How To Check Two Dates To See If They Are In The Same Week
May 14, 2008In sql server 2005, how do I check if two dates are within the same week?
View 6 RepliesIn sql server 2005, how do I check if two dates are within the same week?
View 6 Repliesi have the following table I need to select dates grouping them by weeks, my week start is Saturday to Friday
CREATE TABLE weekdays
(
datevalue datetime NOT NULL
, numericvalue INT NOT NULL
);
INSERT INTO weekdays (datevalue, numericvalue) VALUES
[code]....
The output should look like this
weeknototalvalue
362015-09-01 00:00:00.000
362015-09-02 00:00:00.000
372015-09-07 00:00:00.000
372015-09-08 00:00:00.000
382015-09-12 00:00:00.000
382015-09-13 00:00:00.000
382015-09-14 00:00:00.000
392015-09-19 00:00:00.000
I want to display week between two dates as below.
requirement is as:
suppose there are two dates.(which will comes dynamically, so no. of weeks varied)
10/20/2015 and 01/01/2016
Now between this two dates, i want to calculate number of weeks on another date which is coming from table.
Say for example the column date is coming as 10/23/2015 then it will fall in week-1
Same way if 11/01/2015 falls in week2.
I need a Query for calculating the fiscal_week based on the input dates (start_date and end_date), though I got a query from this forum, it is not giving me exact result.
the sample is in the excel file with the attachment.
In the excel:
First tab tells you the raw_data what I am using to find the Fiscal_week
Second tab tell you the data where i found the mistake, and how I am expecting the output.
I also have attached the query I have got from this forum, query I have modified for fiscal week.
I have a query to check the records of job has received after 4pm Monday to Friday and it has completed before 9am next day and also weekend it should be Friday after 4pm and before Monday 10am for particular financial year period. I have my job table which has full date but it doesn't show the date exactly Monday to Friday it shows only as 12-12-2014 like that.
View 2 Replies View RelatedBasically, I have a membership table that lists each member with an effective period, Eff_Period, that indicates a month when a member was active. So, if a member is active from Jan to Mar, there will be three rows with Eff_Periods of 201501, 201502 and 201503.
All well and good.But, a member may not necessarily have continuous months for active membership. They might have only been active for Jan, Feb and Jun. That would still give them three rows, but with noncontinuous Eff_Periods; they'd be 201501, 201502 and 201506.There is also a table that logs member activity. It has an Activity_Date that holds the date of the activity - betcha didn't see that comin'. What I'm trying to do is determine if an activity took place during a period when the member was active.
My original thought was to count how many rows a member has in the Membership table and compare that number to the number of months between the MIN(Eff_Period) and the MAX(Eff_Period). If the numbers didn't matchup, then I knew that the member had a disconnect somewhere; he became inactive, then active again. But, then I thought of the scenario I detailed above and realized that the counts could match, but still have a discontinuity.So, is there a nifty little SQL shortcut that could determine if a target month is contained within a continuous or discontinuous list of months?
I am trying to create a check constraint that prevents entry of a date range that overlaps any other date range in the table. The below example script results in the error message: The INSERT statement conflicted with the CHECK constraint "ck_dt_overlap". what I am doing wrong?
CREATE TABLE t1 (d1 date,d2 date)
go
create function dbo.dt_overlap (@d1 date, @d2 date) RETURNS BIT
AS
BEGIN
IF EXISTS (SELECT 1 from t1 where d1 between @d1 and @d2 or d2 between @d1 and @d2)
RETURN 1
RETURN 0
END
go
alter table t1 add constraint ck_dt_overlap CHECK (dbo.dt_overlap(d1,d2)=0)
go
insert into t1 values ('2015-01-01','2015-02-01')
insert into t1 values ('2015-01-15','2015-02-15')
--BOTH inserts result in the following message: The INSERT statement conflicted with the CHECK constraint "ck_dt_overlap".
drop table t1
drop function dbo.dt_overlap
We are trying to compare our current calendar week (based on Monday being the first day of the week) with the previous calendar week.
