Transact SQL :: Error - The Datediff Function Resulted In Overflow
Sep 12, 2015
When running a query such as this on a database view:
select count(*) from WWALMDB.dbo.v_AlarmEventHistory2
SQL throws the following error:
The datediff function resulted in an overflow. The number of dateparts separating two date/time instances is too large. Try to use datediff with a less precise datepart.
Oddly on a Table the count(*) function works.
Is there a limit on views or the count(*) function that I am not aware of?
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Oct 20, 2007
We've been using SQL Server 2005 for a while as the db for our web app. Everything has been working fine, until yesterday when we started getting a "Arithmetic operation resulted in an overflow. (System.Data)" error message when trying to connect from SQL Server Management Studio or from our web app. This only happens when trying to connect remotely, although remote connections have worked for us perfectly in the past. The full error message is reproduced below. Thanks ahead of time for any help. ===================================Cannot connect to serverName===================================Arithmetic operation resulted in an overflow. (System.Data)------------------------------Program Location: at System.Data.SqlClient.TdsParser.ConsumePreLoginHandshake(Boolean encrypt, Boolean trustServerCert, Boolean& marsCapable) at System.Data.SqlClient.TdsParser.Connect(ServerInfo serverInfo, SqlInternalConnectionTds connHandler, Boolean ignoreSniOpenTimeout, Int64 timerExpire, Boolean encrypt, Boolean trustServerCert, Boolean integratedSecurity, SqlConnection owningObject) at System.Data.SqlClient.SqlInternalConnectionTds.AttemptOneLogin(ServerInfo serverInfo, String newPassword, Boolean ignoreSniOpenTimeout, Int64 timerExpire, SqlConnection owningObject) at System.Data.SqlClient.SqlInternalConnectionTds.LoginNoFailover(String host, String newPassword, Boolean redirectedUserInstance, SqlConnection owningObject, SqlConnectionString connectionOptions, Int64 timerStart) at System.Data.SqlClient.SqlInternalConnectionTds.OpenLoginEnlist(SqlConnection owningObject, SqlConnectionString connectionOptions, String newPassword, Boolean redirectedUserInstance) at System.Data.SqlClient.SqlInternalConnectionTds..ctor(DbConnectionPoolIdentity identity, SqlConnectionString connectionOptions, Object providerInfo, String newPassword, SqlConnection owningObject, Boolean redirectedUserInstance) at System.Data.SqlClient.SqlConnectionFactory.CreateConnection(DbConnectionOptions options, Object poolGroupProviderInfo, DbConnectionPool pool, DbConnection owningConnection) at System.Data.ProviderBase.DbConnectionFactory.CreateNonPooledConnection(DbConnection owningConnection, DbConnectionPoolGroup poolGroup) at System.Data.ProviderBase.DbConnectionFactory.GetConnection(DbConnection owningConnection) at System.Data.ProviderBase.DbConnectionClosed.OpenConnection(DbConnection outerConnection, DbConnectionFactory connectionFactory) at System.Data.SqlClient.SqlConnection.Open() at Microsoft.SqlServer.Management.UI.VSIntegration.ObjectExplorer.ObjectExplorer.ValidateConnection(UIConnectionInfo ci, IServerType server) at Microsoft.SqlServer.Management.UI.ConnectionDlg.Connector.ConnectionThreadUser()
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Feb 20, 2008
my date_Join is 8char as it is datetime in microsoft sql. cant change to more.
when i type the date 2007-12-12. it says Arithmetic operation resulted in an overflow.
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Oct 16, 2013
this query is running fine in 2008 , but its not working in 2005 below is the error Msg 8115, Level 16, State 2, Line 1 Arithmetic overflow error converting expression to data type int.there is some problem in converting date in cte
with a
as
(
SELECT dbname = DB_NAME(database_id) ,
[DBSize] = CAST( ((SUM(ms.size)* 8) / 1024.0) AS DECIMAL(18,2) )
,
COALESCE(CONVERT(VARCHAR(12), MAX(bus.backup_finish_date), 101),'01/01/1900') AS LastBackUpTime
FROM sys.master_files ms
inner join msdb.dbo.backupset bus ON bus.database_name = DB_NAME()
[code]....
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Nov 23, 2006
Hi, I am facing problem rite now.. I want to calculate the date different minutes between 23:00:00 and 01:00:00.
My code :
datediff(Minute,'01:00:00','23:00:00')
The result is 1320 minutes. (22 hours)... But, the result that I want is 120 minutes (2 hours)....
