Update Clustered Column In Place?

Jul 23, 2005

Is there any way to update a column in a clustered index without incurring
the cost of reordering.

Example:
Create table TableX (
Col1 int,
Col2 smalldatetime,
Col3 varchar(10))
go
create clustered indext ix_test on tableX (Col2, Col1)
go
update TableX set Col2 = '2004-12-07'

-- Yes I specifically left off the criteria to update every row.

It would seem to me in this situation that the data types require the same
storage, all rows are being updated in one transaction, and there's no new
to reorder since all will be the same.

Thanks,
Danny

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Inserting New Column In Specific Place

Jan 15, 2007

Hi

In MySQL it's simple to insert new columns in specific locations in a table like this


sql Code:






Original
- sql Code





alter table foo add column bar integer not null default 0 after baz






 ALTER TABLE foo ADD COLUMN bar integer NOT NULL DEFAULT 0 AFTER baz



But attempting to do the same thing in MSSQL fails with a syntax error on the word "after." I can insert columns in MSSQL but only if they are added to the end. I looked at the Microsoft insert documentation here but don't see any way to replicate the above MySQL command.

Is there any way to do this in MSSQL? Or do I have to completely recreate all my tables from scratch?

Thanks for any help

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Regards

Karen

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have
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--------
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Joe
Blowwwwwww
--------
1

any idea ?

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Jun 10, 2008

Dear All,
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please suggest me.

Arnav
Even you learn 1%, Learn it with 100% confidence.

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Nov 29, 2006

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Jan 25, 2007

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Hello there,

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Apr 3, 2002

I have a database where records are Inserted by an external process.
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I want to add an index on the Start Time, the Downtime Cause, and the
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My question is: should this new index also contain the Machine_id column
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its need in the new index?

RC - Dedicated to only creating original mistakes!

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I am building three partitioned, clustered column store tables.I was researching whether it was faster to populate a staging table and swap it into the partitioned table or to directly insert into the partitioned table.The first partition for the three tables will have:

Table F: 50M rows, 6 columns wide, partitioned on a date column (1 date, 2 bigint keys, and two varchar columns)
Table D1: 50M rows, 150 columns wide, partitioned on a bigint
Table D2: 19M rows, 300 columns wide, partitioned on a bigint

If build the data that would go into partition 1 in a non partitioned column store, I get these table sizes:

Table F: 476 MB
Table D1: 6,800 MB
Table D2: 5,496 MB

If build the same data directly in the partitioned column store, my table sizes end up being:

Table F: 579 MB
Table D1: 6,800 MB
Table D2: 5,364 MB

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Want to check my thinking with you folks...

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Counts of distinct values for columns are C1 425, C2 300,000 & C3 4,000,000

C3 is effectively number of seconds since 01/01/1970.

The usage of the table is typically, insert a row, do something else, then update it.

Currently, the index columns are ordered C3,C1,C2. Fill factor of 90%.

My thinking is that this composite index is better ordered C1,C2,C3.

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Welcome your thoughts.

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The Query executed Successfully and <g class="gr_ gr_135 gr-alert gr_tiny gr_spell undefined ContextualSpelling multiReplace" data-gr-id="135" id="135">i</g>

got composite index key id Gender(-), Salary I <g class="gr_ gr_310 gr-alert gr_gramm undefined Grammar only-ins replaceWithoutSep" data-gr-id="310" id="310">want</g> know why Gender(-) display like this?

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I am extremely new to database design, and I ran into a problem that I know comes up often, however has many opinions...

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Every single query against this table will use the 8 columns, and will NOT use the Identity column (1,1) because they are calls from other systems that do not know the Identity column....

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If not why? Why is putting a clustered index on an identity column (that will literally never be used in a query) a better solution?

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I desire to have a clustered index on a column other than the Primary Key. I have a few junction tables that I may want to alter, create table, or ...

I have practiced with an example table that is not really a junction table. It is just a table I decided to use for practice. When I execute the script, it seems to do everything I expect. For instance, there are not any constraints but there are indexes. The PK is the correct column.

CREATE TABLE [dbo].[tblNotificationMgr](
[NotificationMgrKey] [int] IDENTITY(1,1) NOT NULL,
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[code]....

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ALTER view dbo.FactView
with schemabinding
as
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Hello,


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Thanks in Advance,


Rohit

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