Rank The Employees By Count And Amount (was Query Help)

May 11, 2006

I have a query that returns a result that looks like this:

amount count
steve 122000 12
jim 145213 13
paul 62325 7

I need to add 2 columns to this query that rank the employees by count and amount with a number, so for example:

amount amount_rank count count_rank
steve 122000 2 12 2
jim 145213 1 13 1
paul 62325 3 7 3

I was going to paste the entire query in but I thought I'd try this first to see if I could get by with a hint. So essentially I need to evaluate with an order by or something and then insert a number as amount_rank and number as count_rank.

Any ideas?

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Need To Count And Rank NVARCHAR Column

Apr 2, 2008

Assuming that I have a table similar to this simplified version:

CREATE TABLE [SomeTable] ([Field1] NVARCHAR(50));

How could I count and rank the instances of specific values in the "field1" column? For example, let's say that I want to show the frequency of the column values like so:

field1 count
some value 24
another word 20
a value 5

(and so on...)

How can I do this?

- - - -
- Will -
- - - -
http://www.strohlsitedesign.com
http://blog.strohlsitedesign.com/
http://skins.strohlsitedesign.com/

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The table structure is defined and i cannot edit it .

Please let me know if we could have a single query to do this .

Thank you
kishore

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(
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Col1 Col2 Col3
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Apr 3, 2008

Hi all - struggling a bit with this one... I have made an accounts application and need to make a report called "Aged Debtors". It lists all of the clients with outstanding invoices and breaks them down into periods:

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period 1 (last month)
period 2 (2 months ago)
period 4 (invoices raised 3 months ago or more)

My tables are as follows (simplified)

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clientname varchar(100)

invoices
invoiceid int
clientid int
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I need the following columns in the report

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Mar 18, 2008

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end as transamount,
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FROM
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join
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where
(t.gl7fiscalperiodsid >= 97
And
t.gl7fiscalperiodsid<=@FiscalPeriod_identifier)
And poststatus in (2,3)
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[code]....

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Hi all,



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Thanx in advance.

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Aug 21, 2007

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Here is a test code snippet:


--Test Count/Count subquery

declare @Date datetime

set @date = '8/15/2007'


select
-- count returns unit data
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-- count returns total for all units

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and not (v1.MnyPlyd = v1.MnyWon and v1.ActWin = 0)

and v1.[Date] between DateAdd(dd,-90,@Date) and @Date) as TotalCnt,
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(select Count(substring(m1.PTNumber,3,3))

from tblVGD1_Master m1

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from tblVGD1_Master m

left join tblVGD1_ClassIII v on m.SlotNum_ID = v.SlotNum_ID

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and not (v.MnyPlyd = v.MnyWon and v.ActWin = 0)

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Ok, I have the following table

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, known_as char(20)
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, manager_number char(6) NULL
, unique_identifier char(6) NOT NULL PRIMARY KEY
)
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Except I can't work out the update statement for this!

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employeeID int identity(1,1)
, employee_number char(6)
, job_title char(40)
, department_reference char(10)
, managerID int
, manager_number char(6)
)
GO

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SELECT employee_number, job_title, department_reference, manager_number
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GO

--Update managerID with relevant employeeID
GO

DROP TABLE gvVisioTest

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Oh and this is legacy so the design is flawed, modified over time (the manager field is a bodge put in 5 years ago), so yeah unfortunately I have to work with what I've got :(

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wht i can think of is:

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empId
empName
empManagerId

1
A


2
B
1

3
C
2

4
D
2

5
E
4
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Output will be something like this

12345 | 2 |true |REG
12345 | 15 |false |OVR
12345 | 30 |true |OVER
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Total Validated hours for the Employee 12345 will be 32 NOT 47. How do I list employees who worked less than 80 validated hours. The hours are validated only when it is true.

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how to do this
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empid VAL_OK
--------------------------
111 0
222 0
333 0

now insert multiple insert to my work_table shifts for all month for evry employee
like this
(this is work_table)
empid date val
--------------------------------------------------
111 01/02/2008 1
111 02/02/2008 2
...............
111 29/02/2008 5
--next employee
222 01/02/2008 1
222 02/02/2008 4
...............
222 29/02/2008 6
--next employee
333
--next employee
444
--next employee
555
-------------------------------------------------------------


now i need for evry OK insert (for all month) each employee
go to the TB_Employee
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from VAL_OK=0 to VAL_OK=1
like this

empid VAL_OK
--------------------------
111 1
222 1
333 1
----------------------
like this i know who is the employee have shift for all month and who NOT !

