Datetime To Integer
Apr 30, 2007
I was just told that it is better to convert all datetime values to integers for performance reasons. Is this generally true? I am working with time series data so datetime values hold important information.
View 10 Replies
ADVERTISEMENT
Jul 20, 2015
Working on a new database where the Date and Time are stored in a Date Time Field.
Then working on an OLDER database file within the same SQL Database contains these 2 items as integers:
transDate = "71615" (July 16, 2015)
transTime = "12345" (01:23:45 AM)
How do we convert both of them into a single SQL DateTime field such as "2015-07-16 01:23:45.000" so that it can be used in a join restricting to a date time in a different SQL File that properly has the DateTime in it?
This works well for converting the transDate Part in the select statement:
  dbo.IntegerToDate(at.transDate) as transDate
  * That returns: "2015-07-16 00:00:00.000"
* The resulting data must work directly in a Microsoft SQL Server Management Studio Query using either using the "on" statement or part of the "where" clause. In other words, NOT as a stored procedure!
Also must be able to be used as a date difference calculation when comparing the 2 files Within say + or - 5 seconds.
View 3 Replies
View Related
Oct 5, 2007
Trying to write the most effective UDF to convert INT to Datetime.
We have a column from a table on AS400 that is a INT type. Some are 4, 5, 6 ,7 digits. I have the 4 digits right. I need to fix it for 5 and 6 digits.
ALTER FUNCTION IntegerToDatetime (@int INT)
RETURNS DATETIME
AS
BEGIN
DECLARE @IntegerToDatetime int
DECLARE @time DATETIME
SET @time = '2001-01-01'
SET @IntegerToDatetime =
CASE
WHEN LEN(@int) = 7
THEN '20' + CAST(SUBSTRING(CAST(@int AS CHAR(7)),2,2) AS int)
+ '-' + CAST(SUBSTRING(CAST(@int AS CHAR(7)),4,2) AS int)
+ '-' + CAST(SUBSTRING(CAST(@int AS CHAR(7)),6,2) AS int)
WHEN LEN(@int) = 6
THEN '19' + CAST(SUBSTRING(CAST(@int AS CHAR(6)),1,2) AS int)
+ '-' + CAST(SUBSTRING(CAST(@int AS CHAR(6)),3,2) AS int)
+ '-' + CAST(SUBSTRING(CAST(@int AS CHAR(6)),5,2) AS int)
WHEN LEN(@int) = 5
THEN '200' + CAST(SUBSTRING(CAST(@int AS CHAR(5)),1,1) AS int)
+ '-' + CAST(SUBSTRING(CAST(@int AS CHAR(5)),2,2) AS int)
+ '-' + CAST(SUBSTRING(CAST(@int AS CHAR(5)),4,2) AS int)
WHEN LEN(@int) = 4 THEN cast(@time AS INT)
END
RETURN (@IntegerToDatetime )
END
GO
INPUT
-------------------------------
990831
981019
RESULT
-------------------------------
1900-01-02 00:00:00.000
1900-05-27 00:00:00.000
http://www.sqlserverstudy.com
View 17 Replies
View Related
Apr 18, 2008
Hi
I use this to get all users from active directory.
SELECT *
FROM openquery(
adsi
,'SELECT name, AccountExpires FROM
''LDAP://company/OU=users,dc=company,dc=com''')
WHERE AccountExpires IS NOT NULL AND AccountExpires not in('0','0x7FFFFFFFFFFFFFFF','9223372036854775807','')
AccountExpires returns values like 128514708000000000 (This value represents the number of 100 nanosecond intervals since January 1, 1601 )
How do I convert this value to Datetime?
select getdate() returns a value like 2008-04-18 10:00:00.00 and that's how I'd like my AccountExpires
View 11 Replies
View Related
Jul 20, 2005
Hi All,How do you convert int value to datetime datatype in sql servere.g 900mins to hh:mm:ssRegardsOla*** Sent via Developersdex http://www.developersdex.com ***Don't just participate in USENET...get rewarded for it!
View 3 Replies
View Related
May 2, 2006
Hello Everyone,
I need help with conversion type. I'm using Visual Basic 6.0 as my frontend and SQL Server 2000 as my backend. There has been existing data in the database. I would like to know how to convert an integer to datetime format. For example:
This is the actual value from the database.
1087912290
1087912327
I'd like to know how to convert it datetime format.
Any help would be greatly appreciated.
