Simulating Median On Table Columns In SQLserver2000
Apr 22, 2004
Folks,
I have a an sql table having 10,000 Rows.
The table has 5 columns. They are S1,S2,S3,S4 and M
I need the best way to calculate the MEDIAN for each row and store it in M. i.e. M=median(S1,S2,S3,S4)
I've come across articles where they've calculated medians on table rows, not table columns. But my requirement involves table columns. I guess transposing the columns into rows and then calculating median should be possible, but if I do that for 10000 rows using a cursor, then it would take a loooooong time.
Please suggest the best way to counter this
Thanx
Kiran
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Aug 13, 2015
I have a database with 1million+ records in and i'm trying to collect the median values of column(2) for all distinct values in column (1)
Example DB:
Column 1 Column 2
978555 500
978555 502
978555 480
978555 490
978324 1111
978324 1102
978311 122
978311 120
978994 804
978320 359
and I need it to display on SELECT as
column 1 column 2
978555 495
978324 1106
978311 121
978994 804
978320 359
Is this possible on 2008 R2?
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Oct 27, 2015
I need to get the median for the 10 columns in my table. For the sake of example, I've reduced it to 2 columns.
The code below works perfectly if i compute for only 1 column and certainly doesn't for multiple columns.
Is there a way to better handle the median computation in one pass, if multiple columns are involved?
DECLARE @tbl as table (id_n int, col1 int, col2 int)
insert into @tbl
values (1, 1, 2), (1,3, 4), (1, 5, 7), (2, 4, 7), (2, 7, 7), (2, 3, 5), (2,5, 5), (3, 1, 2), (3, 3, 5), (3, NULL,11)
select *
from @tbl
order by id_n, col1
[Code] .....
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Sep 10, 2007
Hi,
iam having vs2005 installed on my machine and i also installed sqlserver2005 dev edition on my machine...Now iam devloping a Window Appplication in which I need to populate a grid from Sqlserver2000 (dev edition) which installed on remote (i.e another network)....when i try to run my application it gives me a error tht "Unable to connect to sqlserver2005".actaully i specified in my connection string to connect to Sqlserver2000 on the remote machine.
I feel to know how to enable remote connection on Sqlserver 2000.So tht i can access this sqlserver2000 from another machine
With regards
Mahender
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Feb 19, 2012
I need to calculate a median on a column in a table. The code I have is:
Code:
Select gender,
CASE
when gender = 'F' then 'Female'
when gender = 'M' then 'Male'
else 'Unknown'
end as test,
datediff(day, [admit_date], getdate()) as 'datediffcal',
from [tbl_record]
How do I calculate the median on the datediffcal column?
It doesn't matter if the resultset only shows the median result. So if the output shows:
median
15
that's fine. Minimally, I need the median value.
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Oct 11, 2005
How could I create an allocation or consistency error (or otherwise corrupt a db) in a database to test a backup and restore system?
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Nov 21, 2006
Hi EveryBody,
I have the following question :
What components of I.S. would I use, for simulating a cursor in SQL like that?
Example of simple cursor :
declare c_CURSOR cursor FOR
SELECT DISTINCT V.CODIGO FROM GB_RELACIONAL.DBO.VISITA V INNER JOIN MEDIDAS_LINEAL_PROMOCION_200604_02 M
ON M.CODIGO_VISITA=V.CODIGO AND M.TIEMPO_ENTRE_vISITAS <> V.TIEMPO_ENTRE_VISITAS
OPEN C_CURSOR
FETCH NEXT FROM C_CURSOR INTO @CODIGO
WHILE @@FETCH_STATUS=0
Do various Jobs; Doing Selects, Inserts etc.. using @codigo
FETCH NEXT FROM C_CURSOR INTO @CODIGO
end
CLOSE C_CURSOR
DEALLOCATE C_CURSOR
Then what I need is passing the @codigo in every loop, to other components in I.S., for doing inserts in other related tables.
Then my questions are:
a- What Component i would use for simulating the looping cursor like the example ?
b- How i Store and pass de @codigo to the other I.S. components for doing the selects, inserts?
c- What I.S. components and how would use, for receiving the @codigo ,and doing the corresponding Select , Inserts.. in the related tables , using that variable ( @codigo ) ?
I need an Idea of the I.S. components, configurations, and the flow for doing something like this...
Thank in advance!!
