Successive Records With Self Join

We are using a presence checker to register when our employees show up at work, when they leave and whenever they change their working section.

The raw data has this format:

TABLE
-----

TIMESTAMP USERID SECTION INCIDENCE
------------------------------------------------------
2014-06-27 14:52:40.000 77675669 7 0
2014-06-27 15:08:33.000 77675669 6 8
2014-06-27 15:30:58.000 77675669 7 12
2014-06-27 18:52:00.000 77675669 11 15
2014-06-27 19:47:38.000 77675669 7 12
2014-06-27 23:30:18.000 77675669 7 0

In order to determine the exact time people had been working in the sections I have to match every record with the record of the successive timestamp I do:

SELECT TIMESTAMP as START, USERID, SECTION, INCIDENCE, MIN(TIME_END) as STOP
FROM (
SELECT *, TABLE2.TIMESTAMP as TIME_END
FROM TABLE
LEFT OUTER JOIN TABLE as TABLE2 on TABLE.USERID = TABLE2.USERID and
TABLE2.TIMESTAMP > Table.TIMESTAMP and

[Code] ....

How do I get the incidence of the successive timestamp in my query?

The key trick is that I first do a self join which increases the amount of records, including senseless matches from the first timestamp with the last one of that day. Afterwards I group by all columns of TABLE in order to get only the successive timestamp.

But once I include TABLE2.INCIDENCE in the GROUP BY clause, of course the query stops working correctly.

I can't use the TIMESTAMP isself as it is not singular (there are several terminals in the plant); and I prefer not to use Timestamp in combination with Userid, as the userid is actually not stored directly and has to be retrieved through a couple of joined tables. Any smarter way to include a second column once the successive timestamp has been determined.