Week Base Grouping

Aug 7, 2007

Hi

SQL Server 2000
Table_A, Col_1 datetime

I want a query to group the date on weeks.
Please advise how ?

Thanks
Jawad

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Grouping By Week In Stored Procedure

Mar 14, 2007

Hi all,
I am using the below statement to get some dates grouped by date, in my SP. 
SELECT TOP 100 PERCENT COUNT(dbo.test.CallDate) AS CallCount, year(dbo.test.CallDate) AS CallYear, datepart(wk, dbo.test.CallDate) AS [Week] FROM dbo.test LEFT OUTER JOIN dbo.view1 ON dbo.test.CallID = dbo.view1.CallID LEFT OUTER JOIN dbo.view2 ON dbo.test.CallID = dbo.view2.CallID WHERE (dbo.view1.[ACCOUNT ID] = @accountid OR (dbo.view2.[ACCOUNT ID] = @accountid AND (convert(varchar(10),dbo.test.CallDate,121) BETWEEN CONVERT(DATETIME, @StartDate, 102)AND CONVERT(DATETIME, @EndDate, 102)) GROUP BY year(dbo.test.CallDate), datepart(wk, dbo.test.CallDate) ORDER BY year(dbo.test.CallDate), datepart(wk, dbo.test.CallDate) i gave startdate as 1/1/2007 and endDate as 2/18/2007 i am getting the reuslt as count year week 42 2001 32 2 2001 39 1 2001 51 1 2002 17 1 2002 19 106 2002 21 183 2002 22 226 2002 23 ................................. ................................... 1208 2007 1 1292 2007 2 actually i should get only the last 2 rows. Can anyone  please point out, why i am getting the 2001, 2002 data? and how to fix that?Thanks

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SQL Server 2014 :: DATEADD - Grouping By Week

Aug 25, 2015

We have bee using something like the following to get the Monday for the specified date.

However, we came across a scenario where this is not working

DECLARE @dt AS datetime
SET @dt = '2/19/2006'
SELECT DATEADD( ww, DATEDIFF( ww, 0, @dt),0)

It had seemed to be working as expected, but we recently came across a problem where The above is returning 2/20, not 2/13

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Oct 5, 2007



Hi,

I need to run report that shows activity for Paediatrics Consultants who starts their audit week on Fri 5pm and finish next Fri at 5pm.

Set datefirst would work Fri to Thur but not with hours. And does not always seem to work either.

I need to be able to see historical data and do not want people to enter dates (from to), will group it by wek, consultant

Any clues? Cheers

Petr

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Jul 20, 2005

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Power Pivot :: Cumulative Total For Current Week Days And Previous Week

Nov 30, 2015

We are trying to compare our current calendar week (based on Monday being the first day of the week) with the previous calendar week. 

I'm trying to produce a line chart with 2 axis:

- x axis; the day of the week (Mon, Tues, Wed etc - it is fine for this to be a # rather than text e.g. 1 = Mon, 2 = Tues etc)
- y axis; the cumulative number of orders 

The chart needs two series:

Previous Week. The running count of orders placed that week. 
Current Week. The running count of orders placed this week. 

Obviously in such a chart the 'Current Week' series is going not going to have values along the whole axis until the end of the week. This is expected and the aim of the chart is to see the current week compares against the previous week for the same day. 

I have two tables:

Orders TableCalendar Table

The calendar table's main date column is [calDate] and there are columns for the usual [calWeekNum], [calMonth] etc. 

My measure for counting orders is simply; # Orders: = countrows[orders].

How do I take this measure and then work out my two series. I have tried numerous things such as adapting TOTALMTD(), following articles such as these:

- [URL] ...
- [URL] ...

But I have had no luck. The standard cumulative formulas do work e.g. if I wanted a MTD or YTD table I would be ok, it's just adjusting to a WTD that is causing me big issues.