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Feb 24, 2007
Hi,
Can anybody let me know if there are ways to programatically track changes made to a SQL SERVER CE table? I am writing a db monitoring tool on SQL server CE which should track any changes made to the table.(Insert update and delete)
We could have done this using triggers on Sql Server 2005. Since triggers are not supported on SQL Server CE, are there any alternate ways to achieve this functionality?
Regards,
Ananth
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Jan 8, 2007
Damn! SQLServer2000 can't add a NOT NULL COLUMN even in one emptyexisting table!That is, A is the existing table and it is emtpy, I want to add one NOTNULL COLUMN (col_new) to A using following T-SQL statement, then itwill fail.ALTER TABLE A ADDcol_new varchar(600) NOT NULLGOYou should change it to these statements in SQLServer2000:ALTER TABLE A ADDcol_new varchar(600) NULLALTER TABLE A ALTER COLUMN col_new varchar(600) NOT NULLGOah, ridiculous! right?Fortunately, this stupid behavior is changed in SQLServer2005. Thefirst T-SQL statements works.
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Jul 22, 2015
So I have been trying to get mySQL query to work for a large database that I have. I have (lets say) two tables Table_One and Table_Two. Table_One has three columns: Type, Animal and TestID and Table_Two has 2 columns Test_Name and Test_ID. Example with values is below:
**TABLE_ONE**
Type Animal TestID
-----------------------------------------
Mammal Goat 1
Fish Cod 1
Bird Chicken 1
Reptile Snake 1
Bird Crow 2
Mammal Cow 2
Bird Ostrich 3
**Table_Two**
Test_name TestID
-------------------------
Test_1 1
Test_1 1
Test_1 1
Test_1 1
Test_2 2
Test_2 2
Test_3 3
In Table_One all types come under one column and the values of all Types (Mammal, Fish, Bird, Reptile) come under another column (Animals). Table_One and Two can be linked by Test_ID
I am trying to create a table such as shown below:
Test_Name Bird Reptile Mammal Fish
-----------------------------------------------------------------
Test_1 Chicken Snake Goat Cod
Test_2 Crow Cow
Test_3 Ostrich
This should be my final table. The approach I am currently using is to make multiple instances of Table_One and using joins to form this final table. So the column Bird, Reptile, Mammal and Fish all come from a different copy of Table_one.
For e.g
Select
Test_Name AS 'Test_Name',
Table_Bird.Animal AS 'Birds',
Table_Mammal.Animal AS 'Mammal',
Table_Reptile.Animal AS 'Reptile,
Table_Fish.Animal AS 'Fish'
From Table_One
[Code] .....
The problem with this query is it only works when all entries for Birds, Mammals, Reptiles and Fish have some value. If one field is empty as for Test_Two or Test_Three, it doesn't return that record. I used Or instead of And in the WHERE clause but that didn't work as well.
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Sep 19, 2007
Hi,
I have two tables
Table Source
{
category varchar(20),
LastUpdate datetime
}
Table Destination
{
SubjectId varchar(20),
SubjectDate datetime,
category varchar(20),
LastUpdate datetime
}
Please note that the number columns are different in each table.
I wanted to dump the data of Source table to Destination table. I meant to say that the rows of 2 columns in Source table to last 2 rows of Destination table.
And also my oreder of the columns in Destination table will vary. So i need to a way to dynamically insert the data in bulk. but i will know the column names for sure before inserting.
Is there anyway to bulk insert into these columns.
Your quick response will be appreciated
~Mohan Babu
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Apr 29, 2015
I have a business need to create a report by query data from a MS SQL 2008 database and display the result to the users on a web page. The report initially has 6 columns of data and 2 out of 6 have JSON data so the users request to have those 2 JSON columns parse into 15 additional columns (first JSON column has 8 key/value pairs and the second JSON column has 7 key/value pairs). Here what I have done so far:
I found a table value function (fnSplitJson2) from this link [URL]. Using this function I can parse a column of JSON data into a table. So when I use the function above against the first column (with JSON data) in my query (with CROSS APPLY) I got the right data back the but I got 8 additional rows of each of the row in my table. The reason for this side effect is because the function returned a table of 8 row (8 key/value pairs) for each json string data that it parsed.
1. First question: How do I modify my current query (see below) so that for each row in my table i got back one row with 19 columns.
SELECT A.ITEM1,A.ITEM2,A.ITEM3,A.ITEM4, B.*
FROM PRODUCT A
CROSS APPLY fnSplitJson2(A.ITEM5,NULL) B
If updated my query (see below) and call the function twice within the CROSS APPLY clause I got this error: "The multi-part identifier "A.ITEM6" could be be bound.
