How can I order the results of my query in non-linear fasion. I have a
field with these values: Reg S, 144A, US and want to order my results
by US, 144A, Reg S.
I would prefer not to create another field in the table if possible.
my data is like this:
header | data | key
-------------------
500 | 3.2 | 10
500 | 3.4 | 20
500 | 3.6 | 25
500 | 3.7 | 40
501 | 4.1 | 10
501 | 4.2 | 15
501 | 4.4 | 30
501 | 4.6 | 35
and what I want to do is find the median of "data", but keyed off of "key", so if my desired median is 30, I want to take the two records (data, key) nearest to key = 30, and get the average of "data".
...and do this within each "header" value.
actually, to be precise, I want the linear interpolation, so for header = 500, I want to get the (data, key) pairs of (3.6, 25) and (3.7, 40) and return the interpolated "data" value of 3.6333 (as done here (http://en.wikipedia.org/wiki/Linear_interpolation))
so for the above example the query would produce:
header | interp
-----------------
500 | 3.633
501 | 4.4
possible, or am I crazy?
This is a real challenge. I hope someone is smart enough to know howto do this.I have a tableTABLE1[Column 1- 2001][Column 2- 2002][Column 3- 2003][Column 4 - 2004][Column 5 - 2005][Column 6 - 2006][Column 7 - Slope][2001][2002][2003][2004][2005][2006] [Slope][1] [2] [3] [4] [5] [6] [1][1.2] [.9] [4] [5] [5.4] [6.2] [?]Slope is defined as "M" in the equation y=mx+bI need a way a finding the linear equation that best fits the points soI can have SQL calculate the slope.Are there any smart people around that would know how to do this?thanks
View 3 Replies View RelatedHi all
i wants to generate linear sequence number like 1,2,3,.............1000000
,are there any function like NEWID() ( this return unique guide, i want to get integer)
i want to used this generated number inside the SQL query
thanks
IndikaD (Virtusa Cop)
I would like to understand the algorithm that the linear regression method uses to choose the regressors in the model from a list of possible regressors.
I think that it is different from the common methods used in statistics like stepwise, forward or backward.
Laura Lerner
We are trying to create a model of linear regression with nested table. We used the create mining model sintax as follow :
create mining model rate_plan3002_nested2
( CUST_cycle LONG KEY,
VOICE_CHARGES double CONTINUOUS predict,
DUR_PARTNER_GRP_1 double regressor CONTINUOUS ,
nested_taarif_time_3002 table
( CUST_cycle long CONTINUOUS,
TARIFF_TIME text key,
TARIFF_VOICE_DUR_ALL double regressor CONTINUOUS
)
) using microsoft_linear_regression
INSERT INTO MINING STRUCTURE [rate_plan3002_nested2_Structure]
(CUST_cycle ,
VOICE_CHARGES ,
DUR_PARTNER_GRP_1 ,
[nested_taarif_time_3002](SKIP,TARIFF_TIME ,TARIFF_VOICE_DUR_ALL)
)
SHAPE {
OPENQUERY([Cell],
'SELECT CUST_cycle ,
VOICE_CHARGES ,
DUR_PARTNER_GRP_1
FROM dbo.panel_anality_3002
order by CUST_cycle ')}
APPEND
({OPENQUERY([Cell],
'select CUST_cycle,
TARIFF_TIME,
CYCLE_DATE
from dbo.nested_taarif_time_3002
order by CUST_cycle,TARIFF_TIME')
}
relate CUST_cycle to CUST_cycle
) as nested_taarif_time_3002
The results we got are a model with intercept only. if we don't use the nested variable (the red line) we get a rigth model . (we had more variable ....)
Is there a way to do this regression correctly?
Thanks,
Dror
When using linear regression in the SQL Server 2005 Business IntelIigence Studio I interpet the information below as follow: X has a standard deviation of +- 37.046. Is it possible to obtain the standard deviation of each coefficient in the regression expression?
Hi,
I am trying to create a model using microsoft Linear Regression algorithm. But I want to constrain the coefficient of the parameters to non-negative value. There is concept of bound in SAS where we can specify the range of the coefficient. Does any of the SSAS mining algorithms support restricting the coefficient value?
