How To Get Week Data As 1-2 And 3-4 Format

Apr 25, 2008

I am doing reports and I am generating reports for weeks data. And I need data in the format of 1-2 week, 3-4 week and etc. So, I have tried to use aggregate functions also but they are not applicble for table and lists where all my report items are present. So. some one who can come up with the solution will be appreciated.

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How To Get Week Data As 1-2 And 3-4 Format Using Queries

May 6, 2008

I have 1st week and 2 nd week data in my database and for a particular report I need to add up the corresponding values of both the weeks and display them in one column as 1-2 format. I have tried out various options on reporting side but I was not able to do anything. Now can anyone tell me if I can write a query for that?? If so what is the format of the query and where do I need to write it???????

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How To Get Data Untill Last Week From The First Week Of The Year

Apr 29, 2008

In my reports I am extracting the data of number of people joined in all the weeks of the year. And in one of reports I have to extract the data of the number of people joined until the last week from the first week. I am trying out all the logics but nothing is working for me as such. Can any one help me with this issue??????

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SQL Server 2008 :: Return Fiscal Year Based On YYYY-week Format

Nov 6, 2015

I have a table where hours are being loaded in a weekly basis. The YearWeek is populated when the data is loaded. The value format of the Year Week is 2015-39, 2015-41, etc. I need to calculate the total hours per Fiscal Year.For example, week '2015-39' will be return FY15 and week '2015-41' will return FY16, and so on. By extracting the year, I can do a group by and have total hours for each year.

Currently, I have it working by splitting the value into year and week and then looping through each year and week, so I can assign the totals to the corresponding FY.select sum(hours) as total, yearweek from tablename group by yearweek...Then I loop through using C#.I can return the FY using an actual date,how to do it for year-week format for any given year.

select CASE
WHEN CAST(GETDATE() AS DATE) >
SMALLDATETIMEFROMPARTS(DATEPART(YEAR,GETDATE()),09,30,00,000)
THEN
DATEPART(YEAR,GETDATE()) + 1 ELSE DATEPART(YEAR,GETDATE())
END AS FY

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Power Pivot :: Cumulative Total For Current Week Days And Previous Week

Nov 30, 2015

We are trying to compare our current calendar week (based on Monday being the first day of the week) with the previous calendar week. 

I'm trying to produce a line chart with 2 axis:

- x axis; the day of the week (Mon, Tues, Wed etc - it is fine for this to be a # rather than text e.g. 1 = Mon, 2 = Tues etc)
- y axis; the cumulative number of orders 

The chart needs two series:

Previous Week. The running count of orders placed that week. 
Current Week. The running count of orders placed this week. 

Obviously in such a chart the 'Current Week' series is going not going to have values along the whole axis until the end of the week. This is expected and the aim of the chart is to see the current week compares against the previous week for the same day. 

I have two tables:

Orders TableCalendar Table

The calendar table's main date column is [calDate] and there are columns for the usual [calWeekNum], [calMonth] etc. 

My measure for counting orders is simply; # Orders: = countrows[orders].

How do I take this measure and then work out my two series. I have tried numerous things such as adapting TOTALMTD(), following articles such as these:

- [URL] ...
- [URL] ...

But I have had no luck. The standard cumulative formulas do work e.g. if I wanted a MTD or YTD table I would be ok, it's just adjusting to a WTD that is causing me big issues.

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Apr 9, 2013

How can I get Saturday's date given the week number?

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Sep 17, 2015

i have the following table I need to select dates grouping them by weeks, my week start is Saturday to Friday

CREATE TABLE weekdays
(
datevalue datetime NOT NULL
, numericvalue INT NOT NULL
);
INSERT INTO weekdays (datevalue, numericvalue) VALUES

[code]....

The output should look like this

weeknototalvalue
362015-09-01 00:00:00.000
362015-09-02 00:00:00.000
372015-09-07 00:00:00.000
372015-09-08 00:00:00.000
382015-09-12 00:00:00.000
382015-09-13 00:00:00.000
382015-09-14 00:00:00.000
392015-09-19 00:00:00.000

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May 23, 2007

Hi all,

I'd like to add a yesterday dimension member to a new dimension, like a "Time Utility" dimension, that references the second last day of non empty data in a cube.

