My boss would like to see one report with parameter promts. I tried doing this, but I keep getting an error. Can someone help me out here?
Thanks.
WHERE
(@YEAR(CLM_Dout) = YEAR(GetDate()))or
(@YEAR(CLM_DOUT) = YEAR(GetDate()) AND MONTH(CLM_DOUT) = MONTH(GetDate()))or
(@YEAR(CLM_DOUT) = YEAR(GetDate()) AND DATEPART(wk, CLM_DOUT) = DATEPART(wk, GETDATE()))
I am trying to group counts by week,month,quarter, year for a particular activity type and I'm having issues.Here's my code so far:
SELECT
distinct
EmailAddressID,
emailaddress,
SUM(CASE WHEN [ActivityDate] >= DATEADD(WEEK, DATEDIFF(WEEK, 0, @DT), 0)
THEN
SUM(CASE WHEN EmailActivityType = 'OPEN' THEN 1 ELSE 0 END) END AS WeekTotalOpens
FROM EmailActivity
WHERE DATEPART(YEAR, [ActivityDate]) = DATEPART(YEAR, @DT)
GROUP BY EmailAddressID,emailaddress
Desired Output:
EmailAddressId EmailAddress WeekTotalOpens MonthTotalOpens etc. then WeekTotalClicks and so on....
SQL doesn't seem to like the sub-aggregate. What is the best way to approach?
I need developing a query to get the average count by the following:
Day - use daily info for the last ??? days
Weekly - average
- Add all days and divide by 7
- As of Saturday midnight
Monthly - average
- Add all days and divide by days in the month
- As of last save on last day of month
Quarter - average
- Add all days and divide by number of days in the quarter
- As of last day of quarter
Year - average
I don't have requirements for year as of yet.
How can I get the avery count per these timeframes?
I need to build a report that compares a count on a certain day of the week by month by year by stacks. That is,for first Monday in October 2012 against first Monday in October 2013 for stack DM1 against first Monday in October 2014 stack DM1, same for second Monday, first Tuesday, second Tuesday, ect. Attached is a sample dataset and what I want to achieve.
View 9 Replies View RelatedHi every one,
I have a database table and currently users may retrieve records for a specified date range by providing the start and end dates and then records between those dates provided are retrieved. For example if users wanted to view all records entered in april, they would have to select 04/01/2007 as the start date and then 04/30/2007 as the end date. The records for april would then be displayed in a gridview.
How can configure my sql query such that instead the user selectes a month from a dropdownlist of 12 months. I would love a user to just select the desired month from a list instead of selecting start and end dates. Eg if they are intrested in a report for june, then they should just select june from the list instead of specifying the start and stop dates. HOW can i achieve this.
I have a year-month hierarchy that I am using as a parameter in a report. I'm using the From query choice for available values and using the ParameterValue.
My parameter list displasy as:
2006
1
10
11
12
2
3
...
2007
1
10
11
12
2
3
4
Is there a way to get this to display months as integers rather than strings?
Thanks.
In my reports I am extracting the data of number of people joined in all the weeks of the year. And in one of reports I have to extract the data of the number of people joined until the last week from the first week. I am trying out all the logics but nothing is working for me as such. Can any one help me with this issue??????
View 4 Replies View Relatedi have some classes that I want to group by month/year (note:i dont need the day of the month)
how do i wirte my sql so it only gives me the dictinct groups month/year of the classes I have so that it comes out like so..
11/2006
12/2006
1/2007
3/2007
i try with my sql below but i cant get the groups th come out in order. i dont think it sees it as a date value.