Thanks,
DMN
Q1. Model Prediction -- Suppose we already have a trained Microsoft Linear Regression Mining Model, say, target y regressed on two variables:
x1 and x2, where y, x1, x2 are of datatype Float. We try to perform Model Prediction with an Input Table in which some records consist of NULL x2 values. How are the resulting predicted y values calculated?
My guess:
The resulting linear regression formula is in the form:
y = constant + coeff1 * (x1 - avg_x1) + coeff2 * (x2 - avg_x2)
where avg_x1 is the average of x1 in the training set, and avg_x2 is the average of x2 in the training set (Correct?).
I guess that for some variable being NULL in the Input Table, Microsoft Linear Regression just treat it as the average of that variable in the training set.
So for x2 being NULL, the whole term coeff2 * (x2 - avg_x2) just disappear, as it is zero if we substitute x2 with its average value.
Is this correct?
Q2. Model Training -- Using the above example that y regressed on x1 and x2, if we have a train set that, say, consist of 100 records in which
y: no NULL value
x1: no NULL value
x2: 70 records out of 100 records are NULL
Can someone help explain the mathematical procedure or algorithm that produce coeff1 and coeff2?
In particular, how is the information in the "partial records" used in the regression to contribute to coeff1 and the constant, etc ?
Q1. Model Prediction -- Suppose we already have a trained Microsoft Linear Regression Mining Model, say, target y regressed on two variables:
x1 and x2, where y, x1, x2 are of datatype Float. We try to perform Model Prediction with an Input Table in which some records consist of NULL x2 values. How are the resulting predicted y values calculated?
My guess:
The resulting linear regression formula is in the form:
y = constant + coeff1 * (x1 - avg_x1) + coeff2 * (x2 - avg_x2)
where avg_x1 is the average of x1 in the training set, and avg_x2 is the average of x2 in the training set (Correct?).
I guess that for some variable being NULL in the Input Table, Microsoft Linear Regression just treat it as the average of that variable in the training set.
So for x2 being NULL, the whole term coeff2 * (x2 - avg_x2) just disappear, as it is zero if we substitute x2 with its average value.
Is this correct?
Q2. Model Training -- Using the above example that y regressed on x1 and x2, if we have a train set that, say, consist of 100 records in which
y: no NULL value
x1: no NULL value
x2: 70 records out of 100 records are NULL
Can soemone help explain the mathematical procedure or algorithm that produce coeff1 and coeff2?
In particular, how is the information in the "partial records" used in the regression to contribute to coeff1 and the constant, etc ?
With the number of threads it is difficult to know if this has been posted. If I use the Mining Content Viewer for Linear Regression, under Node Distribution, there are values given for Attribute Name, Attribute Value, Support, Probability, Variance, and Value Type. The output is similar to what Joris supplied in his thread about Predict Probability in Decision Trees. My questions:
1. How should these fields be interpreted?
2. With Linear Regression, is it possible to get the coefficient values and tests of significance (t-tests?), if they are not part of the output I have pointed to?
Thanks for your help with this?
Sam
I'm using a bullet chart in a SSRS report and I want to set the Maximum value in the Linear Scale properties to highest value of the following 4 fields. Is there any way to do this?? This will make all charts line up properly.
NC_LAST_YEAR
NC_LINKED
NC_CURRENT
NC_PLAN
Finding the "pieces of information" I need to successfully install the SQL Server Express edition is so complex. Uninstalls do "not" really uninstall completely, leading to failure of SQL install. Can you suggest a thorough, one-stop site for directions for the order of app uninstalls and then the order for app installs for the following...
SQL Server Express edition
Visual Studios 2005
Jet 4.0 newest upgrade
.Net Framework 2.0 (or should I use 3.0)
VS2005 Security upgrade
Anything else I need for just creating a database for my VS2005 Visual Basic project?
I was trying to use MS Access as my backend db but would like to try SQL Express
Thank you, Mark
In SQL sERVER 2008, I have two fields - Depatment and Employees. I need to sort the result set by employee number ascending order, with following exception
1)when department number = 50 - the preferred order is Employee # - 573 followed by 551-572 (employee # belong to Dept 50 = 551-573)
2)When Department number = 20 – the preferred sort order is Employee # 213-220, followed by Employee # 201-213 (employee # belong to Dept 20 = 201-220)
How shall I achieve this?
