Find All The Employees Under One Manager (was Need Help With Query)
Apr 5, 2007
I have an employee table with manager id and employee ids , i need to find all the employee ids for a manager id . Each employee can be a manager in turn . So I need to find all the employees under one manager and if any of the employee is in turn a manager , i need to find the employees under him as well .
The table structure is defined and i cannot edit it .
Please let me know if we could have a single query to do this .
Thank you
kishore
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Jan 31, 2008
I am using SqlServer 2000 with asp.net 2.0, I have a table tbl_employees, with fields (empId, empName, empManagerId), with following data...
empId
empName
empManagerId
1
A
2
B
1
3
C
2
4
D
2
5
E
4
Now the question is that what should be the single line query or best solution if i want to get all employess under a perticular manager ?For example; Employees under 'A' are (B,C,D,E) //(C,D,E are also indirectly under A)Emplloyess under 'B' are (C,D & E; E is also under B as his because his managwer 'D' is himself under 'B')
Please advise..Thanks alot.
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Sep 8, 2006
Hello,I'm facing with a problem though it may look very simple for many ofu it is a bit complicated for me So kindly please help me outi have a table emp with employee id,name and mgridI need to display the managers and the employee working under thatmanager . How should this be done.Thanking uBroken Arrow
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Jul 10, 2014
I have a database of employees and pay rates.
One employee has two pay rates for two different jobs:
Job A: Rate $10.00
Job B: Rate $15.00
I will be updating their record so that they only have one job going forward, Job C. I need Job C to equal their HIGHER of the two existing jobs.
I have a select statement to find what the higher rate is. However, I am not sure how I can apply the rate to be the new job's rate. Here's what I used to find the highest rate for one single person:
SELECT max(rate), employeeID
FROM JobsTable
inner join IDTable
on JobsID2 = IDID2
WHERE JobCode in ('JOBA','JOBB')
and EmployeeID = '12345'
GROUP BY EmployeeID
(this returns the employee ID from one table, and the highest rate from Jobs A and B from another table)
I can get it to update to add JobC -- how can I get it to assign the result from the above query to be the rate used for Job C?
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Oct 25, 2012
Table structure is very simple as below and I know there are solutions with joins (Left outer joins), need to know if it is possible to get o/p without using joins
Note:- also need records who doesn't have manager (null)
table structure
eid------ename------mgrid
1------Nancy------2
2------Andrew------null
3------Janet ------2
4------Margaret------2
5------Steven------4
6------Michael ------5
o/p
Employee------Manager
Nancy------Andrew
Andrew------Null
Janet ------Andrew
.
.
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Feb 28, 2007
I downloaded the trial version of sql server 2005. but after installation, I couldnt find the Enterprise Manager and Query Analyzer. Any idea about that? Thanks.
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Mar 23, 2006
create table employee(empid int,empname varchar(20),managerid int notnull, sal int)insert into employee values(1,'ranga',22,5000)insert into employee values(2,'satish',22,8000)insert into employee values(3,'sunil',11,4500)insert into employee values(4,'sridhar',22,2000)insert into employee values(5,'ramesh',33,12000)insert into employee values(6,'srini',22,16000)insert into employee values(7,'sashi',33,54000)insert into employee values(8,'rajani',22,71000)insert into employee values(9,'praveen',11,6060)insert into employee values(10,'bhaskar',22,11120)insert into employee values(11,'baba',33,9000)create table employment (managerid int,managername varchar(20),sal int)insert into employment values(11,'rob',2500)insert into employment values(22,'babu',5000)insert into employment values(33,'ram',6000)now my problem isUpdate the salary of each manager to be double the averagesalary of the employees he/she managespls helpsati
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Aug 14, 2014
Let us assume that there are 100 employee in a company. And sum of salary of all employee is 10000. Find list of highest paid employees whose sum of salary is 8000. Remaining employee will fall in 20% bracket.
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May 11, 2006
I have a query that returns a result that looks like this:
amount count
steve 122000 12
jim 145213 13
paul 62325 7
I need to add 2 columns to this query that rank the employees by count and amount with a number, so for example:
amount amount_rank count count_rank
steve 122000 2 12 2
jim 145213 1 13 1
paul 62325 3 7 3
I was going to paste the entire query in but I thought I'd try this first to see if I could get by with a hint. So essentially I need to evaluate with an order by or something and then insert a number as amount_rank and number as count_rank.
