Transact SQL :: Difference Between Data With Group By

Jul 28, 2015

I have a SQL table like this

Events time endTime
Tram 2014-11-28 12:35:50.390 2014-11-28 12:43:19.120
Re-Entry 2014-11-28 12:43:19.120 2014-11-28 12:56:07.040
Tram 2014-11-28 12:56:07.040 2014-11-28 13:15:25.060 // EndDate Before dump
Dump 2014-11-28 13:15:25.060 2014-11-28 13:50:07.233
Tram 2014-11-28 13:50:07.233 2014-11-28 13:55:17.473
Load 2014-11-28 13:55:17.473 2014-11-28 14:06:55.063
Tram 2014-11-28 14:06:55.063 2014-11-28 14:37:12.100
Dump 2014-11-28 14:37:12.100 2014-11-28 14:37:12.100

I want to calculate the Difference between 2 dates like endtime before Dump -time..I am expecting output like this

ROW1   ROW2
 1    00:39:34
 2    23:12:55

You can find the details in SQL Fiddle here.

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Transact SQL :: Difference Between Exist And In?

Aug 24, 2015

select count(cars.carid)
from
Cars left
join
RentalOrders
on
cars.CarID=RentalOrders.CarRef
where carid not
in(selectRentalOrders.CarRef
from
RentalOrders)

when I wrote this above-query for sofiacarrental_v2.2 it shows 30 in the result but when I changed it this query to that:

select count(cars.carid)
 from
Cars left
join
RentalOrders
on
cars.CarID=RentalOrders.CarRef
where not exists
(select
RentalOrders.CarRef
from
RentalOrders)

I replaced not in with not exists it showed 0 in the result.there is any point in term of using them or I made a mistake in the second query? 

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Reporting Services :: Calculating Difference Between Columns Within Column Group

Jun 15, 2015

Given the attached report, is there an easy way of calculating the difference between the Today and QTR Start column? Because of the Account Group, the report looks like the sample shown on the second image.

Sample report:

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Transact SQL :: Query On Running Value (difference)

Jun 18, 2015

I have a table that will be loaded over night everyday and I need to write a query on running value difference ?

List of Columns (ID, Branch ,Group, Date, Value)

ID    Branch   Group   Date                   Value
1        A           C      2015-06-01            10
2        A          C       2015-06-02            15
3        A          C       2015-06-03            25
4        A          C       2015-06-04            20
5        B          D       2015-06-01            20
6        B          D       2015-06-02            25
7        B          D       2015-06-03            10
8        B          D       2015-06-04            20

I want the Output like below with a Running value difference in comparison to previous day.

ID    Branch   Group   Date          Value    Running Value
1        A           C      2015-06-01            10         10
2        A          C       2015-06-02            15         05
3        A          C       2015-06-03            25         10
4        A          C       2015-06-04            20         -5
5        B          D       2015-06-01            20         20
6        B          D       2015-06-02            25         05
7        B          D       2015-06-03            10        -15
8        B          D       2015-06-04            20         10

Basically I need to compare the previous day and show the difference. How can I do this in SQL 2008 r2?

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Transact SQL :: Difference Between Index And Primary Key

Aug 10, 2015

What is the difference between the Index and the Primary Key?

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Transact SQL :: Difference Between Heaps And Balanced Tree?

May 28, 2015

What is the difference between Heaps and Balanced Trees? Is it true that if a table has no clustered index it is a heap?

If so , if the table has only Non clustered index, is it still a Heap?

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Transact SQL :: Date Difference Between Two Dates In Due And OverDue

Sep 25, 2015

I want a difference in days 

Select datediff(dd,Target_Date,Achv_Date) 
Now , checks are 
1] when target date greater than achv_Date the difference should be greater than 0 
means for FileID 77608 
Select datediff(dd,'2015-09-24 00:00:00.000','2015-09-24 10:42:32.823')
 
i am getting -6 it should be 6 cant switch Target_Date and Achv_Date in datediff else i will get opposite result in first four records basically, i want a two column TAT and Status beside  achv_date based on the values of two dates difference see above ..and also want a result of (No. of Yes in status / No. of Files that has achv_date )i.e. result= (7/8) = 87% 

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Transact SQL :: Difference Between Batch And Stored Procedure?

