Day Of Week Comparison For Contact Availability?
Sep 19, 2013
I am trying to figure out the availability of a contact by comparing their available flag to the current day of the week. IE, the contact has 7 BIT fields in the table,1 for each day of the week, being T or F depending on if they are available. I'm trying to figure out how to read the correct field based on the day of the week to see if their available (T) that day for a notification. Each field name in the table is as such: mon, tue, wed, etc. I can get the current DOW from sql and trim it to the same length and case of the field names to try and figure out which one I need to check whether that fields contents are true or not.
View 14 Replies
ADVERTISEMENT
Nov 30, 2015
We are trying to compare our current calendar week (based on Monday being the first day of the week) with the previous calendar week.Â
I'm trying to produce a line chart with 2 axis:
- x axis; the day of the week (Mon, Tues, Wed etc - it is fine for this to be a # rather than text e.g. 1 = Mon, 2 = Tues etc)
- y axis; the cumulative number of ordersÂ
The chart needs two series:
Previous Week. The running count of orders placed that week.Â
Current Week. The running count of orders placed this week.Â
Obviously in such a chart the 'Current Week' series is going not going to have values along the whole axis until the end of the week. This is expected and the aim of the chart is to see the current week compares against the previous week for the same day.Â
I have two tables:
Orders TableCalendar Table
The calendar table's main date column is [calDate] and there are columns for the usual [calWeekNum], [calMonth] etc.Â
My measure for counting orders is simply; # Orders: = countrows[orders].
How do I take this measure and then work out my two series. I have tried numerous things such as adapting TOTALMTD(), following articles such as these:
-Â [URL] ...
-Â [URL] ...
But I have had no luck. The standard cumulative formulas do work e.g. if I wanted a MTD or YTD table I would be ok, it's just adjusting to a WTD that is causing me big issues.
View 3 Replies
View Related
Apr 9, 2013
How can I get Saturday's date given the week number?
This is my week number, SELECT DATEPART(WEEK, DATEADD(MONTH, +3, ApptDt2)). I need to get Saturday's date from this week.
View 9 Replies
View Related
Sep 17, 2015
i have the following table I need to select dates grouping them by weeks, my week start is Saturday to Friday
CREATE TABLE weekdays
(
datevalue datetime NOT NULL
, numericvalue INT NOT NULL
);
INSERT INTO weekdays (datevalue, numericvalue) VALUES
[code]....
The output should look like this
weeknototalvalue
362015-09-01 00:00:00.000
362015-09-02 00:00:00.000
372015-09-07 00:00:00.000
372015-09-08 00:00:00.000
382015-09-12 00:00:00.000
382015-09-13 00:00:00.000
382015-09-14 00:00:00.000
392015-09-19 00:00:00.000
View 4 Replies
View Related
May 23, 2007
Hi all,
I'd like to add a yesterday dimension member to a new dimension, like a "Time Utility" dimension, that references the second last day of non empty data in a cube.
At the moment, I'm doing this:
Code Snippet
create member [MIA DW].[DATE TIME].[Date].[Yesterday]
as [DATE TIME].[Date].&[2007-01-01T00:00:00]
select [Measures].members on 0,
non empty [DATE TIME].[Date].members on 1
from [MIA DW]
But the [yesterday] member does not seem to belong to [DATE TIME].[Date].members?
So I guess there's two questions:
1) Can I have a new empty dimension which contains all these special members like "Yesterday" or "This Week" and "Last Week" (these last two obviously refer to a set of Dates)
2)How come the Yesterday member is not returned by the .members function?
Thanks
Greg
View 3 Replies
View Related
Jan 29, 2014
I am adding week hrs using while loop , but it can continue next week hrs also.
I can get every week start hrs while update @tem1 table
employeeidreportdatereportatleftattoaccountwrhrn
12902014-01-29 00:00:00.00009:3019:1556001
12902014-01-28 00:00:00.00009:0018:4555802
12902014-01-27 00:00:00.00009:0018:455585583
12902014-01-25 00:00:00.00008:0010:0012004 -- week end
12902014-01-24 00:00:00.00009:1718:4554105
12902014-01-23 00:00:00.00009:1918:4654606
12902014-01-22 00:00:00.00009:1718:4754507
12902014-01-21 00:00:00.00009:1618:3552608
12902014-01-20 00:00:00.00009:1818:555435439
My loop statement
while(select MAX(wrh) from @tem1 where wrh = 0) < 1
begin
update @tem1
set wrh = (select toaccount from @tem1
where reportdate = (select min(reportdate) from @tem1 where wrh = 0))+(select max(wrh) from @tem1)
where wrh = (select max(wrh) from @tem1 where wrh = 0 )
and reportdate = (select min(reportdate) from @tem1 where wrh = 0)
end
this is the result while executing loop statement .
