Hi all,
i am using sql server 2005.
let me explain the scenario.
i have report where i bring perticular employee totalcall and workeddays(from sp) then in third field i wrote an expresion to evaluate avg call that is totalday/workeddays and all the three field i displayed in table [b]Now requirment is in tablefooter i need to display avg of above calculated avg call
please suggest some idea
thank you.
I have a sum , which is filtered within its table group, and then i have a fields in the footer. How would i aggregate these too together and use the result in another row within the footer.
I tried entering this:
=SUM(Fields!Period_1.Value,"table2_Period") / Max(Fields!Goal_1.Value)
but i get an error:
[rsInvalidAggregateScope] The Value expression for the textbox €˜textbox129€™ has a scope parameter that is not valid for an aggregate function. The scope parameter must be set to a string constant that is equal to either the name of a containing group, the name of a containing data region, or the name of a data set.
Build complete -- 1 errors, 0 warnings
what am i doing wrong, please help!
I currently have an Ungrouped Dataset being displayed in a Table. One of the columns include AMOUNT.
This is an example of what my report looks like atm:
==================
**Report Name**
No Name Amount
Signed By XXXX
==================
I would like to display a SUBTOTAL of the Amounts for each page and, on the final page, a TOTAL of the Amounts.
Yes the Last Page's SubTotal and Total will be the same.
Looking like:
===============================
pg1
**Report Name**
No Name Amount
Sub Total Amount
Signed By XXXX
(lastpage)
**Report Name**
No Name Amount
(<-----no huge spaces between Table/Subtotal)
Sub Total Amount
Total Amount
Signed By XXXX
=================================
Issues:
I've found a way to get a Page's SubTotal, but the way I found requires this to be put in a field on the Page Footer Section.
This means that on the final page, the SubTotal will be at the top of the Page Footer and not neccessarily directly beneath the table.
So:
1. Is there a way to move the Page Footer so that its printed DIRECTLY under neath the Page Body instead of at the bottom of the Page?
2. If not, is there a way to have the SubTotal of each Page and a Final Page Total in the Page Body section.
Cheers.
Hi all,
I have a table with 3 computed columns, the first two reference a function for there value. The last computed column should be total of the other computed columns, however when trying to write the formula for this column SQL Server rejects it.
Am i correct in thinking it is not possible to reference other computed columns in a computed column's forumla.
My current work around is to call the functions again that the other computed columns use to generate the total, though this seems to me like a performance issue.
Could anyone offer some advise on my situation.
Any input apreciated.
Is it possible to get a Computed column in one table to carry out a SELECT & SUM from a column in another table? I have tried a SELECT / FROM / WHERE construct but SQL complains about that.
Regards
Clive
I am working with data that has a lot of records that get updated and inserted frequently, and to avoid having to create formulas through code all over the place, I am experimenting with computed column formulas. I have a question though.. It works well for any addition or subtraction (columnA+columnB), however, when I try to use division (columnA/columnB), it only returns integers, no decimals. I would like to have decimals, particularly with a specific scale and precision and I would really like to attempt this without any coding. Any suggestions?
View 3 Replies View RelatedI have a table with fields called fname (First Name) and lname (Last Name). I need the user´s email thai is compose from lname and fname:
LOWER(LEFT (fname,1) + lname)
Is there any difference between creatig this computed column ia a table or in a view in SQL Server 2000?
I can do:
1. CREATE TABLE Users(
fname varchar(20),
lname varchar(20),
email as LOWER(LEFT (fname,1) + lname) )
Or
2. CREATE TABLE Users (
fname varchar(20),
lname varchar(20))
CREATE VIEW Vw_users (fname, Lname ,
email)
AS
SELECT fname, Lname ,
LOWER(LEFT (fname,1) + lname) )
Is one of them is better?
Paulo
Maybe I am missing something very obvious, but I couldn't do it: begin trangocreate table foo (f1 int not null,f2 int not null,f3 as (f1 + f2) not null primary key clustered)gorollback trango This returns:Server: Msg 8183, Level 16, State 1, Line 8Only UNIQUE or PRIMARY KEY constraints are allowed on computed columns.
