Datediff Function With Hrs And Minutes
Feb 9, 2007
I have two date columns one is sent_date and other is approved_date
my requirment is to find the difference between the two dates
which can be minutes/hrs/days.
using datediff function iam able to get it in minusts or hrs but my
output should be of the format hh:mm
23:10 (ie 23 hrs and 10 min) or say
48:00 (for 2 days)
sample date
sent_date approved_date
2/28/06 11:06 2/28/06 11:39
2/2/06 17:42 2/2/06 18:03
2/8/06 16:55 2/8/06 17:38
1/27/06 17:00 1/27/06 17:54
1/26/06 12:08 1/26/06 12:09
2/28/06 15:46 2/28/06 16:26
1/23/06 10:01 1/23/06 10:43
1/26/06 13:46 1/26/06 13:59
1/13/06 13:51 1/13/06 14:47
View 4 Replies
ADVERTISEMENT
Jul 7, 2015
I am going put in the whole query but my question is on changing a datediff minutes amount into DD:HH:MM.
Query is:
select c.APPLICANT_ID as [Applicant ID], aetc.EVENT_TYPE as [Event Type],
cast(aetr.CREATE_DATE as date) as [Registration Date],
cast(aetc.CREATE_DATE as date) as [C Creation Date],
datediff(mi,cast(aetr.CREATE_DATE as datetime),cast(aetc.CREATE_DATE as datetime)) as [time diff],
[Code] .....
I want this as dd:hh:mm rather than just minutes.
Currently this field is just minutes so a figure such as 20, depending on the time difference between the 2 dates.
I have tried the convert statement convert (char(5) ...........,108) within this but that's not working and I have used floor before to do this type of thing but not sure where that should go.
View 9 Replies
View Related
Apr 15, 2008
I need to create a stored procedure to select records that cal_callin_tm (this is a datetime field in table) is less than 10 minutes of the current system datetime. I want to update cal_callin_tm field with current system time and pass back the cal_assign_off_p field to my VS 2008/C# windows form. I'm new at SQL code, I know the basic stuff but this requires more knowledge than I have. I need from you experts the best practice to accomplish coding the SQL. I have some junk code below I have started with, help me out.
Thanks a bunch,
CREATE PROCEDURE SP_DpOffCallIn
(
@offname varchar(40) = null OUTPUT,
)
AS
SELECT * from dpcalldtl
where cal_callstat = 'ON SCENE' and (datediff(minute,0,cal_callin_tm) < datediff(minute, 0, currentdate)
If minute > 10
BEGIN
UPDATE cal_callstat
SET
cal_callin_tm = @dt,
@offname = cal_assign_off_p
END
RETURN
View 10 Replies
View Related
May 9, 2015
I needed to create a stored procedure to lock a user who makes 3 incorect entries of his password. I did it successfully. Now the problem what i have is that i want to lock the user only if he makes the 3 incorrect entries within 30 minutes.
I created a field named "FirstEntryTime" of type datetime that saves the date of the first incorrect entry. I tried to make an if statement:
if (@timesOfEntry <=2 AND DATEDIFF(MINUTE, firstEntryTime,GETDATE()) <= 30)
Begin
Update myTable set ...
End
View 6 Replies
View Related
Mar 2, 2014
Given the two datetimes below, what's the best way to obtain the total duration in hours, minutes and seconds (HH:mm:ss)?
Start Time: 2014-03-02 20:55:00.000
End Time: 2014-03-03 07:00:00.000
Duration = 10:05:00
View 6 Replies
View Related
Nov 23, 2006
Hi, I am facing problem rite now.. I want to calculate the date different minutes between 23:00:00 and 01:00:00.
My code :
datediff(Minute,'01:00:00','23:00:00')
The result is 1320 minutes. (22 hours)... But, the result that I want is 120 minutes (2 hours)....
Can anybody help ???
Thanks in advance...
View 2 Replies
View Related
Nov 12, 2007
Hi,I'm using the datediff function to display the ages of the users in my database. However the age rounds up once they are 35.5 etc...I could create another function which works similar to the DateDiff function, but use math.floor to always round down, but I need to use this function in a SQL statement WHERE clause. Is there any way around this?Thanks,Curt.