Thanks,
Dennis
View 14 Replies
View Related
Jul 20, 2005
Hi all,I have a problem converting datetime to integer (and than back todatetime).Depending whether the time is AM or PM, same date is converted to twodifferent integer representations, which holds as true on reversalback to datetime.AM Example:declare @DI integer; declare @DD datetimeset @DI = cast(cast('3/12/2003 11:34:02 AM' as datetime) as integer)set @DD = cast (@DI as datetime)print @DI; print @DDResult:37690Mar 12 2003 12:00AMPM Example:declare @DI integer; declare @DD datetimeset @DI = cast(cast('3/12/2003 11:34:02 PM' as datetime) as integer)set @DD = cast (@DI as datetime)print @DI; print @DDResult:37691Mar 13 2003 12:00AMNow, this is not a big problem if I knew that this is how it issupposed to work. Is this how SQL Server is supposed to work?
View 3 Replies
View Related
Aug 5, 2013
I have this datetime:Â '2002-12-20 11:59:59'
I want to convert this to date (yyyy-mm-dd) to integer
This works fine for:Â SELECT CONVERT(INT, GETDATE())
But it doesn't work here:Â SELECT CONVERT(INT, '2002-12-20 11:59:59')
I want to convert date to integer without passing through any varchar conversion/result.
View 6 Replies
View Related
Dec 23, 2014
Iwant to convert the datetime to the integer value as shown within the brackets.
----2014-12-21 0:00:00 (1419091200000)
View 1 Replies
View Related
Jul 23, 2006
Edit: There seems to be some interaction between GROUP BY/NEWID() that can cause problems if these functions are used directly in an aggregate query. Please read the posts on this thread about this, and use caution.
This script creates three functions, F_RANDOM_INTEGER, F_RANDOM_SAMPLE, and F_RANDOM_DATETIME. The last parameter of each function must be function NEWID() to generate the random number.
Theses functions are designed for applications where it is necessary to generate random integers, random datetimes, or take random samples from sets of data. Typical applications would be software testing, inventory control, auditing, and product quality testing.
Function F_RANDOM_INTEGER returns a random integer in the range of the input parameters so that the return value is >= @START_INT and <= @END_INT. It is valid for any range of two integer values.
Function F_RANDOM_SAMPLE returns a 1 or a 0 to determine if a sample should be selected, based on the input sample rate. Input parameter @SAMPLE_RATE should be between 1 and 999,999. The sample rate determines how many samples should be selected out of each 1,000,000 samples. A sample rate below 1 will never select a sample, and a sample rate above 999,999 will always select a sample. A sample rate of 1,000 = 0.1%, 50,000 = 5%, 63,775 = 6.3775%, 100,000 = 10%, and 500,000 = 50%.
F_RANDOM_DATETIME returns a random datetime value >= @START_TIME and < @END_TIME. It is valid for any datetime range. Input parameters default, if null, to @START_TIME = '19000101' and @END_TIME = '19000102’. The datetime is random to the level of clock ticks (1/300 of as second). Note that the latest time is not included in the range of datatime values that can be returned. This is to allow selection of times within adjacent time periods, without having to specify times to the level of milliseconds. This means a range of 1990-12-01 01:00:00.000 through 1990-12-01 02:00:00.000 will never return a value of 1990-12-01 02:00:00.000.
The NEWID() function is the basis of the random numbers. These functions should not to be considered random for purposes of data encryption or other high security applications. However, they should be adequate for business applications of the types mentioned above. I conducted extensive testing with the functions where I generated millions of results, analyzed the results various ways to look for non-random patterns, and I saw no evidence of non-random results.
The script also includes a demo of each function, and sample output from the demos is also included.
The demo script uses the number table function, F_TABLE_NUMBER_RANGE, available on this link:
http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=47685
if objectproperty(object_id('dbo.F_RANDOM_INTEGER'),'IsScalarFunction') = 1
begin drop function dbo.F_RANDOM_INTEGER end
go
create function dbo.F_RANDOM_INTEGER
(
@START_INTint,
@END_INTint,
@NEWIDuniqueidentifier
)
returns
int
as
/*
Function: F_RANDOM_INTEGER
This function returns a random integer
value >= @START_INT and <= @END_INT.
Valid for any integer range.
Requires newid() to be input parameter @NEWID
to generate the random number.