I'm trying to produce a line chart with 2 axis:
- x axis; the day of the week (Mon, Tues, Wed etc - it is fine for this to be a # rather than text e.g. 1 = Mon, 2 = Tues etc)
- y axis; the cumulative number of orders
The chart needs two series:
Previous Week. The running count of orders placed that week.
Current Week. The running count of orders placed this week.
Obviously in such a chart the 'Current Week' series is going not going to have values along the whole axis until the end of the week. This is expected and the aim of the chart is to see the current week compares against the previous week for the same day.
I have two tables:
Orders TableCalendar Table
The calendar table's main date column is [calDate] and there are columns for the usual [calWeekNum], [calMonth] etc.
My measure for counting orders is simply; # Orders: = countrows[orders].
How do I take this measure and then work out my two series. I have tried numerous things such as adapting TOTALMTD(), following articles such as these:
- [URL] ...
- [URL] ...
But I have had no luck. The standard cumulative formulas do work e.g. if I wanted a MTD or YTD table I would be ok, it's just adjusting to a WTD that is causing me big issues.
How can I get Saturday's date given the week number?
This is my week number, SELECT DATEPART(WEEK, DATEADD(MONTH, +3, ApptDt2)). I need to get Saturday's date from this week.
Hi all,
I'd like to add a yesterday dimension member to a new dimension, like a "Time Utility" dimension, that references the second last day of non empty data in a cube.
At the moment, I'm doing this:
Code Snippet
create member [MIA DW].[DATE TIME].[Date].[Yesterday]
as [DATE TIME].[Date].&[2007-01-01T00:00:00]
select [Measures].members on 0,
non empty [DATE TIME].[Date].members on 1
from [MIA DW]
But the [yesterday] member does not seem to belong to [DATE TIME].[Date].members?
So I guess there's two questions:
1) Can I have a new empty dimension which contains all these special members like "Yesterday" or "This Week" and "Last Week" (these last two obviously refer to a set of Dates)
2)How come the Yesterday member is not returned by the .members function?
Thanks
Greg
I am adding week hrs using while loop , but it can continue next week hrs also.
I can get every week start hrs while update @tem1 table
employeeidreportdatereportatleftattoaccountwrhrn
12902014-01-29 00:00:00.00009:3019:1556001
12902014-01-28 00:00:00.00009:0018:4555802
12902014-01-27 00:00:00.00009:0018:455585583
12902014-01-25 00:00:00.00008:0010:0012004 -- week end
12902014-01-24 00:00:00.00009:1718:4554105
12902014-01-23 00:00:00.00009:1918:4654606
12902014-01-22 00:00:00.00009:1718:4754507
12902014-01-21 00:00:00.00009:1618:3552608
12902014-01-20 00:00:00.00009:1818:555435439
My loop statement
while(select MAX(wrh) from @tem1 where wrh = 0) < 1
begin
update @tem1
set wrh = (select toaccount from @tem1
where reportdate = (select min(reportdate) from @tem1 where wrh = 0))+(select max(wrh) from @tem1)
where wrh = (select max(wrh) from @tem1 where wrh = 0 )
and reportdate = (select min(reportdate) from @tem1 where wrh = 0)
end
this is the result while executing loop statement .
employeeidreportdatereportatleftatdehdrhwehwrh
129029 Jan 201409:3019:15008:0009:20024:00065:54
129028 Jan 201409:0018:45008:0009:18016:00056:34
129027 Jan 201409:0018:45008:0009:18008:0009:18
129025 Jan 201408:0010:00005:0002:00045:00047:16 -- week end
129024 Jan 201409:1718:45008:0009:01040:00045:16
129023 Jan 201409:1918:46008:0009:06032:00036:15
129022 Jan 201409:1718:47008:0009:05024:00027:09
129021 Jan 201409:1618:35008:0008:46016:00018:04
129020 Jan 201409:1818:55008:0009:03008:0009:03
How to update only that week hrs , don't continue next week...