View 4 Replies View Relatedi have a table that contains 2 columns
A B (B values are only 1 and 2)
-- --
x 1
y 2
z 1
x 2
z 1
j 1
k 2
i want to make a query that will check for dinstinct x what B values it has Ex. It will show result like this
result
A B
-- --
X 1 and 2
Y 2
z 1
K 2
how to make please help
Dear all,
Pls help me with this
I have 2 tables
Trip (TripID, Duration)
Reserve(ReserveID, TripID, StartDay, EndDate)
in which EndDate = StartDay + Trip.Duration
How can I do this?
I want to create computed column in table.
Suppose I have three physical column A,B and C
I want to create compute column with computed column.
A+B= X
X+C=Z
Is it possible.
I have a table with fields called fname (First Name) and lname (LastName). I need the user´s email thai is compose from lname and fname:LOWER(LEFT (fname,1) + lname)Is there any difference between creatig this computed column ia a tableor in a view in SQL Server 2000?I can do:1. CREATE TABLE Users(fname varchar(20),lname varchar(20),email as LOWER(LEFT (fname,1) + lname) )Or2. CREATE TABLE Users (fname varchar(20),lname varchar(20))CREATE VIEW Vw_users (fname, Lname ,email)ASSELECT fname, Lname ,LOWER(LEFT (fname,1) + lname) )Is one of them is better?Paulo*** Sent via Developersdex http://www.developersdex.com ***Don't just participate in USENET...get rewarded for it!
View 1 Replies View RelatedI created a index on a computed column. I did not see any improvementin performance with a join to this column and also my inserts andupdates to this table are failing. Any ideas?Chender
View 2 Replies View RelatedHi,
Consider the following example
create table sample
(col1 int,
col2 int ,
col3 AS col1 + col2) PERSISTED NOT NULL)
basically col3 is a computed column. Now when ever a row in col1 or col2 is updated the computed column will reflect the new value. how does this happen in the background. does this use row level triggers or what other mechanism is used to maintain col3 - computed column
Hi,
i have to use a datetime field in all the tables in a database as a updated timestamp.
i.e. : whenever an update happens to a row in a table, this column called LASTUPDATED has to be updated with current date time.Is there any way to implement this without using the trigger ?
can i use COMPUTED column to acheive this ?
Please help me..thnks in advance..
I have a SQL table that maintains a field on the status of a report being completed.
I have in the record the date the report is due (DateDue)
I also have a field called DaysLate which I have set to be a calculated field with formula:
DATEDIFF(dd, DateDue, GETDATE())
Thsi works but when the report is *not* late I'd like this to be null is there I way I can do this conditional calculation in a calculated field?
Regards
Cvive
Hi,
What is the difference between a computed column and a UDF?
Is a computed column the same as the "Formula" field under Design Table in Enterprise Manager?
Also, what is the proper syntax for the Formula field? Can I use regular SQL on it or is there more to it?
thanks,
Frank
I have a view that has 2 columns. The first column is associated with a function for the Units. The second column calculates the Market Value:
View
====
Col1: Unit = get_number_of_units()
Col2: MV = get_number_of_units() * get_unit_value()
I need to call get_number_of_units() twice in the view. Is it possible to changes Col2 to something like: MV = Col1 * get_unit_value()?
Is get_unit_value() being called if I do Select Col1 from View?
Thanks.
somehow I am not able to figure this out.
How do I change a computed column using the ALTER TABLE ALTER COLUMN... command?
Hi,
I'm having a problem with a computed field in a table. I have a stored procedure that inserts a row into a table and returns the id and the computed value.
The computed colmn is returned as a decimal (29,6) but for some reason the value is returned with no decimals (confirmed by the Profiler).
The value is calculated and displayed in the database properly with decimals. Also, Is Persisted is OFF.
