Invalid Attribute/option Identifier

Jul 20, 2005

Hi
I currently have a problem with registering a new server in my Enterprise
Manager on a new PC.

I need to connect to a MSSQL2K server on a windows 2003.
My current PC is on the same LAN as the server and has no problem
registering the server in Enterprise manager. This PC uses NT (about time I
change :-)

The new PC runs WIN2K. But this PC is on another LAN and has to access the
server through a firewall. Port 1433 is open in the firewall.
I use a Firewall-1 authentication agent to access the server.

I use SQL authentification to logon (sa account), I have checked that the
new clients network libraries are the same version as the servers.
In the client network Utility I have set up an alias with the server I want
to access.

The registration seems to access the SQL server, but comes out with an error
stating: "invalid attribute/option identifier"

When I search KB with this message, I get nothing. Did anyone in here
experience anything like this? Any pointers to help me move on would be
greatly appreciated.

best regards
René Pedersen

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Invalid Attribute/option Identifier

Oct 14, 2004

Hello all

I am getting this message when connecting to SQL Server through Enterprise Manager. However all my DSNs work without any problems.

================

A Connection could not be established to DBSERVER.

Reason: Invalid attribute/option identifier.

Please verify SQL Server is running and check your SQL Server registration properties (by right-clicking on the DBSERVER node) and try again.


================

I have reinstalled SQL Server 2000 and MDAC (ver 2.6) but no success.

Please help!

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Invalid Attribute/option Identifier (Error HY092)

Jan 21, 2004

I'm using a software called epi suite which is used to print id badges. The system is currently running on an access database and everything works according.

I am trying to migrate it off access to SQL 2k and have run into a problem when trying to insert data back into the system.

I can pull back data w/o any problems (to view and even print badges) but the minute I try to Save anything [New Image or change the card to unprinted], it comes back with the error:

Failed to save the card record.
Database error: Invalid attribute/option identifier

Error HY092[Microsoft][ODBC SQL Server Driver]

Has anybody ran into this type of situation before? The problem is, the company will only support access and says that SQL is a use at your own risk type of deal.

I'm new to using MS SQL so I am unsure what the best solution would be to try and find the problem. Is it possible that the software is just sending some sort of malformed query over to the database? Anything I have found on that error [HY092] seems to point in that general direction.

Thanks for your help.

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Apr 1, 2008

Hi All,

Now i am using window authentication to login to SQL2005 Express. Everything is fine when I logged with administrator.
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Microsoft SQL Native Client (0x80004005)
Invalid connection string attribute

My connection String is:
Provider=SQLNCLI;Initial Catalog=***;Data Source=***;
Persist Security Info=False;User Instance=True;
Integrated Security=SSPI;
AttachDBFileName=directory***.mdf;"

Any idea? Thanks.

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Jan 7, 2008

Hi all,

We have recently been having some problems with our server, and im stuck for ideas of what to try next!

Basically we have a busy period every 2 hours where we have many records that need to be processed etc, but we are getting an error coming back saying 'Invalid connection string attribute'.

Now this would be fine but we are using a UDL and 80% of the records are going in fine and its just this few that are coming back with this error. This happens at 3mins and 55 secs past the hour everytime too.

Now i ran SQL profiler over this time and there are records and such being processed fine, then all of a sudden at 3min and 55 secs past there is a mass 'Audit Logout' noted in profiler.

It would seem to me it has nothing to do with the connection string as it was working perfectly fine before.

The processing is done using a VB6 dll being called through ASP on IIS 6.

Does anyone have any ideas on what to try next or advice?

Thanks all
Danny

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Mar 23, 2007

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The schema it created looks like this:

[cims_output_data.txt]
ColNameHeader=True
Format=TabDelimited
MaxScanRows=0
CharacterSet=OEM
Col1=SIMNAME
Col2=TIMESTAMP
Col3=SIMTYPE
Col4=REGION
Col5=SECTOR
....etc.