dbo.classgiven.classdate date of the class.thank you all
SELECT DISTINCT { fn MONTH(dbo.classgiven.classdate) } " + "/" + "{ fn YEAR(dbo.classgiven.classdate) } AS monthyear,{ fn MONTH(dbo.classgiven.classdate) } AS monthcode FROM dbo.classT INNER JOIN dbo.classgiven ON dbo.classT.classcode = dbo.classgiven.classcode WHERE (dbo.classT.discount = '-1') AND (dbo.classT.coned IS NOT NULL)", conNorthwind )
Does anyone know of a way to use a funtion for returning records based on fiscal reporting periods like Quickbooks uses for example "This Month", "Last Month", "This Quarter", "Last Quarter", "This Year", "Last Year". While I realize that I can create a very long date time parsing routine for this but it is not very elegant or useful. I thought there might be a way to do this already with an existing function.I have created a stored procedure that I pass a @ViewRange Parameter to and it returns the records that I want but I need this ability in several procedures and wanted to turn it into a stored procedure.IF @ViewRange = 'This Month' SELECT TOP 20 Customer.LastName AS Customer, SUM(Sales.AmtCharge) AS Amount FROM Customer INNER JOIN Sales ON Customer.CustNo = Sales.CustNo WHERE (MONTH(Sales.InvDate) = MONTH(CURRENT_TIMESTAMP)) AND (YEAR(Sales.InvDate) = YEAR(CURRENT_TIMESTAMP)) GROUP BY Customer.LastName ORDER BY SUM(Sales.AmtCharge) DESC;IF @ViewRange = 'Last Month' SELECT TOP 20 Customer.LastName AS Customer, Sum(Sales.AmtCharge) AS Amount FROM Customer INNER JOIN Sales ON Customer.CustNo = Sales.CustNo WHERE(MONTH(Sales.InvDate) = MONTH(CURRENT_TIMESTAMP) - 1) And (YEAR(Sales.InvDate) = YEAR(CURRENT_TIMESTAMP)) GROUP BY Customer.LastName ORDER BY Sum(Sales.AmtCharge) DESC; Any ideas?
View 8 Replies View RelatedI need a Select sentence that return me the first week of the month for a given week.
For example If I have week number 12 (Begins 2015/03/16 and Ends 2015/03/22) I need that returns 9, I mean Week number 9 wich is the first week of march (having in mind @@DATEFIRST).
I only need give a week number of the year and then returns the week number of the first week of that month.
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK returns the ISO 8601 Year Week Day of Week in format YYYY-W01-D for the date passed. W01 represents the week of the year from W01 through W53, and D represents the day of the week with 1 = Monday through 7 = Sunday.
The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.
This code creates the function and demos it for the first day, first date+60, and first date+364 for each ISO week/year from 1990 to 2030.
drop function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
GO
create function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
(
@Datedatetime
)
returnsvarchar(10)
as
/*
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK
returns the ISO 8601 Year Week Day of Week
in format YYYY-W01-D for the date passed.
*/
begin
declare @YearWeekDayOfWeekvarchar(10)
Select
--Format to form YYYY-W01-D
@YearWeekDayOfWeek =
convert(varchar(4),year(dateadd(dd,7,a.YearStart)))+'-W'+
right('00'+convert(varchar(2),(datediff(dd,a.YearStart,@Date)/7)+1),2) +
'-'+convert(varchar(1),(datediff(dd,a.YearStart,@Date)%7)+1)
from
(
select
YearStart =
-- Case finds start of year
case
whenNextYrStart <= @date
thenNextYrStart
whenCurrYrStart <= @date
thenCurrYrStart
elsePriorYrStart
end
from
(
select
-- First day of first week of prior year
PriorYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aaa.Jan4))/7)*7,-53690),
-- First day of first week of current year
CurrYrStart =
dateadd(dd,(datediff(dd,-53690,aaa.Jan4)/7)*7,-53690),
-- First day of first week of next year
NextYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aaa.Jan4))/7)*7,-53690)
from
(
select
--Find Jan 4 for the year of the input date
Jan4=
dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0))
) aaa
) aa
) a
return @YearWeekDayOfWeek
end
go
-- Execute function on first day, first day+60,
-- and first day+364 for years from 1990 to 2030.