View 3 Replies
View Related
Apr 25, 2007
hi
select datediff(m,'3/5/2003',getdate as experience
output is
Experience
----------
49
select (datediff(m,'3/5/2003',getdate()))/12 as experience
output is
Experience
----------
4
but 49/12 is 4.08333=4.1
how i can get this
Actually my task is to output as years.months
Thanks in advance
Malathi Rao
View 7 Replies
View Related
Oct 5, 2006
I am trying to break up the age into column from a dob field for a cross tab report. I can query the datediff with an alias but can not individually change the columns I need like a virtual or temp column, but can't figure out how to accomplish it.
use 'Database'
Select datediff(Year, dob, getdate()) As "Under 22", datediff(Year, dob, getdate()) As "22-45",
datediff(Year, dob, getdate()) As "46-65", datediff(Year, dob, getdate()) As "Over 65"
from 'Table'
WHERE (DATEDIFF(yy, dob, GETDATE()) < 22 OR
DATEDIFF(yy, dob, GETDATE()) BETWEEN 22 AND 45 OR
DATEDIFF(yy, dob, GETDATE()) BETWEEN 46 AND 65 OR
DATEDIFF(yy, dob, GETDATE()) > 66) AND (status = 'Current' OR
status = 'Previous' OR
status = 'non-billable')
View 5 Replies
View Related
Feb 7, 2007
This will give you the time information about how apart two dates are.CREATE FUNCTION dbo.fnTimeApart
(
@FromTime DATETIME,
@ToTime DATETIME
)
RETURNS @Time TABLE ([year] SMALLINT, [month] TINYINT, [day] TINYINT, [hour] TINYINT, [minute] TINYINT, [second] TINYINT, [millisecond] SMALLINT)
AS
BEGIN
DECLARE@Temp DATETIME,
@Mts INT,
@year SMALLINT,
@month TINYINT,
@day TINYINT,
@hour TINYINT,
@minute TINYINT,
@second TINYINT,
@millisecond SMALLINT
IF @FromTime > @ToTime
SELECT@Temp = @FromTime,
@FromTime = @ToTime,
@ToTime = @Temp
SET@Mts =CASE
WHEN DATEPART(day, @FromTime) <= DATEPART(day, @ToTime) THEN 0
ELSE -1
END + DATEDIFF(month, @FromTime, @ToTime)
SELECT@year = @Mts / 12,
@month = @Mts % 12,
@Temp = DATEADD(month, @Mts, @FromTime)
SELECT@day = datediff(hour, @Temp, @ToTime) / 24,
@Temp = DATEADD(day, @day, @Temp)
SELECT@hour = DATEDIFF(minute, @Temp, @ToTime) / 60,
@Temp = DATEADD(hour, @hour, @Temp)
SELECT@minute = DATEDIFF(second, @Temp, @ToTime) / 60,
@Temp = DATEADD(minute, @minute, @Temp)
SELECT@second = DATEDIFF(millisecond, @Temp, @ToTime) / 1000,
@Temp = DATEADD(second, @second, @Temp),
@millisecond = DATEDIFF(millisecond, @Temp, @ToTime)
INSERT@Time (year, month, day, hour, minute, second, millisecond)
SELECT@year,
@month,
@day,
@hour,
@minute,
@second,
@millisecond
RETURN
ENDAnd to test the functionSELECTd.FromDate,
d.ToDate,
x.*
FROM(
SELECT'19690906' AS FromDate, '19760608' AS ToDate UNION ALL
SELECT'19991231', '20000101' UNION ALL
SELECT'20070207', '20070208' UNION ALL
SELECT'20000131', '20000228' UNION ALL
SELECT'20070202', '20070201' UNION ALL
SELECT'20070207', '20070307' UNION ALL
SELECT'20000131', '20000301' UNION ALL
SELECT'20011231 15:24:13.080', '20020101 17:15:56.343' UNION ALL
SELECT'20011231 17:15:56.343', '20020101 15:24:13.080' UNION ALL
SELECT'20020101 15:24:13.080', '20011231 17:15:56.343' UNION ALL
SELECT'20000131', '20000229'
) AS d
CROSS APPLYdbo.fnTimeApart(d.FromDate, d.ToDate) AS x
ORDER BYd.FromDate,
d.ToDateAnd the output isFromDateToDateyearmonthdayhourminutesecondmillisecond
19690906197606086920000
19991231200001010010000
200001312000022800280000
200001312000022900290000
20000131200003010110000
20011231 15:24:13.08020020101 17:15:56.34300115143263
20011231 17:15:56.34320020101 15:24:13.08000022816736
20020101 15:24:13.08020011231 17:15:56.34300022816736
20070202200702010010000
20070207200702080010000
20070207200703070100000
Peter Larsson
Helsingborg, Sweden
View 14 Replies
View Related
Nov 2, 2007
recently i created a system using php and mysql to record faults that the ict technicians could get reported faults out of. so far it does everything i want but some senior members of staff now want the front end to give a report of status, one of the things they wish to see is how many jobs have been completed this week month and year
within my tables is a field date. naturally it has the date submited contained within it. the code i have been using to try and get an output is
mysql_query("SELECT date, datediff('day', date, CURRENTDATE) FROM softwarerepairtable WHERE datediff<= '7' and complete='yes' ");
the complete feild is another contained within the datebase. i have also tried SELECT * datediff('day', date, CURRENTDATE) FROM softwarerepairtable WHERE datediff<= '7' and complete='yes' ");
unfortunatly my limited knowledge of php and sql is holding me back on this. any help guys would be appriacted
View 2 Replies
View Related
May 18, 2007
Hi,
I am trying to use DataDiff function and I have used the following queries:
1.