Jun 19, 2015

What is the difference between Batch and Stored Procedure?

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Transact SQL :: Getting Time Difference In Hours And Minutes?

Jul 10, 2015

Currently my script is using the below mentioned query to find the time difference.

DATEDIFF(HH,DATEADD(SS,hcreacion,fcreacion) ,DATEADD(SS,hcerrar,fcreacion))

If there is 1 hr 30 minutes time difference, I am getting 2 hours as output. But we need 1.30 as output. is there any way to achieve this?

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Transact SQL :: Inventory Difference Between Rows Between Stores

May 8, 2015

how to measure a change in inventory over various stores.  My sql2008R2 express db gets a new row of data everyday from each store(about 40 stores) for a single product stock count "OnHand" and if there is any new stock on order.  When the new stock arrives it is added to the "OnHand" count.   I want to measure the delta change per day,per store.  I'm stuck on how to separate the stores and how to query the delta of stock.My data base looks like this
                               
TimeStamp Store
OnHand OnOrder
2015/04/22 18   1 - Concord
12
     0
2015/04/23 11   1 - Concord
11
 
[code]....

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Transact SQL :: Total Difference Time In Last Column?

May 23, 2015

I have the below query

DECLARE @GivenDate DATE='2015-05-13'
create table #table (LedgerID int,AttDate Date, checkedtime time,checkedtype varchar(1))
insert into #table (LedgerID,AttDate,checkedtime,checkedtype) values (1232,'2015-05-13','09:01:48.0000000','I')
insert into #table (LedgerID,AttDate,checkedtime,checkedtype) values (1232,'2015-05-13','13:05:52.0000000','O')
insert into #table (LedgerID,AttDate,checkedtime,checkedtype) values (1232,'2015-05-13','14:10:25.0000000','I')

[code]....

the result is like below

i need 'TotalDiffernceTime' column as new column (OUT1-IN1)+(OUT2-IN2).

i am using SQLServer 2008 R2

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Transact SQL :: Getting Time Difference Between Same Column In Different Rows

Jun 21, 2015

I have a table data like below

id         type      timestamp
1001    start1    10:34:23:545
1001    start2    10:34:24:545
1001    end2     10:34:24:845
1001    end1     10:34:25:545
1002    start1    10:34:25:645
1002    start2    10:34:25:745
1002    end2     10:34:25:945
1002    end1     10:34:25:965

I need the result as follows

id              millisecond diff start1end1                 millisecond diff start2end2
1001    end1 timestamp-start1 timestamp    end2 timestamp-start2 timestamp
1002    end1 timestamp-start1 timestamp    end2 timestamp-start2 timestamp

SQL Server 2008 R2

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Transact SQL :: Calculating Date Difference In Days

Apr 16, 2015

I'm trying to calculate the time difference between a date field and today's date in days. The date field is not mandatory and can therefore be blank. I'm trying to execute the following query:

SELECT employee_code, Civil_ID, DATEDIFF(Day, Civil_ID, GETDATE())
FROM ODEV_VIEW_Credentials_Expiry_Dates
WHERE Civil_ID IS NOT NULL AND Civil_ID != ''
ORDER BY employee_code

I keep getting the following message:

The conversion of a varchar data type to a datetime data type resulted in an out-of-range value.

Warning: Null value is eliminated by an aggregate or other SET operation.

No matter what filter I use to process non-blank dates, it never works.