2. My second question: How to i get around this error?
SELECT A.ITEM1,A.ITEM2,A.ITEM3,A.ITEM4, B.*, C.*
FROM PRODUCT A
CROSS APPLY fnSplitJson2(A.ITEM5,NULL) B, fnSplitJson2(A.ITEM6,NULL) C
I am using Microsoft SQL Server 2008 R2 version. Windows 7 desktop.
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May 26, 2015
Here is My requirement, I'm not sure if this is possible. Creating table called master like col1, col2 col3, col4 , col5 ...Where Col1, col2 are updatable - this can be done easily
Col3, col4 are columns in another table but these can be just a read only ?? Is this possible ? this is possible with View but not friendly with share point CRUD...Col 5 is a computed column of col 2 and col5 ? if above step can be done then sure this can be done I guess.
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Dec 7, 2002
I recently had to use my own little median technique again on a report here at work, and had posted it before, but wasn't sure if anyone had seen it. I have read Celko's and others techniques for generating a median and haven't seen one more efficent.
Does anyone have a better way they can think of? I think this bad boy is pretty short & efficient.
First, if you want to return the middle number or the higher one next to the middle if there is an even number:
SELECT x.Value AS median
FROM Vals x
CROSS JOIN Vals y
GROUP BY x.Value
HAVING SUM(SIGN(x.Value-y.Value)) IN (1,0)
Change the " IN (1,0)" to "IN (-1,0)" to get the lower value if there is an even # of values.
Basically, we are saying compare each number to all possible numbers, and add up values of 1,0 or -1 depending if the first number is less, equal or higher than the second. The number that returns 0 is right in the middle ... If there is no middle, a -1 or 1 is returned. There will never be a 0 and (-1 or 1) at the same time returned.
To get the financial median (avg of the 2 values middle values if there is an even number), you need to encapsulate the results of the above into a subquery, allow for not just (-1,0) but all three (-1,0,1) and then take the AVG of the values returned.
That is,
SELECT Avg(Median) as Median FROM
(
SELECT x.Value AS median
FROM Vals x
CROSS JOIN Vals y
GROUP BY x.Value
HAVING SUM(SIGN(x.Value-y.Value)) IN (1,0,-1)
) A
If there is an even number of values, the lower and higher middle ones are averaged. If there is an odd number, only the middle value is returned and averaged (which of course has no effect).
Most other techniques used several COUNT(*) subqueries which this one avoids.
Critique and enjoy!
- Jeff
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Sep 27, 2007
I have a table that contains the following:
customer (ID of customers)
product (Product description numeric value)
UOM (unit of measure like each or pak)
avgprice (Avg proce that this product and uom was sold)
I need to find the median value for a product, uom. Then I need create a table that shows product,uom,avgprice,median grouped by product and uom
I have been at this for two days with no luck
Thanks in advance for any help
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Jul 20, 2005
Hello,Using SQL Server 2000, I'm trying to put together a query that willtell me the following information about a view:The View NameThe names of the View's columnsThe names of the source tables used in the viewThe names of the columns that are used from the source tablesBorrowing code from the VIEW_COLUMN_USAGE view, I've got the codebelow, which gives me the View Name, Source Table Name, and SourceColumn Name. And I can easily enough get the View columns from thesyscolumns table. The problem is that I haven't figured out how tolink a source column name to a view column name. Any help would beappreciated.Garyselectv_obj.name as ViewName,t_obj.name as SourceTable,t_col.name as SourceColumnfromsysobjects t_obj,sysobjects v_obj,sysdepends dep,syscolumns t_colwherev_obj.xtype = 'V'and dep.id = v_obj.idand dep.depid = t_obj.idand t_obj.id = t_col.idand dep.depnumber = t_col.colidorder byv_obj.name,t_obj.name,t_col.name
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Aug 25, 2004
Hi All,
I have a table that of server names and their execution times that run in to hundreds of thousands of records. What i need is some SQL that gives me the median execution times for each of these different servers. At the moment i have some SQL that only gives me the median for all the records in the table not the median execution time for every different server name. For example my tables looks something like this;
ServerName | ExecTime
-----------------------
server1 | 0.07
server2 | 0.17
server1 | 0.27
server1 | 0.37
server2 | 0.47
server1 | 0.57
server1 | 0.67
server2 | 0.77
My SQL below gives me
ServerName | ExecTime
-----------------------
server1 | 0.37
Where as i want
ServerName | ExecTime
-----------------------
server1 | 0.37
server2 | 0.47
Here is my SQL, hope someone can modify it and thanks in advance.