It looks OK, but if I go back to Define in Administrative Tools and try to review it, I get a similar error message:

Ini File (or Registry) C:Program FilesCIMSschema.ini is corrupt.
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Has anyone seen this before? There is nothing on MSDN as far as I could find. I read on another forum that if you replace the label 'Col1' with 'Col' the problem is solved but it still reports that the schema is corrupt when I try to open it in Administrative Tools.

Bill.

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Aug 10, 2015

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My query :
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Where F1 Is not null

But I get this error :
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May 16, 2008



HI,


I had to change the key columns of a dimension attribute to fix an error. I did this in BIDS. The change was from a single key column to a composite key column. Now I am getting these error when I process the cube:

Measure group attribute key column x does not match source attribute ..

I looked at the cube XMLA definition under mesaure groups and it still shows a single key column with inherited binding. However, the BIDS does not give me an option correct this in any way. I have had to do this once before and the only option seems to be removing the dimension from the cube and add it back in. But that is very error prone since I lose any specific settings at the cube dimension level not to mention aggregations no longer include the dimension, etc.

Not seeing an alternative, I went through each measure group (I have 7) and changed the key columns manually in the XMLA and saved the cube. This worked, but I don't understand why BIDS automatically doesn't do it.

Is this a flaw in the BIDS or I should be missing something.

thanks
MJ

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Apr 27, 2008

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Apr 21, 2008

Hello,

I've got the following query:

SELECT zA."ID" AS fA_A
, zA."TEXT" AS fA_B
, (
SELECT COUNT(zC."ID")
FROM Test."Booking" AS zC
) AS fA_E
FROM Test."Stack" AS zA
WHERE zA."ID" = ?

With this query I call:
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- SQLNumParams -> SQL_SUCCESS=0, pcpar = 1
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Is there a problem with this calling sequence or this query? Or is this a problem of SQL Server?

Regards
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Feb 10, 2015

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From Books Online:
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Thanks again in advance.

Levi Akers

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May 14, 2003

During Index Rebuild, I get the following error:

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Any ideas what might be causing this?

Thanks,
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Jan 19, 2005

I'm trying to create a unique identifier number that meets the following criteria. The unique identifier needs to be a concatenation of two values submitted from a form and the identity value (primary key) for the new record that is inserted into the database.

So, if the first field is the year and the second field is a objnumber, the unique identifier number would have the format: ("YR" + "objnumber" + primary key value), where the year and object number are what the user selected in the form.

I have a stored procedure that I use to handle the insert, which also returns @@identity for the purpose of passing that value into another stored procedure that inserts child records.

So, within my stored procedure, is there a way I can create the unique identifier number and return that value back to the application? I'm not sure how to accomplish this?

Here is my stored procedure:

CREATE PROCEDURE dbo.REQ_HDR_INSERT
@ddo varchar(50) = null,
@requestor varchar(100) = null,
@dt datetime = null,
@abrtype varchar(20) = null,
@subject varchar(250) = null,
@description varchar(500) = null,
@review char(10) = null,
@ay char(4) = null,
@origallo varchar(50) = null,
@reqallo varchar(50) = null,
@logl_del_dt datetime = null,
@phys_del_dt datetime = null
AS
Insert into dbo.DIM_ABR_REQ_HDR (ABR_ddo, ABR_requestor, ABR_dt, ABR_type, ABR_subject, ABR_description, ABR_review, ABR_AY, ABR_orig_fund_allo, ABR_req_fund_allo, ABR_LOGL_DEL_DT, ABR_PHYS_DEL_DT)
values (UPPER(@ddo), UPPER(@requestor), @dt, UPPER(@abrtype), UPPER(@subject), UPPER(@description), UPPER(@review), @ay, convert(money, @origallo), convert(money, @reqallo), @logl_del_dt, @phys_del_dt)
return @@identity
GO

I would be using @ay and @ddo as the first two parts of the unique identifier number. Any help is appreciated.
Thank you,
-D-

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Unique Identifier

Jan 31, 2004

How can i get a numer for using it as unique identifier in two related tables?