In my reports I am extracting the data of number of people joined in all the weeks of the year. And in one of reports I have to extract the data of the number of people joined until the last week from the first week. I am trying out all the logics but nothing is working for me as such. Can any one help me with this issue??????
View 4 Replies View RelatedI need a Select sentence that return me the first week of the month for a given week.
For example If I have week number 12 (Begins 2015/03/16 and Ends 2015/03/22) I need that returns 9, I mean Week number 9 wich is the first week of march (having in mind @@DATEFIRST).
I only need give a week number of the year and then returns the week number of the first week of that month.
I'm looking for a way to convert the [week number, year] back to the date for the 1st day of that week.
Example (assuming DATEFIRST has been set to 1) : Week 3, 2008 = January 14, 2008
Is there a SQL function that will do this?
Thanks,
Mike
seriously now
View 1 Replies View RelatedI have a query that run every day to update a summary table which has week number and day of week. what I currently do is delete all records from the summary table and then summarize all the data availabe from four tables adn then populate the table daily. I want to know if I can run the update query to run only for the week number and day of week depending on getdate. Can I do this?
Please help..
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK returns the ISO 8601 Year Week Day of Week in format YYYY-W01-D for the date passed. W01 represents the week of the year from W01 through W53, and D represents the day of the week with 1 = Monday through 7 = Sunday.
The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.
This code creates the function and demos it for the first day, first date+60, and first date+364 for each ISO week/year from 1990 to 2030.
drop function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
GO
create function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
(
@Datedatetime
)
returnsvarchar(10)
as
/*
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK
returns the ISO 8601 Year Week Day of Week
in format YYYY-W01-D for the date passed.
*/
begin
declare @YearWeekDayOfWeekvarchar(10)
Select
--Format to form YYYY-W01-D
@YearWeekDayOfWeek =
convert(varchar(4),year(dateadd(dd,7,a.YearStart)))+'-W'+
right('00'+convert(varchar(2),(datediff(dd,a.YearStart,@Date)/7)+1),2) +
'-'+convert(varchar(1),(datediff(dd,a.YearStart,@Date)%7)+1)
from
(
select
YearStart =
-- Case finds start of year
case
whenNextYrStart <= @date
thenNextYrStart
whenCurrYrStart <= @date
thenCurrYrStart
elsePriorYrStart
end
from
(
select
-- First day of first week of prior year
PriorYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aaa.Jan4))/7)*7,-53690),
-- First day of first week of current year
CurrYrStart =
dateadd(dd,(datediff(dd,-53690,aaa.Jan4)/7)*7,-53690),
-- First day of first week of next year
NextYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aaa.Jan4))/7)*7,-53690)
from
(
select
--Find Jan 4 for the year of the input date
Jan4=
dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0))
) aaa
) aa
) a
return @YearWeekDayOfWeek
end
go
-- Execute function on first day, first day+60,
-- and first day+364 for years from 1990 to 2030.
