Why Doesnt BETWEEN Give Me My Desired Result?

Dec 9, 2005

I am trying to select records based upon last name

WHERE     (Last_Name BETWEEN 'A%' AND 'C%')

When I run this I get only last names starting with A and B--no C. ?!?

This is confusing to me....I ran it with lastname >= 'A%' and lastname <='C%'
and it returned only names starting with B. Why does SQL ignore the "="


I hope this isnt obvious :/

 

 

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I have a right join query where i have a table where all employees attendance entry are registered and another table where pay master table where al employees details.

I need a query where i get all employee names from right side (pay master table) and the employees in out timings for all employees who punched or not punched their card.

means for selected date i need all the employees details suppose 10 employees who punched or not with empty values even he resigned.

I used right or left join it gives all dates value but when i select particular date i get only the punched details.

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Feb 4, 2008

Hi,
I want to write a query that would display data from the database on the basis of ethnicity in the last 3 years. Not only that, but I also want to see the number of starters, retention and achievement

e.g.

Year 05 Year06 Year 07
Ethnicity 1 Starters
Retention
Achievement

Ethnicity 2 Starters
Retention
Achievement


The problem is that there are multiple ethnicities and I cannot write separate queries for each of them and there are 3 years and I cannot write separate queries for them either. E.g. if i have 5 ethnicities and 3 years, in current situation, I am ending up with writing 15 queries for each of them because I can't write a cross tab query for these.

When I do write the query as follows:


create table #temp_et (
[Year]int NOT NULL,
[Ethnicity] varchar(20),
[Starts]float(4),
[Success]float(4),
[Retention]float(4),
[Achievement]float(4)
)

--Year 05/06
insert into #temp_et
select
CAST(LEFT(pg_expendyrid,2) AS int)[Year],
pg_ethnicgroupname[Ethinicity],
sum([pvstart]) [Starts],

(case when sum(pvstart) = 0 THEN 0 Else convert(decimal(6,3),(sum(pvach)*1.00)/(sum(pvstart)*1.00)*100)end)[Success],
(case when sum(pvstart) = 0 THEN 0 Else convert(decimal(6,3),(sum(pvcomp)*1.00)/(sum(pvstart)*1.00)*100)end)[Retention],
(case when sum(pvstart) = 0 THEN 0 Else convert(decimal(6,3),(sum(pvach)*1.00)/(sum(pvcomp)*1.00)*100)end)[Achievement]
--into temp_et
from pvmd

where pg_expendyrid = '05/06'

group by
pg_ethnicgroupname,
pg_expendyrid
order by
pg_ethnicgroupname




--Year 06/07
insert into #temp_et

select
CAST(LEFT(pg_expendyrid,2) AS int)[Year],
pg_ethnicgroupname[Ethinicity],
sum([pvstart]) [Starts],

(case when sum(pvstart) = 0 THEN 0 Else convert(decimal(6,3),(sum(pvach)*1.00)/(sum(pvstart)*1.00)*100)end)[Success],
(case when sum(pvstart) = 0 THEN 0 Else convert(decimal(6,3),(sum(pvcomp)*1.00)/(sum(pvstart)*1.00)*100)end)[Retention],
(case when sum(pvstart) = 0 THEN 0 Else convert(decimal(6,3),(sum(pvach)*1.00)/(sum(pvcomp)*1.00)*100)end)[Achievement]
--into temp_et
from pvmd

where pg_expendyrid = '06/07'

group by
pg_ethnicgroupname,
pg_expendyrid
order by
pg_ethnicgroupname


--Year 07/08
insert into #temp_et

select
CAST(LEFT(pg_expendyrid,2) AS int)[Year],
pg_ethnicgroupname[Ethinicity],
sum(pvstart) [Starts],