Below is the stored procedure, computed column foruma (both give same result), and the profiler trace.
Thanks
Stored Procedure
================================================== ==============
ALTER PROCEDURE [Purchasing].[ntp_PurchaseOrderDetail_Insert]
(
@PurchaseOrderDetailId int OUTPUT,
@PurchaseOrderId int ,
@OrderQty decimal (11, 4) ,
@VendorProductId int ,
@Description nvarchar (255) ,
@UnitPrice decimal (18, 6) ,
@PackingQty decimal (14, 4) ,
@DueDateValue nvarchar (50) ,
@ModifiedDate datetime ,
@IsUnitPriceManual bit ,
@LineTotal decimal (29, 6) OUTPUT
)
AS
INSERT INTO [Purchasing].[PurchaseOrderDetail]
(
[PurchaseOrderID]
,[OrderQty]
,[VendorVendorProductID]
,[Description]
,[UnitPrice]
,[PackingMethod]
,[PackingQty]
,[DueDateValue]
,[ModifiedDate]
,[IsUnitPriceManual]
)
VALUES
(
@PurchaseOrderId
,@OrderQty
,@VendorVendorProductId
,@Description
,@UnitPrice
,@PackingMethod
,@PackingQty
,@DueDateValue
,@ModifiedDate
,@IsUnitPriceManual
)
-- Get the identity value
SET @PurchaseOrderDetailId = SCOPE_IDENTITY()
-- Select computed columns into output parameters
SELECT
@LineTotal = [LineTotal]
FROM
[Purchasing].[PurchaseOrderDetail]
WHERE
[PurchaseOrderDetailID] = @PurchaseOrderDetailId
Computed Column Formula
================================================== ==============
isnull(CONVERT(DECIMAL (29,6),[OrderQty]*([UnitPrice]*[PackingQty])),0.000000)
or
isnull([OrderQty]*([UnitPrice]*[PackingQty]),0.000000)
Profiler Trace
================================================== ==============
declare @p1 int
set @p1=115
declare @p16 numeric(29,0) <- should be numeric(29,6)
set @p16=5 <- value should be 5.259200
exec Purchasing.PurchaseOrderDetail_Insert @PurchaseOrderDetailId=@p1 output,@PurchaseOrderId=68,@OrderQty=4,@VendorProd uctId=28,@Description=N'93678975 - GL-2222',@UnitPrice=0.657400,@PackingMethod=N'Bags (2)',@PackingQty=2.0000,@DueDateValue=NULL,@Modifi edDate=''2008-05-19 15:06:37:610'',@LineTotal=@p16 output
select @p1, @p16
I have a question about Computed Column Specification which you can specify as a formula for each column inside a table.
I have now columns named Age and Class.
Classes are "Kids" (ID #1) , "Junior" (ID #2) and "Senior" (ID #3)
Kids, which is for age of 6 till 12
Junior, which is for 12 till 16
Senior, 16 and above.
I have already searched for hours (I really did) on the internet for a solution, but ended with more questions because of the complicated solutions.
Now the Age is shown as a result of a formule of DOB (Date of Birth column), now I want the exact same thing, but the age must specify which Class the user is in.
Example, when I add a user with the birthdate 25/03/1988 (DD/MM/YYYY) he/she gets 24 as age.
With this formula : (datediff(year,[age],getdate()))
Now I want that the user gets "Senior" as Class (same table).
Senior is ID 3 in this case.
Now I do know how Case, When and Then works, but the validation fails. After reading some forums I understood that I should use a create function method. I am not really experienced with creating functions. Also the coding looks more different as I am used to. How to link the Computed Column to a created formula.
dear sirs,
this is my first contribution at you reputable forum ..