select
DT= convert(varchar(10),DT,121),
YR_START_DT =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT),
YR_START_DT_60 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+60),
YR_START_DT_365 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+364)
from
(
select DT = getdate()union all
select DT = convert(datetime,'1990/01/01') union all
select DT = convert(datetime,'1990/12/31') union all
select DT = convert(datetime,'1991/12/30') union all
select DT = convert(datetime,'1993/01/04') union all
select DT = convert(datetime,'1994/01/03') union all
select DT = convert(datetime,'1995/01/02') union all
select DT = convert(datetime,'1996/01/01') union all
select DT = convert(datetime,'1996/12/30') union all
select DT = convert(datetime,'1997/12/29') union all
select DT = convert(datetime,'1999/01/04') union all
select DT = convert(datetime,'2000/01/03') union all
select DT = convert(datetime,'2001/01/01') union all
select DT = convert(datetime,'2001/12/31') union all
select DT = convert(datetime,'2002/12/30') union all
select DT = convert(datetime,'2003/12/29') union all
select DT = convert(datetime,'2005/01/03') union all
select DT = convert(datetime,'2006/01/02') union all
select DT = convert(datetime,'2007/01/01') union all
select DT = convert(datetime,'2007/12/31') union all
select DT = convert(datetime,'2008/12/29') union all
select DT = convert(datetime,'2010/01/04') union all
select DT = convert(datetime,'2011/01/03') union all
select DT = convert(datetime,'2012/01/02') union all
select DT = convert(datetime,'2012/12/31') union all
select DT = convert(datetime,'2013/12/30') union all
select DT = convert(datetime,'2014/12/29') union all
select DT = convert(datetime,'2016/01/04') union all
select DT = convert(datetime,'2017/01/02') union all
select DT = convert(datetime,'2018/01/01') union all
select DT = convert(datetime,'2018/12/31') union all
select DT = convert(datetime,'2019/12/30') union all
select DT = convert(datetime,'2021/01/04') union all
select DT = convert(datetime,'2022/01/03') union all
select DT = convert(datetime,'2023/01/02') union all
select DT = convert(datetime,'2024/01/01') union all
select DT = convert(datetime,'2024/12/30') union all
select DT = convert(datetime,'2025/12/29') union all
select DT = convert(datetime,'2027/01/04') union all
select DT = convert(datetime,'2028/01/03') union all
select DT = convert(datetime,'2029/01/01') union all
select DT = convert(datetime,'2029/12/31') union all
select DT = convert(datetime,'2030/12/30')
) a
Function Test Results:
DT YR_START_DT YR_START_DT_60 YR_START_DT_364
---------- ----------- -------------- ---------------
2006-01-18 2006-W03-3 2006-W11-7 2007-W03-3
1990-01-01 1990-W01-1 1990-W09-5 1991-W01-1
1990-12-31 1991-W01-1 1991-W09-5 1992-W01-1
1991-12-30 1992-W01-1 1992-W09-5 1992-W53-1
1993-01-04 1993-W01-1 1993-W09-5 1994-W01-1
1994-01-03 1994-W01-1 1994-W09-5 1995-W01-1
1995-01-02 1995-W01-1 1995-W09-5 1996-W01-1
1996-01-01 1996-W01-1 1996-W09-5 1997-W01-1
1996-12-30 1997-W01-1 1997-W09-5 1998-W01-1
1997-12-29 1998-W01-1 1998-W09-5 1998-W53-1
1999-01-04 1999-W01-1 1999-W09-5 2000-W01-1
2000-01-03 2000-W01-1 2000-W09-5 2001-W01-1
2001-01-01 2001-W01-1 2001-W09-5 2002-W01-1
2001-12-31 2002-W01-1 2002-W09-5 2003-W01-1
2002-12-30 2003-W01-1 2003-W09-5 2004-W01-1
2003-12-29 2004-W01-1 2004-W09-5 2004-W53-1
2005-01-03 2005-W01-1 2005-W09-5 2006-W01-1
2006-01-02 2006-W01-1 2006-W09-5 2007-W01-1
2007-01-01 2007-W01-1 2007-W09-5 2008-W01-1
2007-12-31 2008-W01-1 2008-W09-5 2009-W01-1
2008-12-29 2009-W01-1 2009-W09-5 2009-W53-1
2010-01-04 2010-W01-1 2010-W09-5 2011-W01-1
2011-01-03 2011-W01-1 2011-W09-5 2012-W01-1
2012-01-02 2012-W01-1 2012-W09-5 2013-W01-1
2012-12-31 2013-W01-1 2013-W09-5 2014-W01-1
2013-12-30 2014-W01-1 2014-W09-5 2015-W01-1
2014-12-29 2015-W01-1 2015-W09-5 2015-W53-1
2016-01-04 2016-W01-1 2016-W09-5 2017-W01-1
2017-01-02 2017-W01-1 2017-W09-5 2018-W01-1
2018-01-01 2018-W01-1 2018-W09-5 2019-W01-1
2018-12-31 2019-W01-1 2019-W09-5 2020-W01-1
2019-12-30 2020-W01-1 2020-W09-5 2020-W53-1
2021-01-04 2021-W01-1 2021-W09-5 2022-W01-1
2022-01-03 2022-W01-1 2022-W09-5 2023-W01-1
2023-01-02 2023-W01-1 2023-W09-5 2024-W01-1
2024-01-01 2024-W01-1 2024-W09-5 2025-W01-1
2024-12-30 2025-W01-1 2025-W09-5 2026-W01-1
2025-12-29 2026-W01-1 2026-W09-5 2026-W53-1
2027-01-04 2027-W01-1 2027-W09-5 2028-W01-1
2028-01-03 2028-W01-1 2028-W09-5 2029-W01-1
2029-01-01 2029-W01-1 2029-W09-5 2030-W01-1
2029-12-31 2030-W01-1 2030-W09-5 2031-W01-1
2030-12-30 2031-W01-1 2031-W09-5 2032-W01-1
(43 row(s) affected)
CODO ERGO SUM
I have the following script that calculates Sales by month and current year.