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SQL Server 2008 :: Get Week Ending Date Given Week Number

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How can I get Saturday's date given the week number?

This is my week number, SELECT DATEPART(WEEK, DATEADD(MONTH, +3, ApptDt2)). I need to get Saturday's date from this week.

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T-SQL (SS2K8) :: Get Week Numbers From Dates - Saturday Being Start Of Week

Sep 17, 2015

i have the following table I need to select dates grouping them by weeks, my week start is Saturday to Friday

CREATE TABLE weekdays
(
datevalue datetime NOT NULL
, numericvalue INT NOT NULL
);
INSERT INTO weekdays (datevalue, numericvalue) VALUES

[code]....

The output should look like this

weeknototalvalue
362015-09-01 00:00:00.000
362015-09-02 00:00:00.000
372015-09-07 00:00:00.000
372015-09-08 00:00:00.000
382015-09-12 00:00:00.000
382015-09-13 00:00:00.000
382015-09-14 00:00:00.000
392015-09-19 00:00:00.000

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Create A Yesterday, This Week, Last Week Calculated Member

May 23, 2007

Hi all,

I'd like to add a yesterday dimension member to a new dimension, like a "Time Utility" dimension, that references the second last day of non empty data in a cube.

At the moment, I'm doing this:




Code Snippet

create member [MIA DW].[DATE TIME].[Date].[Yesterday]
as [DATE TIME].[Date].&[2007-01-01T00:00:00]

select [Measures].members on 0,
non empty [DATE TIME].[Date].members on 1
from [MIA DW]
But the [yesterday] member does not seem to belong to [DATE TIME].[Date].members?

So I guess there's two questions:

1) Can I have a new empty dimension which contains all these special members like "Yesterday" or "This Week" and "Last Week" (these last two obviously refer to a set of Dates)

2)How come the Yesterday member is not returned by the .members function?


Thanks

Greg

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How To Stop Week Hours To Continue To Next Week

Jan 29, 2014

I am adding week hrs using while loop , but it can continue next week hrs also.

I can get every week start hrs while update @tem1 table

employeeidreportdatereportatleftattoaccountwrhrn
12902014-01-29 00:00:00.00009:3019:1556001
12902014-01-28 00:00:00.00009:0018:4555802
12902014-01-27 00:00:00.00009:0018:455585583
12902014-01-25 00:00:00.00008:0010:0012004 -- week end
12902014-01-24 00:00:00.00009:1718:4554105
12902014-01-23 00:00:00.00009:1918:4654606
12902014-01-22 00:00:00.00009:1718:4754507
12902014-01-21 00:00:00.00009:1618:3552608
12902014-01-20 00:00:00.00009:1818:555435439

My loop statement

while(select MAX(wrh) from @tem1 where wrh = 0) < 1
begin
update @tem1
set wrh = (select toaccount from @tem1
where reportdate = (select min(reportdate) from @tem1 where wrh = 0))+(select max(wrh) from @tem1)
where wrh = (select max(wrh) from @tem1 where wrh = 0 )
and reportdate = (select min(reportdate) from @tem1 where wrh = 0)
end

this is the result while executing loop statement .

employeeidreportdatereportatleftatdehdrhwehwrh
129029 Jan 201409:3019:15008:0009:20024:00065:54
129028 Jan 201409:0018:45008:0009:18016:00056:34
129027 Jan 201409:0018:45008:0009:18008:0009:18
129025 Jan 201408:0010:00005:0002:00045:00047:16 -- week end
129024 Jan 201409:1718:45008:0009:01040:00045:16
129023 Jan 201409:1918:46008:0009:06032:00036:15
129022 Jan 201409:1718:47008:0009:05024:00027:09
129021 Jan 201409:1618:35008:0008:46016:00018:04
129020 Jan 201409:1818:55008:0009:03008:0009:03

How to update only that week hrs , don't continue next week...

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I only need give a week number of the year and then returns the week number of the first week of that month.