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Identifier Too Long

Oct 14, 2006

hi there, i have following code

SET QUOTED_IDENTIFIER ON
DECLARE @sTableDiff varchar(1000)
SET @sTableDiff= " ""C:Program FilesMicrosoft SQL Server90COM ablediff"" -sourceserver ""VSNET1"" -sourceuser ""sa"" -sourcepassword ""sa2345"" -sourcedatabase ""PMSTEMP"" -sourcetable ""DEMAT"" -destinationserver ""VSNET1"" -destinationuser ""sa"" -destinationpassword ""sa2345"" -destinationdatabase ""PMSRESTORE"" -destinationtable ""DEMAT"" -f ""c:Diff"""
PRINT @sTableDiff
EXEC XP_CMDSHELL @sTableDiff

When i execute it, throws error as


Msg 103, Level 15, State 4, Line 3
The identifier that starts with ' "C:Program FilesMicrosoft SQL Server90COM ablediff" -sourceserver "VSNET1" -sourceuser "sa" -sourcepassword "sysadm" -sour' is too long. Maximum length is 128.


When i split the Identifier as

SET QUOTED_IDENTIFIER ON
DECLARE @sFull varchar(1000)
DECLARE @s1 varchar(1000)
DECLARE @s2 varchar(1000)
DECLARE @s3 varchar(1000)
DECLARE @s4 varchar(1000)
SET @s1= '""C:Program FilesMicrosoft SQL Server90COM ablediff""'
SET @s2= ' -sourceserver "VSNET1" -sourceuser "sa" -sourcepassword "sysadm" -sourcedatabase "PMSTEMP" '
SET @s3=' -sourcetable "DEMAT" -destinationserver "VSNET1" -destinationuser "sa" -destinationpassword '
SET @s4=' "sysadm" -destinationdatabase "PMSRESTORE" -destinationtable "DEMAT" -f "c:Diff"'
SET @sFull = @s1 +@s2 + @s3 + @s4
EXEC XP_CMDSHELL @sFull

this executes fine but the optput is as

The input line is too long.
NULL

What is this?
how could i execute such long commad using CMDSHELL?

Regards,
Thansks.
Gurpreet S. Gill

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Uniqie Identifier

Sep 23, 2006

Hi

I have an salesorders table and products table.

products table (PK) is productid , it is uniqueIdentifier

I added a field to salesorders table to keep the productid and I made INT



so, now I go to vb.net, data connections, diagrams

when I try and relate this two field (salesorders.productid with products.productid) I get an error and it says, data type, size doesn't match.

Could you please help me with this issue.

thanks

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Mar 15, 2008



Is there a field in the SQLException class that identifies what specific exception was thrown. I tried Number and ErrorCode but those seem to change randomly, they are not consistent. Thanks

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Unique Identifier Or Int For Table ID

Feb 29, 2008

I am working on some tables and would like to know which is best way to go when deciding what Type to use for Unique ID in my tables please. Int  Or uniqueIdentifier? Or is it all the same??

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Aug 1, 2005

Hi there,I'm new to sql server. I've created a table which can be updated through an aspx form. However coming from an access background I don't know how to generate an auto number. I've read through a number of the threads on here and keep coming across Identity or unique identifier. However I can't actually find out how to implement these.Any help would be greatCheersStu

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UserID -&> Unique Identifier

Nov 25, 2005

Hello!I work with oracle, mySQL but im completely new to SQLserver.How can i set a auto-increment unique variable for userID ?After deleted user, the userID should be never used again on a new user.Thank you,

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Multi-part Identifier

Jun 18, 2008

use projectserver2003
selectr.RES_NAME, p.PROJ_NAME, a.TASK_NAME, w.WWORK_START, w.WWORK_FINISH, w.WWORK_VALUE
from MSP_WEB_RESOURCES r,
MSP_WEB_ASSIGNMENTS a,
MSP_WEB_PROJECTS p,
MSP_WEB_WORK w
join MSP_VIEW_PROJ_TASKS_ENT TE on r.WPROJ_ID=TE.WPROJ_ID
join MSP_VIEW_PROJ_RES_ENT RE on r.WPROJ_ID=RE.WPROJ_ID
join MSP_VIEW_PROJ_PROJECTS_ENT PE on r.WPROJ_ID=PE.WPROJ_ID
wherew.WWORK_TYPE = 1 -- actual work
andw.WASSN_ID = a.WASSN_ID
anda.WPROJ_ID = p.WPROJ_ID
anda.WRES_ID = r.WRES_ID


This statement is returning the following errors:

Msg 4104, Level 16, State 1, Line 2
The multi-part identifier "r.WPROJ_ID" could not be bound.
Msg 4104, Level 16, State 1, Line 2
The multi-part identifier "r.WPROJ_ID" could not be bound.
Msg 4104, Level 16, State 1, Line 2
The multi-part identifier "r.WPROJ_ID" could not be bound.