select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.320') as test
Expected Result: 0 milliseconds
Actual Result: 0 milliseconds
2.
select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.321') as test
Expected Result: 1 milliseconds
Actual Result: 0 milliseconds
3.
select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.322') as test
Expected Result: 2 milliseconds
Actual Result: 3 milliseconds
4.
select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.323') as test
Expected Result: 3 milliseconds
Actual Result: 3 milliseconds
5.
select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.324') as test
Expected Result: 4 milliseconds
Actual Result: 3 milliseconds
6.
select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.325') as test
Expected Result: 5 milliseconds
Actual Result: 6 milliseconds
7.
select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.326') as test
Expected Result: 6 milliseconds
Actual Result: 6 milliseconds
8.
select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.327') as test
Expected Result: 7 milliseconds
Actual Result: 6 milliseconds
9.
select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.328') as test
Expected Result: 8 milliseconds
Actual Result: 6 milliseconds
10.
select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.329') as test
Expected Result: 9 milliseconds
Actual Result: 10 milliseconds
Does any one know, why datediff does not return the Expected Result? There does not seem to be any consistency.
Thanks,
Tim
View 1 Replies
View Related
Jan 25, 2008
I want to create and expression that basically says if a datetime value is today minus 2 days then do another formula.
Right now it looks like this...
Code Snippet
=iif(Fields!Channel_Id.Value="SFE1" and Fields!Report_Date.Value=Today-2,0,(Fields!Total_Apps.Value-Fields!total_apps_null_status.Value))
Basically, it spits an error saying [BC30452] Operator '-' is not defined for types 'Date' and 'Integer'.
Should this be done with DateDiff? if so, how can you specify two days ago?
Thanks much
C-
View 5 Replies
View Related
Feb 3, 2015
I'm trying to use the DateDiff function within my select statement, but I'd like to add the parameter of greater than 30 days. This will have the query only return records where my bill stop date is greater than 30 days from the completion date. I currently have the datediff function within my select statement as
DATEDIFF (d,A.StopBillDate, a.CompletionDate) as [DIFFERENCE]
I would prefer to keep the datediff function within the select statement so as to have difference in days appear as a column within my output.I have been unable to add the parameter of > 30 days to the query without getting an error.
View 2 Replies
View Related
Apr 9, 2007
Hi Experts,I am working on SSRS 2005, and I am facing a problem in counting theno of days.My database has many fields but here I am using only two fieldsThey are Placement_Date and Discharge_DateIf child is not descharged then Discharge_Date field is empty.I am writing below query to count the number of days but is is notworking it is showing the error"The conversion of a char data type to a datetime data type resultedin an out-of-range datetime value."select casewhen convert(datetime,Discharge_Date,103) = '' thendatediff(day,CONVERT(datetime,Placement_Date,103), GETDATE())elsedatediff(day,CONVERT(datetime,Placement_Date,103),CONVERT(datetime,Discharge_Date,103))end NoOfDaysfrom Placement_DetailsSo please tell me where I am wrong?Any help will be appriciated.RegardsDinesh
View 3 Replies
View Related
May 15, 2007
Hi
I regularly use the T-SQL date functions to return the 1st of a particualr month.
e.g.