At the moment, I'm doing this:




Code Snippet

create member [MIA DW].[DATE TIME].[Date].[Yesterday]
as [DATE TIME].[Date].&[2007-01-01T00:00:00]

select [Measures].members on 0,
non empty [DATE TIME].[Date].members on 1
from [MIA DW]
But the [yesterday] member does not seem to belong to [DATE TIME].[Date].members?

So I guess there's two questions:

1) Can I have a new empty dimension which contains all these special members like "Yesterday" or "This Week" and "Last Week" (these last two obviously refer to a set of Dates)

2)How come the Yesterday member is not returned by the .members function?


Thanks

Greg

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I want to select weekly data from daily data.lets say Today's date-10/23/2014(Thursday) My data is in date time but i want to see only date

output should be from last week Thursday to this week Wednesday. similar for previous dates

Weekly sum(profit)
10/16 - 10/21 - $1000
10/9 - 10/15 - $4100
10/2 - 10/8 - $ 8038
--
--
--

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How To Stop Week Hours To Continue To Next Week

Jan 29, 2014

I am adding week hrs using while loop , but it can continue next week hrs also.

I can get every week start hrs while update @tem1 table

employeeidreportdatereportatleftattoaccountwrhrn
12902014-01-29 00:00:00.00009:3019:1556001
12902014-01-28 00:00:00.00009:0018:4555802
12902014-01-27 00:00:00.00009:0018:455585583
12902014-01-25 00:00:00.00008:0010:0012004 -- week end
12902014-01-24 00:00:00.00009:1718:4554105
12902014-01-23 00:00:00.00009:1918:4654606
12902014-01-22 00:00:00.00009:1718:4754507
12902014-01-21 00:00:00.00009:1618:3552608
12902014-01-20 00:00:00.00009:1818:555435439

My loop statement

while(select MAX(wrh) from @tem1 where wrh = 0) < 1
begin
update @tem1
set wrh = (select toaccount from @tem1
where reportdate = (select min(reportdate) from @tem1 where wrh = 0))+(select max(wrh) from @tem1)
where wrh = (select max(wrh) from @tem1 where wrh = 0 )
and reportdate = (select min(reportdate) from @tem1 where wrh = 0)
end

this is the result while executing loop statement .

employeeidreportdatereportatleftatdehdrhwehwrh
129029 Jan 201409:3019:15008:0009:20024:00065:54
129028 Jan 201409:0018:45008:0009:18016:00056:34
129027 Jan 201409:0018:45008:0009:18008:0009:18
129025 Jan 201408:0010:00005:0002:00045:00047:16 -- week end
129024 Jan 201409:1718:45008:0009:01040:00045:16
129023 Jan 201409:1918:46008:0009:06032:00036:15
129022 Jan 201409:1718:47008:0009:05024:00027:09
129021 Jan 201409:1618:35008:0008:46016:00018:04
129020 Jan 201409:1818:55008:0009:03008:0009:03

How to update only that week hrs , don't continue next week...

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I need a Select sentence that return me the first week of the month for a given week.

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I only need give a week number of the year and then returns the week number of the first week of that month.

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Example (assuming DATEFIRST has been set to 1) : Week 3, 2008 = January 14, 2008

Is there a SQL function that will do this?


Thanks,
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Dear All,
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getdate()-1 week.

please guide me in this regard

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Jul 29, 2014

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Apr 29, 2008

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May 21, 2015

I have a date table(A) for every day of the year from 1990-2016 including the week number.There is another table(B) that has a number, date and week number.

I would like to join these 2 tables together, in order to populate the number from table B on every day of the week (of the week number in table B).

What makes it a little more complex is that the dates in table B not always correspond with the week number in the same row. Adding to the problem are some conditions:

- Every day of the week should have a number, and it should never be 0.

- If the 1st date of all rows in table B with the corresponding week number is not the monday of the week (but for example wednesday) it should start with this number on monday.