Any ideas?
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Sep 22, 2005
After I install Reporting Service for SQL 2000, it will establish two virtual directory in IIS: Reports and ReportServer.and I can manage the Reporting Service with Report ManagerBut after I install Sql2005 and with Reporting Service Selected, I can't find these virtual directory. How can I manage the Reporting Service of Sql2005?
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Jul 23, 2005
I am running Win XP SP2 and MSDE 2000 SP3a. The user is logging on asa POWERUSER. When the user logs on the MSSQLSERVER service starts butthe SQL Server Service Manager, that runs in the system tray, showsthat the instance has not started. The field that displays theinstance name is blank and it is not listed in the drop down list.The MSSQLSERVER service is set to start with a Windows domainadministrator account. The SQL server can be accessed by a remotecomputer through Enterprise Manager. The local programs cannontinteract with the server though.Does anyone know if I could grant some user access rights to allow MSDEto work under a POWERUSER login?
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May 6, 2015
I came across a SQL 2000 instance with a report server database on it - looking at the execution log storage I can see that its still being used and running the following query tells me that the connections are coming from the same server: SELECT hostname, * FROM sysprocesses WHERE dbid = DB_ID ('ReportServer') but I cant find the SSRS instance in the services -Did it work differently with SQL 2000? How can I find the report manager URL?
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Dec 22, 2007
I am a non-technician and have had an .asp site with an SQL database on a shared server for several years. I now need to move to a new shared server and want to understand as much as possible and to be able to continue accessing my data directly. I have used Enterprise Manager in the past, withut really even knowing what it was or what it was a part of, to pull lists, etc. I am now using Vista and the new hosting company says I can download Enterprise Manager from Microsoft.com. I tried and found only the ability to download SQL Server 2005 Express. This seemed to imply I would get Enterprise Manager as a result. I attempted to download SQL Server 2005 Express, following all the instructions. When it said I had sucessfully finished, I went to All Programs to find it and found "MS SQL Server 2005" listed. Under the lising I found "Configuration Tools" .
Under Configuration Tools I find three more options: "SQL ServerConfiguration Manager", SQL Error and Usage Reporting" and SQL Server Surface Area Configuration"
These are all Greek to me and I am uncertain if I even got the "SQL Server 2005 Express" program downloaded.
Please give me whatever guidance you can.
Thank you.
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May 28, 2008
ok can someone tell me why i get two different answers for the same query. (looking for last day of month for a given date)
SELECT DATEADD(ms, - 3, DATEADD(mm, DATEDIFF(m, 0, CAST('12/20/2006' AS datetime)) + 1, 0)) AS Expr1
FROM testsupplierSCNCR
I am getting the result of 01/01/2007
but in query analizer I get the result of
12/31/2006
Why the different dates
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Nov 15, 2007
Ok, I have the following table
CREATE TABLE employees (
employee_number char(6) NOT NULL
, known_as char(20)
, surname char(20)
, job_title char(20)
, manager_number char(6) NULL
, unique_identifier char(6) NOT NULL PRIMARY KEY
)
--unique_identifier is in the format 000123456789
Now I have a conundrum when trying to create organization charts in Visio, so I figured I'd try reproduce the format that a bunch of walkthroughs suggest, which is with the first column being an int identity(1,1) column as the employeeID with the managerID being an int column also, referencing the employeeID.
Hope I've not lost you just yet ;)
So here's what I figured - create a new table with the new integer columns, slap my current data into it and then update the managerID as necessary...
Except I can't work out the update statement for this!
CREATE TABLE gvVisioTest (
employeeID int identity(1,1)
, employee_number char(6)
, job_title char(40)
, department_reference char(10)
, managerID int
, manager_number char(6)
)
GO
INSERT INTO gvVisioTest(employee_number, job_title, department_reference, manager_number)
SELECT employee_number, job_title, department_reference, manager_number
FROM employees
GO
--Update managerID with relevant employeeID
GO
DROP TABLE gvVisioTest
Any ideas?
Oh and this is legacy so the design is flawed, modified over time (the manager field is a bodge put in 5 years ago), so yeah unfortunately I have to work with what I've got :(
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Dec 8, 2011
I need to calculate the salary given to all employees in a year
Code:
select sum(emp_total_sal)from emp_salary
How to modify this code to get what i need ?