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Transact SQL :: Difference Between HOLDLOCK And UPDLOCK In Server

Jul 15, 2015

just see same kind of two sql statement

BEGIN TRAN
SELECT *
FROM authors AU
WITH (HOLDLOCK, ROWLOCK)
WHERE AU.au_id = '274-80-9391'

COMMIT TRAN
BEGIN TRANSELECT *
FROM authors AU
WITH (UPDLOCK, ROWLOCK)
WHERE AU.au_id = '274-80-9391'COMMIT TRAN

i like to know what is the difference between HOLDLOCK and UPDLOCK in sql server. explain with example to better understand.

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Transact SQL :: Pivot Columns Into Rows With Difference

Sep 22, 2015

Here is the table:

empid lastname firstname title titleofcourtesy ModifiedOROriginal

1 Davis1 Sara CEO Ms. Modified
1 Davis Sara CEO Ms. Original

We need an output like this:

empid
1
1

lastname
Davis1
Davis

firstname
Sara
Sara

title
CEO
CEO

titleofcourtesy
Ms.
Ms.

ModifiedOROriginal
Modified
Original

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Transact SQL :: How To Make A Report On Difference Between Rows

Nov 16, 2015

Given a table that has three columns that together create a key and two columns that together define NameValue pairs, how can the difference between instances of values be calculated and displayed?One table is used to contain periodic dumps of data from various sources. Because this is an early stage of development for the software project instead of having explicit columns that contain specific data the table contains name/value pairs. This allows the software to export anything to the database table. When this data is imported, earch row shares the same key (three columns containing a machine type, serial number and a timestamp), a name that identifies the data and a string that contains the actual data. While this arrangement makes it trivial to support the addition of any data that the software developers want to export, it makes it less obvious as to how to generate reports.Let's make an example. Lets assume that there are two vending machines, each of which has just 3 snacks and each of which generates two separate reports.

Type Sn Timestamp Name Value
A 1 2015-08-15 12:34 Snick 5
A 1 2015-08-15 12:34 Mars 10
A 1 2015-08-15 12:34 MandM 0B 2 2015-08-15 15:31 Snick 1
B 2 2015-08-15 15:31 Mars 9
B 2 2015-08-15 15:31 MandM 0A 1 2015-08-21 09:12 Snick 11
A 1 2015-08-21 09:12 Mars 18

[code]...

So, the names of the values become the report's columns. The reports are sorted by timestamp, then by type, then by serial number.The value associated with the previous row that shares the same name is subtracted from the value of the next row in which the same name occurs and that becomes the displayed value in the report.

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Transact SQL :: Date Difference In The Form Of Days And Hours?

May 21, 2015

declare @siva1 datetime;
declare @siva2 datetime;
set @siva1='2014-03-10 05:02:11'
set @siva2='2014-03-12 23:52:11'

i want output like this 2.18 means 2day 18hours difference how using query

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Transact SQL :: How To Get Difference To Two Datatime In Seconds Using Logparser Query

Sep 23, 2015

In sql we have a built in function

DATEDIFF(second, startdate, enddate)

How can we achieve the same using Log parser query for date time in format (2015-09-22 10:25:30.5220)

Example:

startdate = 2015-09-22 10:25:30.5220.
Enddate = 2015-09-22 10:26:30.5220

After DateDiff I need to get 6 seconds.

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Transact SQL :: Huge Performance Difference For Same Select Between Environments

Jun 22, 2015

I have encountered a problem with a specific set of tables. The same select yields slightly differing execution plans in two different environments (instances). But the slight variation seems to contain a huge differences in stats. I don't know the significance of these stats. The two tables have the exact same indices.

This is the selcet statement:

SELECT 'xx' FROM DUKS.dbo.Profiler
WHERE DNA_Løbenummer IN
(SELECT DNA_Løbenummer FROM DUKS.dbo.Effektregister
WHERE Sagsnummer = '2015-00002')

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Transact SQL :: How To Get Date Difference Between 2 Dates In DAYS Excluding Weekends

Oct 14, 2015

Here I have 2 Dates. CreatedDttm & ModifiedDttm.

