declare @siva1 datetime;
declare @siva2 datetime;
set @siva1='2014-03-10 05:02:11'
set @siva2='2014-03-12 23:52:11'
i want output like this 2.18 means 2day 18hours difference how using query
I'm trying to calculate the time difference between a date field and today's date in days. The date field is not mandatory and can therefore be blank. I'm trying to execute the following query:
SELECT employee_code, Civil_ID, DATEDIFF(Day, Civil_ID, GETDATE())
FROM ODEV_VIEW_Credentials_Expiry_Dates
WHERE Civil_ID IS NOT NULL AND Civil_ID != ''
ORDER BY employee_code
I keep getting the following message:
The conversion of a varchar data type to a datetime data type resulted in an out-of-range value.
Warning: Null value is eliminated by an aggregate or other SET operation.
No matter what filter I use to process non-blank dates, it never works.
Here I have 2 Dates. CreatedDttm & ModifiedDttm.
I want - DATEDIFF(Day,CreatedDttm,ModifiedDttm) and I have to exclude the Weekend days from that query result.
I want to display Days Hours Mins Format.
I am Having two columns Like below,
Col1 (in days) col2 (In Hours : Mins)
3days 4:5
In this first have to add Col1 and Col2 (Here one day is equals to 9 hours ) so the addition is 31.5
From this 31.5 I should display 3 Days 4 Hours 30 Mins because 31.5 contains 3 (9 hours) days 4 Hours and .5 is equals to 30 mins.
I have written a function that returns the number of Days, Hours and minutes from a given number of minutes. On testinf the results are close but not quite there. Can anyone see where I have gone wrong or is there an easier way of doing this? Code is as follows:
CREATE FUNCTION dbo.GetTimeBetweenLong
(@StartTime DateTime, @EndTime DateTime, @CurrentDate DateTime)
RETURNS VarChar(50) AS
BEGIN
DECLARE @TotalTime Numeric
DECLARE @Minutes Numeric
DECLARE @Hours Numeric
DECLARE @Days Numeric
DECLARE @MinutesInDays Numeric
IF @EndTime IS NULL
BEGIN
SET @Days = DATEDIFF(Day, @StartTime, @CurrentDate)
SET @Hours = DATEDIFF(Hour, @StartTime, @CurrentDate) - (@Days * 24)
SET @Minutes = DATEDIFF(Minute, @StartTime, @CurrentDate) - ((@Days * 24)*60) - (@Hours * 60)
END
ELSE
BEGIN
SET @Days = DATEDIFF(Day, @StartTime, @EndTime)
SET @Hours = DATEDIFF(Hour, @StartTime, @EndTime) - (@Days * 24)
SET @Minutes = DATEDIFF(Minute, @StartTime, @EndTime) - ((@Days * 24)*60) - (@Hours * 60)
END
IF(@Days <0)
BEGIN
SET @Days = @Days - @Days - @Days
END
IF (@Hours < 0)
BEGIN
SET @Hours = @Hours - @Hours - @Hours
END
IF (@Minutes <0)
BEGIN
SET @Minutes = @Minutes - @Minutes - @Minutes
END
RETURN CONVERT(nVarChar(10),@Days) + ' Days, ' + CONVERT(nVarChar(5), @Hours) + ' Hours, ' + CONVERT(nVarCHar(5), @Minutes) + ' Mins'
END
I get a column in hours in a table and when I try to convert it to months and days its giving me incorrect results.
My timehours column in my table has hours recorded timehours value is 5832 and I get results as 11 months and 27 days.
This query is giving me wrong result -select months=(timehours %365)/30,days= (timehours % 365)%30
I have hours which can be like 32.5 and would like to have them in 1 month 2 Days format.
View 2 Replies View RelatedCurrently my script is using the below mentioned query to find the time difference.
DATEDIFF(HH,DATEADD(SS,hcreacion,fcreacion) ,DATEADD(SS,hcerrar,fcreacion))
If there is 1 hr 30 minutes time difference, I am getting 2 hours as output. But we need 1.30 as output. is there any way to achieve this?
