
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Jun 23, 2007
i was working on a appication and just got stuck with this.
I have a column on a table which is a date column and i need to get the days differenct and copy it in another column
e.g
date days between
27-02-2005 1
28-02-2005 0
28-02-2005 0
28-02-2005 1
01-03-2005 0
01-03-2005
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Nov 27, 2007
This is tricky so please read it through
For displaying data on the report I am using the following query
SELECT ReferenceNumber, ActivityID, ActivityTimeStamp, ActivityType, ActivityPerformedBy FROM ActivityDetails
ORDER BY ReferenceNumber, ActivityID
The result set is
Issue Reference #
Activity ID
Activity Date/Time
Activity Type
100819
4521404
11/4/07 2:06 PM
INIT
100819
4521405
11/4/07 2:07 PM
LOG
100819
4521406
11/4/07 2:07 PM
LOG
100819
4521473
11/4/07 2:28 PM
TR
100819
4521501
11/4/07 2:33 PM
WIP
100819
4521839
11/4/07 3:25 PM
RE
100819
4521844
11/4/07 3:27 PM
RE_Method
100819
4522575
11/4/07 8:53 PM
CL
100820
4521412
11/4/07 2:10 PM
INIT
100820
4521419
11/4/07 2:13 PM
ATTACHTDOC
100820
4525856
11/5/07 2:49 PM
ATTACHTDOC
100820
4525859
11/5/07 2:49 PM
LOG
100820
4525869
11/5/07 2:49 PM
CL
100821
4521423
11/4/07 2:14 PM
INIT
100821
4521425
11/4/07 2:14 PM
LOG
100821
4521429
11/4/07 2:14 PM
TR
100821
4521432
11/4/07 2:14 PM
ACK
100821
4522219
11/4/07 4:58 PM
RE
100821
4522221
11/4/07 4:58 PM
RE_Method
100821
4522447
11/4/07 6:51 PM
CL
On the report I have used the grouped by clause on 'Issue Reference #'. I want one more column which would calculate the difference between two consecutive Activity Date/Time of the same reference #.
e.g. Time difference between 4521404 and 4521405, 4521405 and 4521406, 4521406 and 4521473 etc. Please note that the difference between 4521412 and 4522575 will NOT be calculated since they are from different Reference Numbers.
Thanks,
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Sep 26, 2006
Hi all,
I have a table named Orders and this table has two relevant fields: CustomerId and OrderDate. I am trying to construct a query that will give me the difference, in days, between each customer's order so that the results would be something like: (using Northwind as the example)
...
ALFKI 25/08/1997 03/10/1997 39
ALFKI 03/10/1997 13/10/1997 10
ALFKI 13/10/1997 15/01/1998 94
ALFKI 15/01/1998 16/03/1998 60
ALFKI 16/03/1998 09/04/1998 24
...
At the moment, I have the following query that I think is on the right track:
€¦
SELECT dbo.Orders.CustomerID, dbo.Orders.OrderDate AS LowDate, Orders_1.OrderDate AS HighDate, DATEDIFF([day], dbo.Orders.OrderDate, Orders_1.OrderDate) AS Difference FROM dbo.Orders INNER JOIN dbo.Orders Orders_1 ON dbo.Orders.CustomerID = Orders_1.CustomerID AND dbo.Orders.OrderDate < Orders_1.OrderDate GROUP BY dbo.Orders.CustomerID, dbo.Orders.OrderDate, Orders_1.OrderDate, DATEDIFF([day], dbo.Orders.OrderDate, Orders_1.OrderDate) ORDER BY dbo.Orders.CustomerID, dbo.Orders.OrderDate, Orders_1.OrderDate
€¦
However, this gives me too much data:
€¦
ALFKI 25/08/1997 03/10/1997 39
ALFKI 25/08/1997 13/10/1997 49
ALFKI 25/08/1997 15/01/1998 143
ALFKI 25/08/1997 16/03/1998 203
ALFKI 25/08/1997 09/04/1998 227
ALFKI 03/10/1997 13/10/1997 10
ALFKI 03/10/1997 15/01/1998 104
ALFKI 03/10/1997 16/03/1998 164
ALFKI 03/10/1997 09/04/1998 188
ALFKI 13/10/1997 15/01/1998 94
ALFKI 13/10/1997 16/03/1998 154
ALFKI 13/10/1997 09/04/1998 178
ALFKI 15/01/1998 16/03/1998 60
ALFKI 15/01/1998 09/04/1998 84
€¦
So, do any of you have any ideas how I might achieve this? I know how to do it using a stored procedure, but I am trying to avoid that; I€™d like to do this in a single query.
Thanks for any help you have to offer,
Regards,
Stephen.
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Feb 14, 2008
Its early in the morning and I am struggling with an easy one.
I have a calculated field in a report which displays the difference between 2 dates. The value that is returned is a number which I can then format to display difference like so 'Days.hh:mms'
I need the diffence between the dates to be expressed in hours, minutes and seconds only. eg '36:45:12'
It would also be usefull if I could build a parameter in to the query which would allow me to discount days selected by the user (Using multi select drop down in day format i.e 'Monday', 'Tuesday', etc)
Any Idea's?