(case when sum(pvstart) = 0 THEN 0 Else convert(decimal(6,3),(sum(pvach)*1.00)/(sum(pvstart)*1.00)*100)end)[Success],
(case when sum(pvstart) = 0 THEN 0 ELSE convert(decimal(6,3),(sum(pvcomp)*1.00)/(sum(pvstart)*1.00)*100)end)[Retention],
(case when sum(pvcomp) = 0 THEN 0 ELSE convert(decimal(6,3),(sum(pvach)*1.00)/(sum(pvcomp)*1.00)*100)end)[Achievement]
--into temp_et
from pvmd
where pg_expendyrid = '07/08'--Expected end year

group by
pg_ethnicgroupname,
pg_expendyrid
order by
pg_ethnicgroupname


SELECT

(CASE [Year] WHEN 05 THEN [Starts] ELSE 0 END) AS [Starts],
(CASE [Year] WHEN 05 THEN [Retention] ELSE 0 END) AS [Retention],
(CASE [Year] WHEN 05 THEN [Achievement] ELSE 0 END) AS [Achievement],
(CASE [Year] WHEN 06 THEN [Starts] ELSE 0 END) AS [Starts],
(CASE [Year] WHEN 06 THEN [Retention] ELSE 0 END) AS [Retention],
(CASE [Year] WHEN 06 THEN [Achievement] ELSE 0 END) AS [Achievement],
(CASE [Year] WHEN 07 THEN [Starts] ELSE 0 END) AS [Starts],
(CASE [Year] WHEN 07 THEN [Retention] ELSE 0 END) AS [Retention],
(CASE [Year] WHEN 07 THEN [Achievement] ELSE 0 END) AS [Achievement]


from #temp_et

This is the closest I could get to the output as in the end I want to put it into a report in Visual Studio .Net i.e. Linking that report through a stored procedure in SQL Server. If I copy all this code to a SP, and dont put the data in a temporary table, the SP will only return the top rows and not the data from year 06/07 and 07/08.

All i can think of is creating a crosstab query, which I cant. So help would be much appreciated.

P.S. The data for Ethnic Group is coming from a view and that is joined which I forgot to mention here in the code.

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-Suppliers have the value 'S' in the colomn CardType.
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The idea is that when a user creates a new business partner, the CardCode should be automatically filled when a new assigned number (highest existing number + 1), according to the value that is selected in CardType (either the letter 'C' or 'S').


What's been done so far:
SELECT top 1
(CASE
WHEN CardType='C' THEN (SELECT top 1 'C' + '' + cast((substring(T0.CardCode, 2, 7) + 1) as varchar) as [nummer]
FROM OCRD T0
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[code]...

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(
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AS
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(


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GO

CREATE TABLE [dbo].[tblExtraPhotos](
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[userID] [int] NOT NULL,
[photoDate] [smalldatetime] NOT NULL,
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GO


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I know of several methods to remove duplicate records but I recently encountered a unique situation where some duplicate records were actually acceptable.

Here is my situation:

I have a table that contains records of individuals who have children so 1 person can have 3 children with different birthdates; but there is also a field that has a specified language. The challenge arises when an individual may have only 1 child but has entered a single record twice. Once with a specifed language and again without which produces a default value of UNKNOWN.

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So I can't eliminate the unwanted duplicates by filtering out records that have UNKNOWN because I would also remove individuals that I need.

EX:
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John Doe 210 Somewhere Ave ENG 1993-10-09
John Doe 210 Somewhere Ave UNK 1993-10-09
Jane Doe 210 Anywhere Ave ENG 1969-12-23
Jane Doe 210 Anywhere Ave UNK 1958-04-15

How could you remove the duplicate for John in this example without affecting Janes duplicate record which is actually ok because she apparently has 2 children with different birthdates whereas John's duplicate record is obviously created because it was entered twice; once without entering
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I have tried a number of things short of creating a cursor which isn't really the best way to resolve this issue since there are millions of rows.

Anyone out there have any input that be helpful? Or has anyone ever had this similar issue? I would be interested in knowing how you addressed the problem.

Any help is appreciated. :)

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[Microsoft follow-up]



Hello,

I think I've found a bug.



I have an expression set on the 'Disable' property of a data-flow task. When the expression evaluates to true the data-flow still executes. That seems wrong to me.



