Simple Explanation Please

Jul 23, 2005

PREDICATES

Used as a clause.
A. What does PREDICATES mean?
B. What does it mean when used in a where clause?

I checked BOL (Glossary) but get no explanation there.

Thanks
Jay

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Simple Explanation Of Mining Algorithms

Jun 9, 2007

Hello Everyone,



I am reading DataMining Tutorial and right now I am at the Mining Algorithms section. I cannot understand any of the algorithms. For example take the following text... what a bunch of mouthful bla bla bla it is ....


"The Microsoft Decision Trees algorithm supports both classification and regression and it works well for predictive modeling. Using the algorithm, you can predict both discrete and continuous attributes.
In building a model, the algorithm examines how each input attribute in the dataset affects the result of the predicted attribute, and then it uses the input attributes with the strongest relationship to create a series of splits, called nodes. As new nodes are added to the model, a tree structure begins to form. The top node of the tree describes the breakdown of the predicted attribute over the overall population. Each additional node is created based on the distribution of states of the predicted attribute as compared to the input attributes. If an input attribute is seen to cause the predicted attribute to favor one state over another, a new node is added to the model. The model continues to grow until none of the remaining attributes create a split that provides an improved prediction over the existing node. The model seeks to find a combination of attributes and their states that creates a disproportionate distribution of states in the predicted attribute, therefore allowing you to predict the outcome of the predicted attribute"



In the above text what is meant by discrete and continious attributes? what is regression? what is predicted attributes? what are input attributes? what is distribution of states?



Is there a source which explains these algorighms in a easier way ....

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Simple Explanation To Concatenating Multiple Items Into One Column

Jan 17, 2008

Hi, I am a extreme beginer to sql server and i am i'm having big trouble trying to display my sql query properly. Bascially i want to put the results of a one to many query into one row per record. I have read articles and forums discussing 'concatenating the values' or creating a function??? but i dont follow what they mean and i am completely lost. Can anyone provide a really simple explanation on what i need to do to resolve my duplicate row issue? i urgently need to find a solution to this.
 Regards

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Just An Explanation Of What This Means Please

Jan 22, 2008

Hi,
I have a project that has been given to me and need help please. The complete class is as follows
Public Class CarAccessData
    Public Function Getcarinfo() As List(Of CarInfo)
        Dim AllCarInfo As New List(Of CarInfo)
        Dim SQL As String        SQL = "SELECT [SKU], [CarMake], [CarModel], [Carprice]"
        Dim MyConnection As SqlConnection        MyConnection = New SqlConnection(ConfigurationManager.ConnectionStrings("AntConnectionString1").ConnectionString)
        Dim aCmd As SqlCommand        aCmd = MyConnection.CreateCommand
        aCmd.CommandText = SQL        aCmd.CommandType = CommandType.Text
        Dim aDataReader As SqlDataReader
        Try
            MyConnection.Open()
            aDataReader = aCmd.ExecuteReader
            While aDataReader.Read()
                AllCarInfo.Add(New CarInfo(aDataReader))            End While
        Catch ex As Exception            Throw ex        Finally
            aDataReader.Close()
            MyConnection.Close()        End Try
        Return AllCarInfo    End Function
End Class
 
The bit I dont quite understand is the following snippet from above
 
 
Dim aCmd As SqlCommand        aCmd = MyConnection.CreateCommand
        aCmd.CommandText = SQL        aCmd.CommandType = CommandType.Text
        Dim aDataReader As SqlDataReader
        Try
            MyConnection.Open()
            aDataReader = aCmd.ExecuteReader
            While aDataReader.Read()
                AllCarInfo.Add(New CarInfo(aDataReader))            End While
        Catch ex As Exception            Throw ex        Finally
 
Can anyone explain this in real ABC style step by step please, just so I can start to understand this, ( I am quite new to this)
many thanks,
Anteater

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Explanation Of Columns_updated()

Jun 1, 2004

the statement
if ((columns_updated() & 2 + 4 + 8)) > 0) is supposed to tell me if the 2nd, 3rd or 5th columns were updated. My question is, what desginates the column 2,3,5, when 2,4,8 are in the statement

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Need Some Explanation On Transactions

Apr 28, 2005

I am having some problems with transactions, although it seems that the problem exists within the vb code making the db call it may be that sql is the source of the problem.