Code:
SELECT DISTINCT instance, exec_time AS median
FROM (SELECT instance, exec_time
FROM (SELECT TOP 1 exec_time = exec_time * 1.0, instance
FROM (SELECT TOP 50 PERCENT exec_time, instance
FROM llserverlogs
ORDER BY exec_time) sub_a
ORDER BY 1 DESC) sub_1
UNION ALL
SELECT instance, exec_time
FROM (SELECT TOP 1 exec_time = exec_time * 1.0, instance
FROM (SELECT TOP 50 PERCENT exec_time, instance
FROM llserverlogs
ORDER BY exec_time DESC) sub_b
ORDER BY 1) sub_2)
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Jan 28, 2006
I've noticed that SQL Server (and other DBMSs I've looked at) doesn't seem to have a built-in function for finding the median of a range of numbers.
Gack!
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Sep 28, 2006
I have a long term need for a median function, I was wondering if anyone has or knows of some code or user defined functions somewhere that would do this. Ideally you could use it just liket the rest of the aggregate functions like AVG, etc.
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Mar 12, 2007
Hi,
I have looked all over the web to try to find some very basic / simple explanations of how to get a median value from a group of records in a table but with no luck
the problem i am having is that all the information i find is always centered around getting a median using every single row in the table. except i have groups of data in the table and want to work out a median for each group. the group is identified by 4 different columns (the 5th column is what i want to get the median on but for each group not the entire table) and i want to produce a resulting table that has 1 row for each group and therefore contains the median value for the group instead of the individual numbers that it currently has. e.g. the current table is like this
column1 column2 column3 column 4 column5(median of this)
value 1 value 2 value 3 value 4 1.2
value 1 value 2 value 3 value 4 1.0
value 1 value 2 value 3 value 4 1.5
value 2 value 3 value 4 value 5 0.2
value 2 value 3 value 4 value 5 0.4
etc...
and i need a query to get the results to show like this
column1 column2 column3 column 4 column5
value 1 value 2 value 3 value 4 1.0
value 2 value 3 value 4 value 5 0.3
etc...
This is driving me crazy and i will be very helpful if anyone can help
the statement i need to add it to is:
select pat_demid, pat_lastname, meas_gendate, meas_id, test_gendate, avg(srtot)as meansrtot, avg(sreff)as meansreff, avg(BFRaw)as BF_Rawmean, avg(BFTGV)as BF_TGVmean, count(srtot)as countsrtot, count(sreff)as countsreff
from bodyparametersf
where (srtot is not null) OR (sreff is not null)
group by pat_demid, pat_lastname, meas_gendate, meas_id, test_gendate
thanks very much
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May 29, 2007
I need to calculate Median on each calculated result from the query below. There is one Median function available in SQL2K but it is not working. Can anyone help me in this regard.
------------------------------------------------------------------------
SELECT INS.Code As [code],INS.FinYr as [YEAR], ' ' As [FIRE BUSINESS], (INSRev.FI_NetPremLessIns / INSRev.FI_GrPremium) * 100 As [Rention Ratio],
(INSRev.FI_NetClaimPaid/INSRev.FI_AdjNetPremium)*100 As [Claim Ratio], ((INSRev.FI_AgencyCommPaid+INSRev.FI_ReInsCommPaid+INSRev.FI_MgmtExpenses+INSRev.FI_OthExpenses)/INSRev.FI_AdjNetPremium)*100 As [Expense Ratio],
((INSRev.FI_NetClaimPaid/INSRev.FI_AdjNetPremium)*100)+(((INSRev.FI_AgencyCommPaid+INSRev.FI_ReInsCommPaid+INSRev.FI_MgmtExpe nses+INSRev.FI_OthExpenses)/INSRev.FI_AdjNetPremium)*100) As [Combine Ratio],
(INSRev.FI_ClosingBal/INSRev.FI_NetClaimPaid) As [Unexpired Risk Reserve to Net Claim(x)],(INSRev.FI_MgmtExpenses/INSRev.FI_AdjNetPremium)*100 As [Management Expenses to Adj. Net Premium],
(INSRev.FI_AgencyCommPaid/INSRev.FI_AdjNetPremium)*100 As [Agency Commissioned to Adj. Net Premium]
FROM
(InsuranceGen As INS LEFT JOIN INSURANCEGen As INS1 ON (INS1.FinYr=INS.FinYr-1 AND INS.Code=INS1.Code))
LEFT JOIN INSRevGen as INSRev ON (INS.Code=INSRev.Code AND INS.FinYr=INSRev.FinYr) WHERE INS.Code IN ('ABC1','ABC2','ABC3') AND INS.FinYr=2005 ORDER BY INS.Code, INS.FinYr
----------------------------------------------------------------------
Thanks
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Sep 7, 2007
Im trying to find a funtion for median's if there is one. can anyone help?