-- Return random integer between -100, 200000
select [Random Integer] =
[dbo].[F_RANDOM_INTEGER](-100, 200000,newid())
*/
begin
declare @sn bigint
declare @en bigint
declare @mod bigint
declare @rand_bigint bigint
declare @rand_result int
-- Set default values for input dates if they are null
if @START_INT is null begin set @START_INT = 0 end
if @END_INT is null begin set @END_INT =1000000 end
-- Set order of input parameters so that return value is always
-- the same no matter what order the input values are passed.
if @START_INT > @END_INT
select @sn = @END_INT, @en = @START_INT
else
select @sn = @START_INT, @en = @END_INT
-- Return start int if start int = end int
if @sn = @en return @sn
-- Get modulus
select @mod = @en-@sn+1
-- Get random bigint from input parameter @NEWID
select @rand_bigint = abs(convert(bigint,convert(varbinary(20),@NEWID)))
-- Get random integer
select @rand_result = @sn+(@rand_bigint%@mod)
return @rand_result
end
go
grant execute on dbo.F_RANDOM_INTEGER to public
go
if objectproperty(object_id('dbo.F_RANDOM_SAMPLE'),'IsScalarFunction') = 1
begin drop function dbo.F_RANDOM_SAMPLE end
go
create function dbo.F_RANDOM_SAMPLE
(
@SAMPLE_RATEint,
@NEWIDuniqueidentifier
)
returns
int
as
/*
Function: F_RANDOM_SAMPLE
This function returns a 1 or a 0 to determine if a sample
should be selected, based on the sample rate. It is designed
to select random samples at a specific rate.
Input parameter @SAMPLE_RATE should be between 1 and 999,999.
The sample rate determines how many samples should be
selected out of each 1,000,000 samples. A sample rate below 1
will never select a sample, and a sample rate above 999,999 will
always select a sample. 1,000 = 0.1%, 50,000 = 5%, 63,775 = 6.3775%,
100,000 = 10%, and 500,000 = 50%
Requires newid() to be input parameter @NEWID
to generate the random number.
-- Select sample 200,000 times in 1,000,000 samples (20%)
select [Random Sample] =
[dbo].[F_RANDOM_SAMPLE](200000,newid())
*/
begin
declare @rand_bigint bigint
-- Get random bigint from @NEWID
select @rand_bigint = abs(convert(bigint,convert(varbinary(20),@NEWID)))
-- Select sample if the modulus of @rand_bigint is less than the sample rate
return case when @rand_bigint%1000000 < @SAMPLE_RATE then 1 else 0 end
end
go
grant execute on dbo.F_RANDOM_SAMPLE to public
go
if objectproperty(object_id('dbo.F_RANDOM_DATETIME'),'IsScalarFunction') = 1
begin drop function dbo.F_RANDOM_DATETIME end
go
create function dbo.F_RANDOM_DATETIME
(
@START_TIMEdatetime,
@END_TIMEdatetime,
@NEWIDuniqueidentifier
)
returns
datetime
as
/*
Function: F_RANDOM_DATETIME
This function returns a random datetime
value >= @START_TIME and < @END_TIME.
Valid for any datetime range.
Input parameters default, if null, to:
@START_TIME'19000101'
@END_TIME'19000102'
Requires newid() to be input parameter @NEWID
to generate the random number.
-- Return random time between 08:30 and 12:00
select [Random Time] =
[dbo].[F_RANDOM_DATETIME]('08:30:00.000','12:00:00.000',newid())
*/
begin
declare @st datetime
declare @et datetime
declare @hours int
declare @ms int
declare @ticks bigint
declare @rand_ticks bigint
declare @rand_bigint bigint
declare @remaining_ticks int
declare @return_hours int
declare @return_ms int
-- Set default values for input dates if they are null
if @START_TIME is null begin set @START_TIME = '19000101' end
if @END_TIME is null begin set @END_TIME = '19000102' end
-- Set order of input parameters so that return value is always
-- the same no matter what order the input values are passed.
if @START_TIME > @END_TIME
select @st = @END_TIME, @et = @START_TIME
else
select @st = @START_TIME, @et = @END_TIME
-- Return start time if start time = end time
if @st = @et return @st
-- Get hours boundary difference.