We run a Fiscal year from April 1st thru March 31st.
So April 2012 sales are considered Fiscal Year 2013.
Is there a way I can alter this script to get Fiscal Year Totals?
select ClassificationId, YEAR(inv_dt) as Year, cus_no,
isnull(sum(case when month(inv_dt) = 4 then salesamt end),0) as 'Apr',
isnull(sum(case when month(inv_dt) = 5 then salesamt end),0) as 'May',
isnull(sum(case when month(inv_dt) = 6 then salesamt end),0) as 'Jun',
isnull(sum(case when month(inv_dt) = 7 then salesamt end),0) as 'Jul',
[Code] ....
Data returned looks like the following.
ClassificationID Year Cus_no Apr May June ....
100 2012 100 $23 $30 $400
100 2013 100 $40 $45 $600
What I would need is anything greater than or equal to April to show in the next years row.
I have three web form controls, a ddl that contains the day, another ddl that contains the month and a textbox that contains the current year. To send the date chosen by the user to the database, I join the three web form control values so that the resultant string is ‘day/month/year’ thus:
CmdInsert.Parameters("@Date").Value = day.SelectedItem.Value + "/" + month.SelectedItem.Value + "/" + year.Text()
And the resultant string is: dd/mm/yyyy, for example 30/08/2004.
But the problem is if the user does not select any day or any day and month, then the resultant string is for example; 00/08/2004 or 00/00/2004, but the problem is the database does not accept this format as datetime. How can I do it?
I want the user has the possibility to chose as well only the month and year, and as well only the year. Is it possible to send to the database the datetime format with only the month and year, or only the year?
Thank you,
Cesar
I'm using PHP with SQLServer2k to create a page containing monthly counts of episodes at a facility occurring between two user selected month/year combinations. For instance, the user could select 10/2003 and 2/2004 and facility X and get a line for each month showing the count of episodes occuring in that month.
The problem is that the episode date is stored in three integer fields (epiday, epimonth, epiyear) and I'm having a terrible time getting them into a format where I can use them in a between statement.
I've tried evaluating the parts of the episode date seperately like:
where
(epimonth>=10 and epiyear=2003)
or
(epimonth<=2 and epiyear=2004)
and that works, but what happens when someone wants to see from 10/2002 to 2/2004?
Any suggestions on the best way to do this?
I am trying to get my db to return a date in the format day/month/year but its returning the american version month/day/year.
I'm using a DatePart function that converts my date:
CREATE FUNCTION dbo.DatePart
( @fDate datetime )
RETURNS varchar(10)
AS
BEGIN
RETURN ( CONVERT(varchar(10),@fDate,101) )
END
This returns te american version, can anyone help me to get this to convert the UK way.
Thanks
This is my table and data
CVID | WorkExperience
--------------------------------
2838736
68181101
96568122
1135484
I need to convert into this result
CVID | WorkExperience
--------------------------------
283873 years
681818 years 5 months
9656812 years 2 months
1135484 months
Hello what I'd like to display the following in a matrix report:
Parameter selected: 3 (March), 2008 (Year)
Monthly TO Summed up
ArtNo March <=March
1210 20,500 50,900
1220 21,200 64,000
1230 15,400 40,300
... ... ...
So, in the rows I have the articles and in the column the selected month via parameter. In another column I need to sum up all monthly values up to the selected month, meaning in this example the sum of jan, feb and mar per article.
How to define week of the year in sql? e.g. i want to search all the transcations in week 2, how can i do it?
View 2 Replies View RelatedThis function returns the ISO 8601 week of the year for the date passed. The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.