select
DT= convert(varchar(10),DT,121),
YR_START_DT =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT),
YR_START_DT_60 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+60),
YR_START_DT_365 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+364)
from
(
select DT = getdate()union all
select DT = convert(datetime,'1990/01/01') union all
select DT = convert(datetime,'1990/12/31') union all
select DT = convert(datetime,'1991/12/30') union all
select DT = convert(datetime,'1993/01/04') union all
select DT = convert(datetime,'1994/01/03') union all
select DT = convert(datetime,'1995/01/02') union all
select DT = convert(datetime,'1996/01/01') union all
select DT = convert(datetime,'1996/12/30') union all
select DT = convert(datetime,'1997/12/29') union all
select DT = convert(datetime,'1999/01/04') union all
select DT = convert(datetime,'2000/01/03') union all
select DT = convert(datetime,'2001/01/01') union all
select DT = convert(datetime,'2001/12/31') union all
select DT = convert(datetime,'2002/12/30') union all
select DT = convert(datetime,'2003/12/29') union all
select DT = convert(datetime,'2005/01/03') union all
select DT = convert(datetime,'2006/01/02') union all
select DT = convert(datetime,'2007/01/01') union all
select DT = convert(datetime,'2007/12/31') union all
select DT = convert(datetime,'2008/12/29') union all
select DT = convert(datetime,'2010/01/04') union all
select DT = convert(datetime,'2011/01/03') union all
select DT = convert(datetime,'2012/01/02') union all
select DT = convert(datetime,'2012/12/31') union all
select DT = convert(datetime,'2013/12/30') union all
select DT = convert(datetime,'2014/12/29') union all
select DT = convert(datetime,'2016/01/04') union all
select DT = convert(datetime,'2017/01/02') union all
select DT = convert(datetime,'2018/01/01') union all
select DT = convert(datetime,'2018/12/31') union all
select DT = convert(datetime,'2019/12/30') union all
select DT = convert(datetime,'2021/01/04') union all
select DT = convert(datetime,'2022/01/03') union all
select DT = convert(datetime,'2023/01/02') union all
select DT = convert(datetime,'2024/01/01') union all
select DT = convert(datetime,'2024/12/30') union all
select DT = convert(datetime,'2025/12/29') union all
select DT = convert(datetime,'2027/01/04') union all
select DT = convert(datetime,'2028/01/03') union all
select DT = convert(datetime,'2029/01/01') union all
select DT = convert(datetime,'2029/12/31') union all
select DT = convert(datetime,'2030/12/30')
) a
Function Test Results:
DT YR_START_DT YR_START_DT_60 YR_START_DT_364
---------- ----------- -------------- ---------------
2006-01-18 2006-W03-3 2006-W11-7 2007-W03-3
1990-01-01 1990-W01-1 1990-W09-5 1991-W01-1
1990-12-31 1991-W01-1 1991-W09-5 1992-W01-1
1991-12-30 1992-W01-1 1992-W09-5 1992-W53-1
1993-01-04 1993-W01-1 1993-W09-5 1994-W01-1
1994-01-03 1994-W01-1 1994-W09-5 1995-W01-1
1995-01-02 1995-W01-1 1995-W09-5 1996-W01-1
1996-01-01 1996-W01-1 1996-W09-5 1997-W01-1
1996-12-30 1997-W01-1 1997-W09-5 1998-W01-1
1997-12-29 1998-W01-1 1998-W09-5 1998-W53-1
1999-01-04 1999-W01-1 1999-W09-5 2000-W01-1
2000-01-03 2000-W01-1 2000-W09-5 2001-W01-1
2001-01-01 2001-W01-1 2001-W09-5 2002-W01-1
2001-12-31 2002-W01-1 2002-W09-5 2003-W01-1
2002-12-30 2003-W01-1 2003-W09-5 2004-W01-1
2003-12-29 2004-W01-1 2004-W09-5 2004-W53-1
2005-01-03 2005-W01-1 2005-W09-5 2006-W01-1
2006-01-02 2006-W01-1 2006-W09-5 2007-W01-1
2007-01-01 2007-W01-1 2007-W09-5 2008-W01-1