- Thousands of rows are in table B and for some of them the date corresponds with the week and for some of them they don't

- The rows can be grouped together using the week number.

Take the following example of table B:

B:
ID Date Number WeekNo
1 21-5-2015 25 21
2 23-5-2015 30 21

In this example the dates correspond with the weeknumber, because the 21st and the 23rd of may are week 21. By joining this with the date table (A), by using for example cross apply, I would hope to get the following result;

Date Number WeekNo
18-5 25 21
19-5 25 21
20-5 25 21
21-5 25 21
22-5 25 21
23-5 30 21
24-5 30 21

The same should work if the same example had the week number 22 in every row.

Take the following example of table B:

B:
ID Date Number WeekNo
1 21-5-2015 25 22
2 23-5-2015 30 22

In this example the dates do not correspond with the weeknumber, because the 21st and the 23rd of may are week 21 and not 22. By joining this with the date table (A), I would hope to get the following result;

Date Number WeekNo
25-5 30 22
26-5 30 22
27-5 30 22
28-5 30 22
29-5 30 22
30-5 30 22
31-5 30 22

Because the last result (ordered by date) of the week number 22 is 30, the whole week shows 30 on every day.

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I have a large query that returns a list of records that are marked by day of the business week (Monday, Tuesday, Wed, etc).

I am running into a challenge where I need to provide summaries of data from those days. For example, it needs to look like this:



Date | Day of Week | Total Widgets |

09/01/06 | M | 4
09/02/06 | Tu | 5
09/03/06 | We | 6
09/04/06 | Th | 7
09/05/06 | Fri | 8

Total Widgets: 30

09/08/06 | M | 1
09/09/06 | Tu | 2
09/10/06 | We | 3
09/11/06 | Th | 4
09/12/06 | Fri | 5

Total Widgets: 15

I'm using Reporting Services to format and display the report.

I've got the group by working for the entire data set, but I need to separate it by these sections. Any assisntance is appreciated.

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Jun 6, 2006

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Aug 15, 2006

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Please help..

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ISO Year Week Day Of Week Function

Jan 18, 2006

Function F_ISO_YEAR_WEEK_DAY_OF_WEEK returns the ISO 8601 Year Week Day of Week in format YYYY-W01-D for the date passed. W01 represents the week of the year from W01 through W53, and D represents the day of the week with 1 = Monday through 7 = Sunday.

The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.

This code creates the function and demos it for the first day, first date+60, and first date+364 for each ISO week/year from 1990 to 2030.


drop function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
GO
create function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
(
@Datedatetime
)
returnsvarchar(10)
as
/*
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK
returns the ISO 8601 Year Week Day of Week
in format YYYY-W01-D for the date passed.
*/
begin

declare @YearWeekDayOfWeekvarchar(10)

Select
--Format to form YYYY-W01-D
@YearWeekDayOfWeek =
convert(varchar(4),year(dateadd(dd,7,a.YearStart)))+'-W'+
right('00'+convert(varchar(2),(datediff(dd,a.YearStart,@Date)/7)+1),2) +
'-'+convert(varchar(1),(datediff(dd,a.YearStart,@Date)%7)+1)
from
(
select
YearStart =
-- Case finds start of year
case
whenNextYrStart <= @date
thenNextYrStart
whenCurrYrStart <= @date
thenCurrYrStart
elsePriorYrStart
end
from
(
select
-- First day of first week of prior year
PriorYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aaa.Jan4))/7)*7,-53690),
-- First day of first week of current year
CurrYrStart =
dateadd(dd,(datediff(dd,-53690,aaa.Jan4)/7)*7,-53690),
-- First day of first week of next year
NextYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aaa.Jan4))/7)*7,-53690)
from
(
select
--Find Jan 4 for the year of the input date
Jan4=
dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0))
) aaa
) aa
) a

return @YearWeekDayOfWeek

end
go


-- Execute function on first day, first day+60,
-- and first day+364 for years from 1990 to 2030.