employeeidreportdatereportatleftatdehdrhwehwrh
129029 Jan 201409:3019:15008:0009:20024:00065:54
129028 Jan 201409:0018:45008:0009:18016:00056:34
129027 Jan 201409:0018:45008:0009:18008:0009:18
129025 Jan 201408:0010:00005:0002:00045:00047:16 -- week end
129024 Jan 201409:1718:45008:0009:01040:00045:16
129023 Jan 201409:1918:46008:0009:06032:00036:15
129022 Jan 201409:1718:47008:0009:05024:00027:09
129021 Jan 201409:1618:35008:0008:46016:00018:04
129020 Jan 201409:1818:55008:0009:03008:0009:03
How to update only that week hrs , don't continue next week...
View 4 Replies
View Related
Apr 29, 2008
In my reports I am extracting the data of number of people joined in all the weeks of the year. And in one of reports I have to extract the data of the number of people joined until the last week from the first week. I am trying out all the logics but nothing is working for me as such. Can any one help me with this issue??????
View 4 Replies
View Related
Jul 23, 2015
I need a Select sentence that return me the first week of the month for a given week.
For example If I have week number 12 (Begins 2015/03/16 and Ends 2015/03/22) I need that returns 9, I mean Week number 9 wich is the first week of march (having in mind @@DATEFIRST).
I only need give a week number of the year and then returns the week number of the first week of that month.
View 34 Replies
View Related
Feb 2, 2008
I'm looking for a way to convert the [week number, year] back to the date for the 1st day of that week.
Example (assuming DATEFIRST has been set to 1) : Week 3, 2008 = January 14, 2008
Is there a SQL function that will do this?
Thanks,
Mike
View 11 Replies
View Related
Jun 6, 2006
seriously now
View 1 Replies
View Related
Aug 15, 2006
I have a query that run every day to update a summary table which has week number and day of week. what I currently do is delete all records from the summary table and then summarize all the data availabe from four tables adn then populate the table daily. I want to know if I can run the update query to run only for the week number and day of week depending on getdate. Can I do this?
Please help..
View 1 Replies
View Related
Jan 18, 2006
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK returns the ISO 8601 Year Week Day of Week in format YYYY-W01-D for the date passed. W01 represents the week of the year from W01 through W53, and D represents the day of the week with 1 = Monday through 7 = Sunday.
The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.
This code creates the function and demos it for the first day, first date+60, and first date+364 for each ISO week/year from 1990 to 2030.
drop function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
GO
create function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
(
@Datedatetime
)
returnsvarchar(10)
as
/*
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK
returns the ISO 8601 Year Week Day of Week
in format YYYY-W01-D for the date passed.
*/
begin
declare @YearWeekDayOfWeekvarchar(10)
Select
--Format to form YYYY-W01-D
@YearWeekDayOfWeek =
convert(varchar(4),year(dateadd(dd,7,a.YearStart)))+'-W'+
right('00'+convert(varchar(2),(datediff(dd,a.YearStart,@Date)/7)+1),2) +
'-'+convert(varchar(1),(datediff(dd,a.YearStart,@Date)%7)+1)
from
(
select
YearStart =
-- Case finds start of year
case
whenNextYrStart <= @date
thenNextYrStart
whenCurrYrStart <= @date
thenCurrYrStart
elsePriorYrStart
end
from
(
select
-- First day of first week of prior year
PriorYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aaa.Jan4))/7)*7,-53690),
-- First day of first week of current year
CurrYrStart =
dateadd(dd,(datediff(dd,-53690,aaa.Jan4)/7)*7,-53690),
-- First day of first week of next year
NextYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aaa.Jan4))/7)*7,-53690)
from
(
select
--Find Jan 4 for the year of the input date
Jan4=
dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0))
) aaa
) aa
) a
return @YearWeekDayOfWeek
end
go
-- Execute function on first day, first day+60,
-- and first day+364 for years from 1990 to 2030.