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Apr 22, 2008
Using SQL Server 2005, I have the following query to calculate the median sales of each quarter over the past 5 years:
WITH CompMedian AS
(
SELECT SoldDate, SoldPrice, ROW_NUMBER() OVER(PARTITION BY Convert(Varchar(5),Year(SoldDate)) + Convert(Varchar(5), RIGHT(CAST(100+DATEPART(QQ,SoldDate) AS CHAR(3)), 2)) ORDER BY SoldPrice) AS RowNum, COUNT(*) OVER(PARTITION BY Convert(Varchar(5),Year(SoldDate)) + Convert(Varchar(5), RIGHT(CAST(100+DATEPART(QQ,SoldDate) AS CHAR(3)), 2))) AS Cnt FROM tbl_Orders
WHERE Status = 'Sold'
AND SoldDate >= DATEADD(Year, -5, Convert(DateTime, Convert(Varchar(5),Month(GetDate())) + Convert(Varchar(5), '/1/') + Convert(Varchar(5), YEAR(GetDate()))))
AND SoldDate < DATEADD(Year, 0, Convert(DateTime, Convert(Varchar(5),Month(GetDate())) + Convert(Varchar(5), '/1/') + Convert(Varchar(5), YEAR(GetDate()))))
)
SELECT Convert(Varchar(5),Year(SoldDate)) + Convert(Varchar(5), RIGHT(CAST(100+DATEPART(QQ,SoldDate) AS CHAR(3)), 2)) AS CompDate, AVG(SoldPrice) AS CompMedian
FROM CompMedian
WHERE RowNum IN((Cnt + 1) / 2, (Cnt + 2) / 2)
GROUP BY Convert(Varchar(5),Year(SoldDate)) + Convert(Varchar(5), RIGHT(CAST(100+DATEPART(QQ,SoldDate) AS CHAR(3)), 2))
ORDER BY CompDate;
Now my client would like me to change the query so that each quarter would represent the median for the past 12 months ending with that quarter. I've been looking at this for hours and I'm at a loss. Anyone have any thoughts?
Thanks in advance,
Russ
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Dec 15, 2005
I am converting a report created using Crystal Reports 10 to Reporting Services. The report contains a list of items with dollar values. The original report displays both the Average and Median value. I can easily ( using avg(Field1.Value!) ) determine the average but cannot find a function to determine the median.
How can I add the Median to the report?
Thanks in advance,
Greg
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Feb 24, 2006
I have a table (cars) with 3 fields:VIN, Class, sell_price101, sports, 10000102, sports, 11000103, luxury, 9000104, sports, 11000105, sports, 11000106, luxury, 5000107, sports, 11000108, sports, 11000109, luxury, 9000i need to write a query that WITHOUT USING A FUNCTION will return themedian selling price for each class of car. result should look like:Class, Med_Priceluxury, 9000sports, 11000thanks to all u SQLers
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Jul 20, 2005
I read the follow query about calculating median posted by Daivd Portaon 10/8/03.CREATE TABLE SomeValues (keyx CHAR(1) PRIMARY KEY, valuex INTEGER NOTNULL)INSERT INTO SomeValues VALUES ('A',1)INSERT INTO SomeValues VALUES ('B',2)INSERT INTO SomeValues VALUES ('C',3)INSERT INTO SomeValues VALUES ('D',4)INSERT INTO SomeValues VALUES ('E',5)SELECT S1.valuex AS medianFROM SomeValues AS S1, SomeValues AS S2GROUP BY S1.valuexHAVING SUM(CASE WHEN S2.valuex <= S1.valuexTHEN 1 ELSE 0 END)[color=blue]>= ((COUNT(*) + 1) / 2)[/color]AND SUM(CASE WHEN S2.valuex >= S1.valuexTHEN 1 ELSE 0 END)[color=blue]>= (COUNT(*)/2 + 1)[/color]I have difficulty to understand the having clause. If S1 and S2 arethe same table, what it means by S2.valuex >= S1.valuex? Could somegive me a help?Also, if I have a table structured as:classID field1 field2 field3c1 1 2 3c1 4 5 6c1 7 8 9c2 9 8 7c2 6 5 4c2 3 2 1Is there a way to create a user-defined function that can get themedian for each field as easy as the average function. Such asselect distinct classID,median(field1),median(field2),median(field3)from [tablename]group by classIDThanks in advance
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Mar 4, 2008
I used the Median() function in a calculated measure in a cube. All seemed well until one of my users, a statistician, pointed out that the displayed values were incorrect. I investigated this and finally built the simplest cube with three records and the displayed median does not make sense, i.e. equal what a median value should be.