2007-12-31 2008-W01-1 2008-W09-5 2009-W01-1
2008-12-29 2009-W01-1 2009-W09-5 2009-W53-1
2010-01-04 2010-W01-1 2010-W09-5 2011-W01-1
2011-01-03 2011-W01-1 2011-W09-5 2012-W01-1
2012-01-02 2012-W01-1 2012-W09-5 2013-W01-1
2012-12-31 2013-W01-1 2013-W09-5 2014-W01-1
2013-12-30 2014-W01-1 2014-W09-5 2015-W01-1
2014-12-29 2015-W01-1 2015-W09-5 2015-W53-1
2016-01-04 2016-W01-1 2016-W09-5 2017-W01-1
2017-01-02 2017-W01-1 2017-W09-5 2018-W01-1
2018-01-01 2018-W01-1 2018-W09-5 2019-W01-1
2018-12-31 2019-W01-1 2019-W09-5 2020-W01-1
2019-12-30 2020-W01-1 2020-W09-5 2020-W53-1
2021-01-04 2021-W01-1 2021-W09-5 2022-W01-1
2022-01-03 2022-W01-1 2022-W09-5 2023-W01-1
2023-01-02 2023-W01-1 2023-W09-5 2024-W01-1
2024-01-01 2024-W01-1 2024-W09-5 2025-W01-1
2024-12-30 2025-W01-1 2025-W09-5 2026-W01-1
2025-12-29 2026-W01-1 2026-W09-5 2026-W53-1
2027-01-04 2027-W01-1 2027-W09-5 2028-W01-1
2028-01-03 2028-W01-1 2028-W09-5 2029-W01-1
2029-01-01 2029-W01-1 2029-W09-5 2030-W01-1
2029-12-31 2030-W01-1 2030-W09-5 2031-W01-1
2030-12-30 2031-W01-1 2031-W09-5 2032-W01-1
(43 row(s) affected)
CODO ERGO SUM
can sql server do this ?
table 1 that check table 2 and adding missing dates
this my employee table
table 1
table Employee on work
------------------------
empid basedate shift
----------------------------
12345678 01/04/2007 1
12345678 02/04/2007 1
12345678 03/04/2007 1
12345678 04/04/2007 1
12345678 05/04/2007 1
12345678 06/04/2007 1
12345678 07/04/2007 1
12345678 08/04/2007 1
12345678 09/04/2007 1
12345678 10/04/2007 1
98765432 20/04/2007 1
98765432 21/04/2007 3
98765432 22/04/2007 3
98765432 23/04/2007 5
98765432 25/04/2007 4
98765432 26/04/2007 4
98765432 27/04/2007 4
98765432 28/04/2007 4
98765432 30/04/2007 4
-----------------------------------------------------------------------------------
and i need to see the missing dates lkie this
in table 2
------------------------------------------------------
table 2 (adding missing dates with zero 0)
table Employee_all_month
------------------------
empid basedate shift
----------------------------
12345678 01/04/2007 1
12345678 02/04/2007 1
12345678 03/04/2007 1
12345678 04/04/2007 1
12345678 05/04/2007 1
12345678 06/04/2007 1
12345678 07/04/2007 1
12345678 08/04/2007 1
12345678 09/04/2007 1
12345678 10/04/2007 1
12345678 11/04/2007 0
12345678 12/04/2007 0
12345678 13/04/2007 0
12345678 14/04/2007 0
12345678 15/04/2007 0
12345678 16/04/2007 0
12345678 17/04/2007 0
12345678 18/04/2007 0
12345678 19/04/2007 0
12345678 20/04/2007 0
.................................and adding missing dates with zero 0 until the end of the month
.................................
12345678 31/04/2007 0
98765432 01/04/2007 0
98765432 02/04/2007 0
98765432 03/04/2007 0
98765432 04/04/2007 0
98765432 05/04/2007 0
98765432 06/04/2007 0
98765432 07/04/2007 0
98765432 08/04/2007 0
98765432 09/04/2007 0
..............................and adding missing dates with zero 0 only whre no dates in this month
.......................
98765432 20/04/2007 1
98765432 21/04/2007 3
98765432 22/04/2007 3
98765432 23/04/2007 5
98765432 25/04/2007 4
98765432 26/04/2007 4
98765432 27/04/2007 4
98765432 28/04/2007 4
98765432 30/04/2007 4
TNX
hi friends,
how to get the date of the first/last day of the week in sql...
can any one help me
Cheers,
raj
SQL 2005 Dev
How can I do this with Parameters? I can get a single parameter to filter for a single date (or even a combo list of the dates in DB). But I want my parameters to interact so that they specify a range. Is this possible?