select
DT= convert(varchar(10),DT,121),
YR_START_DT =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT),
YR_START_DT_60 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+60),
YR_START_DT_365 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+364)
from
(
select DT = getdate()union all
select DT = convert(datetime,'1990/01/01') union all
select DT = convert(datetime,'1990/12/31') union all
select DT = convert(datetime,'1991/12/30') union all
select DT = convert(datetime,'1993/01/04') union all
select DT = convert(datetime,'1994/01/03') union all
select DT = convert(datetime,'1995/01/02') union all
select DT = convert(datetime,'1996/01/01') union all
select DT = convert(datetime,'1996/12/30') union all
select DT = convert(datetime,'1997/12/29') union all
select DT = convert(datetime,'1999/01/04') union all
select DT = convert(datetime,'2000/01/03') union all
select DT = convert(datetime,'2001/01/01') union all
select DT = convert(datetime,'2001/12/31') union all
select DT = convert(datetime,'2002/12/30') union all
select DT = convert(datetime,'2003/12/29') union all
select DT = convert(datetime,'2005/01/03') union all
select DT = convert(datetime,'2006/01/02') union all
select DT = convert(datetime,'2007/01/01') union all
select DT = convert(datetime,'2007/12/31') union all
select DT = convert(datetime,'2008/12/29') union all
select DT = convert(datetime,'2010/01/04') union all
select DT = convert(datetime,'2011/01/03') union all
select DT = convert(datetime,'2012/01/02') union all
select DT = convert(datetime,'2012/12/31') union all
select DT = convert(datetime,'2013/12/30') union all
select DT = convert(datetime,'2014/12/29') union all
select DT = convert(datetime,'2016/01/04') union all
select DT = convert(datetime,'2017/01/02') union all
select DT = convert(datetime,'2018/01/01') union all
select DT = convert(datetime,'2018/12/31') union all
select DT = convert(datetime,'2019/12/30') union all
select DT = convert(datetime,'2021/01/04') union all
select DT = convert(datetime,'2022/01/03') union all
select DT = convert(datetime,'2023/01/02') union all
select DT = convert(datetime,'2024/01/01') union all
select DT = convert(datetime,'2024/12/30') union all
select DT = convert(datetime,'2025/12/29') union all
select DT = convert(datetime,'2027/01/04') union all
select DT = convert(datetime,'2028/01/03') union all
select DT = convert(datetime,'2029/01/01') union all
select DT = convert(datetime,'2029/12/31') union all
select DT = convert(datetime,'2030/12/30')
) a
Function Test Results:
DT YR_START_DT YR_START_DT_60 YR_START_DT_364
---------- ----------- -------------- ---------------
2006-01-18 2006-W03-3 2006-W11-7 2007-W03-3
1990-01-01 1990-W01-1 1990-W09-5 1991-W01-1
1990-12-31 1991-W01-1 1991-W09-5 1992-W01-1
1991-12-30 1992-W01-1 1992-W09-5 1992-W53-1
1993-01-04 1993-W01-1 1993-W09-5 1994-W01-1
1994-01-03 1994-W01-1 1994-W09-5 1995-W01-1
1995-01-02 1995-W01-1 1995-W09-5 1996-W01-1
1996-01-01 1996-W01-1 1996-W09-5 1997-W01-1
1996-12-30 1997-W01-1 1997-W09-5 1998-W01-1
1997-12-29 1998-W01-1 1998-W09-5 1998-W53-1
1999-01-04 1999-W01-1 1999-W09-5 2000-W01-1
2000-01-03 2000-W01-1 2000-W09-5 2001-W01-1
2001-01-01 2001-W01-1 2001-W09-5 2002-W01-1
2001-12-31 2002-W01-1 2002-W09-5 2003-W01-1
2002-12-30 2003-W01-1 2003-W09-5 2004-W01-1
2003-12-29 2004-W01-1 2004-W09-5 2004-W53-1
2005-01-03 2005-W01-1 2005-W09-5 2006-W01-1
2006-01-02 2006-W01-1 2006-W09-5 2007-W01-1
2007-01-01 2007-W01-1 2007-W09-5 2008-W01-1
2007-12-31 2008-W01-1 2008-W09-5 2009-W01-1
2008-12-29 2009-W01-1 2009-W09-5 2009-W53-1
2010-01-04 2010-W01-1 2010-W09-5 2011-W01-1
2011-01-03 2011-W01-1 2011-W09-5 2012-W01-1
2012-01-02 2012-W01-1 2012-W09-5 2013-W01-1
2012-12-31 2013-W01-1 2013-W09-5 2014-W01-1
2013-12-30 2014-W01-1 2014-W09-5 2015-W01-1
2014-12-29 2015-W01-1 2015-W09-5 2015-W53-1
2016-01-04 2016-W01-1 2016-W09-5 2017-W01-1
