Extracting DDL's In SQL Server

Sep 17, 2004

I really apprciate any idea's

On extracting ddl's for each object on a separate file in SQL Server?

Something like ddl's for:
procedure1.sql, procedure2.sql.....so on procedure100.sql
onto a file server.

Does SQL Server has any API's like Oracle's dbms_metadata?

Or can we use SQL enterprise manager to do this job?

Thanks, Madhavi.

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Jan 22, 2008

Hi!

I'm analyzing the problem of extracting data from sql server 6.5 in order to load it into oracle.

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regards, and thanks in advance for your help.

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BV

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Aug 18, 2014

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Here is the DDL:

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[Code] ....

What I need to accomplish is to extract the string that is between the third and fifth '-' (dash) and insert it into the StoreNumberParsed while eliminating the fourth dash.

Sample output would be:

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OH174
MD163
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I know that parse, charindex, patindex all might come in play, but not sure how to construct the statement.

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insert into #demo (field1)
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[Code] ....

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The application has an SQL database locally on my computer.

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Please help me on this.

Thanks in advance.

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Apr 22, 2008

Hello, this seems simple but I've been banging my head a while.

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I need to pull out the string after the second / and before the third / in this case the value is 7510-Electronics Mtc but it does change.

I have this function that returns the first value (NYT):

USE [Data_Warehouse]
GO
/****** Object: UserDefinedFunction [dbo].[Get_Dept] Script Date: 04/22/2008 09:22:49 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO

-- Provide the phrase before (ex. 'Worklog Related to'), the field searched (ex. UPDATE_ACTION), and
-- the phrase after (ex. ']').
-- This function returns the string found after any phrase and before any phrase, within any field searched.

ALTER FUNCTION [dbo].[Get_Dept](@in_Phrase_Before varchar(250),@in_Search_Field varchar(250))
RETURNS varchar(250)
AS
BEGIN
Declare @str_String As varchar(250)
Declare @tmp_String as varchar(250)
Set @str_String = null -- to clear the variable buffer

Set @in_Phrase_Before=char(37)+(LTrim(Rtrim(@in_Phrase_Before)))+char(37) -- if 'Null', all strings will be returned

If Left(@in_Search_Field,4) = 'NYT/'
BEGIN
Set @tmp_String = Right(@in_Search_Field,(len(@in_Search_Field) - 4 ) )
Set @in_Search_Field = @tmp_String
END

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RETURN @str_String

END

Thanks in advance for the help

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Thanks,
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SELECT *
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'
SELECT *
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[Code] ....

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SAMPLES WHAT THE DATA MIGHT LOOK LIKE
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:-)

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