I have all tables identified; however unclear as to why it cannot be bound.

Please help.

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How To Return Unique Identifier In SP

Oct 18, 2013

I have trouble to get the uniqueidentifier I just inserted out.

---sp
CREATE PROCEDURE dbo.FAC_Ins_USR
@LAST_NAME AS nvarchar(60)
,@FIRST_NAME AS nvarchar(60)
,@NewID uniqueidentifier output
AS
BEGIN

[Code] ....

The new data went into the table, and the print @myErr shows 0.

But print @myID shows nothing.

---here is the part of the table

CREATE TABLE [dbo].[USERS](
[USER_ID] [uniqueidentifier] DEFAULT NEWID() NOT NULL,...

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Apr 4, 2006

if exists (select 'x' from obj where new_obj.key1 = obj.key1 and new_obj.class = obj.class)
BEGIN
set @temp_old_ref = (select obj.rowid from obj where new_obj.key1 = obj.key1 and new_obj.class = obj.class)
SET IDENTITY_INSERT new_obj ON
insert into new_obj(rid, key1, class, is_searchable, is_deleted, is_loaded, old_rid, old_ref) select rid, key1, class, is_searchable, is_deleted, is_loaded, old_rid, @temp_old_reffrom new_obj
delete from new_obj where old_ref != @temp_old_ref
END


while running it i m getting this error

Msg 4104, Level 16, State 1, Procedure mergeChanges, Line 35
The multi-part identifier "new_obj.key1" could not be bound.
Msg 4104, Level 16, State 1, Procedure mergeChanges, Line 35
The multi-part identifier "new_obj.class" could not be bound.
Msg 4104, Level 16, State 1, Procedure mergeChanges, Line 37
The multi-part identifier "new_obj.key1" could not be bound.
Msg 4104, Level 16, State 1, Procedure mergeChanges, Line 37
The multi-part identifier "new_obj.class" could not be bound.


any thoughts

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Another Multipart-identifier Problem

Mar 20, 2008

Hey everyone,

I've found lot of other people experiencing the same problem I'm having, but I can't get any of their solutions to work for me. I have two tables with the exact same structure Today and Yesterday. I'm trying to compare a price column from Yesterday's column against Today's and I'm getting the 'The multi-part identifier '' could not be bound' error. Here's the code I'm using:

DECLARE @ProgramName varchar(100)
SET @ProgramName = 'AffiliateName'

SELECT CJ_RawImport_Today.* FROM CJ_RawImport_Today
WHERE (CJ_RawImport_Today.ProgramName = @ProgramName) AND (CJ_RawImport_Today.RetailPrice < CJ_RawImport_Yesterday.Price)

Anyone have a suggestion?

Thanks in advance!

--Joel

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Jul 25, 2007

Hello,

Does anyone know if there is a read-only unique identifier of a database in a given server instance? E.g. a value stored somewhere in the database meta data that is generated during CREATE DATABASE...

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Nov 7, 2007

Can anyone explain why i get the folling error.


Msg 4104, Level 16, State 1, Procedure rpt_getChildren, Line 33

The multi-part identifier "c.childID" could not be bound.

Msg 4104, Level 16, State 1, Procedure rpt_getChildren, Line 33

The multi-part identifier "c.siteID" could not be bound.

Msg 4104, Level 16, State 1, Procedure rpt_getChildren, Line 33

The multi-part identifier "c.siteID" could not be bound.