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Dec 4, 2006
i have 2 tables emp and dept
emp has columns:
empid(pk),empname,deptid(fk),salary
dept has columns:
deptid(pk),deptname
now my aim is:
List of the employees and their department who is top salary earner of the department.
wht i can think of is:
select distinct empname,deptname,max(salary) as 'max salary'
from emp e,dept d
where e.deptid=d.deptid
group by empname,deptname
but it gives unexpected result...
help appreciated
cheers
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May 26, 2008
Dear all,
I have a table that contains the following columns:
COMPANY | EMPLOYEE | SALARY
I want to select the TOP 5 PERCENT employees from each company, ordered by salary. Is this possible?! Thanks!
Pedro Martins
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Jun 15, 2007
I'm trying to find the command to open up an odbc conection inside sql2005 express. I only have ues of an odbc connector, we're conection to remedy. We will eventually be using stored procedures to extract the data we need from remedy and doing additional data crunching. I'm a foxpro programmer so once I get the correct syntax for making the odbc connector I shold be ok. Also I need a really good advanced book on sql2005. The type of book that would have my odbc answer. I've spent all morning trying to find this information and was unable to.
Thanks in advance
Daniel Buchanan.
If this was the wrong forum to post this on, please move this question to the correct one. I need this answer soon.
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Sep 14, 2014
I have the employees and department tables(structure below).
Write a sql to get the department name,employee earning maximum salary,employee earning minimum salary for each department
result set:
dname |max_salaried_employee|min_salaried_employee
------------------------------------------------------
Accounts | Blakes | Miller
HR | King | James
Structure :
create table dept(
deptno number(2,0),
dname varchar2(14),
loc varchar2(13),
constraint pk_dept primary key (deptno)
[Code] .....
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Jan 7, 2002
I am trying to run queries against any of the user tables in my MS SQL 7.0 database. I get a message the Query Designer encountered a query error.
We have tried rebooting the SQL Server and I am still getting these messages. Also, the SQL error logs look fine - all database
maintenance are running successfully including the DBCCs which show no errors. Any help would be greatly appreciated as we are to go
into production in a few days.
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Jun 27, 2013
I am uploading input sample data and desired output data, can get the desire output.
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Jul 15, 2013
I have this column Sdate in my Employees table. This value represent the start date working.
I need to get all of the employees that between 8 and 10 month of work from today. How can I do it?
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Jun 17, 2015
I have a table which has name,Speciality,start date and end date. So each person may have 1/more rows .They will have more if they change their specialities. For example if you look at the data below.
AdjusterNameSpecialtyDatestartDateEnd
Test Inside Property2009-08-29 2010-07-31
Test Management2010-08-012012-07-31
If we see at the data above Test has 2 rows because he changed his specialty in the middle.My requirement is to calculate the total number of employees in each month for last 2 years in each speciality. For example if we look at the example above, Test was in Inside property from 2009 Aug to 2010 Aug but if i use just the date start and take the month for each adjuster it gives me the number of adjusters started in that year and month but what i want is Test should be counted in all the months for Inside property until 2010 07 month. Which means i want to have the total number of adjusters present by each speciality for each month of last 2 years .
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Feb 13, 2007
I apologize if this is not the correct forum for this posting. Looking at the descriptions, it appeared to be the best choice.
I am running Windows XP Pro SP2. I have installed the SQL Native Client for
XP. However, when I try to add a new data source through ODBC Connection
Manager, SQL Native Client is not listed as an option. I have followed this procedure on three other systems with no problems. What would be causing the
SQL Native Client to not show up in the list of available ODBC data sources?
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Mar 12, 2015
How do I filter a list of Employees where the Sum of "VALIDATED" hours is less than 80? For example.
Here is the flat table
SELECT EMP_NO, hours, IsValidated, rate_type
FROM Pay_Records
WHERE pay_period_id = 2
Order by EMP_NO
Output will be something like this
12345 | 2 |true |REG
12345 | 15 |false |OVR
12345 | 30 |true |OVER
33334 |2| true |REG
Total Validated hours for the Employee 12345 will be 32 NOT 47. How do I list employees who worked less than 80 validated hours. The hours are validated only when it is true.