Hi All,
I want to get the date Difference with Day,hours,minutes,seconds of the given 2 dates.(Say the difference of
12/6/2007 7:00:00 AM, 12/8/2007 8:00:00 AM as 2 days 1:00:00)
Is there any inbuilt function in SSRS is available to implement this. Or any other way to do this.Please help me with this .Thanks in advance.
With Thanks
M.Mahendra
Suppose I have these two days fields
ddold 1/1/2005 12:00:00 AM
ddnew 2/1/2007 12:00:00 AM
How can i get the DateDifference of these two dates in days.
I am using oracle 10G DB as back end.I have two date fields in a table.
1)premium_paying_start_date
2)premium_paying_end_date
i have to get the premium_term i.e, the difference between the two dates(premium_paying_end_date-premium_paying_start_date).
The difference should show the year,month and no of days difference.
For example :
premium_paying_start_date : 14-10-1984
premium_paying_end_date : 01-03-2008
Difference should be : 23 Y : 4 M : 15 D (Y = years, M = months , D= days)
So please give me the solution for this.
i have written a sql function which returns only number of working days (excludes holidays and Weekends) between given StartDate and EndDate.
USE [XXX]
GO
/****** Object: UserDefinedFunction [dbo].[CalculateNumberOFWorkDays] Script Date: 10/28/2015 10:20:25 AM ******/
SET ANSI_NULLS ON
GO
[code]...
I need a function or stored procedure which will return the date which is 15 working days (should exclude holidays and Weekends) prior to the given future Date? the future date should be passed as a parameter to this function or stored procedure to return the date. Example scenario: If i give date as 12/01/2015, my function or stored procedure should return the date which is 15 working days (should exclude holidays and Weekends) prior to the given date i.e 12/01/2015...In my application i have a table tblMasHolidayList where all the 2015 year holidays dates and info are stored.
A vehicle loading confirm after that what time its gated out so i want to take the time duration between finish loading and gate out, find sample table records , i want to take more than 5 hrs difference between finish loading and gate out.
tld_tripno
tld_sno
tld_activitycode
tld_location
tld_actualdate
TLM3004242015
[Code] .....
I want to take the result like this
Tld_tripno
Finish Loading
Gate Out
Date and Time difference
TLM3004242015
2015-05-11 19:58:00
2015-05-12 08:42:00
12:44:00
I have an SQL code below which removes weekends and non working days when calculating days difference between two dates:
ce.enquiry_time represents when the enquiry was logged
(DATEDIFF(dd, ce.enquiry_time, getdate()) + 1)
-(DATEDIFF(wk, ce.enquiry_time, getdate()) * 2)
-(CASE WHEN DATENAME(dw, ce.enquiry_time) = 'Sunday' THEN 1 ELSE 0 END)
-(CASE WHEN DATENAME(dw, getdate()) = 'Saturday' THEN 1 ELSE 0 END)
-(SELECT COUNT(*) FROM nonworking_day WHERE nonworking_day.nonworking_date >= ce.enquiry_time AND nonworking_day.nonworking_date < dateadd(dd,datediff(dd,0,getdate()),1))
It works but I don't understand how it works it out. I am having issues understanding each coloured piece of code and how it works together.
I have a column which stores a set of dates. I want to tell how many days left of a date till it’s month end. It should be noted that month ends are taken from the date series, not a calendar month end.
Something like below,
DateTD Days left
2009-01-05 14
2009-01-06 13
2009-01-07 12
2009-01-08 11
2009-01-09 10
2009-01-12 9
2009-01-13 8
2009-01-14 7
2009-01-15 6
2009-01-16 5
2009-01-19 4
2009-01-20 3
2009-01-21 2
2009-01-22 1
2009-01-23 0
2009-02-02 /
2009-02-03 /
I require outputting the date difference between two date's if it is greater than 7(DateDiff(day, DateAdd(day, t.[Started], Nxt.started), (t.[started])) > 7).I get incorrect syntax on my operator.What is the correct code?
View 6 Replies View RelatedI need to run a select on Mondays to pull data for 7 days prior to the Thursday of last week; i.e. Friday - Thursday inclusive. I'm sure this is simple, but I work with dates so infrequently that I need a refressher.
