Group By Won't Work??

May 30, 2008

can anyone explain why, when i do a group by clause on the following data....it has no effect?

Part          SubPart         Qty

120887     66743             83

120887     66743            100

120887     667443            25

553212     122987           119

553212     122987             67

here's my select statement:

select part, subpart sum(qty) from partdata group by part,subpart,qty

the resulting data looks identical to the original.

what i was expecting was a return of just two lines:

 

Part          SubPart         Qty

120887     66743             208

553212     122987           186

 

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DISTINCT Or GROUP BY Does Not Work. Help

Oct 17, 2002

I have have a column where there would be some duplicate records, but I have tried using the IN list, DISTINCT, and GROUP BY, and it does not give me distinct record set.

However DISTINCT and GROUP BY will work as long as my columns to display remain only one, but the minute I add more columns to my SELECT statement it does not make them distinct anymore.

Example 1 works, but Example 2 does NOT. In Example 2, I have added more columns otherwise it identical to Example 1. In Example 3, I was using the IN list, but the results of Example 3 is identical to Example 2 !!

EXAMPLE 1:
SELECT DISTINCT email_address AS Email
FROM email_address
WHERE Send = 'y' and (DATEDIFF(DAY, Sent, getdate()) > 30)

EXAMPLE 2:
SELECT distinct email_address AS Email, email_address_ID AS ID, Sent
FROM email_address
WHERE Send = 'y' and (DATEDIFF(DAY, Sent, getdate()) > 30)

EXAMPLE 3:
SELECT email_address_ID AS ID, email_address AS Email, Sent
FROM email_address
WHERE email_address IN (SELECT DISTINCT email_address FROM email_address
WHERE Send = 'y' and (DATEDIFF(DAY, Sent, getdate()) > 30))

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Dec 10, 2007

HI,

I tried to run the following query.






Code Block
WITH YesterdayCTE AS
(
SELECT type = 'Members Joined Yesterday'
, Borrowers = (select count(*)
from LoanApplication INNER JOIN
Member ON LoanApplication.MemberFK = Member.Id AND LoanApplication.Id = Member.LastLoanApplicationFK INNER JOIN
CreditUnion ON Member.CreditUnionFK = CreditUnion.Id
where (LoanApplication.SubmittedOn >= GETDATE()-1) AND (Member.CuStatus = 'Approved')
GROUP BY CreditUnion.Name )
, Depositors = (select count(*)
from CDOrder INNER JOIN
Member ON CDOrder.MemberFK = Member.Id AND CDOrder.Id = Member.LastCDOrderFK INNER JOIN
CreditUnion ON Member.CreditUnionFK = CreditUnion.Id
where (CDOrder.SubmittedOn >= GETDATE()-1) AND (Member.CuStatus = 'Approved')
GROUP BY CreditUnion.Name )

),

MonthlyCTE AS

(
SELECT type = 'Members Joined Last Month'
, Borrowers = (select count(*)
from LoanApplication INNER JOIN
Member ON LoanApplication.MemberFK = Member.Id AND LoanApplication.Id = Member.LastLoanApplicationFK INNER JOIN
CreditUnion ON Member.CreditUnionFK = CreditUnion.Id
where (LoanApplication.SubmittedOn >= GETDATE()-30) AND (Member.CuStatus = 'Approved')
GROUP BY CreditUnion.Name )

, Depositors = (select count(*)
from CDOrder INNER JOIN
Member ON CDOrder.MemberFK = Member.Id AND CDOrder.Id = Member.LastCDOrderFK INNER JOIN
CreditUnion ON Member.CreditUnionFK = CreditUnion.Id
where (CDOrder.SubmittedOn >= GETDATE()-30) AND (Member.CuStatus = 'Approved')
GROUP BY CreditUnion.Name )

),

YearlyCTE AS

(
SELECT type = 'Members Joined Last year'
, Borrowers = (select count(*)
from LoanApplication INNER JOIN
Member ON LoanApplication.MemberFK = Member.Id AND LoanApplication.Id = Member.LastLoanApplicationFK INNER JOIN
CreditUnion ON Member.CreditUnionFK = CreditUnion.Id
where (LoanApplication.SubmittedOn >= GETDATE()-360) AND (Member.CuStatus = 'Approved')
GROUP BY CreditUnion.Name )
, Depositors = (select count(*)
from CDOrder INNER JOIN
Member ON CDOrder.MemberFK = Member.Id AND CDOrder.Id = Member.LastCDOrderFK INNER JOIN
CreditUnion ON Member.CreditUnionFK = CreditUnion.Id
where (CDOrder.SubmittedOn >= GETDATE()-360) AND (Member.CuStatus = 'Approved')
GROUP BY CreditUnion.Name )


),

combinedCTE AS

(
SELECT * FROM YesterdayCTE
UNION ALL
SELECT * FROM MonthlyCTE
UNION ALL
SELECT * FROM YearlyCTE


)

SELECT *
, Members = Borrowers + Depositors
FROM combinedCTE






But I get the following error message.


An error occurred while reading data from the query result set.
Subquery returned more than 1 value. This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the subquery is used as an expression. (Microsoft Report Designer)
===================================
Subquery returned more than 1 value. This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the subquery is used as an expression. (.Net SqlClient Data Provider)

Please can anyone help me to make this work?

Thanks

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Apr 3, 2008



hi guyz i am trying to trap the duplicate records . cannot trap the below dupes any idea. i also used ltrim and rtrim it still thinking it is a duplicate but it is not. what is the best way doing it.


select count(*) , muzenbr from muzealbums_1 where muzenbr = '1000082' group by MuzeNbr, PNOTES, CNOTES, CAT3, Performer having count(*) > 1


MuzeNbr nvarchar no 14 yes (n/a) (n/a) SQL_Latin1_General_CP1_CI_AS
PNOTES nvarchar no -1 yes (n/a) (n/a) SQL_Latin1_General_CP1_CI_AS
CNOTES nvarchar no -1 yes (n/a) (n/a) SQL_Latin1_General_CP1_CI_AS
CAT3 nvarchar no -1 yes (n/a) (n/a) SQL_Latin1_General_CP1_CI_AS
Performer nvarchar no 510 yes (n/a) (n/a) SQL_Latin1_General_CP1_CI_AS


1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL
1000082 NULL NULL Classical NULL

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https://connect.microsoft.com/SQLServer/feedback/ViewFeedback.aspx?FeedbackID=311679

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How do i do that please. Here s what I need, for example for this set of rows:


myItem colum2 colum3
711056 22662 Finances / -2291 -2479916
711056 22663 Finances / -2380 -2576255
711056 43428 Cda) -323 -349635
711056 43428 . -B-(Cda) -44 -47628
711057 44348 . -B-(Cda) -355 -384273
711057 47033 . -B-(Cda) -1278 -1383384

I need 2 extra rows, one at the end of the items 711056 telling me there are 4 rows for the item 711056 and one row at the very end telling me there are: 2 rows for the item: 711057

Thanks a lot.

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