2017-01-02 2017-W01-1 2017-W09-5 2018-W01-1
2018-01-01 2018-W01-1 2018-W09-5 2019-W01-1
2018-12-31 2019-W01-1 2019-W09-5 2020-W01-1
2019-12-30 2020-W01-1 2020-W09-5 2020-W53-1
2021-01-04 2021-W01-1 2021-W09-5 2022-W01-1
2022-01-03 2022-W01-1 2022-W09-5 2023-W01-1
2023-01-02 2023-W01-1 2023-W09-5 2024-W01-1
2024-01-01 2024-W01-1 2024-W09-5 2025-W01-1
2024-12-30 2025-W01-1 2025-W09-5 2026-W01-1
2025-12-29 2026-W01-1 2026-W09-5 2026-W53-1
2027-01-04 2027-W01-1 2027-W09-5 2028-W01-1
2028-01-03 2028-W01-1 2028-W09-5 2029-W01-1
2029-01-01 2029-W01-1 2029-W09-5 2030-W01-1
2029-12-31 2030-W01-1 2030-W09-5 2031-W01-1
2030-12-30 2031-W01-1 2031-W09-5 2032-W01-1
(43 row(s) affected)
CODO ERGO SUM
View 2 Replies
View Related
Nov 20, 2015
need to migrate a cluster with an AG dtabases to new data center cluster with AG.
I was wondering if is possible to do mirroring on top of the AG configuration? or what other options could be to migrate a cluster that has 3 nodes and setup the ag databases to a new datacenter.
View 17 Replies
View Related
May 2, 2007
hi friends,
how to get the date of the first/last day of the week in sql...
can any one help me
Cheers,
raj
View 5 Replies
View Related
Apr 5, 2007
I have a database which has contact column eg. Mr Peter Smith
I am writing a new database which is to have three seperate columns.. saluation, first name and surname. What would be the best way to split the column up?? I was thinking on concentrating on the spaces??
Note: some conacts may not have saluation inc in the contact column, and in this case the saluation column should be blank...
Thanks
View 1 Replies
View Related
Apr 17, 2007
Been learning web dev for five months in c#.
The problem I have is that some weeks ago I moved my application to a new folder in my
hard drive. All seemed ok but now my connection strings to insert data no longer work and
throw exception saying...Object referance not set to an instance of an object.
I dug into the new folder and it has created a new sql server ( I think) in app .data
how do I connect to this new server and how do I find its connection strings.
View 9 Replies
View Related
Feb 8, 2007
I have a contact table and a customer table. The two tables will contain columns like
First name
Last Name,
Date of Birth
Post Code,
House Number
Street Name
etc.
I would like to find the different combinations in which I can relate the customer and contact data.
Like its is possible that the first name and last name are same but date of birth is different. This indicates that the contact and customer is the same. Now I do not know these combinations and I would like to have this set generated for me.
From Integration Service (Sql Server 2005) I get the data and I would like to know the patterns in which data will differ. Is there any way of achieving this?
I am very new to Data Mining and would like to have some direction as to how to progress with this.
View 1 Replies
View Related
Jun 8, 2006
I downloaded Business Contact Manager. With the download an SQL server is part of the download. When I rebooted my machine. The SQL server is not connected.
It's asking for:
Server
Service
How is this process completed to operate correctly?
Thank you,
Golf4Dee
View 3 Replies
View Related
Sep 23, 2005
I'm new to SQL with 2 weeks under my belt....lol, so this may be a simple edit:
When I run the following query, I can get a list of all dups in the contact field:
++++++++++++++++++++++++++++++++++
SELECT full_name,
COUNT(full_name) AS NumOccurrences
FROM contact
GROUP BY full_name
HAVING ( COUNT(full_name) > 1 )
++++++++++++++++++++++++++++++++++
However:
I need to make sure I am de-activating (active = 0) only the contacts where they are listed more then once within the same company table (company.company_id) and the condition is that phone is NULL. I can't seem to make it work. Does anyone have any suggestions for an UPDATE I can use?