View 7 Replies View RelatedI have a calendar table against entire year 2015 with each day with 2 flag,
1. WK_DT_IN == except Satarday and Sunday, value is "Y", for Sat/Sun, value is "N"
2. HOL_DT_IN == value will only be "Y" only for holiday, example for '2015-01-01' date, it's value is "Y"
DECLARE @CAL TABLE (CAL_DT DATE, WK_DT_IN CHAR(1), HOL_DT_IN CHAR(1))
INSERT INTO @CAL VALUES ('2015-01-01', 'Y', 'Y'), ('2015-01-02', 'Y', 'N'),('2015-01-03', 'N', 'N'),
('2015-01-04', 'N', 'N'), ('2015-01-05', 'Y', 'N'), ('2015-01-06', 'Y', 'N'), ('2015-01-07', 'Y', 'N')
We have a given date, example '2015-01-01', I need to find out a date after 2 business days? I can think of loop, but will it work.
I need to exclude date which having HOL_DT_IN = "Y" and WK_DT_IN = "N".
I want a difference in days
Select datediff(dd,Target_Date,Achv_Date)
Now , checks are
1] when target date greater than achv_Date the difference should be greater than 0
means for FileID 77608
Select datediff(dd,'2015-09-24 00:00:00.000','2015-09-24 10:42:32.823')
i am getting -6 it should be 6 cant switch Target_Date and Achv_Date in datediff else i will get opposite result in first four records basically, i want a two column TAT and Status beside achv_date based on the values of two dates difference see above ..and also want a result of (No. of Yes in status / No. of Files that has achv_date )i.e. result= (7/8) = 87%
I have a dynamic sql query where in I am comparing two tables and loading data for last 15 days. e.g today 2050921 then I am going to load till 20150906.
I pass on 2 variables @currentdate and @currentdate-1 to the query which are in date format 'yyyymmdd'
I need to do this for last 15 days how do I do this using while loop.
Note my date format is YYYYMMDD.
DECLARE @SQL VARCHAR(MAX)
@sql = ' insert into target
select from table_1_currentdate a
LEFT JOIN Table_2_currentdate-1 b
on a.col1=b.col1 where b.col1 is null '
exec(@sql)
I have to use while loop and decrement it every time and load data for last 15 days comparing two tables. I tried so many times I am not getting it right .
I created a dbo.Calendar table that stores dates and a work day flag (1=work day, 0=non-work day) so I can use it to calculate the next business date from a date using a function. I'm using a while group to count only the work days and a couple other internal variables but I'm not sure if I can even use them in a function.
Assuming Sats & Suns are all non-work days in April 2014, if my @WorkDays = 10 for 10 work days and my @DateFromValue - 4/1/2014, I would expect my return date to be 4/15/2014.
------ Messages after I click execute on my query window that has my function ------------------------------------------------------
Msg 444, Level 16, State 2, Procedure FGetWorkDate, Line 19
Select statements included within a function cannot return data to a client.
Msg 207, Level 16, State 1, Procedure FGetWorkDate, Line 20
Invalid column name 'WorkDay'.
Msg 207, Level 16, State 1, Procedure FGetWorkDate, Line 22
Invalid column name 'Date'.
------ my function code ----------------------------
CREATE FUNCTION [dbo].[FGetWorkDate](
@WorkDays VARCHAR(5),
@DateFromValue AS DateTime )
RETURNS DATETIME
[Code] ....
HiI have a Platinum database which stores dates in integer form e.g the dateis formatted as below:Column_name Type Length Precision------------------------------ ------------------------------from_date int 4 10Some of the dates in the Platinum database are as follows:729115729359730059730241730302730455How can I bring them into SQL 2000 as valid dates.Thanks for your assistanceSam CJoin Bytes!
View 1 Replies View RelatedThis code displays records by the the month they where recorded and displays the months as names (January...)
How can I do the Same for Days (Mon, Tues) and Hours (9.00,10.00)
Select DATENAME(mm,dDate) as Month, count(iStatID) as Total_Po
from ListingStats
Group by DATENAME(mm,dDate)
Order by DATENAME(mm,dDate)
I have two field and I need to find the sum I guess of them. One is called the clm_dout (process date) and the other one is clm_rcvd (received Date). These are both date and time fields and it looks like this 2006-03-17 00:00:00.000. I need to create a formula that wiil i guess give me the difference and create it into hour and minutes because I an trying to create a turn around report. this is what I had...