select
DT= convert(varchar(10),DT,121),
YR_START_DT =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT),
YR_START_DT_60 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+60),
YR_START_DT_365 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+364)
from
(
select DT = getdate()union all
select DT = convert(datetime,'1990/01/01') union all
select DT = convert(datetime,'1990/12/31') union all
select DT = convert(datetime,'1991/12/30') union all
select DT = convert(datetime,'1993/01/04') union all
select DT = convert(datetime,'1994/01/03') union all
select DT = convert(datetime,'1995/01/02') union all
select DT = convert(datetime,'1996/01/01') union all
select DT = convert(datetime,'1996/12/30') union all
select DT = convert(datetime,'1997/12/29') union all
select DT = convert(datetime,'1999/01/04') union all
select DT = convert(datetime,'2000/01/03') union all
select DT = convert(datetime,'2001/01/01') union all
select DT = convert(datetime,'2001/12/31') union all
select DT = convert(datetime,'2002/12/30') union all
select DT = convert(datetime,'2003/12/29') union all
select DT = convert(datetime,'2005/01/03') union all
select DT = convert(datetime,'2006/01/02') union all
select DT = convert(datetime,'2007/01/01') union all
select DT = convert(datetime,'2007/12/31') union all
select DT = convert(datetime,'2008/12/29') union all
select DT = convert(datetime,'2010/01/04') union all
select DT = convert(datetime,'2011/01/03') union all
select DT = convert(datetime,'2012/01/02') union all
select DT = convert(datetime,'2012/12/31') union all
select DT = convert(datetime,'2013/12/30') union all
select DT = convert(datetime,'2014/12/29') union all
select DT = convert(datetime,'2016/01/04') union all
select DT = convert(datetime,'2017/01/02') union all
select DT = convert(datetime,'2018/01/01') union all
select DT = convert(datetime,'2018/12/31') union all
select DT = convert(datetime,'2019/12/30') union all
select DT = convert(datetime,'2021/01/04') union all
select DT = convert(datetime,'2022/01/03') union all
select DT = convert(datetime,'2023/01/02') union all
select DT = convert(datetime,'2024/01/01') union all
select DT = convert(datetime,'2024/12/30') union all
select DT = convert(datetime,'2025/12/29') union all
select DT = convert(datetime,'2027/01/04') union all
select DT = convert(datetime,'2028/01/03') union all
select DT = convert(datetime,'2029/01/01') union all
select DT = convert(datetime,'2029/12/31') union all
select DT = convert(datetime,'2030/12/30')
) a


Function Test Results:

DT YR_START_DT YR_START_DT_60 YR_START_DT_364
---------- ----------- -------------- ---------------
2006-01-18 2006-W03-3 2006-W11-7 2007-W03-3
1990-01-01 1990-W01-1 1990-W09-5 1991-W01-1
1990-12-31 1991-W01-1 1991-W09-5 1992-W01-1
1991-12-30 1992-W01-1 1992-W09-5 1992-W53-1
1993-01-04 1993-W01-1 1993-W09-5 1994-W01-1
1994-01-03 1994-W01-1 1994-W09-5 1995-W01-1
1995-01-02 1995-W01-1 1995-W09-5 1996-W01-1
1996-01-01 1996-W01-1 1996-W09-5 1997-W01-1
1996-12-30 1997-W01-1 1997-W09-5 1998-W01-1
1997-12-29 1998-W01-1 1998-W09-5 1998-W53-1
1999-01-04 1999-W01-1 1999-W09-5 2000-W01-1
2000-01-03 2000-W01-1 2000-W09-5 2001-W01-1
2001-01-01 2001-W01-1 2001-W09-5 2002-W01-1
2001-12-31 2002-W01-1 2002-W09-5 2003-W01-1
2002-12-30 2003-W01-1 2003-W09-5 2004-W01-1
2003-12-29 2004-W01-1 2004-W09-5 2004-W53-1
2005-01-03 2005-W01-1 2005-W09-5 2006-W01-1
2006-01-02 2006-W01-1 2006-W09-5 2007-W01-1
2007-01-01 2007-W01-1 2007-W09-5 2008-W01-1
2007-12-31 2008-W01-1 2008-W09-5 2009-W01-1
2008-12-29 2009-W01-1 2009-W09-5 2009-W53-1
2010-01-04 2010-W01-1 2010-W09-5 2011-W01-1
2011-01-03 2011-W01-1 2011-W09-5 2012-W01-1
2012-01-02 2012-W01-1 2012-W09-5 2013-W01-1
2012-12-31 2013-W01-1 2013-W09-5 2014-W01-1
2013-12-30 2014-W01-1 2014-W09-5 2015-W01-1
2014-12-29 2015-W01-1 2015-W09-5 2015-W53-1
2016-01-04 2016-W01-1 2016-W09-5 2017-W01-1
2017-01-02 2017-W01-1 2017-W09-5 2018-W01-1
2018-01-01 2018-W01-1 2018-W09-5 2019-W01-1
2018-12-31 2019-W01-1 2019-W09-5 2020-W01-1
2019-12-30 2020-W01-1 2020-W09-5 2020-W53-1
2021-01-04 2021-W01-1 2021-W09-5 2022-W01-1
2022-01-03 2022-W01-1 2022-W09-5 2023-W01-1
2023-01-02 2023-W01-1 2023-W09-5 2024-W01-1
2024-01-01 2024-W01-1 2024-W09-5 2025-W01-1
2024-12-30 2025-W01-1 2025-W09-5 2026-W01-1
2025-12-29 2026-W01-1 2026-W09-5 2026-W53-1
2027-01-04 2027-W01-1 2027-W09-5 2028-W01-1
2028-01-03 2028-W01-1 2028-W09-5 2029-W01-1
2029-01-01 2029-W01-1 2029-W09-5 2030-W01-1
2029-12-31 2030-W01-1 2030-W09-5 2031-W01-1
2030-12-30 2031-W01-1 2031-W09-5 2032-W01-1

(43 row(s) affected)




CODO ERGO SUM

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I am trying to export data from SQL which is ok and I can do that part.  However from the result of the query I need to add the values of certain columns.  Because I'm a newbie to SQL I'll explain and try and show images as best as I can as we go....
So far I have written a query
select Stockitem.code, Warehouseitem.ConfirmedQtyInStock, Warehouseitem.UnConfirmedQtyInStock, Warehouseitem.QuantityAllocatedStock, Warehouseitem.QuantityAllocatedBOM, Warehouseitem.QuantityAllocatedSOP, WarehouseItem.WarehouseIDfrom WarehouseItem INNER JOIN StockItem ONWarehouseItem.ItemID = Stockitem.itemidINNER JOIN BinItem ONBinitem.itemid = stockitem.itemidwhere WarehouseItem.WarehouseID = '3403' AND BinItem.BinName LIKE 'S%' AND BinItem.BinName <> 'S' OR BinItem.BinName LIKE 'T%' AND BinItem.BinName <> 'T'order by stockitem.code
 This returns the following results....
 Code             ConfirmedQtyInStock      UnConfirmedQtyInStock      QuantityAllocatedStock        QuantityAllocatedBOM      QuantityAllocatedSOP       WarehouseID
12345             96.00000                        .00000                              .00000                                 3.00000                            13.00000                           3403
Now I am trying to find out the amount of freestock available for everything with the WarehouseID 3403.  Therefore in the example above to be able to workout how many '12345' (Code) we have in stock, the equation used to find out the free stock available is as follows....
 Free Stock = (ConfirmedQtyInStock + UnConfirmedQtyInStock) – (QuantityAllocatedStock+ QuantityAllocatedBOM + QuantityAllocatedSOP)
Therefore if I manually use the equation above the amount of freestock available =
 Free Stock = (96+0) - (0+3+13) = 80 (free stock).
Then once I have the equation to be able to output the 'freestock' quantity, I need to export the results into an excel spreadsheet with the following layout...
 ColumnA
Code,FreeStock
12345,80
Hope I've explained this in a good manner, any help would be gratefully received.
Simba

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