This code creates the function and demos it for the first day of each ISO week/year from 1990 to 2030.
drop function dbo.F_ISO_WEEK_OF_YEAR
go
create function dbo.F_ISO_WEEK_OF_YEAR
(
@Datedatetime
)
returnsint
as
/*
Function F_ISO_WEEK_OF_YEAR returns the
ISO 8601 week of the year for the date passed.
*/
begin
declare @WeekOfYearint
select
-- Compute week of year as (days since start of year/7)+1
-- Division by 7 gives whole weeks since start of year.
-- Adding 1 starts week number at 1, instead of zero.
@WeekOfYear =
(datediff(dd,
-- Case finds start of year
case
whenNextYrStart <= @date
thenNextYrStart
whenCurrYrStart <= @date
thenCurrYrStart
elsePriorYrStart
end,@date)/7)+1
from
(
select
-- First day of first week of prior year
PriorYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aa.Jan4))/7)*7,-53690),
-- First day of first week of current year
CurrYrStart =
dateadd(dd,(datediff(dd,-53690,aa.Jan4)/7)*7,-53690),
-- First day of first week of next year
NextYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aa.Jan4))/7)*7,-53690)
from
(
select
--Find Jan 4 for the year of the input date
Jan4=
dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0))
) aa
) a
return @WeekOfYear
end
go
-- Execute function on first day of first week of year from 1990 to 2030
select
DT,
ISO_WEEK_OF_YEAR =
dbo.F_ISO_WEEK_OF_YEAR(a.DT)
from
(
select DT = getdate()union all
select DT = convert(datetime,'1990/01/01') union all
select DT = convert(datetime,'1990/12/31') union all
select DT = convert(datetime,'1991/12/30') union all
select DT = convert(datetime,'1993/01/04') union all
select DT = convert(datetime,'1994/01/03') union all
select DT = convert(datetime,'1995/01/02') union all
select DT = convert(datetime,'1996/01/01') union all
select DT = convert(datetime,'1996/12/30') union all
select DT = convert(datetime,'1997/12/29') union all
select DT = convert(datetime,'1999/01/04') union all
select DT = convert(datetime,'2000/01/03') union all
select DT = convert(datetime,'2001/01/01') union all
select DT = convert(datetime,'2001/12/31') union all
select DT = convert(datetime,'2002/12/30') union all
select DT = convert(datetime,'2003/12/29') union all
select DT = convert(datetime,'2005/01/03') union all
select DT = convert(datetime,'2006/01/02') union all
select DT = convert(datetime,'2007/01/01') union all
select DT = convert(datetime,'2007/12/31') union all
select DT = convert(datetime,'2008/12/29') union all
select DT = convert(datetime,'2010/01/04') union all
select DT = convert(datetime,'2011/01/03') union all
select DT = convert(datetime,'2012/01/02') union all
select DT = convert(datetime,'2012/12/31') union all
select DT = convert(datetime,'2013/12/30') union all
select DT = convert(datetime,'2014/12/29') union all
select DT = convert(datetime,'2016/01/04') union all
select DT = convert(datetime,'2017/01/02') union all
select DT = convert(datetime,'2018/01/01') union all
select DT = convert(datetime,'2018/12/31') union all
select DT = convert(datetime,'2019/12/30') union all
select DT = convert(datetime,'2021/01/04') union all
select DT = convert(datetime,'2022/01/03') union all
select DT = convert(datetime,'2023/01/02') union all
select DT = convert(datetime,'2024/01/01') union all
select DT = convert(datetime,'2024/12/30') union all
select DT = convert(datetime,'2025/12/29') union all
select DT = convert(datetime,'2027/01/04') union all
select DT = convert(datetime,'2028/01/03') union all
select DT = convert(datetime,'2029/01/01') union all
select DT = convert(datetime,'2029/12/31') union all
select DT = convert(datetime,'2030/12/30')
) a
CODO ERGO SUM
Does anyone know how I can get last day of month
if I pass a function a given month and and given year.
@Month = 2
@Year = 2004
The result I would need is 29 because there are 29 in
the month of February in the 2004.
Any help on this is greatly appreciated.
Kellie
Hi Guys,
Can anyone please let me know How to find the first day of the week, if I know the weekno and the year.
For ex: If I know the week no is 22 and Year is 2003 then I should find a way to output the date. which is the first day (monday) of that week
for the above query the date will be eg:26/06/2003
I really appreciate your Help
Thanks:confused: Find the Date if I know the week and year
i have this SQL table with a year, week and day-of-week field, but no field containing the actual date
is there a way (e.g. in a view of the SQL table) to transform the year/week/day combination into a date string (e.g. format dd/mm/yyyy) ?