SELECT DATEADD(m,DATEDIFF(m,0,getdate()),0)
returns 2007-05-01 00:00:00.000
i.e the first of the current month at midnight.
However, when I try to use a similar expression as a derived column in SSIS it returns a completely different date.
DATEADD("month",DATEDIFF("month",(DT_DATE)0,GETDATE()),(DT_DATE)0)
returns 30/05/2007 00:00:00
Any ideas why and how I can obtain the first of a particualr month using SSIS derived column?
View 3 Replies
View Related
Sep 12, 2015
When running a query such as this on a database view:
select count(*) from WWALMDB.dbo.v_AlarmEventHistory2
SQL throws the following error:
The datediff function resulted in an overflow. The number of dateparts separating two date/time instances is too large. Try to use datediff with a less precise datepart.
Oddly on a Table the count(*) function works.
Is there a limit on views or the count(*) function that I am not aware of?
View 3 Replies
View Related
Feb 12, 2008
Dear all, I have the Following Query:SELECT DATEDIFF(day, GETDATE(), RECENT_RESERVATION)AS Expr1,RECENT_RESERVATION FROM EMP WHERE SUN=empName;when i run it inside the query analyzer, it returns two columns. but if run it inside The ASPX page it retuns only one column wich is RECENT_RESERVATION date.Note: i am using one methode that takes care of reading from SQL and assigning the result into an array, it works fine everywhere, but with this query it dosen't work. Any suggestions??
View 6 Replies
View Related
May 2, 2015
I have added one webpage designed in ASP.Net with C# and sql server 2005 as database. There is table for user registration in which there is a column for ProfileCreationDate the data type of that column is date time .
I would like to fetch data of those user who have created profile within 7 days. For getting desired result I am trying this query.
select Name ,Profession,ProfileCreationDate from tblRegistration where DATEDIFF ( Day , '" + System.DateTime.Now + "',ProfileCreationDate)<7 order by ProfileCreationDate DESC
System.DateTime.Now is a function for getting current date time in C#
The query is neither giving error nor giving desired result.
View 4 Replies
View Related
Aug 7, 2015
I have a requirement to use DateDiff(Months,DateTime1,DateTime2) and this must return positive integer values.
Currently negative numbers are being returned because DateTime1 < DateTime2 or DateTime1 > DateTime2 .
The DateTime1 and DateTime2 values are dynamic and either of them can be bigger than the other.
Any query solution so that always positive value is returned.
View 3 Replies
View Related
Apr 21, 2015
My table as data as follow,
IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[table_Data]') AND type in (N'U'))
DROP TABLE [dbo].[table_Data]
GO
/****** Object: Table [dbo].[table_Data] Script Date: 04/21/2015 22:07:49 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
IF NOT EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[table_Data]') AND type in (N'U'))
[code].....
View 6 Replies
View Related
Aug 12, 2005
Hi,
I have a job where the first step starts and checks for a condition. If its not true, I want it to reset itself and start again in 10 minutes. I'm using sp_stop_job and sp_update_jobschedule and, initially, it looks like it works. But since it's a Daily job, the 'Next Run Date' increments to the following day. Even though I'm using sp_update_jobschedule to keep the active_start_date as the same day, it still increments. I've tried updating sysjobschedules directly, but get the same results.
Any thoughts much appreciated! Here's my code:
USE msdb
--This is the part that goes in the job step
--and increments the next_run_time if the condition is true.
If
(Select count('x') from mytable (NoLock)
Where PublicationDate > getdate()) < 1
BEGIN
Declare @ActiveStartDate int
Declare @ActiveStartTime int
Select @ActiveStartDate = active_start_date from msdb.dbo.sysjobschedules (NoLock)
Where schedule_id = 61
Select @ActiveStartTime = active_start_time from msdb.dbo.sysjobschedules (NoLock)
Where schedule_id = 61
EXEC msdb.dbo.sp_stop_job @job_name = 'Owners'
Select @ActiveStartTime = @ActiveStartTime + 1000
EXEC sp_update_jobschedule @job_id = '46C074D4-908D-46AE-8B0C-A23E3AD4A4F6',
@name = 'Daily',
@active_start_date = @ActiveStartDate,
@active_start_time = @ActiveStartTime
End
View 3 Replies
View Related
Mar 27, 2006
I am trying to develop a sql statement that will create a recordset of the min (or max) values in x minute increments over a period of time.
e.g. over a period of 7 days, I have data that was collected in 1 minute intervals. I need to know the min (or max) value in each 10 minute interval over that same period of time.