Can anybody help ???
Thanks in advance...
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Nov 12, 2007
Hi,I'm using the datediff function to display the ages of the users in my database. However the age rounds up once they are 35.5 etc...I could create another function which works similar to the DateDiff function, but use math.floor to always round down, but I need to use this function in a SQL statement WHERE clause. Is there any way around this?Thanks,Curt.
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Apr 25, 2007
hi
select datediff(m,'3/5/2003',getdate as experience
output is
Experience
----------
49
select (datediff(m,'3/5/2003',getdate()))/12 as experience
output is
Experience
----------
4
but 49/12 is 4.08333=4.1
how i can get this
Actually my task is to output as years.months
Thanks in advance
Malathi Rao
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Oct 5, 2006
I am trying to break up the age into column from a dob field for a cross tab report. I can query the datediff with an alias but can not individually change the columns I need like a virtual or temp column, but can't figure out how to accomplish it.
use 'Database'
Select datediff(Year, dob, getdate()) As "Under 22", datediff(Year, dob, getdate()) As "22-45",
datediff(Year, dob, getdate()) As "46-65", datediff(Year, dob, getdate()) As "Over 65"
from 'Table'
WHERE (DATEDIFF(yy, dob, GETDATE()) < 22 OR
DATEDIFF(yy, dob, GETDATE()) BETWEEN 22 AND 45 OR
DATEDIFF(yy, dob, GETDATE()) BETWEEN 46 AND 65 OR
DATEDIFF(yy, dob, GETDATE()) > 66) AND (status = 'Current' OR
status = 'Previous' OR
status = 'non-billable')
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Feb 7, 2007
This will give you the time information about how apart two dates are.CREATE FUNCTION dbo.fnTimeApart
(
@FromTime DATETIME,
@ToTime DATETIME
)
RETURNS @Time TABLE ([year] SMALLINT, [month] TINYINT, [day] TINYINT, [hour] TINYINT, [minute] TINYINT, [second] TINYINT, [millisecond] SMALLINT)
AS
BEGIN
DECLARE@Temp DATETIME,
@Mts INT,
@year SMALLINT,
@month TINYINT,
@day TINYINT,
@hour TINYINT,
@minute TINYINT,
@second TINYINT,
@millisecond SMALLINT
IF @FromTime > @ToTime
SELECT@Temp = @FromTime,
@FromTime = @ToTime,
@ToTime = @Temp
SET@Mts =CASE
WHEN DATEPART(day, @FromTime) <= DATEPART(day, @ToTime) THEN 0
ELSE -1
END + DATEDIFF(month, @FromTime, @ToTime)
SELECT@year = @Mts / 12,
@month = @Mts % 12,
@Temp = DATEADD(month, @Mts, @FromTime)
SELECT@day = datediff(hour, @Temp, @ToTime) / 24,
@Temp = DATEADD(day, @day, @Temp)
SELECT@hour = DATEDIFF(minute, @Temp, @ToTime) / 60,
@Temp = DATEADD(hour, @hour, @Temp)
SELECT@minute = DATEDIFF(second, @Temp, @ToTime) / 60,
@Temp = DATEADD(minute, @minute, @Temp)
SELECT@second = DATEDIFF(millisecond, @Temp, @ToTime) / 1000,
@Temp = DATEADD(second, @second, @Temp),
@millisecond = DATEDIFF(millisecond, @Temp, @ToTime)
INSERT@Time (year, month, day, hour, minute, second, millisecond)
SELECT@year,
@month,
@day,
@hour,
@minute,
@second,
@millisecond
RETURN
ENDAnd to test the functionSELECTd.FromDate,
d.ToDate,
x.*
FROM(
SELECT'19690906' AS FromDate, '19760608' AS ToDate UNION ALL
SELECT'19991231', '20000101' UNION ALL
SELECT'20070207', '20070208' UNION ALL
SELECT'20000131', '20000228' UNION ALL
SELECT'20070202', '20070201' UNION ALL
SELECT'20070207', '20070307' UNION ALL
SELECT'20000131', '20000301' UNION ALL
SELECT'20011231 15:24:13.080', '20020101 17:15:56.343' UNION ALL
SELECT'20011231 17:15:56.343', '20020101 15:24:13.080' UNION ALL
SELECT'20020101 15:24:13.080', '20011231 17:15:56.343' UNION ALL
SELECT'20000131', '20000229'
) AS d
CROSS APPLYdbo.fnTimeApart(d.FromDate, d.ToDate) AS x
ORDER BYd.FromDate,
d.ToDateAnd the output isFromDateToDateyearmonthdayhourminutesecondmillisecond
19690906197606086920000
19991231200001010010000
200001312000022800280000
200001312000022900290000
20000131200003010110000
20011231 15:24:13.08020020101 17:15:56.34300115143263
20011231 17:15:56.34320020101 15:24:13.08000022816736
20020101 15:24:13.08020011231 17:15:56.34300022816736
20070202200702010010000
20070207200702080010000
20070207200703070100000
Peter Larsson
Helsingborg, Sweden
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Feb 9, 2007
I have two date columns one is sent_date and other is approved_date
my requirment is to find the difference between the two dates
which can be minutes/hrs/days.