i think it like this



Code Snippet
Create trigger for_insert on tb_work
For insert
begin
if @@rowcount = 1
Update tb_employee
Set
val_ok= 1

else
/* when @@rowcount is greater than 1,
use a group by clause */
Update tb_employee
set
val_ok= 1
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TNX

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need help
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if it double days fix it

if the employees have less days ! > move to temp table

for eny problem with this employee (check continuity or error) move to temp table !
i have stored procedure that insert employees for next month "Full month"
from start of the month until end of the month
how to check continuity and if i don't give less days OR double days in month
like if the month is 29 days the employee must have 29 not more

for eny problem with this employee move to temp table !

situation 1 employees have less days !
sn empid ShiftDate day
-------------------------------------------------
1 111111 2008-02-01 Tuesday
2 111111 2008-03-02 Wednesday
3 111111 2008-04-03 Thursday
4 111111 2008-03-04 Friday
5 111111 2008-03-05 Saturday
6 111111 2008-03-06 Sunday
7 111111 2008-03-07 Monday
. ----------------------------------------------
8 111111 2008-03-09 Wednesday
9 111111 2008-03-10 Thursday
.......................................................................until end of the month
99 222222 2008-02-01 Tuesday
100 222222 2008-03-02 Wednesday
101 222222 2008-04-03 Thursday
102 222222 2008-03-04 Friday
. ----------------------------------------------
104 222222 2008-03-06 Sunday
105 222222 2008-03-07 Monday
106 22222 2008-03-09 Wednesday
108 22222 2008-03-09 Wednesday
109 22222 2008-03-10 Thursday
.......................................................................until end of the month

situation 2 employee have double days!
sn empid ShiftDate day
-------------------------------------------------
1 111111 2008-02-01 Tuesday
2 111111 2008-03-02 Wednesday
3 111111 2008-04-03 Thursday
4 111111 2008-03-04 Friday
5 111111 2008-03-05 Saturday
6 111111 2008-03-06 Sunday
7 111111 2008-03-07 Monday
8 111111 2008-03-09 Wednesday
9 111111 2008-03-09 Wednesday
10 111111 2008-03-10 Thursday
.......................................................................until end of the month
99 222222 2008-02-01 Tuesday
100 222222 2008-03-02 Wednesday
101 222222 2008-04-03 Thursday
102 222222 2008-03-04 Friday
103 222222 2008-03-04 Friday
104 222222 2008-03-05 Saturday
105 222222 2008-03-06 Sunday
106 222222 2008-03-07 Monday
107 22222 2008-03-09 Wednesday
108 22222 2008-03-09 Wednesday
109 22222 2008-03-10 Thursday
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TNX

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Here are my tables:

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- EmployeeID
- EmployeeName

tblQualifications (table of qualifications)
- Qualification_ID
- QualificationTitle

tblEmployeeQualification (table of all employees qualifications)
-EmpQualificationID
-EmployeeID (fk for tblEmployees)
-QualificationID (fk for tblQualifications)

tblPrograms (table of programs)
-ProgramID
-ProgramTitle

tblProgramModules (table of qualifications required by each program)
-ProgramModuleID
-ProgramID (fk for tblPrograms)
-QualificationID (fk for tblQualifications)

Here is the query I was working with that works when there are only records in the ProgramModules table that use the same ProgramID

SELECT
tblProgramModules.TrainingProgramID,
tblEmployees.EmployeeID,
tblEmployees.EmployeeName

FROM
tblEmployees

[Code] .....

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Hi,

Why adidas is better-ranked than nike??

Table "indice":

idcCod fabCod mcaCod catCod fabNom mcaNom catNom
1111NikeNikeRopa
2221AdidasAdidasRopa
3113NikeNikeMedias
4118NikeNikeLargas

SELECT[RANK] ,[KEY],idc.*
FROMFREETEXTTABL (dbo.indice,mcaNombre,fabNombre,catNombre),
'ropa adidas nike',
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182
03
04
01

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Imran,
"You truly do not know someone untill you fight them."-THE MATRIX.

EmpID Empname EmpSalary RankNormal RankCorrective
1 A 150001 1
2 B 100002 4
3 C 150001 1
4 D 40003 5
5 E 150001 1
6 F 15004 6
7 G 15004 6
8 H 5005 8

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Rank In Sql ?

Aug 17, 2006

I have table :
Result1 Rank
5
6
78
4
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3

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