-- Subtract 1 from diff, before dividing by 2 and multiplying by 2
-- so the milliseconds remaining is always positive and
-- hours is always >= zero.
set @hours = ((datediff(hh,@st,@et)-1)/2)*2
-- Get remainder milliseconds
set @ms = datediff(ms,0,@et-dateadd(hh,@hours,@st))
-- Convert remainder milliseconds to
-- SQL Server 'clock ticks' of 1/300 of a second
set @ticks = ((@ms/10)*3) + ((@ms%10)/3)
-- Add hours * tick per hour (3600*300) to give total
-- ticks between @START_TIME and @END_TIME
set @ticks = @ticks + (@hours * 0000001080000 )
-- Get random bigint from input parameter @NEWID
select @rand_bigint = abs(convert(bigint,convert(varbinary(20),@NEWID)))
-- Get random number of ticks
select @rand_ticks = @rand_bigint%@ticks
-- Get hours component of random ticks
select @return_hours = @rand_ticks/1080000
-- Get left over ticks after removing hours.
select @remaining_ticks = @rand_ticks%1080000
--Convert remaining clock ticks back to milliseconds
select @return_ms = ((@remaining_ticks/3)*10) + floor(((@remaining_ticks%3)*3.5))
-- Return the random time between the start and end time
return dateadd(ms,@return_ms,dateadd(hh,@return_hours,@st))
end
go
grant execute on dbo.F_RANDOM_DATETIME to public
go
print '-----------------------------------------------------------------'
print ' Demo F_RANDOM_INTEGER function'
print '-----------------------------------------------------------------'
print ''
declare @t table ([Random Integer] int not null )
insert into @t
select
-- Get integert in range of 1 to 10,000,000
[Random Integer] =
[dbo].[F_RANDOM_INTEGER](1,10000000,newid() )
from
-- Function F_TABLE_NUMBER_RANGE
-- available in Script Library forum
F_TABLE_NUMBER_RANGE(1,100000)
select
[Right Int] = [Random Integer]%10,
[Count] = count(*)
from
@t a
group by
[Random Integer]%10
order by
1,2
select
[Million Range] = [Random Integer]/1000000,
[Count] = count(*)
from
@t a
group by
[Random Integer]/1000000
order by
1,2
go
print '-----------------------------------------------------------------'
print ' Demo F_RANDOM_SAMPLE function'
print '-----------------------------------------------------------------'
print ''
declare @t table ([Sample Taken] int not null )
insert into @t
select
-- Sample rate = 6.3775%
[Sample Taken] = [dbo].[F_RANDOM_SAMPLE](63775,newid())
from
-- Function F_TABLE_NUMBER_RANGE
-- available in Script Library forum
F_TABLE_NUMBER_RANGE(1,100000)
select
[Sample Taken],
[Result Count] = count(*)
from
@t a
group by
[Sample Taken]
order by
1,2
go
print '-----------------------------------------------------------------'
print ' Demo F_RANDOM_DATETIME function'
print '-----------------------------------------------------------------'
print ''
select
Random_Datetime =
convert(varchar(23),[dbo].[F_RANDOM_DATETIME]( a.ST, a.ET,newid() ) ,121) ,
[Start] = convert(varchar(23),a.ST ,121) ,
[End] = convert(varchar(23),a.ET ,121) ,
a.Comment
from
(
select ST = getdate(), ET = getdate()+2 ,
Comment = 'Now thru 2 days from now' union all
select '20060101', '20060102' , 'One day diff' union all
select '20030101', '20030101' ,'Both times same' union all
select '20030101', '20030108' ,'One week diff' union all
select '20021228', '20030104' ,'One week diff' union all
select '20010701', '20010713' ,'12 day diff' union all
select '20010701', '20010714' ,'13 day diff' union all
select '20010630', '20010713' ,'13 day diff' union all
select '19901201 01:00:00.000', '19901201 02:00:00.000' ,'1 hour diff' union all
select '19901201 01:00:33.003', '19901201 02:00:33.003' ,'1 hour diff' union all
select '19901201 01:00:00.000', '19901201 01:30:00.000' ,'30 min diff' union all
select '19901201 01:00:33.447', '19901201 01:30:33.447' ,'30 min diff' union all
select '19901201 01:00:00.000', '19901201 01:05:00.000' ,'5 min diff' union all
select '19901201 01:00:29.123', '19901201 01:05:29.123' ,'5 min diff' union all