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Convert Week Number To Date Of 1st Day Of That Week...

Feb 2, 2008



I'm looking for a way to convert the [week number, year] back to the date for the 1st day of that week.

Example (assuming DATEFIRST has been set to 1) : Week 3, 2008 = January 14, 2008

Is there a SQL function that will do this?


Thanks,
Mike

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Date Of First Day Of Week For Current Week

Jun 6, 2006

seriously now

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Aug 15, 2006

I have a query that run every day to update a summary table which has week number and day of week. what I currently do is delete all records from the summary table and then summarize all the data availabe from four tables adn then populate the table daily. I want to know if I can run the update query to run only for the week number and day of week depending on getdate. Can I do this?

Please help..

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ISO Year Week Day Of Week Function

Jan 18, 2006

Function F_ISO_YEAR_WEEK_DAY_OF_WEEK returns the ISO 8601 Year Week Day of Week in format YYYY-W01-D for the date passed. W01 represents the week of the year from W01 through W53, and D represents the day of the week with 1 = Monday through 7 = Sunday.

The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.

This code creates the function and demos it for the first day, first date+60, and first date+364 for each ISO week/year from 1990 to 2030.


drop function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
GO
create function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
(
@Datedatetime
)
returnsvarchar(10)
as
/*
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK
returns the ISO 8601 Year Week Day of Week
in format YYYY-W01-D for the date passed.
*/
begin

declare @YearWeekDayOfWeekvarchar(10)

Select
--Format to form YYYY-W01-D
@YearWeekDayOfWeek =
convert(varchar(4),year(dateadd(dd,7,a.YearStart)))+'-W'+
right('00'+convert(varchar(2),(datediff(dd,a.YearStart,@Date)/7)+1),2) +
'-'+convert(varchar(1),(datediff(dd,a.YearStart,@Date)%7)+1)
from
(
select
YearStart =
-- Case finds start of year
case
whenNextYrStart <= @date
thenNextYrStart
whenCurrYrStart <= @date
thenCurrYrStart
elsePriorYrStart
end
from
(
select
-- First day of first week of prior year
PriorYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aaa.Jan4))/7)*7,-53690),
-- First day of first week of current year
CurrYrStart =
dateadd(dd,(datediff(dd,-53690,aaa.Jan4)/7)*7,-53690),
-- First day of first week of next year
NextYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aaa.Jan4))/7)*7,-53690)
from
(
select
--Find Jan 4 for the year of the input date
Jan4=
dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0))
) aaa
) aa
) a

return @YearWeekDayOfWeek

end
go


-- Execute function on first day, first day+60,
-- and first day+364 for years from 1990 to 2030.

