How To Write A Logic ( Give To Same Suggation )

May 20, 2008

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HOW TO WRITE A LOGIC IN SQL SERVER USING THIS COBAL CODE

May 25, 2008

sub = 1

DETAILED-VOUCHER

VOUCHER-A OCCURS 13 TIMES.
ACC-NUM PIC X(6).

ADB-V OCCURS 12 TIMES.
CNT-V PIC 9999 COMP-3.
AMT-V PIC S9(9)V99 COMP-3.

It is a initialization of the two dimensional array DETAILED-VOUCHER(Temporary Variable) which consists of the account number for that account number different group of people say as (teachers, state police etc) have different 12 kinds of amounts such as (DEATH-AMT, PAYEE-AMTetc ) for every account number. SUB (Temporary Variable) is used as subscript whose value will be incremented by 1 after initializing current position by zero in order to initialize all 12 positions in array.



LOP-ZERO-2.
MOVE ZEROS TO CNT-V (1 SUB).
MOVE ZEROS TO AMT-V (1 SUB).
ADD 1 TO SUB.
IF SUB NOT GREATER THAN 12
GO TO LOP-ZERO-2.


MOVE 2 TO SUB.

LOP-ZERO-3.
MOVE CNTS (1) TO CNTS (sub).
ADD 1 TO SUB.
IF SUB NOT > 13 GO TO LOP-ZERO-3.



MOVE '401.21' TO ACC-NO-V (1). ---------- This are the hotcode values
MOVE '410.01' TO ACC-NO-V (2).
MOVE '410.02' TO ACC-NO-V (3).
MOVE '410.03' TO ACC-NO-V (4).
MOVE '410.04' TO ACC-NO-V (5).
MOVE '410.06' TO ACC-NO-V (6).
MOVE '410.05' TO ACC-NO-V (7).
MOVE '411.01' TO ACC-NO-V (8).
MOVE '411.02' TO ACC-NO-V (9).
MOVE '331.01' TO ACC-NO-V (10).
MOVE '212.19' TO ACC-NO-V (11).
MOVE '212.22' TO ACC-NO-V (12).


MOVE ZEROS TO XYZ-S (1).
MOVE ZEROS TO MNO-B (1).
MOVE ALL '9' TO A-KEY
MOVE 01 TO D-X.
MOVE 1 TO SYS-Y



Please give suggest me how to write logic in the sql server. I want to how to write two dimensional array loop in the sql server.

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Hi,



I tried to backup the master key by the following syntax :

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Regards,

Tarek Ghazali

SQL Server MVP

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Feb 29, 2008

username      work_date               no_of_working_hours(nvarchar)a                02/17/2008                  0:50 a                02/18/2008                  0:50 a                02/23/2008                  0:20b                02/18/2008                  0:30 b                02/23/2008                  0:30 b                02/24/2008                  0:30 suppose i pass work_date from 02/18/2008 to 02/23/2008.i want following result username     total_no_of_working_hours(nvarchar)a                      1:10b                      1:00 How to write stored procedure?Thanks,Durai   

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Dec 9, 2005

I am trying to select records based upon last name
WHERE     (Last_Name BETWEEN 'A%' AND 'C%')
When I run this I get only last names starting with A and B--no C. ?!?
This is confusing to me....I ran it with lastname >= 'A%' and lastname <='C%'and it returned only names starting with B. Why does SQL ignore the "="
I hope this isnt obvious :/
 
 

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Aug 20, 2001

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Jan 8, 2002

Hello , everybody

Is possible to set up server role to NT user in order to backup ONLY
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CASE Does Not Give Correct Result

Aug 31, 2007

How do I automatically assign a new cardcode-number? (according to the following formula: highest existing number + 1)

Scenario:
-There are two types of business partners: Customers and Suppliers.
-Customers have the value 'C' in the colomn CardType.
-Suppliers have the value 'S' in the colomn CardType.
-Customers have the following syntax 'C123456' in the colomn CardCode.
-Suppliers have the following syntax 'S123456' in the colomn CardCode.
-Existing CardCode-values in the DB for the Customers: C000001 - C100599.
-Existing CardCode-values in the DB for the Suppliers: S000001 - S200199.

The idea is that when a user creates a new business partner, the CardCode should be automatically filled when a new assigned number (highest existing number + 1), according to the value that is selected in CardType (either the letter 'C' or 'S').


What's been done so far:
SELECT top 1
(CASE
WHEN CardType='C' THEN (SELECT top 1 'C' + '' + cast((substring(T0.CardCode, 2, 7) + 1) as varchar) as [nummer]
FROM OCRD T0
WHERE T0. CardCode like 'C%' AND T0. CardType='C'
order BY T0.CardCode desc FOR BROWSE)
WHEN CardType='S' THEN (SELECT top 1 'S' + '' + cast((substring(T0.CardCode, 2, 7) + 1) as varchar) as [nummer]
FROM OCRD T0
WHERE T0. CardCode like 'S%' AND T0. CardType='S'
order BY T0.CardCode desc FOR BROWSE)
END)
FROM OCRD T0


The current result:
The result that it gives is 'C100600'.
The problem however is that it always gives this result and does not take into account what has been selected in CardType.

When I add the following: "order BY T0.CardCode desc FOR BROWSE" it gives the result 'S200200'.

So, what does work is that it takes the highest existing value and adds 1. But what doesn't work is the taking account what value is selected in CardType.

Does anyone know how I can make this work?

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May 17, 2004

Hi Everybody,

In a table there´s a field for store real values,
so...in the database, using the SQL Server Enterprise Manager
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Thanks for attention

Leonardo Almeida

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Aug 12, 2014

I've table and data as following,

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[idx] [int] IDENTITY(-2147483648,1) NOT NULL,
[CVID] [int] NOT NULL,
[myGender] [char](1) NULL,
[whatGender] [char](1) NULL,
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[Code] ....

So, my table and data must be as following,

This is the calculation for CVID=1449

1- myGender=M
2- whatGender=M
3- point_Gender=4
4- So, score_Gender=4

5- myBMI=23.53
6- min_BMI=20.22
7- max_BMI=30.00
8- point_BMI=3
9- myBMI is between 20.22 and 30.00
10- So, score_BMI=3

This is the calculation for CVID=1925

1- myGender=F
2- whatGender=M
3- point_Gender=4
4- So, score_Gender=0

5- myBMI=35.43
6- min_BMI=20.22
7- max_BMI=30.00
8- point_BMI=3
9- myBMI IS NOT between 20.22 and 30.00
10- So, score_BMI=0

After calculation, my data should be as following :

The variant for each row IS SAME. See as following :

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Aug 12, 2014

I have a table of customer information (ci), but I have to link to another table in order to get the street address (sa).

If I exclude the street address I get 33 results. If I make the link to street address I will only get 30 results.

What I found is that if the ci table field for country is blank and I try linking to sa table then that result will not be shown.

Is there a way to get all 33 results while linking the two tables?

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