Distinct Not Showing. Kinda URGENT!

Jan 20, 2008

Quick question, I have a sql query with a distinct at the start of it. Its being put into a gridview in c# but I don't want the first column to show.

I've tried GridView2.Columns[0].Visible = true; but that hides the column with the Select button which I need. Column[1] throws back an error.

Any Ideas?

Much Thanks :-)

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Distinct Value (urgent)

Nov 1, 2007

i have a report that is grouped by department and name

Department H
Mike J

Type Houres
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A 2
A 1
B 5


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Department H
Mike J

Type Houres
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can i do such thing in sql report?
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===================================
Temp table
===================================
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==================================
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Hi,

I have two tbls joined via a varchar field.. which in tbl I have to use a CASE statement to format it correctly for the JOIN..

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Why is this?



Here's the SQL:



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dbo.UkPostcodes.Master_Account
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GROUP BY dbo.UkPostcodes.Postcode, dbo.UkPostcodes.Town, dbo.UkPostcodes.County, dbo.UkPostcodes.Area, dbo.UkPostcodes.Country,
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does not show the nulls:



where as:



SELECT ISNULL(COUNT(CASE LEN(REPLACE(dbo.Customers_Trade.PostCode, ' ', '')) WHEN 5 THEN LEFT(REPLACE(dbo.Customers_Trade.PostCode, ' ', ''), 2)
WHEN 6 THEN LEFT(REPLACE(dbo.Customers_Trade.PostCode, ' ', ''), 3) ELSE LEFT(REPLACE(dbo.Customers_Trade.PostCode, ' ', ''), 4) END), 0)
AS PCCount, dbo.UkPostcodes.Postcode, dbo.UkPostcodes.Town, dbo.UkPostcodes.County, dbo.UkPostcodes.Area, dbo.UkPostcodes.Country,
dbo.UkPostcodes.Master_Account
FROM dbo.UkPostcodes LEFT OUTER JOIN
dbo.Customers_Trade ON dbo.UkPostcodes.Postcode = CASE LEN(REPLACE(dbo.Customers_Trade.PostCode, ' ', ''))
WHEN 5 THEN LEFT(REPLACE(dbo.Customers_Trade.PostCode, ' ', ''), 2) WHEN 6 THEN LEFT(REPLACE(dbo.Customers_Trade.PostCode, ' ', ''), 3)
ELSE LEFT(REPLACE(dbo.Customers_Trade.PostCode, ' ', ''), 4) END
GROUP BY dbo.UkPostcodes.Postcode, dbo.UkPostcodes.Town, dbo.UkPostcodes.County, dbo.UkPostcodes.Area, dbo.UkPostcodes.Country,
dbo.Customers_Trade.Master_Account, dbo.UkPostcodes.Master_Account

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Hi,

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