Selecting First 10 Addresses In Each City In Each State
Oct 4, 2007
Greetings:
I read with great interest a post on getting hte top 75 per cent by month, but still get through this problem. I have a table containing addresses, city names and state names, Each row has a unique address. I want to get the first ten addresses for each city in each state. I've tried something like the following which didn't work. Suggestions on how to solve the (simple) problem would be appreciated.
Select top (10) city,state,address
from address_list
alan
I have the following code, which returns a list of nearby cities based on a city name as input. Most cities have multiple zipcodes per city name, thus it can list multiple rows with the same city name, but with different zipcodes like below:
Zip | Cityname 111 belmont 112 belmont 113 belmont 114 san francisco 115 san francisco
---------------- etc----------------
I do not really care about each group of zipcodes. I only need one pair of zipcode/city name like the following:
ZIP | City name 111 belmont 114 San Francisco
How do I change my select to only return a distinct city name. I do not care which if the city/zipcodes it returns from the similar city.
The select statement is below:
CREATE PROCEDURE ZipSearchByCity @city varchar(40), @State varchar(5), @distance int
AS
SELECT distinct o.City AS City, o.zip_code, o.State AS State, (3956 * (2 * ASIN(SQRT( POWER(SIN((z.RADlatitude-o.RADlatitude)/2),2) + COS(z.RADlatitude) * COS(o.RADlatitude) * POWER(SIN((z.RADlongitude-o.RADlongitude)/2),2) )))) dist
FROM zipcodes z, zipcodes o, zipcodes a
WHERE z.city = @city AND z.State = @State AND z.zip_code=a.zip_code AND (3956 * (2 * ASIN(SQRT( POWER(SIN((z.RADlatitude-o.RADlatitude)/2),2) + COS(z.RADlatitude) * COS(o.RADlatitude) * POWER(SIN((z.RADlongitude-o.RADlongitude)/2),2) )))) < @distance GO
what I want to achieve is to load a text file that has email addreses from disk and using the email addresses in the text file look it up against the email addresses in the database table then once matched delete all the users in the table whose email address were in the text file.
I also want to update some users using a different text file.
In the database, most of our cities are stored in all upper case. For reporting purposes, I need to have them returned as upper/lower.  I used the below function, which works great for one word cities.  However I can’t figure out how to get it to capitalize the 1st letter of each word, for addresses containing multiple names such as Rancho Santa Margarita.Â
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Two things I don't like about query:
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Below is a raw data with SQL script to create the temp table. This table is a scale down version of what I am working with. I am taking the addresses from several different sources and putting them in a temp table. Now, I need to remove the duplicate addresses for each ID. Duplicate addresses are okay for different IDs.
Raw Data IDAddr1 CityStateZip 26205 N Main STChicagoIL52147 26205 N Main STChicagoIL52147 2685 Park AveChicagoIL52147 3535 Main StAustinTX78715 35976 Ponco StDallasTX79757 359587 MopacAustinTX78715 4558741 Len LnDaytonFL74717 455518 Spring DrDaytonFL74717 45585 Park AveChicagoIL52147
Desired Result IDAddr1 CityStateZip 26205 N Main STChicagoIL52147 2685 Park AveChicagoIL52147 3535 Main StAustinTX78715 35976 Ponco StDallasTX79757 359587 MopacAustinTX78715 4558741 Len LnDaytonFL74717 455518 Spring DrDaytonFL74717 45585 Park AveChicagoIL52147
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In the Navigation pane in the cell that corresponds to the Topic, for now I have an address like this: =string.Format("http://{0}/SFA/opps/edit.aspx?id={1}", Parameters!srv.Value, Fields!objectid.Value)
What I need to change when it€™s a category 5 Opportunity is €œopps€? to €œcat5€?and add €œ&etc=10008€? to the end of the address. Any ideas?
PS. {0} and {1} are parameters, one server parameter and one opportunity ID parameter.
Hi all, I'm having a bit of an issue with this query. I'm not that familiar with MS SQL so please forgive me. I'm trying to select the bad email addresses in a table so I can remove them or correct them but I'm not getting any results that are helpfull. Bellow are some of the queries I've tried
select email from person where email != "*@*" returned all addresses plus null fields.
select email from person where email not like "%@%" (this didn't work at all)
And a few other that are similar Could somebody please kick me in the right direction.
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SELECT RIGHT(@email, LEN(@email) - CHARINDEX('@', @email)) as Domain
but have been unable to extract whole email addresses.
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This database has several bulk inserts performed throughout the day and am sure there is some latency due to the size of these transactions.
Not sure as to why this is happening all of a sudden, but the db in question has been in this state for the past 12 hrs. I checked the mirroring status on the principal and it states that it is "synchronizing: data is being transferred from principal to mirror", but the mirror server states that db is in "restoring" state. Can anyone suggest as to how I can get the database on the mirroring server to get back to "mirror, synchronizing/restoring..." state? Or suggest on how I can troubleshoot this?
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We have SQL Server 2000 Standard and recently moved from Exchange 5.5to Exchange 2003. This problem occurred both before and after thee-mail change.We would like to send notifications of failed jobs to multiple peoplein case one person happens not to be in on the day there is a problem.Setting up an operator with an e-mail name that combines twoaddresses seems to work ok as long as we use a format like thefollowing:smith_john; jones_maryorJoin Bytes!; Join Bytes!However, when we add a third name, we start getting problems. Thefirst and third accounts listed get the message but the second onedoes not -- apparently because the address gets corrupted. Forexample (based on the message received at one of the good addresses),a message sent to:Join Bytes!; Join Bytes!;Join Bytes!goes to Smith and Jackson successfully but Jones' address is corruptedto:Join Bytes!omand, of course, fails.From some other testing, it appears that the last three characters ofthe first address always get appended to the end of the secondaddress.Has anyone else run across this? If so, is there a known fix? I hadhoped Exchange 2003 would fix the problem. Most likely, we will trysetting up a personal distribution list under the account from whichthe messages are sent. I just wanted to give one more shot to findingthe problem -- both because I would like to know and because beingable to string together addresses is a little easier than having to gothrough the person who can give us access to the account to set thePDL.Thanks.Jonathan LevyChicago Department of Public Health