using datediff function iam able to get it in minusts or hrs but my
output should be of the format hh:mm
23:10 (ie 23 hrs and 10 min) or say
48:00 (for 2 days)
sample date
sent_date approved_date
2/28/06 11:06 2/28/06 11:39
2/2/06 17:42 2/2/06 18:03
2/8/06 16:55 2/8/06 17:38
1/27/06 17:00 1/27/06 17:54
1/26/06 12:08 1/26/06 12:09
2/28/06 15:46 2/28/06 16:26
1/23/06 10:01 1/23/06 10:43
1/26/06 13:46 1/26/06 13:59
1/13/06 13:51 1/13/06 14:47
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Nov 2, 2007
recently i created a system using php and mysql to record faults that the ict technicians could get reported faults out of. so far it does everything i want but some senior members of staff now want the front end to give a report of status, one of the things they wish to see is how many jobs have been completed this week month and year
within my tables is a field date. naturally it has the date submited contained within it. the code i have been using to try and get an output is
mysql_query("SELECT date, datediff('day', date, CURRENTDATE) FROM softwarerepairtable WHERE datediff<= '7' and complete='yes' ");
the complete feild is another contained within the datebase. i have also tried SELECT * datediff('day', date, CURRENTDATE) FROM softwarerepairtable WHERE datediff<= '7' and complete='yes' ");
unfortunatly my limited knowledge of php and sql is holding me back on this. any help guys would be appriacted
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May 18, 2007
Hi,
I am trying to use DataDiff function and I have used the following queries:
1.
select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.320') as test
Expected Result: 0 milliseconds
Actual Result: 0 milliseconds
2.
select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.321') as test
Expected Result: 1 milliseconds
Actual Result: 0 milliseconds
3.
select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.322') as test
Expected Result: 2 milliseconds
Actual Result: 3 milliseconds
4.
select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.323') as test
Expected Result: 3 milliseconds
Actual Result: 3 milliseconds
5.
select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.324') as test
Expected Result: 4 milliseconds
Actual Result: 3 milliseconds
6.
select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.325') as test
Expected Result: 5 milliseconds
Actual Result: 6 milliseconds
7.
select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.326') as test
Expected Result: 6 milliseconds
Actual Result: 6 milliseconds
8.
select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.327') as test
Expected Result: 7 milliseconds
Actual Result: 6 milliseconds
9.
select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.328') as test
Expected Result: 8 milliseconds
Actual Result: 6 milliseconds
10.
select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.329') as test
Expected Result: 9 milliseconds
Actual Result: 10 milliseconds
Does any one know, why datediff does not return the Expected Result? There does not seem to be any consistency.
Thanks,
Tim
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Jan 25, 2008
I want to create and expression that basically says if a datetime value is today minus 2 days then do another formula.
Right now it looks like this...
Code Snippet
=iif(Fields!Channel_Id.Value="SFE1" and Fields!Report_Date.Value=Today-2,0,(Fields!Total_Apps.Value-Fields!total_apps_null_status.Value))
Basically, it spits an error saying [BC30452] Operator '-' is not defined for types 'Date' and 'Integer'.
Should this be done with DateDiff? if so, how can you specify two days ago?
Thanks much
C-
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Feb 3, 2015
I'm trying to use the DateDiff function within my select statement, but I'd like to add the parameter of greater than 30 days. This will have the query only return records where my bill stop date is greater than 30 days from the completion date. I currently have the datediff function within my select statement as
DATEDIFF (d,A.StopBillDate, a.CompletionDate) as [DIFFERENCE]
I would prefer to keep the datediff function within the select statement so as to have difference in days appear as a column within my output.I have been unable to add the parameter of > 30 days to the query without getting an error.