I never paid much attention to this before but I noticed this today in a new table I was creating.
For tables defined in the tabular model the table properties have something like SELECT Blah FROM TableName ORDER BY Blah Then in the tabular model the table's data is in the same order it was ordered by in the data source for the table.
I have a date table I setup and I noticed it is NOT respecting the sort order.
I have it sorted by DateID which sorts with the oldest date first and newest date as last row.However, the table that is imported and stored in the data model is not in that order.
I can of course manually sort the rows in BIDS/DataTools, but I find this discrepancy odd.
Would this have negative impacts on the EARLIER function for example if the data rows are not in the order specified?
I have a query that calculate the total amount of order details based on a particular order:
Select a.OrderID,SUM(UnitPrice*Quantity-Discount)
From [Order Details]
Inner Join Orders a
On a.OrderID=[Order Details].OrderID
Group by a.OrderID
My question is what if I wanted to create a formula to something like:
UnitPrice * Quantity - DiscountAmount Where DiscountAmount = UnitPrice Quantity * Discount
Do I need to create a function for that? Also is it possible to have m y query as a table variable?
Hi!
I recently run into a senario when a procedure quiered a table without a order by clause. Luckily it retrived data in the prefered order.
The table returns the data in the same order in SQL Manager "Open Table"
So I started to wonder what deterimins the sort order when there is no order by clause ?
I researched this for a bit but found no straight answers. My table has no PK, but an identiy column.
Peace.
/P
Hey guys, i need to find out how can i add order items under a Purchase Order number.
My table relationship is PurchaseOrder ->PurchaseOrderItem.
below is a Stored Procedure that i have wrote in creating a PO:
CREATE PROC spCreatePO (@SupplierID SmallInt, @date datetime, @POno SmallInt OUTPUT)
AS
BEGIN
INSERT INTO PurchaseOrder (PurchaseOrderDate, SupplierID) VALUES(@date, @SupplierID)
END
SET @POno = @@IDENTITY
RETURN
However, how do i make it that it will automatically adds item under the POno being gernerated? can i use a trigger so that whenever a Insert for PO is success, it automaticallys proceed to adding the items into the table PurcahseOrderItem?
CREATE TRIGGER trgInsertPOItem
ON PurchaseOrderItem
FOR INSERT
AS
BEGIN
'What do i entered???'
END
RETURN
help is needed asap! thanks!
hi basically what i have is 3 text boxes. one for start date, one for end date and one for order id, i also have this bit of SQL
SelectCommand="SELECT [Order_ID], [Customer_Id], [Date_ordered], [status] FROM [tbl_order]WHERE (([Date_ordered] >= @Date_ordered OR @Date_ordered IS NULL) AND ([Date_ordered] <= @Date_ordered2 OR @Date_ordered2 IS NULL OR (Order_ID=ISNULL(@OrderID_ID,Order_ID) OR @Order_ID IS NULL))">
but the problem is it does not seem to work! i am not an SQL guru but i cant figure it out, someone help me please!
Thanks
Jez
Hi,
We got a problem.
supposing we have a table like this:
CREATE TABLE a (
aId int IDENTITY(1,1) NOT NULL,
aName string2 NOT NULL
)
go
ALTER TABLE a ADD
CONSTRAINT PK_a PRIMARY KEY CLUSTERED (aId)
go
insert into a values ('bank of abcde');
insert into a values ('bank of abcde');
...
... (20 times)
select top 5 * from a order by aName
Result is:
6Bank of abcde
5Bank of abcde
4Bank of abcde
3Bank of abcde
2Bank of abcde
select top 10 * from a order by aName
Result is:
11Bank of abcde
10Bank of abcde
9Bank of abcde
8Bank of abcde
7Bank of abcde
6Bank of abcde
5Bank of abcde
4Bank of abcde
3Bank of abcde
2Bank of abcde
According to this result, user see the first 5 records with id 6, 5, 4, 3, 2 in page 1, but when he tries to view page 2, he still see the records with id 6, 5, 4, 3, 2. This is not correct for users. :eek:
Of course we can add order by aid also, but there are tons of sqls like this, we can't update our application in one shot.