1.
There is a number of stored procs that contain transactions most of which are inserts followed by a select statement to retrieve the most recently added ID. So to start with is a select the best way or is the @@Identity. I have read the @@Identity is global, so for a external server that is running a number of databases I stayed away from it. Did I take the right actions or is there a better way?

2.
Is having sql transactions within a call from vb.net ok? I know that the sqlClient class doesn't support nested transactions, but does that include transactions within sql?

3.
if a stored proc is called, from vb contained in a sqlClient transaction, are ALL the calls from within the sproc able to be rolled back?

If there is a reliable way to obtain the Identity without containing it in a transaction, and having the internal sql transactions in the problem, then I am home free, so I am hoping this is the case.

Thanks for any help

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Oct 31, 2007

I am wondering what are od1 and od2 used for in SQL Queries? Are they used for joining... can anyone explain their significance in the queries below... (especially the commands in red)


USE Northwind
SELECT OrderID, CustomerID
FROM Orders o
WHERE 20 < (SELECT Quantity
FROM [Order Details] od
WHERE o.OrderID = od.OrderID AND od.ProductID = 23)USE Northwind
SELECT DISTINCT ProductName, Quantity
FROM [Order Details] od1 JOIN Products p
ON od1.ProductID = p.ProductID
WHERE Quantity = (SELECT MAX(Quantity)
FROM [Order Details] od2
WHERE od1.ProductID = od2.ProductID)

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Query To Find Nth Value Explanation

Jun 20, 2007

can anyone explain how this works:

USE NORTHWIND

GO

SELECT freight
FROM orders E1
WHERE (N =
(SELECT COUNT(DISTINCT (E2.freight))
FROM orders E2
WHERE E2.freight >= E1.freight))

replace N by a number. To find that Nth value from the table.

Ashley Rhodes

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Jul 23, 2005

In T sql for sql server, what is the technical difference between thecomparisons "is" and "="for example:set @test = nullprint @test is null -> trueprint @test = null -> false

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Very Chalanging Question - Explanation

May 31, 2006

Ok, here is a asample table representing the problem more clearlyA | B | C | D-----------------a1 b1 c1 d1a1 b2 c2 d2a3 b3 c1 d3a4 b4 c4 d3a5 b5 c5 d5a6 b6 c6 d3Tha duplications are:row 1+2 in param Arow 1+3 in param Crow 3+4+6 in param Donly row 5 is unique in all parameters.conclusion: row 1+2+3+4+6 are the same usergoal: to find all duplicated rows & to delete them all accept oneinstance to leave.Note:Finding that row 1similar to 2 in A & deleting it will loose databecause we won't know that row 1 is ALSO similar to 3 on C & later onfinding that 3 is similar to 4 & 6 on D & so onThe simple time consuming (about 2 weaks) query to acomplish the taskis:SELECT count(*),A.B,C,DFROM tblGROUP BY A,B,C,DHAVING count(*)>1I THANK YOU ALL

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Feb 22, 2000

When a database is created in SQL Server, 4 files are made:

(example)
DB_Data.DAT
DB_data.mdf
DB_Log.DAT
DB_log.ldf


What do each of these files contain? I can figure out that the main database is the DB_Data.DAT, but why is the transaction log a .DAT and why is there four files instead of two? etceterea.

Llyal

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Jan 15, 2001

I went to Microsoft to find some info about the function Instr. I need to
perform a search with a string similar to their example I found below. Can
anyone explain to me Microsoft's example?? I am little confused by the
parameters used and the explanation it gives back to me??

Dim SearchString, SearchChar, MyPos
SearchString ="XXpXXpXXPXXP" ' String to search in.
SearchChar = "P" ' Search for "P".
MyPos = Instr(4, SearchString, SearchChar, 1) ' A textual comparison
starting at position 4. Returns 6.
MyPos = Instr(1, SearchString, SearchChar, 0) ' A binary comparison
starting at position 1. Returns 9.
MyPos = Instr(SearchString, SearchChar) ' Comparison is binary by default
(last argument is omitted). Returns 9.
MyPos = Instr(1, SearchString, "W") ' A binary comparison starting at
position 1. Returns 0 ("W" is not found).

My problem is this:

I need to scan within SearchString for blanks/spaces characters. When I
find one, then place the values to the left and right of it in seperate
columns. For example, I would need to scan 'John Smith A' and then place
'John' in FirstName column, 'Smith' in LastName column, and 'A' in MidName
column.