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Apr 9, 2007
Hi Experts,I am working on SSRS 2005, and I am facing a problem in counting theno of days.My database has many fields but here I am using only two fieldsThey are Placement_Date and Discharge_DateIf child is not descharged then Discharge_Date field is empty.I am writing below query to count the number of days but is is notworking it is showing the error"The conversion of a char data type to a datetime data type resultedin an out-of-range datetime value."select casewhen convert(datetime,Discharge_Date,103) = '' thendatediff(day,CONVERT(datetime,Placement_Date,103), GETDATE())elsedatediff(day,CONVERT(datetime,Placement_Date,103),CONVERT(datetime,Discharge_Date,103))end NoOfDaysfrom Placement_DetailsSo please tell me where I am wrong?Any help will be appriciated.RegardsDinesh
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Oct 9, 2015
I have a work database where I implemented a table-valued function. One colleague of mine reported to me that this function gave a Divide by Zero error when executed with some specific values given to its arguments (there are a 15 arguments). Then I started debugging, and I introduced some exit points to the function before its end in order to detect the point where the error appeared, since I don't have access to the database server and I cannot use the debugging tools from remote, due to the network configuration of my office. I can only do attempts on the code to try to find a solution.
Since I didn't manage to get rid of this error, I decided to make a silly and desperate attempt: I put a RETURN statement immediately after the BEGIN of the function body, with the idea that the function should not raie any error if it exit immediately after its beginning, despite the fact that this results in an empty table in return.
The result of my attempt is that the Divide by Zero error is still THERE (!), even if my function looks like
ALTER FUNCTION [dbo][<myFuncName>](...parameters...) RETURNS TABLE (...table definition...) AS BEGIN
RETURN
END
GO
How I can check it.
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May 15, 2007
Hi
I regularly use the T-SQL date functions to return the 1st of a particualr month.
e.g.
SELECT DATEADD(m,DATEDIFF(m,0,getdate()),0)
returns 2007-05-01 00:00:00.000
i.e the first of the current month at midnight.
However, when I try to use a similar expression as a derived column in SSIS it returns a completely different date.
DATEADD("month",DATEDIFF("month",(DT_DATE)0,GETDATE()),(DT_DATE)0)
returns 30/05/2007 00:00:00
Any ideas why and how I can obtain the first of a particualr month using SSIS derived column?
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Sep 4, 2015
What is a more efficient way of doing the following such that DATEDIFF() does not have to calculated numerous times?
CASE
WHEN DATEDIFF(DD, @Today, COALESCE(POS.[PurchaseDate], POS.[FinalizedDate])) <= 0 THEN '<= 0D'
WHEN DATEDIFF(DD, @Today, COALESCE(POS.[PurchaseDate], POS.[FinalizedDate])) > 0 AND DATEDIFF(DD, @Today, COALESCE(POS.[PurchaseDate], POS.[FinalizedDate])) <= 7 THEN '> 0D AND <= 7D'
WHEN DATEDIFF(DD, @Today, COALESCE(POS.[PurchaseDate], POS.[FinalizedDate])) > 7 AND DATEDIFF(DD, @Today, COALESCE(POS.[PurchaseDate], POS.[FinalizedDate])) <= 30 THEN '> 7D AND <= 30D'
[code]....
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May 13, 2015
I have a few tables I am trying to join to create a report. Everything was working fine until I tried to add an aggregate Sum function to a column (MaxCap) in table ctfBarn.
select
x.*, y.division, y.department, y.location
,(right(z.SvcMgrName,len(z.SvcMgrName)-len(left(z.SvcMgrName,CHARINDEX(', ',z.SvcMgrName)-1))-2)+' '+
left(z.SvcMgrName,CHARINDEX(', ',z.SvcMgrName)-1))AS SvcMgrName
,(right(z.SrSvcName,len(z.SrSvcName)-len(left(z.SrSvcName,CHARINDEX(', ',z.SrSvcName)-1))-2)+' '+
[Code] .....
I think I probable need to include a group by but can't figure out the correct syntax.
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Feb 12, 2008
Dear all, I have the Following Query:SELECT DATEDIFF(day, GETDATE(), RECENT_RESERVATION)AS Expr1,RECENT_RESERVATION FROM EMP WHERE SUN=empName;when i run it inside the query analyzer, it returns two columns. but if run it inside The ASPX page it retuns only one column wich is RECENT_RESERVATION date.Note: i am using one methode that takes care of reading from SQL and assigning the result into an array, it works fine everywhere, but with this query it dosen't work. Any suggestions??