select
DT= convert(varchar(10),DT,121),
YR_START_DT =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT),
YR_START_DT_60 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+60),
YR_START_DT_365 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+364)
from
(
select DT = getdate()union all
select DT = convert(datetime,'1990/01/01') union all
select DT = convert(datetime,'1990/12/31') union all
select DT = convert(datetime,'1991/12/30') union all
select DT = convert(datetime,'1993/01/04') union all
select DT = convert(datetime,'1994/01/03') union all
select DT = convert(datetime,'1995/01/02') union all
select DT = convert(datetime,'1996/01/01') union all
select DT = convert(datetime,'1996/12/30') union all
select DT = convert(datetime,'1997/12/29') union all
select DT = convert(datetime,'1999/01/04') union all
select DT = convert(datetime,'2000/01/03') union all
select DT = convert(datetime,'2001/01/01') union all
select DT = convert(datetime,'2001/12/31') union all
select DT = convert(datetime,'2002/12/30') union all
select DT = convert(datetime,'2003/12/29') union all
select DT = convert(datetime,'2005/01/03') union all
select DT = convert(datetime,'2006/01/02') union all
select DT = convert(datetime,'2007/01/01') union all
select DT = convert(datetime,'2007/12/31') union all
select DT = convert(datetime,'2008/12/29') union all
select DT = convert(datetime,'2010/01/04') union all
select DT = convert(datetime,'2011/01/03') union all
select DT = convert(datetime,'2012/01/02') union all
select DT = convert(datetime,'2012/12/31') union all
select DT = convert(datetime,'2013/12/30') union all
select DT = convert(datetime,'2014/12/29') union all
select DT = convert(datetime,'2016/01/04') union all
select DT = convert(datetime,'2017/01/02') union all
select DT = convert(datetime,'2018/01/01') union all
select DT = convert(datetime,'2018/12/31') union all
select DT = convert(datetime,'2019/12/30') union all
select DT = convert(datetime,'2021/01/04') union all
select DT = convert(datetime,'2022/01/03') union all
select DT = convert(datetime,'2023/01/02') union all
select DT = convert(datetime,'2024/01/01') union all
select DT = convert(datetime,'2024/12/30') union all
select DT = convert(datetime,'2025/12/29') union all
select DT = convert(datetime,'2027/01/04') union all
select DT = convert(datetime,'2028/01/03') union all
select DT = convert(datetime,'2029/01/01') union all
select DT = convert(datetime,'2029/12/31') union all
select DT = convert(datetime,'2030/12/30')
) a


Function Test Results:

DT YR_START_DT YR_START_DT_60 YR_START_DT_364
---------- ----------- -------------- ---------------
2006-01-18 2006-W03-3 2006-W11-7 2007-W03-3
1990-01-01 1990-W01-1 1990-W09-5 1991-W01-1
1990-12-31 1991-W01-1 1991-W09-5 1992-W01-1
1991-12-30 1992-W01-1 1992-W09-5 1992-W53-1
1993-01-04 1993-W01-1 1993-W09-5 1994-W01-1
1994-01-03 1994-W01-1 1994-W09-5 1995-W01-1
1995-01-02 1995-W01-1 1995-W09-5 1996-W01-1
1996-01-01 1996-W01-1 1996-W09-5 1997-W01-1
1996-12-30 1997-W01-1 1997-W09-5 1998-W01-1
1997-12-29 1998-W01-1 1998-W09-5 1998-W53-1
1999-01-04 1999-W01-1 1999-W09-5 2000-W01-1
2000-01-03 2000-W01-1 2000-W09-5 2001-W01-1
2001-01-01 2001-W01-1 2001-W09-5 2002-W01-1
2001-12-31 2002-W01-1 2002-W09-5 2003-W01-1
2002-12-30 2003-W01-1 2003-W09-5 2004-W01-1
2003-12-29 2004-W01-1 2004-W09-5 2004-W53-1
2005-01-03 2005-W01-1 2005-W09-5 2006-W01-1
2006-01-02 2006-W01-1 2006-W09-5 2007-W01-1
2007-01-01 2007-W01-1 2007-W09-5 2008-W01-1
2007-12-31 2008-W01-1 2008-W09-5 2009-W01-1
2008-12-29 2009-W01-1 2009-W09-5 2009-W53-1
2010-01-04 2010-W01-1 2010-W09-5 2011-W01-1
2011-01-03 2011-W01-1 2011-W09-5 2012-W01-1
2012-01-02 2012-W01-1 2012-W09-5 2013-W01-1
2012-12-31 2013-W01-1 2013-W09-5 2014-W01-1
2013-12-30 2014-W01-1 2014-W09-5 2015-W01-1
2014-12-29 2015-W01-1 2015-W09-5 2015-W53-1
2016-01-04 2016-W01-1 2016-W09-5 2017-W01-1
2017-01-02 2017-W01-1 2017-W09-5 2018-W01-1
2018-01-01 2018-W01-1 2018-W09-5 2019-W01-1
2018-12-31 2019-W01-1 2019-W09-5 2020-W01-1
2019-12-30 2020-W01-1 2020-W09-5 2020-W53-1
2021-01-04 2021-W01-1 2021-W09-5 2022-W01-1
2022-01-03 2022-W01-1 2022-W09-5 2023-W01-1
2023-01-02 2023-W01-1 2023-W09-5 2024-W01-1
2024-01-01 2024-W01-1 2024-W09-5 2025-W01-1
2024-12-30 2025-W01-1 2025-W09-5 2026-W01-1
2025-12-29 2026-W01-1 2026-W09-5 2026-W53-1
2027-01-04 2027-W01-1 2027-W09-5 2028-W01-1
2028-01-03 2028-W01-1 2028-W09-5 2029-W01-1
2029-01-01 2029-W01-1 2029-W09-5 2030-W01-1
2029-12-31 2030-W01-1 2030-W09-5 2031-W01-1
2030-12-30 2031-W01-1 2031-W09-5 2032-W01-1