TimeValue({clm_doubt}-{clm_rcvd})
This is not working for me. Can someone give me a suggestion please.
Thanks!
Hi Guys,
I have data in minutes which is integer value ex 14454.I wanto convert it to days,hours,minutes & seconds.
Is there any simple way?
Regards.
I have to calculate the total working hours between days, there hours must get automatically round off to nearest value example:
Date :12-05-2013 time : 4:15 will change to 4.00 and if Date :13-05-2013 time: 4:25 then needs to 4.30 and sum the above total hours and results Total : 8.30 hrs.
How can I change the output into the total hours between 2 smalldatetime data? TIF
DECLARE @iDAY AS SmallDatetime
SET @iDAY = '2004-08-12 10:05:00'
PRINT @iDAY
PRINT GETDATE()
PRINT GETDATE()-@iDAY
+++++++++++++++
Aug 12 2004 10:05AM
Aug 13 2004 10:05AM
Jan 2 1900 12:00AM <--- I want to get the total hours (i.e. 24)
I have two nvarchar fields with time data 12:34:34 and the second one 12:34 I want to calculate the difference in Hours. The first field is called (OTIM) the second field is called (ReportedTime) if the name matters. I tried substring to trim the OTIM, I am unable to make it work.
View 3 Replies View RelatedHi! I am totally new to the forum and to the SQL.
Need your advice. My report will run on Friday automatically and I need to retrieve the data from previous Friday until Today’s Friday.
I have an example from another developer’s code, but this one gets the data on the previous day. Can you please help me to right the expression?
Here is an example ‘on the previous day’
CAST(CONVERT(CHAR(10), tbl1.closeddate,120) as datetime) = CAST(CONVERT(CHAR(10), dateadd(day, -1,getdate()), 120) as datetime)
This is what I did (assuming today is Friday)
(tbl1.closedDate BETWEEN CAST(CONVERT(CHAR(10), DATEADD(day, - 8, GETDATE()), 120) AS datetime) AND CAST(CONVERT(CHAR(10),
DATEADD(day, - 1, GETDATE()), 120) AS datetime))
I don't get any records back.
Please help.
Thanks a lot.
i have a table
a1
-----
id t1
How can I calculate the difference between getdate() and t1 how many days.
I have a table of sample data
Samples(sample_no, sample_date..)
I have no idea how to do the following in sql server or if its even possible:
1. Calculate the difference in days between all samples.
2. Select the median result
Any trick to get this done would be really helpful
thanks,
DB
I have a table of sample data
Samples(sample_no, sample_date..)
I have no idea how to do the following in sql server or if its even possible:
1. Calculate the difference in days between all samples.
2. Select the median result
Any trick to get this done would be really helpful
thanks,
DB
I am trying to write a query to calculate the running difference between data on different dates. Below is what my table of data looks like. Basically I want to calculate the difference between the total_completed for each state and date.
DateStatesTotal_Completed
08/27/15CA 19,952
09/11/15CA 26,336
10/02/15CA 35,444
10/08/15CA 38,278
08/27/15CO2797
09/11/15CO3264
10/02/15CO4270
10/08/15CO4297
below is what I am trying to achieve:
DateStatesTotal_CompletedCompleted_Difference
08/27/15CA 19,952 0
09/11/15CA 26,336 6,384
10/02/15CA 35,444 9,108
10/08/15CA 38,278 2,834
08/27/15CO27970
09/11/15CO3264467
10/02/15CO42701,006
10/08/15CO429727
below is my code (I almost have what I need) I just can't figure out how show 0 as the completed_difference for the first Date for each state since there is no prior date to calculate against.
MRR_TOTALS_WEEK_OVER_WEEK AS
(
SELECT
T1.[Date]
,T1.States
,T2.Total_Completed
,ROW_NUMBER() OVER(PARTITION BY T1.States ORDER BY T1.States,T1.[Date]) AS ORDERING
FROM TOTAL_CHARTS T1
LEFT JOIN TOTAL_COMPLETED T2 ON T1.[Date] = T2.[Date] AND T1.States = T2.States
)
[code].....