So I ask for your advice here, is there any settings can tell the db use default sort order when the order by column value are the same? Or is there any other solution to resolve this problem in one shot?
Hi,guys!I have a table below:CREATE TABLE rsccategory(categoryid NUMERIC(2) IDENTITY(1,1),categoryname VARCHAR(20) NOT NULL,PRIMARY KEY(categoryid))Then I do:INSERT rsccategory(categoryname) VALUES('url')INSERT rsccategory(categoryname) VALUES('document')INSERT rsccategory(categoryname) VALUES('book')INSERT rsccategory(categoryname) VALUES('software')INSERT rsccategory(categoryname) VALUES('casus')INSERT rsccategory(categoryname) VALUES('project')INSERT rsccategory(categoryname) VALUES('disert')Then SELECT * FROM rsccategory in ,I can get a recordeset with the'categoryid' in order(1,2,3,4,5,6,7)But If I change the table definition this way:categoryname VARCHAR(20) NOT NULL UNIQUE,The select result is in this order (3,5,7,2,6,4,1),and 'categoryname 'in alphabetic.Q:why the recordset's order is not the same as the first time since'categoryid' is clustered indexed.If I change the table definition again:categoryname VARCHAR(20) NOT NULL UNIQUE CLUSTEREDthe result is the same as the first time.Q:'categoryname' is clustered indexed this time,why isn't in alphabeticorder?I am a newbie in ms-sqlserver,or actually in database,and I do havesought for the answer for some time,but more confused,Thanks for yourkind help in advance!
View 2 Replies View RelatedHi,
We got a problem.
supposing we have a table like this:
CREATE TABLE a (
aId int IDENTITY(1,1) NOT NULL,
aName string2 NOT NULL
)
go
ALTER TABLE a ADD
CONSTRAINT PK_a PRIMARY KEY CLUSTERED (aId)
go
insert into a values ('bank of abcde');
insert into a values ('bank of abcde');
...
... (20 times)
select top 5 * from a order by aName
Result is:
6 Bank of abcde
5 Bank of abcde
4 Bank of abcde
3 Bank of abcde
2 Bank of abcde
select top 10 * from a order by aName
Result is:
11 Bank of abcde
10 Bank of abcde
9 Bank of abcde
8 Bank of abcde
7 Bank of abcde
6 Bank of abcde
5 Bank of abcde
4 Bank of abcde
3 Bank of abcde
2 Bank of abcde
According to this result, user see the first 5 records with id 6, 5, 4, 3, 2 in page 1, but when he tries to view page 2, he still see the records with id 6, 5, 4, 3, 2. This is not correct for users.
Of course we can add order by aid also, but there are tons of sqls like this, we can't update our application in one shot.
So I ask for your advice here, is there any settings can tell the db use default sort order when the order by column value are the same? Or is there any other solution to resolve this problem in one shot?
I have created view by jaoining two table and have order by clause.
The sql generated is as follows
SELECT TOP (100) PERCENT dbo.UWYearDetail.*, dbo.UWYearGroup.*
FROM dbo.UWYearDetail INNER JOIN
dbo.UWYearGroup ON dbo.UWYearDetail.UWYearGroupId = dbo.UWYearGroup.UWYearGroupId
ORDER BY dbo.UWYearDetail.PlanVersionId, dbo.UWYearGroup.UWFinancialPlanSegmentId, dbo.UWYearGroup.UWYear, dbo.UWYearGroup.MandDFlag,
dbo.UWYearGroup.EarningsMethod, dbo.UWYearGroup.EffectiveMonth
If I run sql the results are displayed in proper order but the view only order by first item in order by clause.
Has somebody experience same thing? How to fix this issue?
Thanks,
I am getting the resultset sorted differently if I use a column number in the ORDER BY clause instead of a column name.