I think this is how my code would read, but I am confused on how to place
the results into my table to the correct columns?

my search string would be SearchString = 'John Smith A'
my SearchChar would be SearchChar = ' ' (note I am searching for a
space/blank character)

So would then my code be like:

Dim SearchString, SearchChar, MyPos
SearchString = 'John Smith A'
SearchChar = ' '
MyPos = Instr(1, SearchString, SearchChar, 0)

How do I get whatever is returned from the Instr function to a column in a
table??

Any help would be great.

Rey

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Apr 30, 2008

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1 - If msdtssrvr is modified to reference a named instance, such as <ServerName>SQLTESTINST1<ServerName>, when I connect to Integration Services through Management Studio do I still specify the default instance name in the login window? That's the only way we have been able to connect and despite specifying the default instance name, the packages displayed are those of the named instance.

2 - If I am correct that you must always specify the default instance name when connecting to Integration Services, then in order to eliminate confusion regarding what SQL instance's SSIS packages I am viewing under the folder structure I can create SQL Server folders by modifying msdtssrvr.ini.xml. For example:


<?xml version="1.0" encoding="utf-8"?>
<DtsServiceConfiguration xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<StopExecutingPackagesOnShutdown>true</StopExecutingPackagesOnShutdown>
<TopLevelFolders>
<Folder xsi:type="SqlServerFolder">
<Name>MSDB</Name>
<ServerName>.</ServerName>
</Folder>
<Folder xsi:type="SqlServerFolder">
<Name>MSDB-INST1</Name>
<ServerName>SQLTESTINST1</ServerName>
</Folder>
<Folder xsi:type="SqlServerFolder">
<Name>MSDB-INST2</Name>
<ServerName>SQLTESTINST2</ServerName>
</Folder>
<Folder xsi:type="FileSystemFolder">
<Name>File System</Name>
<StorePath>..Packages</StorePath>
</Folder>
</TopLevelFolders>
</DtsServiceConfiguration>


I then restart the SSIS service and can now see the following folder structure.

Running Packages
Stored Packages

+ File System
+ MSDB
+ MSDB-INST1
+ MSDB-INST2

If I expand MSDB-INST1 I will only see packages saved on the instance named INST1. The same is true for INST2. If I expand MSDB I will only see packages saved on the default instance.

Does this sound like I am doing things correctly?

Thanks, Dave

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Explanation Wanted About The Service Principal Name ( SPN )

Jun 26, 2007

Hello,



In the ErrorLog of my Sql Server , i found this line :

2007-06-26 05:35:18.37 Serveur The SQL Network Interface library could not register the Service Principal Name (SPN) for the SQL Server service. Error: 0x54b, state: 3. Failure to register an SPN may cause integrated authentication to fall back to NTLM instead of Kerberos. This is an informational message. Further action is only required if Kerberos authentication is required by authentication policies.


Operating System XP Home SP2

SQL Server 2005 Express Edition with Advanced SP1 )



( idem for another workstation with XP Pro SP2 and same version of SQL Server 2005 Express



My problem is :

i want use the windows authentification but my computers are on Worhkgroup linked by a router ( no window server )

i have read that's possible to connect from a remote computer to a computer having a SQL Server 2005 Express through SPN

How can i do it ? ( activating NTLM ? but how ?)

I'm writing a C# program which must be executing on several computers with a SQL Server 2005 Express installed on a particular computer. These computers will belong to a domain of Windows Server 2003.

As i can't connect to this "normal" network, i am trying to simulate this network at home because i want to test this program and especially the possible locks problems.

I don't know whether i'm querying with the "correct" forum.

Sorry for my poor english.

I shall appreciate any help about this problem

Have a nice day

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Sep 21, 2005

I've been reconfiguring my Windows service accounts for the SQL Server service and the SQL Agent service to comply with the security best practices for SQL Server 2005.  Specifically, I created two new network accounts.  One account runs the SQL Server service, the other runs the SQL Agent service.