Is there an efficient way of doing this?
View 3 Replies
View Related
Dec 5, 2005
If I wanted to get everyone DOB who is over 18 how would I do that? I am currently trying something like this, but no luck...
Declare @todays_date datetime
Select from person
CASE
WHEN dateadd(year, datediff (year, Date_Of_Birth, @Todays_Date), Date_Of_Birth) > @Todays_Date -- Date of Birth check
THEN datediff (year, Date_Of_Birth, @Todays_Date) - 1
ELSE datediff (year, Date_Of_Birth, @Todays_Date)
END
>= 18
View 3 Replies
View Related
Jul 27, 2004
I'm using a datediff(mi, start, stop) to get the duration of an operation. i want it displayed in HH:MM format. can anyone help me w/ a way to do that????
tia,
e3witt
View 4 Replies
View Related
Mar 9, 2004
Hello,
My string is:
SELECT weight FROM progress WHERE dateInput = (SELECT MAX(dateInput) FROM progress) AND memberID = 1
The problem is that the MAX dateInput doesn't belongs to memberID 1. It belongs to memberID 2. What I want is that I wanna choose the MAX Date of memberID 1. I thought of maybe using datadiff function. But I don't know how to make the datediff statement. Maybe I can write the datediff statement whereby the least datediff between the dateInput and getdate() will be the row I want. I really appreciate the person that helps me this problem... Thanks 1st of all!
View 2 Replies
View Related
Apr 15, 2004
I am trying to select records from whatever the current date would be and 12 months before whatever the current date is. How would I go about doing this. The table that I am trying to do this with has a year column and a month column.
I was playing with the date diff function, but I can only get dates from the specified date range. I need it to be where if I run it tomorrow, it will get that day and everything within the last 12 months.
View 7 Replies
View Related
Apr 25, 2008
I need to get a listing of all persons who are atleast 18 years of age. A date of birth field in the database is in this format:
4/25/2008 12:00:00 AM
My solution would be where the difference between the current date and the dob is >= 18.
I tried...
select * from table where datediff(yy,dob,getdate)) >= 18.
But this only seems to subtract the years and ignore the days/months, which I need. Could anyone provide the syntax I need?
Help is appreciated. Thanks.
View 3 Replies
View Related
Jun 24, 2008
Hi there i am using the datediff funtion but it does not seem to be inclusive of the two dates eg
SELECT DATEDIFF(day, s_Date, e_date) AS NumberOfDays,*
FROM weekendtest
i know i could do
SELECT DATEDIFF(day, s_Date, e_date)+1 AS NumberOfDays,*
FROM weekendtest
but i was just wondering if there some other function i should use that would be more appropriate
View 3 Replies
View Related
Oct 21, 2004
Hi
I've a problem!!!
i want to use datediff thats no problem. But the first parameter has to
be parameterised. What datatype do i declare it as. i declare it as varchar
it returns me an error : Invalid parameter 1 specified for datediff.
i'm doing this in a stored procedure.
Is there a way out or do i've to use the good old 'IF' or 'Case' ?
regards
pradeep
View 1 Replies
View Related
Oct 19, 2006
Hi,
I have a Table Where I have Two Date columns and I want to find the Differnce in the 3rd column.ie DateReceived - AsOnDate = NoofDays.I tried this code
SELECT SRNO,CONVERT (VARCHAR,AsonDate,102)as ASONDATE,CONVERT(VARCHAR, DateReceived, 102) AS DateReceived,CONVERT(VARCHAR, DateAcknowledged, 102) AS NoofDays,
sum(CASE WHEN DATEDIFF(DAY, DATERECEIVED,ASONDATE, GETDATE())
FROM Details
Plz help me...
Thanks
View 7 Replies
View Related
Jan 27, 2008
SELECT DATEDIFF(mm,0,'01/25/2008')
Returns 1296 what does it represent...
Thanks
View 2 Replies
View Related
Feb 29, 2008
Could somebody please explain to me why I get the following results:
select datepart (ww, '10/02/08') --returns 6
select datepart (ww, '18/02/08') --returns 8
select datediff (ww, '10/02/08', '18/02/08') -- returns 1
I was expecting the third query to return 2.
Thanks.
View 11 Replies
View Related