I want  - DATEDIFF(Day,CreatedDttm,ModifiedDttm)  and I have to exclude the Weekend days from that query result.

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Transact SQL :: Split Rows Based On Time Difference More Than 1day

Aug 5, 2015

equipmentid downtimestartdate downtimeenddate  dowtime
a3er 2015-03-15 02:00 2015-03-17 23:00            69
b6e4 2015-03-18 13:00 2015-03-20 04:00            39

i have many rows(in our production table, thousands of rows are there) like above in a table and i want like below output(in output total 6rows only)

equipmentid downtimestartdate downtimeenddate dowtime
a3er          2015-03-15 02:00 2015-03-15 24:00            22 
a3er          2015-03-16 00:00 2015-03-15 24:00            24
a3er          2015-03-17 00:00 2015-03-15 23:00            23

[code]...

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Transact SQL :: Any Reason For Difference In Order Of Columns Between Index Of Constraint And Its Statistics Definition?

Sep 5, 2015

I am really puzzled by an apparent difference between table index key column order and its statistics order. I was under understanding that index statistics mirror index definition. However, in my db 2470 index ordinal definitions match statistics definition but 66 do not. I also can reproduce such discrepancy in 2008 R2, 2012 and 2014.

As per definition,

stats_column_id
int

1-based ordinal within set of stats columns

This script duplicates this for me.

BEGIN TRAN
GO
use tempdb
GO
CREATE TABLE [dbo].[ItemProperties](
[itmID] [int] NOT NULL,
[cpID] [smallint] NOT NULL,
[ipuID] [tinyint] NOT NULL,

[Code] ....

The result I get is this:

object_id       stats_name                                     
stats_column_list
1525580473 PK_ItemProperties_itmID_ipuID_cpID itmID,  cpID,  ipuID,

and

object_id      index_name                                     
index_column_list
1525580473 PK_ItemProperties_itmID_ipuID_cpID itmID,  ipuID,  cpID,

Also a query I used to discover this in my db is:

WITH stat AS
(
SELECT
s.object_id
,s.name as stats_name
,(
SELECT
c.name + ', ' as [data()]
FROM sys.stats_columns as sc

[Code] .....

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Difference Between Partial Backup (SQL 2005) And File Group Backup

Dec 5, 2006

What is the difference between "Files aned File Groups" backup and Partial Backup?

Looks like both are same.. Please comment.

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Transact SQL :: Flag Yes Or No Within ID Group

May 20, 2015

I have a table with 4 columns,let say ID, WorkId , HireDate ,TerminateDate

My source date

ID   WorkId   HireDate    TerminateDate
1     123    2006-01-05   2013-01-13
1     456    2006-02-23   2013-04-13
1     789    2005-12-12   2013-06-13
2     913    2004-12-15   2012-01-13
2     406    2006-04-13   2014-04-13
3     113    2009-11-15   2011-01-13
3     106    2010-04-13  
4     513    2002-11-15  
4     168    2011-10-23  
5     342    2007-01-05   2009-01-13      
5     416    2008-02-23                   
5     159    2008-12-12   2010-06-13   
6     542    2005-01-03   2007-01-13      

Rule -1:  set flag = yes

-Whenever terminatedate is not null
-Also with in the ID group if one record terminatedate is null then set flag=yes

Rule-2: Set flag=No
- with in the ID group Whenever terminatedate is null

My output should look like this..

ID   WorkId   HireDate    TerminateDate     Flag
1     123    2006-01-05   2013-01-13        yes ( Rule-1: set flag = yes within the group for ID =1 because all the 3 records terminatedate is not null)
1     456    2006-02-23   2013-04-13        yes
1     789    2005-12-12   2013-06-13        yes
 2     913    2004-12-15   2012-01-13       yes (Rule-1: set flag = yes within the group for ID =2 because all the 2 records terminatedate is not null)

[Code] .....

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Transact SQL :: Get Max Occurring Value Using GROUP BY

May 14, 2015

I have 3 columns of data CustomerNum, Newsletter, and NumSent.