View 2 Replies
View Related
May 26, 2000
Hello,
I am looking for SQL Server contact management software options. Our company is currently looking at GoldMine Sales & Marketing, but we would be interested in knowing about options that may be a little more intuitive/user-friendly. Please let me know if you have some leads.
THANKS!
Sharon
View 1 Replies
View Related
Feb 20, 2012
I am trying to find out the the Average number of contact hours per student. in Reporting Services 2005. The contact hours is the in the Totaltime field
Is this formula correct
=Sum(Fields!TotalTime.Value)/Avg(Fields!TotalTime.Value) is in the =Fields!StateServices.Value Group
My groups are
=Fields!Student_ID.Value
=Fields!StateCategory.Value
=Fields!StateServices.Value
Code:
SELECT Student_ind.[Student ID], ParticipantActivity.ActivityDate, School_tbl.[Studentschool Id], School_tbl.schoolID, ParticipantActivity.TotalTime,
ParticipantActivity.Services, ParticipantActivity.Activity, Student_ind.SSID, ParticipantActivity.StateCategory, ParticipantActivity.StateServices
FROM ParticipantActivity INNER JOIN
School_tbl INNER JOIN
Student_ind ON School_tbl.[Student ID] = Student_ind.[Student ID] ON ParticipantActivity.[Student ID] = Student_ind.[Student ID]
[code]....
View 6 Replies
View Related
May 25, 2007
Hi, this is my first post to this forum so thank you all in advance..
I am trying to design a database to store information about the Specification required by each customer. And the main problem I am having is how to store 2 instants of ContactID (from CustomerContacts table) in a seperate table called CustomerSpec.
For example each Customer has many contacts,(the Customer data is stored in a table called Customers which has a one to many relationship with the CustomerContacts table) each customer has one and only one Customer spec, and each customer spec needs to have 2 customer contacts, ie. one for Artwork and one production. (it should also be possible to have the same contact for both Artwork and production).
The problem is how to associate these contactId's with the customer spec...(if there was only one Contact per spec I could simply link the CustomerContacts table with the CustomerSpec table and drop ContactID into CustomerSpec as a foreign key.. But I am stuck to how to save more than one ID..
Can you help please..
View 6 Replies
View Related
May 22, 2015
I have a large data set with 10s of millions of rows of contact information. The data is in CSV format and contains 48 columns of information (First name, MI, last name, 4 part address, 10+ demographic points, etc.) and I'm struggling with how I should design the database and normalize this data, or if I should normalize this data.
My 2 thoughts for design were either:
Break the columns into logical categorical tables (i.e. BasicContactInfo, Demographics, Financials, Interests, etc.) Keep the entire row in one table, and pull out the "Objects" into another table (i.e. ContactInformation, States, ZIPCodes, EmployementStatus, EthnicityCodes, etc.)
The data will be immutable for the most part, and when I get new data, I'll just create a new database and replace the old one.
The reason I like option 1 is because it makes importing easier, since I can just insert the appropriate columns from each row into the appropriate tables. Option number 2 feels like it would be faster to get metrics on the data, like how many contacts live in which states, or what is the total number of unique occupations in the data set. Plus I'll be able to make relationships between the tables, like which state is tied to which zipcode, which city is tied with which county, etc. Importing that data might be more tricky, since I don't think SQL Bulk Copy will allow for inserting into normalized tables like that.
The primary use for this data is to allow our sales force to create custom lists of contact information based on a faceted search page. The sales person would create the filter, and then I will provide them with the resulting data so they can start making business contacts. Search performance needs to be good. Insert, update, and deletes won't happen once the data has been imported.
What should I look for in designing this database? Any good articles on designing tables around wide data sets like my contact information?Â
View 6 Replies
View Related
Aug 14, 2007
Is there any web sit or weblog for contacting SQL Serve Database Engine Team?
View 4 Replies
View Related
Jan 9, 2015
Split function. I have records of multiple users, the last value of every record is a contact number (10 Digits- Numeric), I want a split function which can take the whole text and split the records on the basis of contact number.
In order words i want SQL to locate the contact number and move to the next record after that and so on till the end of the text.
create table
tbl_1
(txt varchar (max))
insert into tbl_1 values ('john asfasdf 535 summit ave franklin lks nj 15521 510_644_1079 na na 5,8/12 executive,
finance finance and planning far 5537 21133 8.25 126 ronald d hensor jr. 5575621596
[Code] .....