select '19901201 01:00:00.000', '19901201 01:01:00.000' ,'1 min diff' union all
select '19901201 01:00:00.000', '19901201 01:00:01.000' ,'1 sec diff' union all
select '19901201 01:00:00.000', '19901201 01:00:00.100' ,'100 ms diff' union all
select '19901201 01:00:00.000', '19901201 01:00:00.050' ,'50 ms diff' union all
select '19901201 01:00:00.000', '19901201 01:00:00.023' ,'23 ms diff' union all
select '19901201 01:00:00.000', '19901201 01:00:00.020' ,'20 ms diff' union all
select '19901201 01:00:00.000', '19901201 01:00:00.013' ,'13 ms diff' union all
select '19901201 01:00:00.000', '19901201 01:00:00.010' ,'10 ms diff' union all
select '19901201 01:00:00.000', '19901201 01:00:00.007' ,'7 ms diff' union all
select '19901201 01:00:00.000', '19901201 01:00:00.003' ,'3 ms diff' union all
select '20030101', '20030201' ,'One month diff 31 days' union all
select '20030101', '20040101' ,'One year diff' union all
select '20050101', '20070101' ,'Two year diff' union all
select '20060101', '20060301' ,'2 month diff' union all
select null, '20060101' ,'Start time null' union all
select '20060102', null ,'End time null' union all
select null, null ,'Both null' union all
select '17530101', '99991231 23:59:59.997' ,'Max datetime diff' union all
select '99991231 23:59:59.997','17530101' ,'Max datetime diff reversed'
) a
Demo Results:
-----------------------------------------------------------------
Demo F_RANDOM_INTEGER function
-----------------------------------------------------------------
(100000 row(s) affected)
Right Int Count
----------- -----------
0 9929
1 10055
2 10009
3 10082
4 9919
5 10022
6 9914
7 9985
8 10098
9 9987
(10 row(s) affected)
Million Range Count
------------- -----------
0 10009
1 9985
2 10142
3 10047
4 9967
5 9907
6 10078
7 10071
8 9790
9 10004
(10 row(s) affected)
-----------------------------------------------------------------
Demo F_RANDOM_SAMPLE function
-----------------------------------------------------------------
(100000 row(s) affected)
Sample Taken Result Count
------------ ------------
0 93669
1 6331
(2 row(s) affected)
-----------------------------------------------------------------
Demo F_RANDOM_DATETIME function
-----------------------------------------------------------------
Random_Datetime Start End Comment
----------------------- ----------------------- ----------------------- --------------------------
2006-07-24 08:21:22.593 2006-07-23 17:54:47.283 2006-07-25 17:54:47.283 Now thru 2 days from now
2006-01-01 06:44:36.897 2006-01-01 00:00:00.000 2006-01-02 00:00:00.000 One day diff
2003-01-01 00:00:00.000 2003-01-01 00:00:00.000 2003-01-01 00:00:00.000 Both times same
2003-01-05 01:57:02.183 2003-01-01 00:00:00.000 2003-01-08 00:00:00.000 One week diff
2003-01-01 20:02:05.550 2002-12-28 00:00:00.000 2003-01-04 00:00:00.000 One week diff
2001-07-02 11:35:11.147 2001-07-01 00:00:00.000 2001-07-13 00:00:00.000 12 day diff
2001-07-02 16:39:57.433 2001-07-01 00:00:00.000 2001-07-14 00:00:00.000 13 day diff
2001-07-06 12:33:53.087 2001-06-30 00:00:00.000 2001-07-13 00:00:00.000 13 day diff
1990-12-01 01:15:42.530 1990-12-01 01:00:00.000 1990-12-01 02:00:00.000 1 hour diff
1990-12-01 01:02:21.647 1990-12-01 01:00:33.003 1990-12-01 02:00:33.003 1 hour diff
1990-12-01 01:21:06.267 1990-12-01 01:00:00.000 1990-12-01 01:30:00.000 30 min diff
1990-12-01 01:26:17.983 1990-12-01 01:00:33.447 1990-12-01 01:30:33.447 30 min diff
1990-12-01 01:00:56.327 1990-12-01 01:00:00.000 1990-12-01 01:05:00.000 5 min diff
1990-12-01 01:03:20.423 1990-12-01 01:00:29.123 1990-12-01 01:05:29.123 5 min diff
1990-12-01 01:00:21.617 1990-12-01 01:00:00.000 1990-12-01 01:01:00.000 1 min diff
1990-12-01 01:00:00.443 1990-12-01 01:00:00.000 1990-12-01 01:00:01.000 1 sec diff
1990-12-01 01:00:00.050 1990-12-01 01:00:00.000 1990-12-01 01:00:00.100 100 ms diff
1990-12-01 01:00:00.000 1990-12-01 01:00:00.000 1990-12-01 01:00:00.050 50 ms diff
