Retrieve Part Of Address - Column Is Varchar?

Mar 25, 2015

I want to just retrieve the numbers left of the space in this address column what can I use? The Address column is Varchar.

Address:
6501 Red Hook Place #201
32 Orchard St
1 Hardy Rd ste 210
379 E Center St.
170 Bridge St
399 Interpace Pkwy
1800 Valley Rd
2210 Harding Hwy
41 Maple Ct

Expected Results:

Address
6501
32
1
379
170
399
1800
2210
41

I tried using this:

Left([ADDRESS], Charindex(' ',[ADDRESS] - 1)) as 'Address'

But i received an error:

Conversion failed when converting the nvarchar value '6501 Red Hook Place #201' to data type int.

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Mar 11, 2014

i have a situation where is need to get email address from a varchar column. Here is some sample data for five records; The format can be change.

dummy text;
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Email: bbc@co.uk

Admissions dummy text;
T: +44 (0)1234 4444;
E: xyz@co.uk;

dummy text;
dummy text;
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Email: test@yahoo.com;

dummy text;
t: +88 (0) 115 333 5553;
f: +99 (0) 115 222 8888
e: dummy@gmail.com;

dummy text;
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w:http://www.yahoo.com/faqs;

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[OLE DB Source [277]] Error: The "output column "LIST_DATA_RCVD" (324)" failed because error code 0xC0209071 occurred, and the error row disposition on "output column "LIST_DATA_RCVD" (324)" specifies failure on error. An error occurred on the specified object of the specified component.

[DTS.Pipeline] Error: The PrimeOutput method on component "OLE DB Source" (277) returned error code 0xC0209029. The component returned a failure code when the pipeline engine called PrimeOutput(). The meaning of the failure code is defined by the component, but the error is fatal and the pipeline stopped executing.

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/*
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----- ----------- ----------- ----------- ----------- -----------
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st002 110 110 0 0 0


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