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Jan 24, 2008
how to do this
i have table of employee ,evry employee have a unique ID "empid"
empid VAL_OK
--------------------------
111 0
222 0
333 0
now insert multiple insert to my work_table shifts for all month for evry employee
like this
(this is work_table)
empid date val
--------------------------------------------------
111 01/02/2008 1
111 02/02/2008 2
...............
111 29/02/2008 5
--next employee
222 01/02/2008 1
222 02/02/2008 4
...............
222 29/02/2008 6
--next employee
333
--next employee
444
--next employee
555
-------------------------------------------------------------
now i need for evry OK insert (for all month) each employee
go to the TB_Employee
and update each employee once !!
from VAL_OK=0 to VAL_OK=1
like this
empid VAL_OK
--------------------------
111 1
222 1
333 1
----------------------
like this i know who is the employee have shift for all month and who NOT !
i think it like this
Code Snippet
Create trigger for_insert on tb_work
For insert
begin
if @@rowcount = 1
Update tb_employee
Set
val_ok= 1
else
/* when @@rowcount is greater than 1,
use a group by clause */
Update tb_employee
set
val_ok= 1
select empid from tb_work
group by tb_work.empid
End
TNX
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Jan 10, 2008
need help
how to check in table if all the employees have Full month
if it double days fix it
if the employees have less days ! > move to temp table
for eny problem with this employee (check continuity or error) move to temp table !
i have stored procedure that insert employees for next month "Full month"
from start of the month until end of the month
how to check continuity and if i don't give less days OR double days in month
like if the month is 29 days the employee must have 29 not more
for eny problem with this employee move to temp table !
situation 1 employees have less days !
sn empid ShiftDate day
-------------------------------------------------
1 111111 2008-02-01 Tuesday
2 111111 2008-03-02 Wednesday
3 111111 2008-04-03 Thursday
4 111111 2008-03-04 Friday
5 111111 2008-03-05 Saturday
6 111111 2008-03-06 Sunday
7 111111 2008-03-07 Monday
. ----------------------------------------------
8 111111 2008-03-09 Wednesday
9 111111 2008-03-10 Thursday
.......................................................................until end of the month
99 222222 2008-02-01 Tuesday
100 222222 2008-03-02 Wednesday
101 222222 2008-04-03 Thursday
102 222222 2008-03-04 Friday
. ----------------------------------------------
104 222222 2008-03-06 Sunday
105 222222 2008-03-07 Monday
106 22222 2008-03-09 Wednesday
108 22222 2008-03-09 Wednesday
109 22222 2008-03-10 Thursday
.......................................................................until end of the month
situation 2 employee have double days!
sn empid ShiftDate day
-------------------------------------------------
1 111111 2008-02-01 Tuesday
2 111111 2008-03-02 Wednesday
3 111111 2008-04-03 Thursday
4 111111 2008-03-04 Friday
5 111111 2008-03-05 Saturday
6 111111 2008-03-06 Sunday
7 111111 2008-03-07 Monday
8 111111 2008-03-09 Wednesday
9 111111 2008-03-09 Wednesday
10 111111 2008-03-10 Thursday
.......................................................................until end of the month
99 222222 2008-02-01 Tuesday
100 222222 2008-03-02 Wednesday
101 222222 2008-04-03 Thursday
102 222222 2008-03-04 Friday
103 222222 2008-03-04 Friday
104 222222 2008-03-05 Saturday
105 222222 2008-03-06 Sunday
106 222222 2008-03-07 Monday
107 22222 2008-03-09 Wednesday
108 22222 2008-03-09 Wednesday
109 22222 2008-03-10 Thursday
.......................................................................until end of the month
TNX
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Jul 31, 2015
Basically I'm trying to produce a report that shows qualified employees for each program. Each employee can possess many qualifications. There will be no programID parameter submitted by the user. I just want to produce the report which shows the programs and the qualified employees for each. I thought I had a query that was working but once I added a different ProgramID into the ProgramModules table things went south.
Here are my tables:
tblEmployees (table of employees)
- EmployeeID
- EmployeeName
tblQualifications (table of qualifications)
- Qualification_ID
- QualificationTitle
tblEmployeeQualification (table of all employees qualifications)
-EmpQualificationID
-EmployeeID (fk for tblEmployees)
-QualificationID (fk for tblQualifications)
tblPrograms (table of programs)
-ProgramID
-ProgramTitle
tblProgramModules (table of qualifications required by each program)
-ProgramModuleID
-ProgramID (fk for tblPrograms)
-QualificationID (fk for tblQualifications)
Here is the query I was working with that works when there are only records in the ProgramModules table that use the same ProgramID
SELECT
tblProgramModules.TrainingProgramID,
tblEmployees.EmployeeID,
tblEmployees.EmployeeName
FROM
tblEmployees
[Code] .....