I have a serious problem which is .. I want to create a trigger which runs at the begining of each month .. so I created a table which has a field --> formula --> month(getdate()) i tested it by changing the month in the windows calender and each time i change the month it is updated in the table when I crated a trigger i checked if update(sal_month)
the trigger is as follows
========================================
create trigger tr_update_loan
on salary_month
for update
as
if update(sal_month)
begin
update hr_emp_loan
set payed = payed + one_loan , rest = rest - one_loan
end
=========================================
it returned an error "Column 'sal_month' cannot be used in an IF UPDATE clause because it is a computed column."
I tried to not to use if update() but when I change the date in the calender it is not updated in the other table
can any one help my in this because I'm doing my graduation project
I am currently developing a stored procedure that includes a number of computed fields. Is it possible to reference a computed value, (eg. FLdA), or do I need to CREATE a temp file and then reference the FldA and FldB values. I have simplified my code, it is much more extensive in that there are numerous WHEN clauses attached to each FldA and FldB computation.
SELECT FldA = CASE
WHEN .... THEN CurQty * 1.5
WHEN .... THEN CurQty * 1.75 ELSE 0 END),
FldB = CASE .....
NewValue = CASE
WHEN .... THEN FldA * CurValue
WHEN .... THEN FldB * CurValue
etc.
need help ,
i have a table called "Loans" where i need to compute a column i.e. NoofDays based on which other calculation like interest calculation needs to be done.
my query goes like this
"select datediff(dd,VDate, MDate) as NoOfDays ,NoOfDays * Principal * Rate /100 * 365 from Loans".
if i run the above query it says
"Invalid column name 'NoOfDays'".
this executes fine if i use Access but not in SQL Server.
can anybody say what might be the problem and how i can solve it.
regards
Rajesh :)
hi
i want to create a table that has a computed column like this :
create table resources(
id int identity(0,1) primary key,
currentDate int not null,
currentMonth int default 0,
monthBefore as (currentMonth - (select top 1 currentMonth from resources where (currentDate - resources.currentDate) = 1)))
as u can see, monthBefore is computed column, and i want get currentMonth value of previous month, for this work, i define a column as currentDate that hold only year+month (like 971,082,083,...) and by this expression, i want to get currentMonth of previous record (previous month), but the following error has shown me :
Subqueries are not allowed in this context. Only scalar expressions are allowed.
how to solve this problem to get currentMonth of previous record ?
thanks
I have downloaded the SQL Server Books online and found the section on Computed columns. In my small banking program I have columns named Deposit/Withdrawel and Balance. If I am reading this right I need to set the Computed Column Specification of my Balance Column in order to perform the calculation. My problem now is that I have no idea how to word the formula and other than telling me what a formula is the SQL Server Books online is no help whatsoever, so any help would be awesome.
If i've misunderstood what I am meant to do somebody please please tell me. Thanks
how do you change the allow null on a column to be 0,
so instead of having null when empty, it would be 0,
I tried default value or binding to 0 to -1, and to 1
and in 0 or -1, it stays null, in 1 it puts the 1
for example if is quantity, it puts as if I would have 1 quantity,
so it's either null, or whathever number I put visides -1 or 0
how can I make it be 0 as defult?
I'm using it to add and substract with computed column, formula;
and the problem is that if it's the first time it's used it does not add or substract, becsause it does not add null with a number, if it has 0 than it works,
whata I had to do is add it manually, but of course it doesn't suppoesed to be that way
any suggestions will be appriciated:
If i want to split a computed column into two or more columns based onthe the length (its a varchar) of the computed column, how often willsql server determine what the computed column is? roughly along thelines ofselect comp_col,'comp_col 2'=case when datalength(comp_col)<=100 then comp_colelse left(comp_col,99) + '~' end,datalength(comp_col)from aTableAs you can see, in this scenario we use the computed coulumn,comp_col, in a few places, so does SQL server need to calculate thiseach time? I'm playing with this on the basis that it does and thustrying to shift the computed column out to a variable and thenmanipulte and return from their, but that has its own problems whenyou throw in additional parameters (trying to join table udf's) so ifSQL server is smart enough to not calculate the column each time Iwould save a lot of hassle?Cheers Dave
View 9 Replies View RelatedCan I create an index on a variation of a column that isn't actually inthe table?I have a ParcelNumber column, with values like123 AB-67012345ABC 000-00-04012-345-67AP34567890The blanks and non-alphanumeric characters cause problems with users,because sometimes they're there, and sometimes they aren't. So I wouldlike to create an index based on this column, with the non-alphanumericcharacters squeezed out. Of course I can add such a column to thetable and index it, but I'm wondering if it can be done withoutactually adding the column.Thanks,Jim
View 6 Replies View RelatedHello,I want to assign a column a computed value, which is the multiplicationof a value from the table within and a value from another table.How can I do that?Say the current table is A, column1; and the other table is B, column3.What should I write as formula?I tried someting like;column1 * (SELECT column3 FROM B WHERE A.ID = B.ID)but it didn't work.