Output
john jimenez 535 summit ave franklin lks nj 15521 510_644_1079 na na 5,8/12 executive,finance finance and planning far 5537 21133 8.25 126 ronald d hensor jr. 5575621596
jeffrey galione 57 allen dr wayne nj 15810 562_434_0710 na na 5,8/12 executive, technical sales and support good 8137 91630 8.25 126 eileen oneal 8258364083
[Code] ....
View 6 Replies
View Related
Aug 11, 2015
I have a bunch of contacts that I've scored how well their names match to other contacts in the same business. I can programmatically figure out how to parse the results, but would like to know how to do this via SQL. My problem is for Business_fk 968976 I have 7 contacts. In the end I should have 4 contacts based on name match. For the business key listed Gerardo Lopez is in the ContactScore table twice for Contact keys 7355719 and 57028145. I then have two rows like so:
PossibleBusinessContactMatch_pk BusinessContact_fk Business_fk BusinessContactMatch_fk MatchTypeCode MatchScore MatchRank FirstName LastName Phone Email
------------------------------- ------------------ ----------- ----------------------- ------------- ----------- ----------- -------------------------------------------------- -------------------------------------------------- ---------- --------------------------------------------------------------------------------------------------------------------------------
1772960 57028145 968976 7355719 C 46 1 GERARDO I LOPEZ 8162214000
838834 7355719 968976 57028145 C 50 1 GERARDO
Each reference each other, and 2 is a good case, a more difficult case would have key 1 listed 10 times showing a ContactMatch_fk of 2 - 11, and then Contact_fk 2 listed 10 times with a ContactMatch_fk of 1, 3-11.I know 57028145 maps to 7355719 from the first row in the ContactScore table, so when Contact_fk of 7355719 comes up I should be able to skip it and not process that match. Hopefully that makes sense. Anyway here is the test data:
IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[ContactScore]') AND type in (N'U'))
DROP TABLE [dbo].[ContactScore];
GO
CREATE TABLE [dbo].[ContactScore]
(
[ContactScore_pk]INT NOT NULL,
[Contact_fk]INT NOT NULL,
[code]..
View 9 Replies
View Related
Oct 17, 2007
I have tried a number of times to install BCM and it just does not want to reinstall and it tells me to look at log file. I cant understand what I am looking at in log file. This is a reinstall and there is very little help I can find. It does not even install SQl express?
View 1 Replies
View Related
Feb 27, 2008
I previously installed Office 2007. I tried to install the Business Contact Manager (disk 2) and this error appeared.
Setup failed to install the required component Microsoft SQL Server 2005 Express (MSSMLBIZ). Microsoft Office Professional 2007 CD 2 cannot continue. See C:Program FilesMicrosoft SQL Server90Setup BootstrapLOGSummary.txt for more detail.
(The results are below) I am not extremely technical (I can follow clear directions) but have tried a couple of the options I have seen on this site, none of them worked. I took off encryption and compression, i uninstalled all SQL componets in add/remove hardware and domain was already in my regedit. PLEASE HELP.
Microsoft SQL Server 2005 9.00.2047.00
==============================
OS Version : Microsoft Windows XP Professional Service Pack 2 (Build 2600)
Time : Wed Feb 27 17:50:58 2008
DAMON : The current system does not meet recommended hardware requirements for this SQL Server release. For detailed hardware requirements, see the readme file or SQL Server Books Online.
Machine : DAMON
Product : Microsoft SQL Server Setup Support Files (English)
Product Version : 9.00.2047.00
Install : Successful
Log File : c:Program FilesMicrosoft SQL Server90Setup BootstrapLOGFilesSQLSetup0008_DAMON_SQLSupport_1.log
--------------------------------------------------------------------------------
Machine : DAMON
Product : Microsoft SQL Server Native Client
Product Version : 9.00.2047.00
Install : Successful
Log File : c:Program FilesMicrosoft SQL Server90Setup BootstrapLOGFilesSQLSetup0008_DAMON_SQLNCLI_1.log
--------------------------------------------------------------------------------
Machine : DAMON
Product : Microsoft SQL Server VSS Writer
Product Version : 9.00.2047.00
Install : Successful
Log File : c:Program FilesMicrosoft SQL Server90Setup BootstrapLOGFilesSQLSetup0008_DAMON_SqlWriter_1.log
--------------------------------------------------------------------------------
Machine : DAMON
Product : MSXML 6.0 Parser (KB933579)
Product Version : 6.10.1200.0
Install : Successful
Log File : c:Program FilesMicrosoft SQL Server90Setup BootstrapLOGFilesSQLSetup0008_DAMON_MSXML6_1.log
--------------------------------------------------------------------------------
Machine : DAMON
Product : SQL Server Database Services
Error : The SQL Server service failed to start. For more information, see the SQL Server Books Online topics, "How to: View SQL Server 2005 Setup Log Files" and "Starting SQL Server Manually."