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May 6, 2014
I would like to generate a working schedule for employees for x-days ahead based on a starting date that the user can enter.
I have got 3 relevant tables:
1. Table X with (1) resourcenumber, (2) starting date working schedule and (3) the daynumber representing the starting date (this is ISO so 1 for Monday, 2 for Tuesday etc.)
2. Table Y has the schedule itself and can hold a 7-days schedule or a 14-days schedule. In case of 7 days schedule there a 14 (!) records with (1) resourcenumber, (2) daynumber, (3) starting hour a.m. (4) ending hour a.m (5) starting hour p.m and (6) ending hour p.m. In case of a 14-days schedule there are 28 records (a.m. and p.m. records)
3. Table Z with resource data.
An example to clarify (for fake employee 100):
Table X:
Resource: 100
Starting date: 2012-03-01 (from this date the schedule will be effective)
Daynumber: 4 (2012-03-01 was a Thursday)
Table Y (Resource has a 14 days schedule because per 2 weeks Monday is an off-day):
Record 1 shows: Resource: 100, Daynumber: 1 (= Monday, working day), AM-Starting hour: 09:00, AM-Ending hour: 13:00, PM-starting hour: 13:30, PM-ending hour: 17:30
Record 2: same but daynumber is 2
Record 3: same but daynumber is 3 etc.
...
Record 8 shows: Resource: 100, Daynumber: 8 (= Monday, off-day), AM-Starting hour: 00:00, AM-Ending hour: 00:00, PM-starting hour: 00:00, PM-ending hour: 00:00
Record 9: same as record 2 but daynumber is 9.
etc.
...
Record 14: same as record 7 but day is 14 (= last day)
The weekend days show as 00:00 for the hours (same as day 8 in example)
I generated the working schedule with a CROSS APPLY function based on the starting date and the x-number of days ahead.
I then evaluate the actual daynumber corresponding with that date with the daynumber in table Y. That works fine with a 7-days schedule but I can't get it fixed with a 14-days schedule. Day 8 in that schedule represents an actual day 1 but how do I know what actual date day 8 is ... I think I have to start with the starting date in table X ...
I think ideally I would like to have the generated days as follows (as an example in case of a 14-days schedule starting 2014-05-01 for 30 days ahead):
2014-05-01 = day 4 (= actual daynumber)
2014-05-02 = day 5
2014-05-03 = day 6
...
2014-05-10 = day 13
2014-05-11 = day 14
2014-05-12 = day 1
2014-05-13 = day 2
2014-05-14 = day 3
...
2014-05-24 = day 13
2014-05-25 = day 14
2014-05-26 = day 1
2014-05-27 = day 2
...
2014-05-31 = day 6
With this done I can compare the actual daynumber with the daynumber in Table Y.
The rownumber that the CROSS APPLY function generates has to be reset to 1 after day 14. I tried PARTITION BY in THE ROW_NUMBER function but to no avail ... The only field I can partition by is the maximum value of the daynumber (14 is the example) but that is not allowed in the rownumber function.
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Jul 17, 2004
anybody can help me how to get into the SQL Query Manager. I downloaded already the MSSQL Server 2000 and it's already running.
efren
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Jul 18, 2000
Iam trying to see the rows using e/m i.e by right clicking tables and choosing return all rows option but it gives me an error but if i chose the other options(i.e. design table etc) it works well.only that return rows option in all the databases doesn't work.
Again iam able to retrieve rows from query analyzer.
The error which it gives is:
An unexpected error happened during the operation.
[Query]-Query Designer encountered a Query error:Unspecified error.
Please if anyone knows the solution mail it to l_muthu@hotmail.com
Thanks.
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Jun 23, 2000
I have a need to identify the name of a user and would like to access the NT userlist. Or failing a realtime access, can I achieve a periodic update of a SQL table with userid, username from the NT userlist?
TIA
Bob Morrow - Tennessee General Assembly
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