1990-12-01 01:00:00.010 1990-12-01 01:00:00.000 1990-12-01 01:00:00.023 23 ms diff
1990-12-01 01:00:00.017 1990-12-01 01:00:00.000 1990-12-01 01:00:00.020 20 ms diff
1990-12-01 01:00:00.007 1990-12-01 01:00:00.000 1990-12-01 01:00:00.013 13 ms diff
1990-12-01 01:00:00.000 1990-12-01 01:00:00.000 1990-12-01 01:00:00.010 10 ms diff
1990-12-01 01:00:00.003 1990-12-01 01:00:00.000 1990-12-01 01:00:00.007 7 ms diff
1990-12-01 01:00:00.000 1990-12-01 01:00:00.000 1990-12-01 01:00:00.003 3 ms diff
2003-01-14 09:00:09.520 2003-01-01 00:00:00.000 2003-02-01 00:00:00.000 One month diff 31 days
2003-08-27 11:47:04.100 2003-01-01 00:00:00.000 2004-01-01 00:00:00.000 One year diff
2006-11-23 03:57:21.737 2005-01-01 00:00:00.000 2007-01-01 00:00:00.000 Two year diff
2006-01-12 08:50:40.717 2006-01-01 00:00:00.000 2006-03-01 00:00:00.000 2 month diff
1933-11-15 13:39:10.050 NULL 2006-01-01 00:00:00.000 Start time null
1997-05-28 06:42:32.407 2006-01-02 00:00:00.000 NULL End time null
1900-01-01 01:50:42.743 NULL NULL Both null
2758-10-18 13:50:47.987 1753-01-01 00:00:00.000 9999-12-31 23:59:59.997 Max datetime diff
8426-03-24 13:51:08.407 9999-12-31 23:59:59.997 1753-01-01 00:00:00.000 Max datetime diff reversed
(33 row(s) affected)
CODO ERGO SUM
View 6 Replies
View Related
Feb 12, 2008
hello everone i have a table named "Concerned_Department" in which i ve a filed "Deadline"of type DateTime.i ve another table named "Cat_description" in wh i ve a filed "Max_Days"of type int in wh i ve values 1,2 and 3.in "Cat_Description" table i ve "Cat_ID" as Primary key of type int.all i want is if i select a row from "Cat_description" with "Max_Days"=1, i want to add this 1 to current date and and place it in the "deadline" field of "Concerned_Department" table.like if today is 12/02/2008 then i want to place 13/02/2008 in "Deadline" filed of "Concerned_Deprtment"tablewhen a row with "Max_Days"=1 from "Cat_Description" is selected.i am using SQL SERVER 2005 Exprees and C#(in source behind).regardsAhmed Bilal Jan
View 2 Replies
View Related
Jul 9, 2007
Hi,
I'm inserting a datetime values into sql server 2000 from c#
SQL server table details
Table nameate_test
columnname datatype
No int
date_t DateTime
C# coding
SqlConnection connectionToDatabase = new SqlConnection("Data Source=.\SQLEXPRESS;Initial Catalog=testdb;Integrated Security=SSPI");
connectionToDatabase.Open();
DataTable dt1 = new DataTable();
dt1.Columns.Add("no",typeof(System.Int16));
dt1.Columns.Add("date_t", typeof(System.DateTime));
DataRow dr = dt1.NewRow();
dr["no"] = 1;
dr["date_t"] = DateTime.Now;
dt1.Rows.Add(dr);
for(int i=0;i<dt1.Rows.Count;i++)
{
string str=dt1.Rows["no"].ToString();
DateTime dt=(DateTime)dt1.Rows["date_t"];
string insertQuery = "insert into date_test values(" + str + ",'" + dt + "')";
SqlCommand cmd = new SqlCommand(insertQuery, connectionToDatabase);
cmd.ExecuteNonQuery();
MessageBox.Show("saved");
}
When I run the above code, data is inserted into the table
The value in the date_t column is 2007-07-09 22:10:11 000.The milliseconds value is always 000 only.I need the millisecond values also in date_t column.
Is there any conversion needed for millisecond values?
thanks,
Mani
View 3 Replies
View Related
Dec 6, 2006
I'm getting error:
String was not recognized as a valid DateTime.
my insert parameter:
<asp:Parameter Name="LastModified" Type="DateTime" DefaultValue= "<%=DateTime.Now.ToString() %>"
my insert command:
InsertCommand="INSERT INTO [Product] ([Enabled], [ProductCode], [ProductName], [ProductAlias], [CarrierId], [DfltPlanId], [DoubleRating], [DoubleRateProductId], [ConnCharges], [StartDate], [EndDate], [Contracted], [BaseProductId], [LastModified], [LastUser]) VALUES (@Enabled, @ProductCode, @ProductName, @ProductAlias, @CarrierId, @DfltPlanId, @DoubleRating, @DoubleRateProductId, @ConnCharges, @StartDate, @EndDate, @Contracted, @BaseProductId, @LastModified, @LastUser)"
LastModified is a datetime field.