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Jan 7, 2008

If you know the answer please explain what you're doing if possible, that'll help me :)I have the following tables:CREATE TABLE [dbo].[tblUserData](    [UserCode] [int] IDENTITY(1,1) NOT NULL,    [UserName] [nvarchar](50) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,    [DisplayName] [nvarchar](50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,) ON [PRIMARY]CREATE TABLE [dbo].[tblFriends](    [UserCodeOwner] [int] NOT NULL,    [UserCodeFriend] [int] NOT NULL,    [createdate] [datetime] NOT NULL CONSTRAINT [DF_tblFriends_createdate]  DEFAULT (getdate())) ON [PRIMARY]in tblFriends relations are stored twice, so for a relation between user 5 and 6, there will be 2 rows: 5-6 and 6-5Now, I want to get the columns (UsercodeOwner,UsercodeFriend,createdate,username,displayname) for relations that were created in tblFriends in the last 10 days for the FRIENDS of a person with usercode 5.Example:tblUserdata5 peter Petertje6 john Johnny11 simon SimonSays15 monique MontjetblFriends5 6 'createdate 30 days ago'5 11 'createdate 5 days ago'6 5 'createdate 30 days ago'6 11 'createdate 3 days ago'6 15 'createdate 7 days ago'11 5 'createdate 5 days ago'11 6 'createdate 3 days ago'15 6 'createdate 7 days ago'The resultset for a query on usercode 5 would now be (usercode1, username1, displayname1,usercode2, username2, displayname2,createdate):6 john Johnny 11 simon SimonSays 'createdate 3 days ago'6 john Johnny 15 monique Montje 'createdate 7 days ago'As you can see each relation is only returned twice even though there are always two entriesWhat would be the SQL statement, if possible without temp table..Thanks!

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Apr 3, 2006

I am getting a new server online at a customer, and our system shows very funny erorrs under full load. No explanations could be found. Anyone has some?
Here we go:
Server failed to resume the transaction, desc: 360000054a. The transaction active in this session has been committed or aborted by another session.,
at System.Data.SqlClient.SqlCommand.ExecuteNonQuery()
and
New request is not allowed to start because it should come with valid transaction descriptor.
System.Data.SqlClient.SqlException
I am a little lost on those. Simple fact is that I do not find any description of those. Anyone an idea what causes these?

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Checksum_agg And Row Size Error. Require Explanation.

Jul 23, 2005

Hi,I can see that by using the object ID rather that the object name, thefollowing SQL query works. Has anybody got any idea what is causing theerror?-- Works OKselect o.id,checksum_agg(binary_checksum(m.text))from sysobjects o,syscomments mwhere o.id = m.idand o.xtype in ('FN','IF','P','TF','TR','V')group by o.id-- Error-- Server: Msg 1540, Level 16, State 1, Line 1-- Cannot sort a row of size 8096, which is greater than the-- allowable maximum of 8094.select object_name(o.id),checksum_agg(binary_checksum(m.text))from sysobjects o,syscomments mwhere o.id = m.idand o.xtype in ('FN','IF','P','TF','TR','V')group by object_name(o.id)-- Error-- Server: Msg 1540, Level 16, State 1, Line 1-- Cannot sort a row of size 8096, which is greater than the-- allowable maximum of 8094.select o.name,checksum_agg(binary_checksum(m.text))from sysobjects o,syscomments mwhere o.id = m.idand o.xtype in ('FN','IF','P','TF','TR','V')group by o.name-- Workaroundselect getdate(),object_name(x.id),check_sumfrom (select m.id,checksum_agg(binary_checksum(m.text)) as check_sumfrom syscomments minner joinsysobjects oon m.id = o.idwhere o.xtype in ('FN','IF','P','TF','TR','V')group by m.id) as xRegardsLiam

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Linear Regression With Nested Explanation Variable

Jan 22, 2007

We are trying to create a model of linear regression with nested table. We used the create mining model sintax as follow :

create mining model rate_plan3002_nested2

( CUST_cycle LONG KEY,

VOICE_CHARGES double CONTINUOUS predict,

DUR_PARTNER_GRP_1 double regressor CONTINUOUS ,

nested_taarif_time_3002 table

( CUST_cycle long CONTINUOUS,

TARIFF_TIME text key,

TARIFF_VOICE_DUR_ALL double regressor CONTINUOUS

)

) using microsoft_linear_regression

INSERT INTO MINING STRUCTURE [rate_plan3002_nested2_Structure]

(CUST_cycle ,

VOICE_CHARGES ,

DUR_PARTNER_GRP_1 ,

[nested_taarif_time_3002](SKIP,TARIFF_TIME ,TARIFF_VOICE_DUR_ALL)

)

SHAPE {

OPENQUERY([Cell],

'SELECT CUST_cycle ,

VOICE_CHARGES ,

DUR_PARTNER_GRP_1

FROM dbo.panel_anality_3002

order by CUST_cycle ')}

APPEND

({OPENQUERY([Cell],

'select CUST_cycle,

TARIFF_TIME,

CYCLE_DATE

from dbo.nested_taarif_time_3002

order by CUST_cycle,TARIFF_TIME')

}

relate CUST_cycle to CUST_cycle

) as nested_taarif_time_3002



The results we got are a model with intercept only. if we don't use the nested variable (the red line) we get a rigth model . (we had more variable ....)