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May 9, 2015
I needed to create a stored procedure to lock a user who makes 3 incorect entries of his password. I did it successfully. Now the problem what i have is that i want to lock the user only if he makes the 3 incorrect entries within 30 minutes.
I created a field named "FirstEntryTime" of type datetime that saves the date of the first incorrect entry. I tried to make an if statement:
if (@timesOfEntry <=2 AND DATEDIFF(MINUTE, firstEntryTime,GETDATE()) <= 30)
Begin
Update myTable set ...
End
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Oct 12, 2015
I am working on adding DBs to the AG but for some reason I am getting this error.
"Joining DB on secondary replica resulted in error"
Msg: The remote copy of the database is not recovered far enough to enable DB mirroring or to join AG. Missing log records have to be applied to the remote DB by restoring the current log backups" Which I did. I took the log backup of DB1, restored it on DB2 with no recovery, but still I am getting the same error.
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Apr 28, 2015
I've written sql code which takes a date and finds the Last Day of the Month one year ago. For example, it takes the date '2015-04-17' and returns the date '2014-04-30'. The code works fine in a query. Now I'm trying to turn this into a function. However, when I try to create the function I get the error:
Operand type clash: date is incompatible with int
Why is this error being returned?
Here is my function:
CREATE FUNCTION dbo.zEOM_LY_D(@Input Date)
RETURNS date
AS
BEGIN;
DECLARE @Result date;
SET @Result = convert(DATE, DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,dateadd(m, -11, @Input)+1),0)),101)
RETURN @Result;
END;
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May 2, 2015
I have added one webpage designed in ASP.Net with C# and sql server 2005 as database. There is table for user registration in which there is a column for ProfileCreationDate the data type of that column is date time .
I would like to fetch data of those user who have created profile within 7 days. For getting desired result I am trying this query.
select Name ,Profession,ProfileCreationDate from tblRegistration where DATEDIFF ( Day , '" + System.DateTime.Now + "',ProfileCreationDate)<7 order by ProfileCreationDate DESC
System.DateTime.Now is a function for getting current date time in C#
The query is neither giving error nor giving desired result.
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Aug 7, 2015
I have a requirement to use DateDiff(Months,DateTime1,DateTime2) and this must return positive integer values.
Currently negative numbers are being returned because DateTime1 < DateTime2 or DateTime1 > DateTime2 .
The DateTime1 and DateTime2 values are dynamic and either of them can be bigger than the other.
Any query solution so that always positive value is returned.
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Mar 22, 2007
$exception {"Arithmetic overflow error converting expression to data type smalldatetime.
The statement has been terminated."} System.Exception {System.Data.SqlClient.SqlException}
occurs
here is my code
protected void EmailSubmitBtn_Click(object sender, EventArgs e)
{
SqlDataSource NewsletterSqlDataSource = new SqlDataSource();
NewsletterSqlDataSource.ConnectionString = ConfigurationManager.ConnectionStrings["NewsletterConnectionString"].ToString();
//Text version
NewsletterSqlDataSource.InsertCommandType = SqlDataSourceCommandType.Text;
NewsletterSqlDataSource.InsertCommand = "INSERT INTO NewsLetter (EmailAddress, IPAddress, DateTimeStamp) VALUES (@EmailAddress, @IPAddress, @DateTimeStamp)";
//storeprocedure version
//NewsletterSqlDataSource.InsertCommandType = SqlDataSourceCommandType.StoredProcedure;
//NewsletterSqlDataSource.InsertCommand = "EmailInsert";
NewsletterSqlDataSource.InsertParameters.Add("EmailAddress", EmailTb.Text);
NewsletterSqlDataSource.InsertParameters.Add("IPAddress", Request.UserHostAddress.ToString());
NewsletterSqlDataSource.InsertParameters.Add("DateTimeStamp", DateTime.Now.ToString());
int rowsAffected = 0;
try
{
rowsAffected = NewsletterSqlDataSource.Insert();
}
catch (Exception ex)
{
Server.Transfer("NewsletterProblem.aspx");
}
finally
{
NewsletterSqlDataSource = null;
}
if (rowsAffected != 1)
{
Server.Transfer("NewsletterProblem.aspx");
}
else
{
Server.Transfer("NewsletterSuccess.aspx");
}
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Feb 7, 2004
Can i change from datetime data type to small datetime coz when i tried it produced an overflow error??