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Dec 9, 2011
I have data in which i need to calculate employees working hours for a day...
name time in_out
manisha 2011-01-01 9:30:00.000am 1
manisha 2011-01-01 10:30:00.000 0
manisha 2011-01-01 10:45:00.000 1
manisha 2011-01-02 1:00:00.000am 0
How can i calculate time in that two dates as 1 is for entry an 0 is for exit..
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Feb 27, 2013
It has been a while since I have used SQL server and require to show a time difference between a start and end time, with only 1 date to determine these times
SQL
select
Arrival_date
locationdate as LocDate,
locationid as Loc_ID,
locations.loc_name as Location_Name
from current_locations
left outer join locations on
locations.loc_id = current_locations.location_id
where current_locations.Attend_ID = '1234567'
Results
Arrival Date LocDate Loc_IDloc_name
26/02/2013 19:2126/02/2013 19:271270Queue
26/02/2013 19:2126/02/2013 19:341278Dept 1
26/02/2013 19:2126/02/2013 21:10222Dept 2
26/02/2013 19:2127/02/2013 02:5631Left Department
What I want to acheive is the following where the Start location date is either the arrival date or the next location date and the endLocDate is the next finish date.
StartLocDateEndLocDateTime DifferenceDept
26/02/2013 19:2126/02/2013 19:2700/01/1900 00:06Queue
26/02/2013 19:2726/02/2013 19:3400/01/1900 00:07Dept 1
26/02/2013 19:3427/02/2013 02:5600/01/1900 07:22Dept 2
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Jun 2, 2015
Is it possible to get difference between two dates - first one and last one per every group in table (records are sorted by ID)?
ID Group Date
739 Group 1 2015-04-17 14:27
740 Group 1 2015-04-19 06:51
760 Group 1 2015-04-19 11:51
762 Group 1 2015-04-21 09:30
763 Group 1 2015-04-20 09:20
[Code] ....
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Feb 28, 2007
I have a need to display the difference between two dates, a start date and a end date in the format HH:mm where the hours could be greater than 60.
For example:
Start Date - 30/01/2007 09:00:01
End Date - 01/02/2007 20:40:04
When i use the following code (=Fields!dateend.Value - Fields!DateStart.Value) i get 2.11:40:03 which i can easily understand, but the customer wants it as above!
I would like to be able to get it to be 59:40:03.
Any help would be much appreciated.
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Jan 19, 2015
select datediff(wk, '2015-01-11', '2015-01-19') returns 1 (shouldn't it return 2?)
select datediff(wk, '2015-01-10', '2015-01-19') returns 2
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Aug 21, 2005
I have table with three columns: 1) TodaysDate,
2)
DueBackDate,
3) DaysOverdue
The problem I am having is creating a formula in MS SQL, so that when
the 'DueBackDate' column is more than todays date, I want the
'DaysOverdue' column to be incremented accordingly.
I have tried creating an SQL Query something like this:
UPDATE rental
SET DaysOverdue = DaysOverdue + 1
WHERE ({ fn NOW() } > DueBackDate)
But the problem with this that it only increments the 'DaysOverdue'
field by 1. When I want it to basically subtract todays date by
'DueBackDate'.
I have tried to also create a formula within MS SQL but I come up with
errors. I have done something like this in Access which worked. The
Formula looked like this:
IIF(Now()>[DueBackDate],int(Now()-[DueBackDate]),0)
Is there a way to convert this formula so that is would work in MS SQL?
Thanks.
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May 19, 2014
I have a table with a list of jobs along with their start and end datetime values.
I am looking for a function which will return the time taken to process a job using a start date and an end date. If the date range covers a Saturday or Sunday I want the time to ignore the weekends.
Example
Start Date=2014-05-15 12:00:00.000
End Date=2014-05-19 13:00:00.000
Total Time should be: 2 Days, 1 Hour and 0 Minutes
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Mar 17, 2015
How do I find the time difference when the dates are in one column? I need to find hours and minutes between each row.
CREATE TABLE #Time ([TimeStamp] DATETIME, TimeDiff INT)
INSERT INTO #Time (TimeStamp)
VALUES ('2014-09-02 07:51:02.810'), ('2014-09-02 07:48:09.567'), ('2014-09-02 08:37:09.647')
, ('2014-09-02 16:16:42.593'), ('2014-09-02 08:06:13.387'),('2014-09-02 14:32:00.113')
DROP TABLE #Time
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Sep 4, 2015
I have a table with appdt as first appointment date and the another record for the same customer# has follow up appointment.
Each customer is uniquely identified by a customer#
I need to find out if the customer came back after 200 days or more when the first appointment date was between jan12014 and Aug 31 2014. I am only interested in first follow up appointment after 30 days or more.
How can i do that in a query?
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May 28, 2015
I need getting the HH:MM:SS format when we do datepart.
For example, am using a variable to capture the time taken to execute the package using Start and End time stamps captured.
I would like to get the HH:MM:SS format of the datediff.
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