I need to return the only the CustomerNumber and Newsletter combinations having the Max(NumSent) So it should be a unique customernumber with the newletter having the most numsent.

For the data below, my result set will be:

0000000000000000101 Healthcare
0000000000000000102 Construction-Environ Svcs

How can I do this easily with GROUP BY , Max or subselect?

Sample Data:
0000000000000000101 Healthcare                       19
0000000000000000101 Construction-Environ Svcs 11
0000000000000000101 Manufacturing                   8               

0000000000000000101 Homecare                        5
0000000000000000101 Daycare                          4
0000000000000000102 Healthcare                       9
0000000000000000102 Construction-Environ Svcs 21
0000000000000000102 Manufacturing                   5              

0000000000000000102 Homecare                        11
0000000000000000102 Daycare                          1

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Transact SQL :: Row Over Partition - How To Group It

Sep 8, 2015

If I have the first two columns from a SQL query and would like to create the third (row):

personid new_commsstream row
1 0 1
1 0 1
1 0 1
1 1 2
1 0 2
2 0 1
3 0 1
4 0 1
5 0 1
5 1 2
5 1 3

Is this possible? I have tried using row over partition but I'm not sure how group it correctly, so basically every time there is a new 1 in new_commsstream within a personid the row number goes up by one.

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Transact SQL :: How To Show Value In Only One Group

Nov 3, 2015

I have a table with "Project", "Demo" and "Value". Here is a sample. Is there a way to show the "Value" in just one Demo after a I use group by?

Project  Demo Value

Project1 Adult 100
Project1 Kids 100
Project1 Adult 100
Project2 Adult 200
Project2 Adult 200
Project2 Kids 200
Project2 Kids 200

That is after I ran the SQL: I will get only: (see Project1's Kids's value is null now.

Project  Demo Value

Project1 Adult 100
Project1 Kids
Project2 Adult 200
Project2 Kids 200

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Transact SQL :: Get Sum From 2 Table By Group

Sep 3, 2015

I have 2 table (Employee T0 & Employee Absense T1), T0 & T1 use Employee Code to connect.

In T0, I have EmployeeCode, Location Code, Shift Code & Hour Rate....,

T1 has EmployeeCode, Date, Quantity ...,

How to write a query to get summary of

T1.[Quantity] * T0.[Hour Rate] as AbsHR group by T0.[Location], T0.[Shift] ?

so the result has [Location], [Shift], [Date], [AbsHR] 4 column.

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Group By Month And Year Transact SQL

Feb 13, 2001

I want to set up stored procedures that let me group data into months. I use the data to produce charts so I need to be able to group into month and year like '01, 2000', '02, 2000'. What is the best way to produce data grouped into month and year from a date field? Using the Month and Year functions I get data like 1,2000 and 11,2000 which don't stand up to a text sort.

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Transact-SQL Help - CASE Statement And Group By