Can I get a date from a week number in a certain year, like I know it's week 7 in 2014 (I may know the month.)
View 7 Replies View RelatedHi,
I have a Serial No which has a length as 14.For eg IL010730123456. IL01 is The Default Code. 07 is the current year and 30 is the week of the year. 123456 is Serial. How shoud I find The Year and week with the help of this serial no ie The First day of the 30th week of 2007.Is it Possible?
Plz Help me with an appropriate solution.
Thanks.....
This seems like a difficult one ..
I am trying to calculate the number of the week within a month of a given date. in other words, given a date I need to find out whether it's the 1st week or 2nd or 3rd or 4th or 5th week of that given month.
for instance let's call my function "weekOfMonth()":
weekOfMonth(4/19/2004) should return 4 (it's the fourth week of april)
weekOfMonth(4/7/2004) should return 2 (it's the second week of april)
etc ..
I want to have the first day of last week for the month of may using getdate()
example for this year is : 26th May
I want the format as 2013-05-26
also
I want to add 28 days for that in anther query.
Running a SQL 7 system on a Windows 2000 server using Access 2000 on clientmachines as a front end. System administrator currently reboots the serveronce a month. Yesterday we had some weird thing with the database whereusers were getting ODBC errors when trying to access it. Rebooted theserver, everything was fine. Suggested to the sa that he reboot the serveronce a week. He said he already does it once a month, and that's sufficient.My POV is that: a) doing it once a week might prevent situations such as theone yesterday; b) even without situations like the one yesterday,performance may be degrading over the course of the month, without our beingaware of it, and rebooting once a week might help performance.Any thoughts on this?Thanks!Neil
View 29 Replies View RelatedI have one matrix that shows the CrashCount (measure) by month. Looks like this:
Jan Feb Mar Apr May Jun Jul Aug Sep Oct Dec
25 90 100 55 52 55 22 55 22 35 65
The user selects a Year as a parameter. I want to put another matrix in that displays the previous year, just as the first year is displayed. How do i edit the second matrix? Do i put the parameter as
=(Parameters!CrashStatisticalYear.Value)-1 or is there some other way this can be done. Without having the user put 2 years. I just want them to pick one. And the previous year shows up in the matrix below this one. Can anyone help me with this...what should i do?
I have to insert YEAR WEEKNUMBER STARTDATE ENDDATE values to a datatable (sayweekrange), if I pass 2011 as year.
Week range starts at 2011-03-28 to 2011-04-03 (because in my database 2010 last week range ends with 2011-03-27) like this I have to generate for 52 weeks.
I want to write a stored procedure, that takes only year as parameter. with this year I have to generate week ranges and insert into my table as shown above.
How can I do this ?
Please provide a function or logic to find week of month..
View 1 Replies View RelatedHi frnds,
Could u pls help me in solving this:
I have a table where i store the Daily details of the stock ( Columns:
Id, Name,Qty,Date)..here in this table it has been populated for the entire year.
I have to get the Sum of the Qty for the Week1,Week2,Week3,Week4,Week5 for all the Stocks(stockid) for any Month given as input.
Pls help me out.
Thanks in Advance
Banu
SQL express 2012. I am trying to case in the where part and having a syntax errors - This is what i am trying to do:
select all the days in week number x including last year if necessary... so if the year start not at the beginning of the week then look in last year as well ( for the same week number of this year and last week nu of last year)
declare
@yyyy int = 2014,-- THE YEAR
@mm int = 1,-- THE MONTH
@week1No int = 1,-- THE WEEK NUMBER IN THE YEAR
@week2No int = 37-- THE last WEEK NUMBER IN last YEAR
select count(tblDay.start)-- tblDay.start IS smallDatetime
[Code] ....
SQL express 2012
I am trying to case in the where part and having a syntax errors - this is what i am trying to do:
Select all the days in week number x including last year if necessary... so if the year start not at the beginning of the week then look in last year as well ( for the same week number of this year and last week nu of last year)
declare
@yyyy int = 2014,-- THE YEAR
@mm int = 1,-- THE MONTH
@week1No int = 1,-- THE WEEK NUMBER IN THE YEAR
@week2No int = 37-- THE last WEEK NUMBER IN last YEAR
select count(tblDay.start)-- tblDay.start IS smallDatetime
[Code] ...