Is there a way to do this regression correctly?

Thanks,

Dror

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May 1, 2008

(I wish I was able to attach pictures....anyhow I'll try my best without them)

The customer's goal is to via ReportBuilder to select fields from multiple
many-to-many relationships. They are able to see the fields that exists
within the various many-to-many relationships but IS ONLY able to select
fields from ONE many-to-many relationship. Example using AdventureWorks:

DataSourceView (relationships automatically generated by wizard)
Contact ---< VendorContact >--- Vendor
Contact ---< StoreContact >--- Store
Contact ---< ContactCreditCard >--- CreditCard

So the goal in the ReportBuilder is to be able select fields from
Contact/Vendor/Store/ and CreditCard.
PROBLEM is that the ReportBuilder ONLY allows user to select fields from
Contact/Vendor OR Contact/Store OR Contact/CreditCard (exclusively)

The only workaround I've found is to reverse the relationships in the
DataSourceView to the following

Contact >--- VendorContact ---< Vendor
Contact >--- StoreContact ---< Store
Contact >--- ContactCreditCard ---< CreditCard

This works however we need an explanation as to why it only works this way?

Thanks in advance

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Simple Simple Linking Tables & Perform Calculation

Mar 22, 2007

found it

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Oct 24, 2007

Question is in the subject.

Thanks in advance
-Jamie

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Simple Question (Hope Simple Answer Too)

May 26, 2004

Hey,

I have MS SQL database.
I have procedure:



code:--------------------------------------------------------------------------------
CREATE PROCEDURE dbo.Reg_DropTable
@ModuleId varchar(10)
AS
declare @TableName varchar, @kiek numeric
set @TableName = 'reg_'+@ModuleId

begin
DROP TABLE @TableName <- HERE I GOT ERROR
end
GO
--------------------------------------------------------------------------------


I got error when using variable with tables names.
How to do this?

Ps. Number is send to this function and it must drop table with name Reg_[That number]

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Jul 15, 2002

Can somebody explain to me how to best do inserts where you have primary keys and foreign keys.l'm battling.

Is there an article on primary keys/Pk ?

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Feb 21, 2007

I am receiving funny results from a query. To simplify, I have 2 tables (todayyesterday). Each tbl has the same 8 columns. My query joins the two tables then looks where either of two columns has changed. What is happening is that when checking one of the columns it seems as though sql is flipping the column, causing it to be returned in error.

result set

colA colB colC colD colE colF colG colG (from yesterday)
1 1 a b c d e m
1 1 a b c d m e

So what's happening is that the record above is actually the same record and should not be returned. There is a daily pmt column that changes but I am not using that in the query. Aside from that the two records are identicle.

Any help is appreciated.

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Simple Join Not So Simple

Aug 19, 2006

Hi,

I have the following situation (with a site that already works and i cannot modify the database architecture and following CrossRef tables -- you will see what i mean by CrossRef tables below)

I have:


Master table Hotel

table AddressCrossRef (with: RefID = Hotel.ID, RefType = 'Hotel', AddrID)
joins
table Address (key = AddrID)


table MediaCrossRef (with RefID = Hotel.ID, RefType= 'Hotel', MediaID)
joins
table Media (with MediaID,mediaType = 'thumbnail')


foreach hotel, there definitely is a crossRef entry in AddressCrossRef and Address tables respectively (since every hotel has an address)

however not all hotels have thumbnail image

hence i have hotel inner join AddressXReff inner join Address ..... however i must have
left outer join mediaXref left outer join media


the problem is that if there is no entry in Media or mediaXref, I don't get any results

i tried to get over it by using
where (media.mediaTyple like 'thumbnail' or media.mediaType is null)
but then i started getting multiple results for each hotel because media's of type movie or full_image or etc... all got returned


any clue?

thanks

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This All Seemed Simple Enough...