Msg 1011, Level 16, State 1, Procedure rpt_getChildren, Line 33

The correlation name 'sg' is specified multiple times in a FROM clause.


create procedure rpt_getChildren

@cmb1 as varchar(100)

AS


BEGIN


set dateformat YMD

set datefirst 7


CREATE TABLE #ChildSessions (

siteid integer null

,childid integer null

,sessionid integer null

,sun integer default 0

,mon integer default 0

,tue integer default 0

,wed integer default 0

,thr integer default 0

,fri integer default 0

,sat integer default 0)


declare @firstofweek as datetime

declare @lastofweek as datetime


select @firstofweek=cast(floor(cast(dateadd(day,(-1*datepart(dw,getdate())+1),getdate()) as float)) as datetime)

select @lastofweek=dateadd(minute,-1,dateadd(day,7,@firstofweek))

declare @myday integer


set @myday=0

while @myday<7


BEGIN


INSERT INTO #ChildSessions


SELECT


c.siteid

,c.childid

,sg.sessionid



,case @myday WHEN 1 THEN 1 ELSE 0 end

,case @myday WHEN 2 THEN 1 ELSE 0 end

,case @myday WHEN 3 THEN 1 ELSE 0 end

,case @myday WHEN 4 THEN 1 ELSE 0 end

,case @myday WHEN 5 THEN 1 ELSE 0 end

,case @myday WHEN 6 THEN 1 ELSE 0 end

,case @myday WHEN 7 THEN 1 ELSE 0 end


FROM




Child c


,sessionAttendance sa

,session s

,sessiongroup sg

INNER JOIN


SessionAttendance sa

ON c.childID = sa.childID

INNER JOIN


Session s

ON c.siteID = s.siteID

INNER JOIN


Site

ON c.siteID = s.siteID


INNER JOIN

SessionGroup sg

ON c.siteID = sg.siteID


WHERE


c.childID = sa.childid



AND c.siteid = sa.siteid

AND c.active = 1

AND c.potential = 0

AND s.identityid = sa.identityid

AND s.siteid = sa.siteid

AND sg.sessionid = s.sessionID

AND sg.siteid = s.siteid

--AND site.sitename = @cmb1

AND s.dayofweek = @myday

AND @firstofweek <= sa.dateTo

AND @lastofweek >= sa.dateFrom

SET @myday=@myday+1

END


SELECT



c.forename,

c.surname,

sg.sessionname,

--sitename,

CASE (sum(sun)) WHEN 0 THEN ' ' ELSE 'X' END as sun,

CASE (sum(mon)) WHEN 0 THEN ' ' ELSE 'X' END as mon,

CASE (sum(tue)) WHEN 0 THEN ' ' ELSE 'X' END as tue,

CASE (sum(wed)) WHEN 0 THEN ' ' ELSE 'X' END as wed,

CASE (sum(thr)) WHEN 0 THEN ' ' ELSE 'X' END as thr,

CASE (sum(fri)) WHEN 0 THEN ' ' ELSE 'X' END as fri,

CASE (sum(sat)) WHEN 0 THEN ' ' ELSE 'X' END as sat,



case when datepart(day,c.dob)<=datepart(day,getdate())

then cast((datediff(month,c.dob,getdate())/12) as varchar(3)) + ' Yr '

+ cast((datediff(month,c.dob,getdate())% 12) as varchar(2)) + ' Mnth'

when datepart(day,c.dob)>datepart(day,getdate())

then cast(((datediff(month,c.dob,getdate())-1)/12) as varchar(3)) + ' Yr '

+ cast(((datediff(month,c.dob,getdate())-1)% 12) as varchar(2)) + ' Mnth' end as Child_Age


FROM child c,sessiongroup sg, site, #childsessions cs


WHERE c.childid=cs.childid



AND c.siteid=cs.siteid

AND sg.sessionid=cs.sessionid

AND sg.siteid=cs.siteid

--AND s.sitename = @cmb1


GROUP BY c.forename,c.surname,sg.sessionname,c.dob,c.childid

ORDER BY sg.sessionname,c.forename,c.surname

DROP TABLE #ChildSessions

END

GO












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Hello !

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The year 1901 is included in the time period of the time dimension.
The calendar includes the following dates :
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Please help me because it is urgent and I cannot find a solution..

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