--------------------------------------------------------------------------------
Machine : DAMON
Product : SQL Server Database Services
Error : The SQL Server service failed to start. For more information, see the SQL Server Books Online topics, "How to: View SQL Server 2005 Setup Log Files" and "Starting SQL Server Manually."
--------------------------------------------------------------------------------
Machine : DAMON
Product : Microsoft SQL Server 2005 Express Edition
Product Version : 9.1.2047.00
Install : Failed
Log File : c:Program FilesMicrosoft SQL Server90Setup BootstrapLOGFilesSQLSetup0008_DAMON_SQL.log
Last Action : InstallFinalize
Error String : The SQL Server service failed to start. For more information, see the SQL Server Books Online topics, "How to: View SQL Server 2005 Setup Log Files" and "Starting SQL Server Manually."
The error is (1067) The process terminated unexpectedly.
Error Number : 29503
--------------------------------------------------------------------------------
SQL Server Setup failed. For more information, review the Setup log file in %ProgramFiles%Microsoft SQL Server90Setup BootstrapLOGSummary.txt.
View 5 Replies
View Related
Jan 28, 2008
I'm looking for a little help on a strange problem, used Business Contact Manager 2007 Database Tool to create a shared database in SQL Server 2005 on a server on the LAN, placed the database in the default instance of MSSQLSERVER then used the database tools to restore a 2003 BCM database to the newly created database in SQL. Everything worked as it should and I verified the database existed and was populated with data and all the permissions were set correctly to access the database. Then I loaded 2007 Business Contact Manager on a workstation on the LAN and attempted to use the wizard to connect to the remote database. I keep receiving errors that the database cannot be found. I have used the SQLCMD (Sqlcmd €“S €œtcp:erverNameinstanceName,portNumber€?) to verify access to the server and named instance and can connect with no problem, so it appears that would eliminate any firewall (which I turned off) problem or permission problem on the SQL Server. This is a connection between a Vista computer and a Server 2003 domain controller. DNS appears to work without a problem as a ping from the Vista machine by server name yields the correct IP. I have several databases running on the sequel server and have no problem accessing them. Any help would be greatly appreciated.
View 3 Replies
View Related
Sep 28, 2007
Hello and Thank You in advance:
I would like to Use the SQL Tab in the Filter Selection of the View-Modify Current View Option in Outlook 2003.
I am specifically trying to create a statement that only displays those Contacts that have a Modified Date that is different than the Created date. In other words I want to view all the records that have been modified at any time after the date of their creation.
I have been unable to create a SQL statement that compares the Created and Modified fields in the Contacts. Would you please explain and show what the correct syntax is in order to compare the values of two fields within a given Contact?
These are all examples of what I have tried and that have not worked. I cannot find documentation for this anywhere only small articles here and there that are not enough for me to develop a complete answer from:
(("urnchemas:calendar:created" >= '1/1/2001 12:00 AM' AND
"urnchemas:calendar:created" <= '12/31/2001 12:00 AM')
AND ("urnchemas:calendar:created" <> "urnchemas:calendar:lastmodified" ))
("urnchemas:calendar:created" <> "urnchemas:calendar:lastmodified" )
(("urnchemas:calendar:created" >= '1/1/2001 12:00 AM' AND
"urnchemas:calendar:created" <= '12/31/2001 12:00 AM') AND
("DAV:getlastmodified" >= '1/1/2001 12:00 AM' AND
"DAV:getlastmodified" <= '12/31/2007 12:00 AM'))
("urnchemas:calendar:created" <> "DAV:getlastmodified")
("DAV:getlastmodified" <> "urnchemas:calendar:created")
("DAV:getlastmodified" <> 'urnchemas:calendar:created')
("urnchemas:calendar:created" <> 'DAV:getlastmodified')
View 2 Replies
View Related
Feb 26, 2008
Hi, i have created a database in business contact manager which is currently been used by five toher employees. I was trying to move that database to my server. Well I found this tool online called "Business contact manager 2007 database tool". I am trying to run it on the server but it is giving me a following error:
"Cannot retrive the list of SQL Server instances. Please make sure that SQL Server 2005 or SQL 2005 Express is installed and that the service is running."
