What Does Object Was Open Error Mean?

Feb 14, 2005

Hi, I am accessing an MSDE Database from within a C# program. When calling the OleDbConnection.Open() method, I get the following error:





Exception: System.Data.OleDb.OleDbException


Message: Object was open.


at System.Data.OleDb.OleDbConnection.ProcessResults(Int32 hr)


at System.Data.OleDb.OleDbConnection.InitializeProvider()


at System.Data.OleDb.OleDbConnection.Open()





Now I do not know what this means, since the Connection isn't open. And I do not know why this occurs. I am accessing the same database (but other tables) in the same program several times in the same way and do not get this error.





Any ideas?

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using System;
using System.Data;
using System.Configuration;
using System.Collections;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;
using System.Data.SqlClient;
using System.Web.Configuration;
using System.IO;
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}
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}
}
}
 
Object reference not set to an instance of an object.
Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.NullReferenceException: Object reference not set to an instance of an object.Source Error:



Line 32:
Line 33: string str2 = FileUpload.PostedFile.ContentType;
Line 34: string connectionString = WebConfigurationManager.ConnectionStrings["GSGA"].ConnectionString;
Line 35:
Line 36: //Initialize SQL Server Connection Source File: c:UsersManojDocumentsVisual Studio 2005WebSitesGSGABinaryfrmUpload.aspx.cs    Line: 34  
Stack Trace:




[NullReferenceException: Object reference not set to an instance of an object.]
Binary_frmUpload.btnUpload_Click(Object sender, EventArgs e) in c:UsersManojDocumentsVisual Studio 2005WebSitesGSGABinaryfrmUpload.aspx.cs:34
System.Web.UI.WebControls.Button.OnClick(EventArgs e) +105
System.Web.UI.WebControls.Button.RaisePostBackEvent(String eventArgument) +107
System.Web.UI.WebControls.Button.System.Web.UI.IPostBackEventHandler.RaisePostBackEvent(String eventArgument) +7
System.Web.UI.Page.RaisePostBackEvent(IPostBackEventHandler sourceControl, String eventArgument) +11
System.Web.UI.Page.RaisePostBackEvent(NameValueCollection postData) +33
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'
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Friend WithEvents SqlSelectCommand1 As System.Data.SqlClient.SqlCommand
Friend WithEvents MDData As System.Data.SqlClient.SqlConnection
Friend WithEvents DaAuthorLogin As System.Data.SqlClient.SqlDataAdapter
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Private designerPlaceholderDeclaration As System.Object
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'Do not modify it using the code editor.
InitializeComponent()
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'no code here
End Sub
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'for new author registration
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'to navigate back
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AuthorLoginPassword.Text = ""
End If
End Sub
End Class
 
Thanks in advance,
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Line 63:
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TITLE: Connect to Server
------------------------------

------------------------------
ADDITIONAL INFORMATION:

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