Today I have got one scenario to calculate the (sum of days difference minus(-) the dates if the same date is appearing both in assgn_dtm and complet_dtm)/* Here goes the table schema and sample data */
IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[temp_tbl]') AND type in (N'U'))
DROP TABLE [dbo].[temp_tbl]
GO
CREATE TABLE [dbo].[temp_tbl](
[tbl_id] [bigint] NULL,
[cs_id] [int] NOT NULL,
[USERID] [int] NOT NULL,
[code]....
I have a table that has hotel guests and their start stay date and end stay date, i would like to insert into a new table the original information + add all days in between.
CREATE TABLE hotel_guests
(
[guest_name] [varchar](25) NULL,
[start_date] [date] NULL,
[end_date] [date] NULL,
[comment] [varchar](255) NULL
[code]...
I have multiple ODBC connection and how to check all connection automatically during routine check by using batch file.
View 5 Replies View RelatedI want to know if there is a way to compare dates in the sql statement with dates that I input into a database and todays date. the datatype that I'm using is smalldatetime.The statement I used is:Select Date from Table where Date > 'Today.now'I get an errorCould this be done or is there another approach?
View 1 Replies View RelatedHi,
I have a table which records employees'time-off records. There are 6 columns in this TimeOff table. They are RequestID, EmpName, StartDate, EndDate, Type, NumofDays. I have another table which has all the dates from 01/01/1950 to 01/01/2056.
I am trying write a query which lists all the dates between the timeoff startdate and enddate, including the the start and end dates, but my query so far only lists the start and end date in a timeoff record:
SELECT D.[Date], Datename(dw,D.[Date]) AS Weekday
FROM Dates D LEFT JOIN TimeOff T ON D.[Date] = T.OffStartDate OR D.[Date] = T.OffEndDate
WHERE (OffType = 'Sick Day' AND EmpName = 'Cat White') AND (D.[Date] BETWEEN T.StartDate AND T.EndDate)
Any advice will be greatly appreciated!
Has anyone ever written a function to retrieve all individual dates between two given dates? Using DATEDIFF I can get the number of days between two dates. However I need to iterate through the days to identify weekend and holiday dates. Has anyone ever written a function to do this?
So, if select datediff(d,'07/01/2007','07/15/2007') as NumOfDays returns 14, I'd need to iterate through the 14 days and get the weekends and holidays. Would I have to use a cursor to iterate through the days?
How to find the saturday in the current week using sql server 2000
View 5 Replies View RelatedI am trying to convert a field that has a Date and Time in smallDateTime format into something that will give me the day of the week that each Date corresponds to. For example, if my Date/Time field says "Jun 7 2001 09:30:00" I want my Day field to automatically say "Thursday". Is there a function that will do this? Or is there something close that will convert a variable of smalldatetime format into a number 0-6 which then can be converted to a day of the week?
View 3 Replies View RelatedIs it possible to write a sql querry to display day of the week?
If it is what is the syntax Pls.
Elsie Reed
Is there a way I can filter dates for last week (May 4 - 10)? This mean that every Mondays, I'll be getting last week's date range. Thanks
View 17 Replies View RelatedHow do I see which is the first day of the week setting in my server?
I was reading about @@DATEFIRST and SET FIRSTDATE, etc. But I don't want to set anything, I just want to know what is the first day of the week set on my server.
Any help will be appreciated.
Thanks
OPi
I need to write a user defined function that will return the date of the first day of a week when provided with the week number. I had an idea of using a while loop with that will keep adding 1 day from January 1st until the week number (found via the DATEPART function) is equal to the supplied week number. Not sure if this is the best way though - any ideas?
Donald.
Is there anyway to get SQL to convert a date to days of the week?
Example, I have a query where the date is "01/01/2006" but I would like it to display "Sunday". Thank you.