I have SQL 2005 installed on my computer and I dont have any idea how to resolve this issue. It would be great if someone could help me.
View 1 Replies
View Related
Dec 16, 2013
I am attempting to set up an always on cluster on VMware for testing. setting up everything through the Failover cluster is fine, the trouble comes when I try to set up the AlwaysOn availability group. Whenever I attempt to specify a network location I receive the following error: Operating System Error 1265(The system cannot contact a domain controller to service the authentication request..).
I looked up this error and most sites point towards a Windows 8 homegroup issue. Since this is a on a domain, I don't think it is relevant. I also added the service accounts from server A to Server B and visa versa. I even added the computer objects to its opposite partner..I have attempted to use "Join Only" and do a manual copy.
View 1 Replies
View Related
Jul 11, 2007
Hi,
We try to install Business Contact Manager for Outlook 2007 and get installation failed without any error. It simply refers to the log file. I have posted below the last 40 lines of this huge log file. The information in there are not vary help full since it refers to error codes that nobody seem to be able to explain. Now this is happening on 3 brand new dell computers running XP Pro. I would be happy for any assistance to either explain the error coded (if any MS guy is monitoring this) or maybe someone had a similar problem and could let me know some options on what I could try to get this resolved and my program installed.
Thank you all very much for assisting me.
Thom
--- Log file last 40 lines (more on request) ---
Property(S): RemoteAdminTS = 1
Property(S): WindowsVolume = C:
Property(S): MsiNTProductType = 1
Property(S): ServicePackLevelMinor = 0
Property(S): AdminUser = 1
Property(S): ServicePackLevel = 2
Property(S): WindowsBuild = 2600
Property(S): DigitalProductID = #xA40000000300000038393431302D3238312D323037393634372D3034383138000800000000000000000000000000000000000000003AD3F42CD592998379FDEF3D020300000000005C9495464B6CAB0D0000000000000000000000000000000000000000000000003236333037000000000000009B2D00008555946CBF070000EC3E0000000000000000000000000000000000000000000000000000000000003316ABDF
Property(S): VersionMsi = 3.01
Property(S): VersionDatabase = 200
Property(S): CLIENTPROCESSID = 200
Property(S): CLIENTUILEVEL = 3
Property(S): CURRENTDIRECTORY = C:Documents and SettingsJustin JongMy DocumentsShareFilesBusiness Contact 2007
Property(S): BOOTSTRAPPED = 1
Property(S): REBOOT = ReallySuppress
Property(S): PackagecodeChanging = 1
Property(S): ProductState = -1
Property(S): PackageCode = {A8529450-48A4-4346-92F8-8A9634381267}
Property(S): CostingComplete = 1
Property(S): OutOfDiskSpace = 0
Property(S): OutOfNoRbDiskSpace = 0
Property(S): PrimaryVolumeSpaceAvailable = 0
Property(S): PrimaryVolumeSpaceRequired = 0
Property(S): PrimaryVolumeSpaceRemaining = 0
Property(S): SOURCEDIR = C:Documents and SettingsJustin JongMy DocumentsShareFilesBusiness Contact 2007
Property(S): SourcedirProduct = {B32C4059-6E7A-41EF-AD20-56DF1872B923}
Property(S): ProductToBeRegistered = 1
MSI (s) (64:0C) [02:39:28:441]: Note: 1: 1708
MSI (s) (64:0C) [02:39:28:441]: Product: Business Contact Manager for Outlook 2007 -- Installation operation failed.
MSI (s) (64:0C) [02:39:28:441]: Cleaning up uninstalled install packages, if any exist
MSI (s) (64:0C) [02:39:28:441]: MainEngineThread is returning 1603
MSI (s) (64:04) [02:39:28:535]: Destroying RemoteAPI object.
MSI (s) (64:9C) [02:39:28:535]: Custom Action Manager thread ending.
=== Logging stopped: 7/12/2007 2:39:28 ===
MSI (c) (C8:50) [02:39:28:550]: Decrementing counter to disable shutdown. If counter >= 0, shutdown will be denied. Counter after decrement: -1
MSI (c) (C8:50) [02:39:28:550]: MainEngineThread is returning 1603
=== Verbose logging stopped: 7/12/2007 2:39:28 ===
View 2 Replies
View Related