Mar 24, 2007

...when I started this endeavor.
I have a previously developed Lotus Notes App. The idea was simple; as
I am sefl taught on Lotus Script, I figured I'd be able to stumble my
way through VB.Well,
it started OK. I used VB Express to get familiar with the stuff, but
decided to go with a full version of VS 2005 and try and get this thing
properly developed as a web app. I purchased several reference books
etc., and have become relatively familiar with the forums here.First
issue I have is that I simply want to use code to update or add records
to an SQL DB. I know about datagridview etc., but I want to update the
DB using forms, not the tabular view those controls provide. I thought
it would be relatively straight forward, but found my ignorance runs
deeper than I thought. When I tried to do so I am finding I am not
really clear on where to make declarations etc. in the web app.  If anyone could point me in the right direction that would be great. The
issue with searching these forums is most posts deal with datagridview
or something similar.I have spent a ton of time trying to find relevant
posts or articles, but have had no luck yet.Again, all Ireally
need is a nudge in the right direction. I am more than willing to plod
through reference materials or articles/posts to find what I need to
know, I just can't find where to even start on the info I need. Regards, Joe
 

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Feb 24, 2008

 Hi
I have a problem with my sql WHERE query, if i manually type ([Area] = 'The First Area')  then it is okay but if i try and pass the variable 'The First Area' using the

([Area] = @Area) it doesnt work. 
 ALTER PROCEDURE dbo.StoredProcedure1(@oby nvarchar,@Area char,@Startrow INT,@Maxrow INT, @Minp INT,@Maxp INT,@Bed INT)ASSELECT * FROM(SELECT row_number() OVER (ORDER BY @oby DESC) AS rownum,Ref,Price,Area,Town,BedFROM [Houses] WHERE ([Price] >= @Minp) AND ([Price] <= @Maxp) AND ([Bed] >= @Bed) AND ([Area] = @Area)) AS AWHERE A.rownum BETWEEN (@Startrow) AND (@Startrow + @Maxrow) Please Help I know it must be something simple as the sql works but not when i pass the variable.... Thanks In Advance  

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Simple SQL

Dec 30, 2004

How can i get an output like this from this sql??

HEM_PATIENT_ID is primary key...

Output:
First row: initial values of the fields
Second row: average of the same fields

Please help me...



select * from (
select HEM_LOKOSIT, HEM_NNS
from LPMS.HEMOGRAMS
where HEM_PATIENT_ID = 33
union
select AVG(HEM_LOKOSIT), AVG(HEM_NNS)
from LPMS.HEMOGRAMS
where HEM_PATIENT_ID = 33)
order by HEM_LOKOSIT desc nulls last;

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Simple Help

May 20, 2001

Am new to SQL Server , can any1 tell me is there anyway to display date in this format month and year like Apr 2000 ,excluding the day.

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Should Be Simple !!!!

Jan 25, 2001

Hi,

I'm relatively new to SQL7 but I did use 6.5 a fair bit.
I'm trying to test the restore of the Transaction log backup and having a bit of difficulty. The idea is that I make a complete database backup at 1am backup the transaction log every 30 minutes between 7am and 7pm. I need to be able to restore the database to a known state between 7am and 7pm with a max data loss of 30 minutes.

What I am trying to achieve is (as a test):

1)Create a small test database with a test table
2)Add some data to the test table
3)Back up the transaction log
4)Restore the transaction log to 'undo' the data added in step 2

Should be simple I think !!! The problem I am encountering is that in step 4 it won't let me restore only the transaction log (a tick automatically appears in the database backup as well). Bah !

Can someone please tell me what simple steps are required to get this to work. I need specifically on what options to chose during the backup and restore processes.

Thankyou,

Tim

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Simple SQL

Nov 8, 1999

Given one table with one column and two rows, one containing the string 'Bill', one containing the string 'Gates'.

Write a select statement which gives you the result 'Bill Gates'.

???+

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Simple SQL

Apr 2, 2003

Hi All,

I have a table with 2 columns which looks like the following.

IDText
-------------
1AAA
1BBB
1CCC
2DDD
2EEE
2FFF
3GGG
3HHH
3III

Each ID can have multiple texts associated with it. I want to write a query that gives me the following output.

IDText
-------------
1AAA; BBB; CCC
2DDD; EEE; FFF
3GGG; HHH; III

I appreciate your help

Thanks

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