The 3 records have loan amounts as a measure with these values: $102,500, $168,400, and $172,181 and loan number keys of 1, 2, and 3. That's it.
The median should be $168,400 since the number of items is odd and that is the middle value.
But the cube calculated measure displays $170,290.50. It appears to be taking the average of the middle row and the next value.
When I increase the number of records I get the same odd behavior but it not only alternates (of course) with odd and even (since they use different formulats for odd and even) but the odd wrong results alternate within themselves. The apparent calculations for 5 or 7 records are different compared to 3, 9, 11, 13, 15, 17 records. The first set seems to be calculating odd number of items median by averaging the middle value + the value BEFORE the middle value while the second set of odd rows (3, 9, etc) seem to be calculating median by averaging the middle value + the value AFTER the middel value. The even numbers result in the larger of the two middle values being selected instead of the average (financial median) or the lower number (as one poster claimed for statistical median).
My calculated measure MDX is very simple:
MEDIAN( [Test Fact].[Loan Number].Members, [Measures].[Loan Amount])
Ideas anyone? Am I missing something? Is this a bug?
Thanks!
- Grant
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Oct 13, 2006
Hello!
I have been trying to find a T-SQL function that would calculates a Median statistical value for me. I am runnnig on SS 2005? Any examples of using this function would be greatly appreciated.
Thanks for any responses!
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May 28, 2015
I have a fact table fct_line_details having two columns mtid, productivity
mtid productivity
1 400
1 200
1 600
2 700
3 900
I want to calculate the median for each mtid in SSAS . (median for mtid 1=400 )
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Sep 14, 2015
I'm using custom code in an expression to calculate the median of a column. It works fine up to a point. Like if there are 35 rows in the result set (or up to some number) but when it gets bigger results, like 42 rows or more it doesn't work, the median is -1. This is the custom code I'm using (found online).
I don't see anything limiting the count, but it comes back with a -1 median so I think that means the count is not > 0.
I have a column in the report called arrival_to_complete which is like: 53 min
I create a column with expression: =MAX(Code.AddValue(Val(Fields!Arrival_to_complete.Value))) to fill the array using just the number part of the column. Then in the report I have 'Median =' <expression>, where the expression is: =Code.GetMedian() I run the report with 2 parameters a begin date and an end date. I don't see where any of this should be limiting the median calculation so I don't get why it works sometimes and not other times.
Dim values As New System.Collections.ArrayList
Function AddValue(newValue As Decimal)
If values is Nothing Then
values = New System.Collections.ArrayList
End If
values.Add(newValue)
[code]....
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May 24, 2007
I am facing some problem in calculating Median
I am trying to calculate the median value using one of the measures and a dimension value.
Time is a measure in my cube and OpId is one of the dimensions.The result is as follows:
opid time median
1 55
2 23
3 23
Total 23
The Time here for Op Id 1 is the aggregation for all the rows whose OpId is 1.I want the median of the values whose OpId is 1 which is not showing at the moment.
What I am getting here is the median for all of the OpId but what I really want is the median for each of the individual Opid's as well.
I am using a calculated field Median with the following expression.
MEDIAN
( [Dim Operation].[Dim Operation].currentmember.children ,[Measures].[Elapsed Time])
Thanks
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Jan 24, 2006
I have a table of sample data
Samples(sample_no, sample_date..)
I have no idea how to do the following in sql server or if its even possible:
1. Calculate the difference in days between all samples.
2. Select the median result
Any trick to get this done would be really helpful
thanks,
DB
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Jan 24, 2006
I have a table of sample data
Samples(sample_no, sample_date..)
I have no idea how to do the following in sql server or if its even possible:
1. Calculate the difference in days between all samples.
2. Select the median result
Any trick to get this done would be really helpful
thanks,
DB
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