Running sql2005
View 1 Replies
View Related
Mar 14, 2007
Hi all, having a little problem with saving dates to sql databaseI've got the CreatedOn field in the table set to datetime type, but every time i try and run it i get an error kicked up Error "The conversion of a char data type to a datetime data type resulted in an out-of-range datetime value.The statement has been terminated."I've tried researching it but not been able to find something similar. Heres the code: DateTime createOn = DateTime.Now;string sSQLStatement = "INSERT INTO Index (Name, Description, Creator,CreatedOn) values ('" + name + "','" + description + "','" + userName + "','" + createOn + "')"; Any help would be much appreciated
View 4 Replies
View Related
Mar 17, 2007
Hey :)I'm facing a lot of troubles trying to create a new pause/break-system. Right now i'm building up the query that counts how many records that is inside 2 fields. Let me first show you my table:
ID (int) | stamp_start (Type: DateTime) | stamp_end (Type: DateTime) | Username (varchar)0 | 17-03-07 12:00:00 | 17-03-07 12:30:00 | Hovgaard
The client will enter a start time and a end time and this query should then count how many records that are inside this periode of time.
Example: The client enter starttime: 12:05 and endtime: 12:35.The query shall then return 1 record found. The same thing if the user enters 12:20 and 12:50.My current query looks like this:SELECT COUNT(ID) AS Expr1 FROM table WHERE (start_stamp <= @pausetime_start) AND (end_stamp >= @pausetime_end)But this will only count if I enter the exact same times as the one inside the table.Any ideas how I can figure this out?Thanks for your time so far :)/Jonas Hovgaard - Denmark
View 2 Replies
View Related
May 13, 2006
Hi,
I have a column of type datetime in sqlserver 2000. Whenever I try to insert the date
'31/08/2006 23:28:59'
I get the error "...datetime data type resulted in an out-of-range datetime value"
I've looked everywhere and I can't solve the problem. Please note, I first got this error from an asp.net page and in order to ensure that it wasn't some problem with culture settings I decided to run the query straight in Sql Query Anaylser. The results were the same. What else could it be?
cheers,
Ernest
View 2 Replies
View Related
Mar 11, 2014
I am inserting date and time data into a SQL Server 2012 Express table from an application. The application is providing the date and time as a string data type. Is there a TSQL way to convert the date and time string to an SQL datetime date type? I want to do the conversion, because SQL displays an error due to the
My date and time string from the application looks like : 3/11/2014 12:57:57 PM
View 1 Replies
View Related
Sep 7, 2007
Nothing difficult, I just need a way to generate a new datetime column based on the column [PostedDate], datetime. So basically I want to truncate the time. Thanks a lot.
View 5 Replies
View Related
Jan 17, 2008
e.g.
1st March 2005 12:00:00
is showing as
01/03/2005 00:00:00
instead of
01/03/2005
Why does this happen?
View 4 Replies
View Related
Jun 15, 2004
I have the following SQL:
select convert(datetime,'04-20-' + right(term,4)) as dt,
'Deposit' as type, a.* from
dbo.status_view a
where right(term,4) always returns a string which constitutes a 4 digit year eg '1999','2004',etc.
The SQL above returns
2004-04-20 00:00:00.000 Deposit ...
Which makes me think that it is able to successfully construct the datetime object inline. But then when I try and do:
select * from
(
select convert(datetime,'04-20-' + right(term,4)) as dt,
'Deposit' as type, a.* from
dbo.status_view a
) where dt >= a.submit_date
I get the following error:
Syntax error converting datetime from character string.
Given that it executes the innermost SQL just fine and seems to convert the string to a datetime object, I don't see why subsequently trying to USE that datetime object for something (in this case comparison with submit_date which is a datetime in the table a) should screw it up. Help!!! Thanks...
View 6 Replies
View Related
Jul 20, 2005
Hi,I have a text file that contains a date column. The text file will beimported to database in SQL 2000 server. After to be imported, I wantto convert the date column to date type.For ex. the text file look likeName dateSmith 20003112Jennifer 19991506It would be converted date column to ydm database in SQL 2000 server.In the table it should look like thisName DateSmith 2000.31.12Jennifer 1999.15.06Thanks in advance- Loi -
View 1 Replies
View Related
Nov 5, 2007
Hi,
I am trying to access a date column up to millisecond precession. So I cast date to as follows:
Code BlockCONVERT(varchar(23),CREATE_DATE,121)
I get millisecond part as a result of query but it€™s €œ000€?.