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Oct 13, 2005
On Thu, 13 Oct 2005 19:35:16 GMT, Mike wrote:[color=blue]>I have the SQL table column PRICE set for decimal (14,14).[/color]Hi Mike,That means that you have a total of 14 digits, 14 of which are to theright of the decimal. Leaving no digits to the left.[color=blue]>Any one know why I would get an overflow error.[/color]Probably because there's a value above 1.000 or below -1.000 in yourdata.Best, Hugo--(Remove _NO_ and _SPAM_ to get my e-mail address)
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Mar 2, 2007
Hi:
I am trying to pump data from Sybase to SQL Server using SSIS and I get this error:
Conversion failed because the data overflowed the specified type
The data on the external column metadata shows as type database timestamp, as does the output column. The database values are all datetime, coming in through OLEDB to Sybase. Any idea what could be going on here?
Thanks,
Kayda
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Feb 16, 2008
hi, can someone please tell me what this error is, i am trying to create a quiz engine but i keep getting this error when i try to save the results of me quiz in the results page. i have been following the tutorial from this website. Please can someone help me, thanks
Arithmetic overflow error converting expression to data type smalldatetime.The statement has been terminated.
Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.Data.SqlClient.SqlException: Arithmetic overflow error converting expression to data type smalldatetime.The statement has been terminated.Source Error:
Line 46: userQuizDataSource.InsertParameters.Add("UserName", User.Identity.Name)
Line 47:
Line 48: Dim rowsAffected As Integer = userQuizDataSource.Insert()
Line 49: If rowsAffected = 0 Then
Line 50: ' Let's just notify that the insertion didn't
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Jul 24, 2004
When I run my query
dr = Me.SqlComm_Chk_ATLGroup.ExecuteReader
it give me this error:
SqlDateTime overflow. Must be between 1/1/1753 12:00:00 AM and 12/31/9999 11:59:59 PM.
This is my Query :
SELECT break_time, break_rep_no, break_type, break_user_id
FROM breaks
WHERE (break_date = @p1) AND (break_group = @p2) AND (break_time > @p3) AND (break_time < @P4)
ORDER BY break_time
This is the code
Dim dr As SqlClient.SqlDataReader
Me.SqlConn.Open()
Me.SqlComm_Chk_ATLGroup.Parameters(0).Value = #7/23/2004#
Me.SqlComm_Chk_ATLGroup.Parameters(1).Value = 0
Me.SqlComm_Chk_ATLGroup.Parameters(2).Value = #10:00:00 AM#
Me.SqlComm_Chk_ATLGroup.Parameters(3).Value = #2:00:00 PM#
dr = Me.SqlComm_Chk_ATLGroup.ExecuteReader
While dr.Read
End While
Me.SqlConn.Close()
Note : when I store the time in a string and display it it gives me 10:00:00 AM 1/1/0001 or something like that ?
Where is the problem?
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Jan 16, 2006
I encounter the following error :
Server: Msg 8115, Level 16, State 2, Procedure kssp_UpdateLeague, Line 107
Arithmetic overflow error converting expression to data type tinyint.
When I hit the following code:
SET @A = @B - @C
-------------------------------------------
@A is defined as :
DECLARE @A INT
@B and @C are populated in a fetch :
FETCH NEXT FROM FixtureList INTO @B, @C
and FixtureList is defined as :
DECLARE FixtureList CURSOR FOR
SELECT HomeScore, AwayScore FROM fixtures
WHERE homescore IS NOT NULL AND awayscore IS NOT NULL
The fields HomeScore and AwayScore are defined as Tinyint
@B and @C are typically between 0 and 10. I reckon the problem may be with the precision of the data types but I don't know how to prove this or how to fix. I've tried various combinations of convert and cast at various points in the expression (SET @A = @B - @C) but to no avail.
Interestingly (or not) if I run the following select I get the same error :
SELECT DATE01, HOMESCORE, AWAYSCORE, HOMESCORE - AWAYSCORE FROM fixtures
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Feb 26, 1999
When doing a DATEDIFF on two dates, I get the error:
Msg 535, Level 16, State 0
Difference of two datetime fields caused overflow at runtime.
I have tracked the error down to a field in a couple of records out of several thousand records.
I don't know how to fix it the problem. BOL describes the error as a field having the wrong datatype that both datatypes are DATETIME.
Running: SQL Server 6.5 with SP4.
Any help is appreciated because we are going into code freeze this afternoon and going live next week.
TIA,
Virginia
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