Left Pad Zeros To Integer Field

Feb 4, 2004

I have an integer field that ranges from 3 to 6 numbers and I need to left pad leading zeros so the field is always a char(7). What is the syntax to do this? Thanks in advance.

0001234
0012345
0123456
1234567

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Add Leading Zeros To Integer?

Jul 1, 2004

I need to cast an integer to a string to append to another string for a barcode.

How can I get 1 -> '0001' OR 100 -> '0100'

Any suggestions?

Mike B

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Mar 10, 2014

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Ex:

100.000000 will be 100
100.001000 will be 100.001
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Sep 14, 2006

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TIA,



Barkingdog





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Oct 7, 2004

hi all,

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Aug 27, 2004

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OR

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I'm using SQL Server 7.0.

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May 29, 2006

Hi everybody,
Could someone help me ???
Iam starting with sql

My problem ..

Ihave a table Table_customer

In this table a column Table_customer.no
This column contain 8000 rows.
with customer numbers: like 30789
I would like to modify once all this row adding just before the number
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This column is an integer.

I have try a simple select wich give me this result
How i can do this with update ?
probably i have to convert fisrt to caracters

select kunr,nov_kunr=
'30'+ltrim(str(kunr))
from event
where kunr is not null

Thank

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Feb 17, 2007

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Apr 1, 2008

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Oct 9, 2007



We have account numbers that are string values, looking like: "01.02.02.00.0040.000.000".

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We've been trying to do something with the like clause: LIKE '__.__.__.__.[0-0][0-0][4-6][0-0]'.

We want 40 through 60 but we're getting 40, 50, and 60. If we change the last bracket to [0-9] we get 40 through 69.

Does anyone have any suggestions as to either fix our like clause or another approach?

Thanks.

John

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Sep 3, 2007

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Sep 22, 2014

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102 0 171
103 1 171
104 2 171
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here how to renumbering stickyId values when deleted particular stickyId from UI. Here stickyId field is Integer type only. not primarykey/identity field.

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Jul 2, 2007

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Nov 27, 2006

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Need to know if the varchar datatype field will ingore leading zeros when compared with numeric datatype ?

create table #temp
(
code varchar(4) null,
id int not null
)
insert into #temp

[Code] .....

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Dec 6, 2004

Hello!

I am trying to run a query on an SQL-server database:

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How can I bypass this problem? Can I convert the commentfield to varchar in the QUERY?


noccy

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Mar 20, 2007

Greetings,

I have several reports for which the user has asked to have an optional muti-value parameter. They want to be able to select zero, one, many, or all values in the parameter list. The parm list is created through a query and the values are not static.

I would like to allow the user to leave the muti-value field empty if they want to allow all values to appear on the report. I've read some discussion about populating a multi-value default with the same query that produces the multi-value list values - presto, everything is selected. However, this is not a desirable solution for me because I "echo" the users parameter selections in the report heading. Selecting all values (and some parms have a lot of values) would cause the "parm feedback" section to grow large and unreadable.

In short, I don't want to tell the user they have to select everything when they really want to select nothing.

Is there any way to have a muti-value parm that won't insist the user select one or more values?

Thanks,

BCB

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Jan 4, 2007

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Jul 20, 2015

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This works well for converting the transDate Part in the select statement:

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* The resulting data must work directly in a Microsoft SQL Server Management Studio Query using either using the "on" statement or part of the "where" clause. In other words, NOT as a stored procedure!

Also must be able to be used as a date difference calculation when comparing the 2 files Within say + or - 5 seconds.

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Oct 28, 2015

I have a table PLACE with a character column CODE

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How can I do that in transact SQL?

I tried:
     
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ON a.id = b.id

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INSERT @LeftTable (LeftValue)
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[code]....

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Dec 20, 2006

hello

for MS SQL 2000, i cannot get it

i am having names like AB_12 I want to get all rows with left part similar , AB im that case


SELECT id, name
FROM Users
WHERE LEFT(name, CHARINDEX('_', name) - 1) AS name IN
(
SELECT LEFT(name, CHARINDEX('_', name) - 1) AS ns
FROM Users
GROUP BY LEFT(name, CHARINDEX('_', name) - 1)
HAVING (COUNT(*) > 1)
)



does not work



is there any way to use a variable ?

declare @nm nvarchar
set @nm = SELECT LEFT(name, CHARINDEX('_', name) - 1) AS ns
FROM Users


thank you for helping

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Sep 1, 2005

Hi All,

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Microsoft OLE DB Provider for ODBC Drivers error '80040e14'

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May 6, 2008

I would like to add leading zeros in the date. Thsi is my existing procedure, it adds leading zeros, but it formats using "yyyy/mm/dd", instead of "yyyy-mm-dd"
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Jan 9, 2004

Hi all,
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So is there another way of solving this other than truncating off the zeroes?

If so feel free to assist me, your help is greatly appreciated.
Thanks.

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Jun 27, 2006

Hi All,

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24
2356
61

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Sep 24, 2007

Hi,
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