Jul 20, 2005

I've always been mistified why you can't use a column alias in the group byclause (i.e. you have to re-iterate the entire expression in the group byclause after having already done it once in the select statement). I'mmostly a SQL hobbiest, so it's possible that I am not doing this in the mostefficient manner. Anyone care to comment on this with relation to thefollowing example (is there a way to acheive this without re-stating theentire CASE statement again in the Group By clause?):Select 'Age' =CaseWHEN(SubmittedOn >= DATEADD(dd, - 30, GETDATE())) AND (SubmittedOn <=DATEADD(dd, - 0, GETDATE()))THEN '0-30 Days Old'WHEN(SubmittedOn >= DATEADD(dd, - 60, GETDATE())) AND (SubmittedOn <=DATEADD(dd, - 31, GETDATE())) Then '31-60 Days Old'WHEN(SubmittedOn >= DATEADD(dd, - 90, GETDATE())) AND (SubmittedOn <=DATEADD(dd, - 61, GETDATE())) Then '61-90 Days Old'WHEN(SubmittedOn <= DATEADD(dd, - 91, GETDATE())) THEN '91+ Days Old'ELSE cast(SubmittedOn as varchar(22))end,max(SubmittedOn), COUNT(SCRID) AS NbrSCRsFrom SCRViewWHERE(StatusSort < 90) ANDCustomerID = 8 andUserID = 133group byCaseWHEN(SubmittedOn >= DATEADD(dd, - 30, GETDATE())) AND (SubmittedOn <=DATEADD(dd, - 0, GETDATE()))THEN '0-30 Days Old'WHEN(SubmittedOn >= DATEADD(dd, - 60, GETDATE())) AND (SubmittedOn <=DATEADD(dd, - 31, GETDATE())) Then '31-60 Days Old'WHEN(SubmittedOn >= DATEADD(dd, - 90, GETDATE())) AND (SubmittedOn <=DATEADD(dd, - 61, GETDATE())) Then '61-90 Days Old'WHEN(SubmittedOn <= DATEADD(dd, - 91, GETDATE())) THEN '91+ Days Old'ELSE cast(SubmittedOn as varchar(22))endOrder by max(submittedon) descThanks,Chad

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Transact SQL :: Way To Keep Duplicates Without Removing Group By

May 6, 2015

I'm trying to pull records from a source/staging table where there is a duplicate row in it.I don't need that as the requirement is to garbage in /garbage out.when I do that from mart and use joins btw fact and dimensions, Im not getting this duplicate record as Im using distinct/group by. If I removed it, then it returns more than 3000 rows which is not correct. Is there a way I can keep these duplicates without removing group by...Im using correct joins and filters.

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Transact SQL :: Group By With Non-aggregate Columns

Aug 5, 2015

How can I aggregate this result into 1 row? (I got it from a UNION ALL)

Article         Assort1    Assort2
50095811    K1             NULL
50095811    NULL          K3

I would like to have

Article         Assort1    Assort2
50095811    K1             K3

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Transact SQL :: Show Particular Records Within Same Group?

Aug 13, 2015

I have a table with 5 columns, let say ID,PersionID, Date, Type,Qty  and source data looks like this

ID   PersonID    Date            Type       Qty  

1      1        01/01/2011       Accept      5          
2      1        01/01/2011       Accept      5  
3      2        02/01/2010       Accept      10             
4      2        02/01/2010       Deny        20  
5      3        02/01/2012       Accept      15

[Code] .....

Output should look like this..look for only Type=Accept until deny is reached. After Deny,if there is a Accept ignore it.

ID  PersonID    Date            Type         Qty
1    1        01/01/2011       Accept        5      (show only one Accept row=1 becoz Type is Accept and date is same,Qtyis
same)
3    2        02/01/2010       Accept        10     (show Accept row=3,ignore deny row)

5    3        02/01/2012       Accept        15     (show Accept row=5)

6    4        05/05/2012       Accept        25     (show Accept rows=6,7 and ignore Deny & Accept rows = 8,9)

7    4        07/08/2012       Accept        20
        
11   6        01/01/2011       Accept        5      (show Accept rows=11,12 because Qty is different)  

12   6        01/01/2011       Accept        15

Create Sample Table (ID int null, PersonID Int null, Date Datetime null , Type varchar(10) null, Qty int null)

Insert into sample values (1 ,1,'01/01/2011','Accept',5),

(2,1,'01/01/2011','Accept',5),  
(3,2,'02/01/2010','Accept',10),             
(4,2,'02/01/2010','Deny',20),  
(5,3,'02/01/2012','Accept',15),  
(6,4,'05/05/2012','Accept',25),  
(7,4,'07/08/2012','Accept',20), 
(8,4,'07/08/2012','Deny',5),
(9,4,'09/23/2012','Accept',23),
(10,5,'09/08/2012','Deny',12),
(11,6,'01/01/2011','Accept',5),          
(12,6,'01/01/2011','Accept',15)

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