When I try to test the format by using getDate instead of DateTime column I get right milliseconds.
CONVERT(varchar(23),GetDate(),121) --Gives right milliseconds in return
View 4 Replies
View Related
May 19, 2008
Hi All,
If I run "SELECT 610/100", query analyser returns 6! (wrong)
If I run "SELECT 610.0/100", query analyser returns 6.100000! (correct)
I know I can get the correct result by running "SELECT Cast(610.0 as Float)/100", but why doesn't the first example return 6.1?
Is there some setting on my server which says Integer / Integer = Integer ?
Regards
Xo
View 12 Replies
View Related
Sep 11, 2007
hi,
How do i convert a varchar field into the datetime data type? the reason i need this lies in the requirement that in the earlier data base the column that is hlding the date value is having the data type as varchar. and in the new design the column data type is datetime. i am using sql scripts for the data migration from the older design to the newer and got stuck with this datetime convertion issue. do let me know the best possible solution.
following are the sample data that is theer in the older table for the date.
12/12/2003
1/13/2007
01132004
1-1-2004
1.2.2001
there is no uniformity of the data that is stored currently.
thnkx in adv.
rahul jha
View 11 Replies
View Related
May 21, 2015
I have a table that has a unique ID and a datetime of when something changed.
See example:
IDÂ Â Â TimeStamp
16094Â Â Â 2013-11-25 11:46:38.357
16095Â Â Â 2013-11-25 11:46:38.430
16096Â Â Â 2013-11-25 11:46:38.713
16097Â Â Â 2013-11-25 11:46:38.717
16098Â Â Â 2013-11-25 11:46:38.780
[Code] ....
Is there a way I can calculate the difference between row 16106 and 16105 and enter it in line 10601.
View 10 Replies
View Related
Feb 13, 2008
My question is, i guess, a simple one:
When is it more convenient to use a uniqueid Data Type instead of a smallint, tinyint, bigint, etc (any type of int) when the field is gonna be the primary key for the table?
View 1 Replies
View Related
Oct 7, 2004
hi all,
i have an autonumber field (primary key) and another integer field as part of a table. What i want to do is when a record is created, the default value of the integer field should be the_autonumber+1000 for eg record with pk 82 will have an integer field that's automatically 1082. Would it be possible to do this ? Thanks in advance.
View 2 Replies
View Related
May 19, 2005
Public Function insertReport(ByVal userID As String, ByVal taskID As Integer) As DataSet
Dim ds As New DataSet
Dim da As New SqlDataAdapter("INSERT INTO report(userID, taskID) VALUES ('" + userID + "', " + taskID + ")", cn)
cn.Open()
da.Fill(ds)
cn.Close()
Return ds
End Function
Above is my code I used to invoke when inserting a record. But i receive an error message when i try to insert the integer. I cannot see where the problem lies..my datatype in sql server is int. Can anyone see what is wrong with it. Thank you in advance.
View 2 Replies
View Related
Mar 16, 2006
I have an sql statmetn that counts all the votes in the table. i need this to calculate the quota. My problem is how to i get the value(i.e the count of the votes) into the area thats colored red below?
SqlCommand SqlCmd1 = new SqlCommand("SELECT count(vote)FROM PRTest", SqlCon1);
int quota = (count(Vote) + 1) / ((11) + 1);
Response.Write(quota);
View 1 Replies
View Related
Apr 17, 2006
I use MS SQL Server 2005...Is there a structural advantage/disadvantage with using GUID as oposed to an integer?(also I use the sqltableprofileprovider and it doesnt seem to work with uniqueidentifiers)
View 6 Replies
View Related
Dec 4, 2000
Hi all,
I have a situation where I will have to insert a value(whole number) into the table where the the value is more than what the Integer can hold , I was wondering is there any other datatype which i can use other than integer
Thanks in advance.
Sanjeev Kumar
View 1 Replies
View Related
Dec 3, 2004
I had a field called camp is integer data type. I just found it had a default value, but the value is " (0) ", not just " 0 ". It should be 0, right? why it use (0), are they same? thanks.
View 7 Replies
View Related
May 18, 2008
I have some integers I want to format prefixed with zeros, e.g. 1235 would become 001235 and 445 would become 000445,
View 2 Replies
View Related