Product: Microsoft SQL Server Express Edition
Version: 9.00.1399.06
Server Collation: SQL_Latin1_General_CP1_CI_AS
for example,
create table test_sort
( description varchar(75) );
insert into test_sort values('Non-A');
insert into test_sort values('Non-O');
insert into test_sort values('Noni');
insert into test_sort values('Nons');
then execute the following selects:
select
*
from
test_sort
order by
cast( 1 as nvarchar(75));
select
*
from
test_sort
order by
cast( description as nvarchar(75));
Resultset1
----------
Non-A
Non-O
Noni
Nons
Resultset2
----------
Non-A
Noni
Non-O
Nons
Any ideas?
I have a DB with items which can have lengths from 0 to 400 meter.In my resultset I want to show the items with length 1-400 meter and then the results with length 0 meterHow to build my SQL?
View 4 Replies View RelatedI noticed the StockDate is not sorted in proper order, like ascending order...
Code:
select top 1000 CONVERT(char, StockDate, 101) AS StockDate, timestamp from tblpurchaseraw where accountid = '119' order by stockdate desc
I noticed that StockDate is a datetime datatype so why does the month get ordered 1st, then day get ordered 2nd and year get ordered 3rd...
The sample data is MM/DD/YYYY...
So, how do I get it ordered propery by Year, Month then Day??
Lets say I have a table named [Leadership] and I want to select the field 'leadershipName' from the [Leadership] Table.
My query would look something like this:
Select leadershipName
From Leadership
Now, I would like to order the results of this query... but I don't want to simply order them by ASC or DESC. Instead, I need to order them as follows:
Executive Board Members, Delegates, Grievance Chairs, and Negotiators
My question: Can this be done through MS SQL or do I need to add a field to my [Leadership] table named 'leadershipImportance' or something as an integer to denote the level of importance of the position so that I can order on that value ASC or DESC?
Thanks,
Zoop
Hi,
I have some hierarchical data in a table. Say for example:
Parent Child
------------------------
NULL 1
1 2
1 3
2 4
2 5
3 6
3 7
5 8
5 9
7 10
7 11
11 12
11 13
Now I want to be able to use CTE's to be able to traverse this tree in
1) level by level order 1,2,3,4,5,6,7,8,9,10....
2) in order 1,2,4,5,8,9,3,6,7,10,11,12,13...
What would be the aueries for this. Using the following i get: 1,2,3,6,7,10,11,12,13,4,5,8,9 (interesting and potentially useful) but I would like to be able to experiment with the aforementioned orders as well.
with Tree (id)
as
(
select id from WithTest
where parent is null
union all
select a.id
from Tree b join WithTest a
on b.id = a.parent
)
select * from Tree
Any ideas? Thanks.
Hi!
For the Orders table (let's assume for the Northwind database), I'm trying
to get the order id of the latest order for every customer.
That means that the result should be one record per customer and that would
display CustomerID and OrderID.
Any ideas?
Thanks,
Assaf
The data file is a simple Unicode file with lines of text. BCPapparently doesn't guarantee this ordering, and neither does theimport tool. I want to be able to load the data either sequentially oradd line numbering to large Unicode file (1 million lines). I don'twant to deal with another programming language if possible and Iwonder if there's a trick in SQL Server to get this accomplished.Thanks for any help.Mark Leary----== Posted via Newsfeeds.Com - Unlimited-Uncensored-Secure Usenet News==----http://www.newsfeeds.com The #1 Newsgroup Service in the World! >100,000 Newsgroups---= East/West-Coast Server Farms - Total Privacy via Encryption =---
View 15 Replies View RelatedHi ,
i am dealing with around 14000 rows which need to be put into the sql destination.,But what i see is that the order of the rows in the desination is not the same as in the source,
However it is same for smaller number of rows.
Please help ...i want the order to be same.
Hi all,
I had one question on sql statement.
I had a table with a field named severity. The field severity will either consist of Minor, Moderate or Severe. How can I construct an sql statement whereby the severity will be order as Severe follow by Moderate and Minor.
Thanks
Hi All, I have a question in sql.... How can i sort a select statement depending on nvarchar not on Int ??My select statement is : " select * from table1 order by st_name asc"can anyone help me? thanks a lot
View 3 Replies View Related