(43 row(s) affected)




CODO ERGO SUM

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May 2, 2007

hi friends,



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can any one help me





Cheers,

raj

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Nov 26, 2007

I'm really stumped on this one. I'm a self taught SQL guy, so there is probobly something I'm overlooking.

I'm trying to get information like this in to a report:

WO#
-WO Line #
--(Details)
--Work Order Line Detail #1
--Work Order Line Detail #2
--Work Order Line Detail #3
--Work Order Line Detail #etc
--(Parts)
--Work Order Line Parts #1
--Work Order Line Parts #2
--Work Order Line Detail #etc
WO#
-WO Line #
--(Details)
--Work Order Line Detail #1
--Work Order Line Detail #2
--Work Order Line Detail #3
--Work Order Line Detail #etc
--(Parts)
--Work Order Line Parts #1
--Work Order Line Parts #2
--Work Order Line Parts #etc

I'm unable to get the grouping right on this. Since the line details and line parts both are children of the line #, how do you do "parallel groups"?

There are 4 tables:

Work Order Header
Work Order Line
Work Order Line Details
Work Order Line Requisitions

The Header has a unique PK.
The Line uses the Header and a Line # as foreign keys that together are unique.
The Detail and requisition tables use the header and line #'s in addition to their own line number foreign keys. My queries ends up looking like this:

WO WOL WOLR WOLD
226952 10000 10000 10000
226952 10000 10000 20000
226952 10000 10000 30000
226952 10000 10000 40000
226952 10000 20000 10000
226952 10000 20000 20000
226952 10000 20000 30000
226952 10000 20000 40000
399999 10000 NULL 10000
375654 10000 10000 NULL
etc


Hierarchy:
WO > WOL > WOLD
WO > WOL > WOLR

It probobly isn't best practice, but I'm kinda new so I need some guidance. I'd really appreciate any help! Here's my query:

SELECT [Work Order Header].No_ AS WO_No, [Work Order Line].[Line No_] AS WOL_No,
[Work Order Requisition].[Line No_] AS WOLR_No, [Work Order Line Detail].[Line No_] AS WOLD_No
FROM [Work Order Header] LEFT OUTER JOIN
[Work Order Line] ON [Work Order Header].No_ = [Work Order Line].[Work Order No_] LEFT OUTER JOIN
[Work Order Line Detail] ON [Work Order Line].[Work Order No_] = [Work Order Line Detail].[Work Order No_] AND
[Work Order Line].[Line No_] = [Work Order Line Detail].[Work Order Line No_] LEFT OUTER JOIN
[Work Order Requisition] ON [Work Order Line].[Work Order No_] = [Work Order Requisition].[Work Order No_] AND
[Work Order Line].[Line No_] = [Work Order Requisition].[Work Order Line No_]

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Failed
to generate a user instance of SQL Server due to afailure in starting
the process for the user instance. The connection will be closed.



Description: An
unhandled exception occurred during the execution of the current web
request. Please review the stack trace for more information about the
error and where it originated in the code.

