Embedding Quotes On Recipent Name In Xp_sendmail

Nov 27, 2007

hello:

can anyone tell me how to embed a single quote that is part of a name in the @recipients= paramter of the xp_sendmail.

for instance:

xp_sendmail @recipients=joe.smith@xx.com;nancy.o'donnell@xx.com;tim.bim@xx.com',@attachments='xx.txt',@subject='subject'

i tried ' and `.

thanks

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below is the code of my sp
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Thanks!


Code:

ALTER PROCEDURE sp_name
(
@param1 int = NULL,
@param2 int = NULL,
@Result int OUTPUT
)

AS

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DECLARE @var2 AS varchar(255)
DECLARE @x AS varchar(1000)

IF @param1 IS NOT NULL
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WHILE @@FETCH_STATUS = 0
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CLOSE crsr
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END
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END

PRINT @var2

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OR
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BEGIN
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END
ELSE
BEGIN
SET @Result = 0
END

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Hi all,

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Hello Everyone!

I am having a problem with updating a password within a table. Below is the old and new password that needs to be updated.
Old2"3("-"3#@(%P="''_DD@D*
New :"I+)#]*1#E,%R-''7^,TEA$X&^O_-68DIK,@

Below is the query that I am trying to run. I believe my problem is becuase of the Single Quotes found within both the old and new password.

I have tried to escape the single quotes, @local_variable, CHAR(39) and other ways of playing with the string. I cannot seem to find a solution.

If you were to ignore the update statement, the SELECT statement would return no results even though the PRINT statement displays the required data.
This is what baffles me and why I cannot run the UPDATE statement, becuase of course, nothing would be updated since no results were returned.

Can anyone offer their assistance?

Thank you in advance.

__________________________________________________ _______________

DECLARE
@OLD_PASSWORD VARCHAR(50),
@NEW_PASSWORD VARCHAR(50)

-- 2"3("-"3#@(%P="''_DD@D* ///// The old password.

SET @OLD_PASSWORD = '2"3("-"3#@(%P="' + CHAR(39) + CHAR(39) + '_DD@D*'

-- :"I+)#]*1#E,%R-''7^,TEA$X&^O_-68DIK,@ ///// The new password.

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PRINT @OLD_PASSWORD
PRINT @NEW_PASSWORD

SELECT *
FROM Credentials
WHERE
Is_Active = 1 AND
[Password] = @OLD_PASSWORD

/* Attempt to update the password table. */
UPDATE Credentials
SET [Password] = @NEW_PASSWORD
WHERE [ID] IN
(SELECT [ID]
FROM Credentials
WHERE
Is_Active = 1 AND
[Password] = @OLD_PASSWORD )

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