View 2 Replies View Related hi
i want to create a table that has a computed column like this :
Code Snippetcreate table resources(id int identity(0,1) primary key,currentDate int not null,currentMonth int default 0,monthBefore as (currentMonth - (select top 1 currentMonth from resources where (currentDate - resources.currentDate) = 1)))
as u can see, monthBefore is computed column, and i want get currentMonth value of previous month, for this work, i define a column as currentDate that hold only year+month (like 971,082,083,...) and by this expression, i want to get currentMonth of previous record (previous month), but the following error has shown me :
Code SnippetSubqueries are not allowed in this context. Only scalar expressions are allowed.
how to solve this problem to get currentMonth of previous record ?
thanks
Is it possible to use a cursor in computed column?
I have two table (Table1 and Table2). Table 2 is child of Table 1.
Table 2 has more than one record for each record in table 1. What I want is, to concat records from table 2 and show it as a column value for Table1.
e.g.
Code Block
Table 1:
Col1 Col2
1 ABC
1 DEF
Table 2
T1Col1 Col2
1 A
1 -
1 B
1 1
1 -
1 C
I want to see the Results as
Table 1
Col1 Col2 Col3
1 ABC A-B1-C
Is it possible to add computed column for the table1 to get the result as shown in above block.
Thanks
Hello everybody!
I have question about indexed and not indexed Persisted columns on sql server 2005. It's a bug?
First?, my version of SQL Server is
Microsoft SQL Server 2005 - 9.00.3186.00 (Intel X86) Aug 11 2007 03:13:58 Copyright (c) 1988-2005 Microsoft Corporation Developer Edition on Windows NT 5.1 (Build 2600: Service Pack 2)
Now I create two tables and try four select queries:
Code Snippet
SET ANSI_NULLS ON
SET ANSI_PADDING ON
SET ANSI_WARNINGS ON
SET ARITHABORT ON
SET CONCAT_NULL_YIELDS_NULL ON
SET NUMERIC_ROUNDABORT OFF
SET QUOTED_IDENTIFIER ON
GO
create table t1 (id int primary key, id_bigint as cast(id as bigint))
GO
create table t2 (id int primary key, id_bigint as cast(id as bigint) persisted)
GO
select * from t1 -- (1)
-- Clustered index scan with two times Compute Scalar
GO
select * from t2 -- (2)
-- Clustered index scan with one times Compute Scalar
GO
create index IX_t2 on t2 (id_bigint)
GO
select * from t2 -- (3)
-- Index Scan with one times Compute Scalar
GO
select * from t2 where id_bigint = 0 -- (4)
-- Index Seek with one times Compute Scalar
GO
drop table t1
GO
drop table t2
GO
SET ANSI_PADDING OFF
1. I don't understand why access to computed column raise scalar computation wto times?
2. I don't understand why access to persisted computed column raise any scalar computation?
3. I don't understand why access to persisted computed column over index required any scalar computations?
Can anyone from Microsoft SQL Server Team told me about this mistake?
It's a BUG or I incorrect understand value of the "PERSISTED" word?
--
Thanks with avanced.
WBR, Roman S. Golubin
grominc[at]gmail.com