SQLExpress database file auto-creation error:The
connection string specifies a local Sql Server Express instance using a
database location within the applications App_Data directory. The
provider attempted to automatically create the application services
database because the provider determined that the database does not
exist. The following configuration requirements are necessary to
successfully check for existence of the application services database
and automatically create the application services database:
If
the applications App_Data directory does not already exist, the web
server account must have read and write access to the applications
directory. This is necessary because the web server account will
automatically create the App_Data directory if it does not already
exist.
If the applications App_Data directory already exists, the web
server account only requires read and write access to the applications
App_Data directory. This is necessary because the web server account
will attempt to verify that the Sql Server Express database already
exists within the applications App_Data directory. Revoking read access
on the App_Data directory from the web server account will prevent the
provider from correctly determining if the Sql Server Express database
already exists. This will cause an error when the provider attempts to
create a duplicate of an already existing database. Write access is
required because the web server accounts credentials are used when
creating the new database.
Sql Server Express must be installed on the machine.
The process identity for the web server account must have a local
user profile. See the readme document for details on how to create a
local user profile for both machine and domain accounts.

Source Error:





An unhandled exception was generated during the execution of the
current web request. Information regarding the origin and location of
the exception can be identified using the exception stack trace below.







Stack Trace:


[SqlException (0x80131904): Failed to generate a user instance of SQL Server due to a failure in starting the process for the user instance. The connection will be closed.] System.Data.SqlClient.SqlInternalConnection.OnError(SqlException exception, Boolean breakConnection) +735043 System.Data.SqlClient.TdsParser.ThrowExceptionAndWarning(TdsParserStateObject stateObj) +188 System.Data.SqlClient.TdsParser.Run(RunBehavior runBehavior, SqlCommand cmdHandler, SqlDataReader dataStream, BulkCopySimpleResultSet bulkCopyHandler, TdsParserStateObject stateObj) +1838 System.Data.SqlClient.SqlInternalConnectionTds.CompleteLogin(Boolean enlistOK) +33 System.Data.SqlClient.SqlInternalConnectionTds.OpenLoginEnlist(SqlConnection owningObject, SqlConnectionString connectionOptions, String newPassword, Boolean redirectedUserInstance) +628 System.Data.SqlClient.SqlInternalConnectionTds..ctor(DbConnectionPoolIdentity identity, SqlConnectionString connectionOptions, Object providerInfo, String newPassword, SqlConnection owningObject, Boolean redirectedUserInstance) +170 System.Data.SqlClient.SqlConnectionFactory.CreateConnection(DbConnectionOptions options, Object poolGroupProviderInfo, DbConnectionPool pool, DbConnection owningConnection) +130 System.Data.ProviderBase.DbConnectionFactory.CreateNonPooledConnection(DbConnection owningConnection, DbConnectionPoolGroup poolGroup) +27 System.Data.ProviderBase.DbConnectionFactory.GetConnection(DbConnection owningConnection) +47 System.Data.ProviderBase.DbConnectionClosed.OpenConnection(DbConnection outerConnection, DbConnectionFactory connectionFactory) +105 System.Data.SqlClient.SqlConnection.Open() +111 System.Web.Management.SqlServices.GetSqlConnection(String server, String user, String password, Boolean trusted, String connectionString) +68[HttpException (0x80004005): Unable to connect to SQL Server database.] System.Web.Management.SqlServices.GetSqlConnection(String server, String user, String password, Boolean trusted, String connectionString) +124 System.Web.Management.SqlServices.SetupApplicationServices(String server, String user, String password, Boolean trusted, String connectionString, String database, String dbFileName, SqlFeatures features, Boolean install) +86 System.Web.Management.SqlServices.Install(String database, String dbFileName, String connectionString) +25 System.Web.DataAccess.SqlConnectionHelper.CreateMdfFile(String fullFileName, String dataDir, String connectionString) +397

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