I ahve a demo package here: http://folders.live.com/self.aspx/VQ9oHa1TJjc/Public/SSIS%20Stuff/ExamplePackages/20070717%20Expression%20on%20Disable%20property%20has%20no%20effect/Package1.zip



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I'm on SP1 by the way.



Regards

Jamie

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Hi all,

I copied the following code from Microsoft SQL Server 2005 Online (September 2007):
UDF_table.sql:

USE AdventureWorks;

GO

IF OBJECT_ID(N'dbo.ufnGetContactInformation', N'TF') IS NOT NULL

DROP FUNCTION dbo.ufnGetContactInformation;

GO

CREATE FUNCTION dbo.ufnGetContactInformation(@ContactID int)

RETURNS @retContactInformation TABLE

(

-- Columns returned by the function

ContactID int PRIMARY KEY NOT NULL,

FirstName nvarchar(50) NULL,

LastName nvarchar(50) NULL,

JobTitle nvarchar(50) NULL,

ContactType nvarchar(50) NULL

)

AS

-- Returns the first name, last name, job title, and contact type for the specified contact.

BEGIN

DECLARE

@FirstName nvarchar(50),

@LastName nvarchar(50),

@JobTitle nvarchar(50),

@ContactType nvarchar(50);

-- Get common contact information

SELECT

@ContactID = ContactID,

@FirstName = FirstName,

@LastName = LastName

FROM Person.Contact

WHERE ContactID = @ContactID;

SELECT @JobTitle =

CASE

-- Check for employee

WHEN EXISTS(SELECT * FROM HumanResources.Employee e

WHERE e.ContactID = @ContactID)

THEN (SELECT Title

FROM HumanResources.Employee

WHERE ContactID = @ContactID)

-- Check for vendor

WHEN EXISTS(SELECT * FROM Purchasing.VendorContact vc

INNER JOIN Person.ContactType ct

ON vc.ContactTypeID = ct.ContactTypeID

WHERE vc.ContactID = @ContactID)

THEN (SELECT ct.Name

FROM Purchasing.VendorContact vc

INNER JOIN Person.ContactType ct

ON vc.ContactTypeID = ct.ContactTypeID

WHERE vc.ContactID = @ContactID)

-- Check for store

WHEN EXISTS(SELECT * FROM Sales.StoreContact sc

INNER JOIN Person.ContactType ct

ON sc.ContactTypeID = ct.ContactTypeID

WHERE sc.ContactID = @ContactID)

THEN (SELECT ct.Name

FROM Sales.StoreContact sc

INNER JOIN Person.ContactType ct

ON sc.ContactTypeID = ct.ContactTypeID

WHERE ContactID = @ContactID)

ELSE NULL

END;

SET @ContactType =

CASE

-- Check for employee

WHEN EXISTS(SELECT * FROM HumanResources.Employee e

WHERE e.ContactID = @ContactID)

THEN 'Employee'

-- Check for vendor

WHEN EXISTS(SELECT * FROM Purchasing.VendorContact vc

INNER JOIN Person.ContactType ct

ON vc.ContactTypeID = ct.ContactTypeID

WHERE vc.ContactID = @ContactID)

THEN 'Vendor Contact'

-- Check for store

WHEN EXISTS(SELECT * FROM Sales.StoreContact sc

INNER JOIN Person.ContactType ct

ON sc.ContactTypeID = ct.ContactTypeID

WHERE sc.ContactID = @ContactID)

THEN 'Store Contact'

-- Check for individual consumer

WHEN EXISTS(SELECT * FROM Sales.Individual i

WHERE i.ContactID = @ContactID)

THEN 'Consumer'

END;

-- Return the information to the caller

IF @ContactID IS NOT NULL

BEGIN

INSERT @retContactInformation

SELECT @ContactID, @FirstName, @LastName, @JobTitle, @ContactType;

END;

RETURN;

END;

GO

----------------------------------------------------------------------
I executed it in my SQL Server Management Studio Express and I got: Commands completed successfully. I do not know where the result is and how to get the result viewed. Please help and advise.

Thanks in advance,
Scott Chang

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